V = , TH tốc độ tàu tương ứng với chế độ
2.3.Chương trình tính.
3. Phân tích ảnh hưởng của chế độ chuyển tiếp đến sự mài mòn xilanh của động cơ Diesel.
2.3.Chương trình tính.
' CHUONG TRINH - thay doi tai
'L2t#0 co the tinh cho cac truong hop khi thay doi dieu kien ngoai:dong tai '(fid=0,hp=0,ntk=22000,ga=.21,va thay cac phu tai)-tang toc(thay cac gia tri 'cua cac thong so dong tai o thoi diem 10 giay vao thong so ban dau ntk,ga, 'fid,hp,nd,fizad)
' - Thay doi dieu kien moi truong voi cac phuong an khac nhau :
' + Khi giu nguyen ap suat,thay doi nhiet do moi truong P0=95000pa,T0 = 0 ' 20,43 do c
' +Khi giu nguyen nhiet do,thay doi ap suat moi truong T0 = 0 hoac 20,40 'va thay doi P0 = 95000,101300,102000.
' - Phu tai thay doi theo chu ky : Tn = .5 + .5*sin(a*tim)
' a=1.58 - tan so 0,25 Hz ; 3.18 - tan so 0,5 Hz ; 6.28 - tan so 1 Hz ' - Phu tai khong thay doi : Tn = A ; A= .5 ; .75 ; .9 ; 1
' Tr = .5 ; 1 ; 3 ;
' Momen quan tinh tuabin-may nen : J = .027 ; .04 ' Tang ap cao (nn;pitn;picn;pefn;gan;bn):
' - tang ap xung (cac he so k1,k2,k3,k4 >0) ' - tang ap dang ap (cac he so k1=k2=k3=k4 =0)
' Thay doi luong nhien lieu cap vao de thay doi he so alfa va cac thong so ' khac hpm = .73 + .07 * tim va hpm = .8 , hpm=1.1
DECLARE SUB koeffimp (pd!, p0!, kn!) DECLARE SUB ghidia (tim!, n!, alf!, ei!) DECLARE SUB dothi (x1!, y1!, x2!, y2!, col!)
DECLARE SUB form (t$, x!, y!, a!, b!, c!, d!, e!, f!, g!, H!, v!, n!, j!, z!, o!, p!, i!, u!, m!, s!)
'DECLARE SUB turbina (gg!, ggn!, nras!, rr!, ff!, mfen!, p2n!, p0!, n!, ucopt!, ucn!, etn!, flag!, pd!, tg!, nt!)
'DECLARE SUB koeffimp (pd!, p0!, kn!)
DECLARE SUB timgraf (lm!, rm!, um!, dm!, col!, tbeg!, tend!, parbeg!, parend!, t!, par!)
DECLARE SUB comp (T0, p0, pic!(), ec!(), n!, gac!, by!, ay!, bx!, ax!, pic!, ec!) 'DECLARE SUB Mexn (a1!, b!, s!, ndn!, aa!, pefn!, cm!)
