BANG DO KHO VA DO PHAN CACH TUNG CAU TRAC NGHIEN

Một phần của tài liệu Khóa luận tốt nghiệp Hóa học: Kiểm tra kiến thức học sinh phổ thông chương dẫn xuất halogen - ancol - phenol bằng phương pháp trắc nghiệm khách quan nhiều lựa chọn (Trang 184 - 200)

*** Mean(cau) = DO KHO(cau)

eer §6=—s Rpbis = DO PHAN CACH (cau)

Cau TDcau MEANicau) SÐ(cau) | Mp Mq Rpbis

1 lá 9.280 0.454 | 24.500 23.194 0.097

2 30 0.600 0.495 | 24.067 22.800 0.103

3 26 0.560 0.501 | 26.107 20.318 0.476 **

+ 30 0.600 0.495 25.733 20.300 0.441 **

5 28 0.560 0.501 | 24.964 21.773 0.262

6 39 0.780 0.418 24.051 21.618 0.153

7 37 0.740 0.443 | 24.946 19.615 0.387 **

8 16 0.320 0.471 | 23.612 23.441 0.029

3 37 0.740 0.443 25.135 19.077 0.440 **

10 16 0.320 0.471 25.062 22.853 0.171

12 40 0.800 0.404 24.575 19.500 0.336 * 12 40 0.800 0.404 | 23.700 23.000 0.046

13 41 0.820 0.388 | 24.439 19.556 0.313 * 14 33 0.660 0.479 | 26.030 18.765 0.570 **

15 32 9.640 0.485 | 25.250 20.556 0.373 *¢

16 25 0.500 0.505 | 25.440 21.680 0/311 * 17 34 0.680 0.471 | 24 441 21.688 0.213

18 26 0.520 0.505 | 25.500 21.458 0.334 ° 19 2é 0.520 0.50S i 24.692 22.333 0.195

20 19 0.380 0.490 | 26.579 21.710 9.391 **

21 20 0.400 0.495 | 26. 500 21.600 0.1398 **

22 39 0.780 0.418 | 25.000 18.455 0.449 **

23 25 0.500 0.505 | 26.840 20.280 0,543 **

24 42 0.840 0.370 | 24.000 21.250 0,167

25 36 0.720 0.454 | 24.222 21.857 0.176

26 17 0.340 0.479 | 26.529 22.030 0.353 * 27 34 0.680 0.471 | 24.559 22.437 0,241

28 26 0.520 0.505 | 24.731 22.292 0.202

29 28 0.560 0.501 | 25.679 20.864 0.396 **

30 15 0.300 0.463 