' TUA BIN - MAY NEN
' TINH TOAN CHE DO KHONG ON DINH 'Cac hang so
CONST k = 1.41, pi = 3.1415, r = 287
CONST lo = 14.3, tatm = 273, patm = 101300 CONST kg = 1.35, Rg = 285, khr = 1123 'Dieu kien ngoai
T0 = 293 p0 = 103000
'Cac ham cong thuc tinh
DEF fni (a, b, c, d) = a + (b - a) * (c - d)
DEF fnras (rr, pp, ff) = (1 - rr / 2 * (pp - 1)) ^ 2 + ff ^ 2
DEF fnri (a) = 1.065 - .426 / a ^ (3 / 2)
DEF fntm (nd, pint) = (a1 + b1 * nd) / aa * (pint / pintn) ^ .1 * (km - 1) '*******
fmt1$ = "tim= ##.## ntk= ##### Nt=##### Nk=##### wc=#.#### alfc=#.#### eic=#.####"
fmt2$ = " Pint ###### Pa P1=Pg=###### Pa tr= #.# jtk=#.### hpmax=#.## fimax=#.######"
'fmt2$ = " alfa ##.### ’g = ####.#, eta= #.### pik= #.###"
fmt4$ = "nd ###.## ttq= #.### bco= #.#### bsum= #.#### hp #.### ro=#.### be=#.###" (adsbygoogle = window.adsbygoogle || []).push({});
'*******
' So lieu ban dau ' Dong co CONST d = .18, s = .22, e = 11, z = 6 CONST vsz = pi * d * d / 4 * s * (1 + 1 / e) * z CONST tdies = 4'3.4 CONST tr = .5 CONST kr = 50
alfm = 2: eim = .4: dei1 = .0536: dei2 = .133: df = .214 falfn = .145: falf = .564 ac = .533: dc = .048: dc1 = .023: dc2 = .012 gc1 = .0024: gc2 = .00413 aw = .785: bw = .0215: bw1 = .011: bw2 = .006 gw1 = .00115: gw2 = .0016 m1 = .42: m2 = .058 ee = 0 '******
' Ton that co gioi a1 = 120000: bp = 16000' b1 = bp * s / 30
ndn = 750: pefn = 753000
'CALL Mexn(a1, bp, s, ndn, aa, pefn, km) aa = a1 + bp * s * ndn / 30
etmn = 1 / (1 + aa / pefn)'hieu suat co gioi etm km = 1 / etmn
'****** 't = T0
'Bau lam mat khong khi tawng ap tw = 293 etcool = .67: etgxn = .97 '****** 'Tua bin nn = 32000 p2n = p0: pitn = 1.364 p1n = pitn * p2n pitx = 1.07: p2x = p0 p1x = pitx * p2x '******
'CHE DO DINH MUC tgn = 623
ein = .867 * .42: ecn = .72
gan = .337'thay lai Pint=1,46;Pitn=1.3;gan=0,337 bn = .0139'bn=Ge/3600=50/3600=0,0139
ggn = gan + bn '****** 'May nen picn = 1.54 pdn = picn * p0 tdn = T0 * (1 + (picn ^ ((k - 1) / k) - 1) / ecn) dpcooln = (1 - etgxn) * pdn
ksicool = dpcooln * pdn / gan ^ 2 / tdn tintn = tdn - (tdn - tw) * etcool
pintn = pdn - dpcooln rointn = pintn / r / tintn sprn = SQR(pintn * rointn) pspn = fnpsipr(p1n / pdn)
fin = gan / (fcn * (rointn * ndn * vsz / 30 / 4)) alfn = gan / lo / bn / fin
dgpn = (fin - 1) * gan '*******
'CHE DO KHONG TAI
tgx = 473: ndx = 750: ecx = .6 gax = .21: bco = .108: bx = .0026: fcx = fcn 'May nen pdx = 106300 picx = pdx / p0 tdx = T0 * (1 + (picx ^ ((k - 1) / k) - 1) / ecx) tintx = tdx - (tdx - tw) * etcool
dpcoolx = (gax / gan) ^ 2 * ((tdx / tdn) / (pdx / pdn)) * dpcooln pintx = pdx - dpcoolx
fipx = gax / (fcx * (pintx / tintx / r * ndx * vsz / 30 / 4)) alfx = gax / lo / bx / fipx
eixo = fnri(alfx) / fnri(alfn) dgzx = (1 - fcn) * gax tmx = fntm(ndx, pintx) bcxo = tmx / km / eixo 'He so tinh xung tang ap CONST mega = 1000000 k1i = 0' .005
k2i = 0' .0015 k3i = 0' .033 k4i = 0' .012
rr = .4'Muc do phan kich ff = .82
nras = fnras(rr, pitn, ff)
w = (1 / pitn) ^ (2 / kg) - (1 / pitn) ^ ((kg + 1) / kg) psi = SQR(2 * (kg / (kg - 1)) * w) mfen = ggn / SQR(p1n ^ 2 / Rg / tgn) / psi CONST jtk = .04, rk = .07 CONST ku = pi * rk / 30 un = ku * nn hrn = khr * tgn * (1 - (p2n / p1n) ^ ((kg - 1) / kg)) cn = SQR(2 * hrn) ucopt = .42 + .28 / .6 * rr ucn = un / cn / ucopt: etn = .72 'Nap dac tinh may nen vao chuong trinh CLS
namf$ = "c:fi2.dat"
'INPUT "Dua vao ten fai so lieu ", namf$: namf$ = namf$ + ".dat" PRINT "Fai dang nap"; namf$
OPEN namf$ FOR INPUT AS #1 INPUT #1, ng, nv, ay, by, ax, bx DIM ec(ng, nv), pic(ng, nv) FOR y = 0 TO nv
' Tren xuong (adsbygoogle = window.adsbygoogle || []).push({});
n = ay * y + by: PRINT n ' trai sang phai
FOR x = 0 TO ng ga = ax * x + bx
INPUT #1, pic(x, y), ec(x, y) NEXT
NEXT CLOSE #1
CLS : SCREEN 2
LOCATE 25, 1: PRINT " Ve dac tinh khong (Y/N) ?" GOSUB os:
IF q$ = "Y" OR q$ = "y" THEN GOSUB figraf: GOSUB osq:
CLS
p$ = " Ket thuc tinh (Y/N) ? "
DIM tim(1200), ei(1200), pint(1200), tg(1200), nd(1200), alf(1200), npr(1200), b(1200), be(1200), tint(1200), ttq(1200), Ge(1200), etm(1200), ete(1200), Ne(1200)
n = 22000
tint = tintx: ga = .21: gad = ga pitr = pitx: pit = pitr: pic = picx pc = p0 * pic: p1 = p1x fid = 0: hp = 0
ws = (pi * n / 30) ^ 2 nd = 750: wd = nd / ndn H = .01
tim(0) = 0: bsum = 0: fimax = 0: alfmin = 0: ndmin = 250: fimin = 0 hr = .00001
grafinterval = .1: timg = 0 alfint = 0'chi so khoi tich phan
alfdop = 1.45'gia tri alfa xuat hien khoi
wyc = 78: wn = 0: eis = 0: kozs = 0: boss = 0 i = 0
'beep '*******
DO'Bat dau chu trinh tim = tim + H
'IF tim >= .01 THEN H = .02 Esc$ = INKEY$
IF Esc$ = CHR$(27) THEN LOCATE 25, 1: PRINT p$; : GOSUB os: IF q$ = "Y" OR q$ = "y" THEN EXIT DO
DO'tim kiem diem lam viec dong thoi IF ga >= .2 AND n >= 20300 THEN
CALL comp(T0, p0, pic(), ec(), n, ga, by, ay, bx, ax, pic, ec) td = T0 * (1 + (pic ^ ((k - 1) / k) - 1) / ec)
pd = pic * p0 + 10 ELSE
flag = 1: td = T0: pd = p0 END IF
'Dong co
'Bau lam mat khong khi tang ap 'td, pd - ap suat, nhiet do sau may nen
'tint, pint - ap suat, nhiet do sau bau lam mat tint = td - (td - tw) * etcool
dpcool = ksicool * gad ^ 2 * td / pd pint = pd - dpcools
'Dac tinh suat tieu hao qua dong co nd = 750 (adsbygoogle = window.adsbygoogle || []).push({});
roint = pint / r / tint
gad1 = roint * nd * vsz / 30 / 4 spro = SQR(pint * roint) / sprn IF pspn = 0 THEN pspn = 1 IF (pint - p1) > 0 THEN
dg = spro * fnpsipr(p1 / pint) / pspn * wd * dgpn ELSEIF (pint - p1) < 0 THEN
dg = -spro * fnpsipr(pint / p1) / pspn * wd * dgzx END IF
gad = (gad1 + dg)
gadpr = gad * patm / p0 * SQR(T0 / tatm) IF dg > 0 THEN fipr = gad / gad1 ELSE fipr = 1 delg = gad - ga
'IF 7.32 >= tim >= 7.2 THEN LPRINT USING " pic =#.### Ga=#.### dg=#.###"; pic; ga; dg;
LOCATE 23, 2: PRINT USING " Gd =#.### Ga=#.### dg=#.###"; gad; ga; dg; IF ABS(gad - ga) < (.05 * ga) THEN EXIT DO
ga = (ga + gad) / 2 LOOP
gad = ga' Ket thuc tinh gan dung '********
'Giai phuong trinh vi phan dong co va bo dieu toc
'IF tim <= 1 THEN tn = tim ^ .5 ELSE tn = tim ^ 1.3 / (tim ^ 1.29 + tim ^ .4 - 1) 'IF tim < 10 THEN tn = .9 ELSE tn = .5
tn = .9
dfid = (ti - tn - tm) / tdies
dhp = (-33 * (fid - fizad) - hp) / tr fid = fid + dfid * H
wd = 1 + fid
IF wd > 1 THEN wd = 1 nd = wd * ndn
wnd = .1047 * nd
IF wnd <= wyc THEN delwnd = (wyc - wnd) * H / wyc wn = wn + delwnd
wc = wn / tim'chi so chat luong chu trinh IF ABS(fid) > ABS(fimax) THEN fimax = fid ndmin = (ndn + (fimax * ndn))
IF ABS(fid) < ABS(fimin) THEN tpr = tim hp = (hp + (dhp * H))
hpmax = 1.1
IF hp < 0 THEN hp = 0
IF hp < -bcxo THEN hp = -bcxo bco = (bcxo + hp) / (bcxo + 1) bc = bco * bcn b = bc * nd * z / 120 Ge = b * 3600 bsum = bsum + b * H dee = .1047 * nd * (ti - tm) * H Ne = .1047 * nd * (ti - tm) ee = ee + dee IF ee = 0 THEN ee = .00001 bm = bsum / ee
alf = gad / (lo * b)
IF alf > alfmin THEN alfmin = alf IF bco > 1 THEN bco = 1
IF alf <= 1.4 THEN dc = 0
IF alf <= alfdop THEN delalf = (alfdop - alf) * H ELSE delalf = 0 alfint = alfint + delalf
alfd = alfint
alfdc = alfint / tim 'chi so khoi 'Dac tinh kinh te cua dong co (adsbygoogle = window.adsbygoogle || []).push({});
ei = .267 * (alf - .1) ^ (1 / (alf + .2)): eio = ei / ein eis = eis + ei * H
eic = eis / tim 'Dac tinh nhiet do
falf = falfn + df * (alf - alfn) IF falf > .35 THEN falf = .35
tg = (.8 * tint) + 2450 * (1 - enst - ei - .1) / (1.25 * alf) 'Ton that co khi
tm = fntm(nd, pint) ti = km * bco * eio etm = 1 - tm / ti ete = ei * etm ttq = (ti - tm) * 2012 Ne = (ttq * nd / 9550) be = Ge / Ne IF tim = .01 THEN
CALL form("tim=.01", 3, 62, nd, (ti - tm), fid, hp, bco, alf, tg, pint, ei, bsum, nn, pitn, picn, pefn, gan, bn, T0, p0)
END IF IF flag <> 1 THEN lc = 1005 * (td - T0) nc = gad * lc ELSE nc = 5E-10 * n ^ 3 * roint END IF
vtur: 'Tua bin gg = gad + b DO
'Dac tinh suat tieu hao, p2
mfe = SQR(nras / fnras(rr, pit, ff)) * mfen p2 = (gg / ggn) ^ 2 * (p2n - p0) + p0
'Tinh Pit
a = (gg / p2 / mfe) ^ 2 * Rg * tg / 2 / (kg / (kg - 1)) x = .5 + SQR(a + .25)
pitr = x ^ (kg / (kg - 1)) dpit = ABS(pit - pitr) IF dpit < .005 THEN EXIT DO pit = (pit + pitr) / 2:
LOOP pit = pitr
p1 = pit * p2
'Cong doan nhiet tren canh tua bin
hr = khr * tg * (1 - (1 / pit) ^ ((kg - 1) / kg)) 'Hieu suat tua bin
u = ku * n: cad = SQR(2 * hr) uc = (u / cad) / ucopt
et = (uc / ucn) * ((2 - uc) / (2 - ucn)) * etn IF et <= 0 THEN et = 0 IF flag = 1 THEN kn = 1.3 ELSE pdiz = (pd - p0) / mega kh = 1 + k1i / pdiz kgi = 1 + k2i / pdiz
etpop = 1 + k3i * (1 + k4i / pdiz) kn = kh * kgi * etpop
'CALL koeffimp(pd, p0, kn) END IF
'Cong suat tua bin
nt = hr * gg * et * kn
IF ABS(nt - nc) < .5 THEN EXIT DO 'Can bang cong suat TBMN
dw = (nt - nc) / jtk * 2 ws = ws + dw * H n = 30 / pi * SQR(ws) npr = n * SQR(tatm / T0) 'IF tim > 9.05 THEN GOTO gh:
LOCATE 1, 1: PRINT USING fmt1$; tim; n; nt; nc; wc; alfc; eic LOCATE 23, 33: PRINT USING "tn=#.#### pit #.### "; tn; pit 'LOCATE 22, 9: PRINT "0 3 6 9 12 15 18 21 24 27 t" LOCATE 22, 9: PRINT "0 2 4 6 8 10 12 14 16 18 t" 'LOCATE 22, 9: PRINT "0 1 2 3 4 5 6 7 8 9 t" LOCATE 3, 1: PRINT "750 1600" LOCATE 4, 1: PRINT "nd tg" LOCATE 7, 1: PRINT "650 300" LOCATE 9, 1: PRINT " 40 20 " LOCATE 10, 1: PRINT "ntk p1" LOCATE 13, 1: PRINT " 21 10" LOCATE 15, 1: PRINT "5.2 .47" LOCATE 16, 1: PRINT "alf ei" LOCATE 20, 1: PRINT " 1 .15"
LOCATE 2, 1: PRINT USING fmt2$; pint; p1; tr; jtk; hpmax; fimax;
LOCATE 24, 1: PRINT USING fmt4$; nd; ti - tm; bco; bsum; hp; roint; be;
LOCATE 25, 1: PRINT USING "ei #.### alf ##.### tg ####.# pic #.### kn #.## bm #.###### Ne=###.#"; ei; alf; tg; pic; kn; bm; Ne;
IF tim >= timg THEN (adsbygoogle = window.adsbygoogle || []).push({});
timg = timg + grafinterval CALL dothi(30, 20, 30, 60, 3) CALL dothi(30, 65, 30, 105, 3) CALL dothi(30, 110, 30, 160, 3)
'CALL timgraf(70, 470, 65, 105, 3, 0, 20, 0, 1.2, tim, bco) 'CALL timgraf(70, 470, 65, 105, 3, 0, 20, -.004, .085, tim, dg) 'CALL timgraf(70, 470, 65, 105, 3, 0, 20, .1, 1.2, tim, bc) 'CALL timgraf(70, 470, 65, 105, 3, 0, 20, .1, .6, tim, falf) CALL timgraf(70, 470, 20, 60, 3, 0, 20, 0, 1.6, tim, hp)
'CALL timgraf(70, 470, 65, 105, 3, 0, 20, 21000, 41000, tim, n) CALL timgraf(70, 470, 65, 105, 4, 0, 20, 100000, 200000, tim, pint) CALL timgraf(70, 470, 65, 105, 3, 0, 20, 100000, 200000, tim, p1) CALL timgraf(70, 470, 110, 160, 3, 0, 20, 0, 1.2, tim, ti - tm) 'CALL timgraf(70, 470, 20, 60, 3, 0, 20, 1.12, 1.8, tim, pic) 'CALL timgraf(70, 470, 20, 60, 3, 0, 20, .24, .356, tim, ga) CALL timgraf(70, 470, 20, 60, 3, 0, 20, 650, 750, tim, nd) 'CALL timgraf(70, 470, 20, 60, 3, 0, 20, .2, .9, tim, gad) 'CALL timgraf(70, 470, 20, 60, 3, 0, 20, 0!, .03, tim, b) CALL timgraf(70, 470, 110, 160, 3, 0, 20, 1, 10, tim, alf) 'CALL timgraf(70, 470, 20, 60, 3, 0, 20, 300, 2000, tim, tg) CALL timgraf(70, 470, 20, 60, 3, 0, 20, 0, .01, tim, alfd) CALL timgraf(70, 470, 20, 60, 3, 0, 20, 0, .01, tim, alfdc) CALL timgraf(70, 470, 110, 160, 3, 0, 20, .25, .57, tim, ei) CALL timgraf(70, 470, 110, 160, 3, 0, 20, 0, 1.2, tim, tn) END IF
'y = i kon:
alfint = alfint / tim'Chi so tich phan trung binh khoi trong qua trinh chuyen tiep bt = bn / tim * bsum * 3600
LOCATE 23, 2: PRINT "Suat tieu hao nhien lieu trung binh"; PRINT USING "Gtb = #.##### kg/s"; bt
PRINT " Do thay doi vong quay cuc dai";
PRINT USING "### 1/ph (##.# %)"; fimax * ndn; fimax * 100; 'GOSUB dia:
LOCATE 25, 1: PRINT "Goi lai - [ Enter ], Thoat - [ Esc ]"; DO
q$ = INKEY$
IF q$ = CHR$(27) THEN END IF q$ = CHR$(13) GOTO vcom: LOOP
' Chuong trinh con figraf:
SCREEN 2
VIEW (150, 20)-(450, 160)' Dac tinh may nen WINDOW (.2, 1!)-(.6, 2)
FOR o = .2 TO .6 STEP .1: LINE (o, 1)-(o, 1.1): NEXT FOR o = 1 TO 2 STEP .25: LINE (.2, o)-(.21, o): NEXT FOR y = 0 TO nv
FOR x = 0 TO ng ga = ax * x + bx PSET (ga, pic(x, y)) NEXT: NEXT
RETURN fgraf:
PSET (ga, pic): RETURN fipset:
IF fgr = 1 THEN PSET (ga, pic) RETURN
gh:
LPRINT USING "tim ##.## n=###.# pic=#.### tn=#.# be=#.### Ge=###.# ec=#.### P0=######"; tim; nd; pic; tn; be; Ge; ec; p0
LPRINT USING "Ne=###.# ee=### bm=#.####### ga=#.### tg=#### gd=#.## ei=#.### T0=###"; Ne; ee; bm; ga; tg; gad; ei; T0
LPRINT USING "ntk=##### Nk=###### P1=###### Pint=###### hp=#.## alf=#.### b=#.##### "; n; nc; p1; pint; hp; alf; b
LPRINT USING "kr=##.# tr=#.## hpmax=#.## jtk=#.### Nt=#####.# kn=#.## ndm = ###.##"; kr; tr; hpmax; jtk; nt; kn; ndmin
LPRINT USING "alfc=#.### eic=#.### wc=#.#### kozs=####.# tint=###.# ro=#.###"; alfc; eic; wc; kozs; tint; roint
LPRINT USING "######"; fimax 'RETURN
GOTO os: RETURN osq:
'LOCATE 25, 1: PRINT "An phim bat ky de tiep tuc"; os:
DO
q$ = INKEY$ (adsbygoogle = window.adsbygoogle || []).push({});
LOCATE 25, 1: PRINT STRING$(80, " "); : RETURN END
SUB comp (T0, p0, pic(), ec(), n, gac, by, ay, bx, ax, pic, ec) npr = n * SQR(tatm / T0)
gacpr = gac * patm / p0 * SQR(T0 / tatm) ' May nen
' Xac dinh he toa do
y = (npr - by) / ay: x = (gacpr - bx) / ax ' Xac dinh cac diem noi suy
yd = INT(y): xl = INT(x): yu = CINT(y): xr = CINT(x) ' Tinh pic
picl = fni(pic(xl, yd), pic(xl, yu), y, yd) picr = fni(pic(xr, yd), pic(xr, yu), y, yd) pic = fni(picl, picr, y, yd)
' Kiem tra mat on dinh
IF pic(xl, yd) * pic(xl, yu) * pic(xr, yd) * pic(xr, yu) = 0 THEN LOCATE 24, 2: PRINT " * * *Mat on dinh* * *"; SPC(30); ': BEEP END IF
' Tinh hieu suat may nen
ecu = fni(ec(xl, yu), ec(xr, yu), x, xl) ecd = fni(ec(xl, yd), ec(xr, yd), x, xl) ec = fni(ecd, ecu, x, xl)
END SUB
SUB dothi (x1, y1, x2, y2, l) LINE (x1, y1)-(x2, y2), l END SUB
LOCATE x, y: PRINT t$;
LOCATE x + 1, y: PRINT USING "Ttq =##.###"; b; LOCATE x + 2, y: PRINT USING "fi =##.###"; c; LOCATE x + 3, y: PRINT USING "hp =##.###"; d; LOCATE x + 4, y: PRINT USING "bco =#.######"; e; LOCATE x + 5, y: PRINT USING "alf=##.###"; f; LOCATE x + 6, y: PRINT USING "Tg1=####.###"; g; LOCATE x + 7, y: PRINT USING "n =###.###"; a; LOCATE x + 8, y: PRINT USING "pint=######"; H; LOCATE x + 9, y: PRINT USING "ei=.###"; v;
LOCATE x + 10, y: PRINT USING "bsum=.######"; n; LOCATE x + 11, y: PRINT USING "nn=#####"; j; LOCATE x + 12, y: PRINT USING "pitn=#.##"; z; LOCATE x + 13, y: PRINT USING "picn=#.##"; o; LOCATE x + 14, y: PRINT USING "pefn=#######"; p; LOCATE x + 15, y: PRINT USING "gan=.#"; i;
LOCATE x + 16, y: PRINT USING "bn=.####"; u; LOCATE x + 17, y: PRINT USING "T0=###"; m; LOCATE x + 18, y: PRINT USING "p0=######"; s; END SUB
SUB ghidia (tim, n, alf, ei) CLS
ten$ = "f:f3.bas"
PRINT " cho fai vao"; ten$; "cho ..." OPEN ten$ FOR OUTPUT AS #3
DIM tim(1200), n(1200), alf(1200), ei(1200) WRITE #3, tim, n, alf, ei
CLOSE #3 END SUB
SUB in (n, nt, nk, pint, p1, bsum, pit, pic, tg, ei, alf, bm) IF tim = .05 THEN
LPRINT USING " #####.# #####.# #####.# ###### ###### #.####"; n; nt; nk; pint; p1; bsum
LPRINT USING " #.### #.### #####.# #.### #.### #.######"; pit; pic; tg; ei; alf; bm END IF END SUB SUB koeffimp (pd, p0, kn) ' He so xung pdiz = (pd - p0) / mega kh = 1 + k1i / pdiz kgi = 1 + k2i / pdiz
etpop = 1 + k3i * (1 + k4i / pdiz) kn = kh * kgi * etpop
END SUB
SUB timgraf (lm, rm, um, dm, col, tbeg, tend, parbeg, parend, t, par) VIEW (lm, um)-(rm, dm), , col
WINDOW (tbeg, parbeg)-(tend, parend)
'FOR y = 0 TO 30 STEP 3: LINE (y, parbeg)-(y, parbeg): NEXT FOR y = 0 TO 20 STEP 2: LINE (y, parbeg)-(y, parbeg): NEXT (adsbygoogle = window.adsbygoogle || []).push({});
FOR x = parbeg TO parend STEP (parend - parbeg) / 2: LINE ((tbeg - 1), x)-((tbeg - 1), x): NEXT
LINE (460, 110)-(460, 160), 7 PSET (t, par)
END SUB
SUB turbina (gg, ggn, nras, rr, ff, mfen, p2n, p0, n, ucopt, ucn, etn, flag, pd, tg, nt) DO
' Dac tinh suat tieu hao khi, p2
mfe = SQR(nras / fnras(rr, pit, ff)) * mfen p2 = (gg / ggn) ^ 2 * (p2n - p0) + p0 ' Ty so giam ap trong tua bin
a = (gg / p2 / mfe) ^ 2 * Rg * tg / 2 / (kg / (kg - 1)) x = .5 + SQR(a + .25)
pitr = x ^ (kg / (kg - 1)) dpit = ABS(pit - pitr)
IF dpit < .05 THEN EXIT DO pit = (pit + pitr) / 2:
LOOP pit = pitr p1 = pit * p2
' Cong doan nhiet trong tua bin
hr = khr * tg * (1 - (1 / pit) ^ ((kg - 1) / kg)) ' Hieu suat tua bin
u = ku * n: cad = SQR(2 * hr) uc = (u / cad) / ucopt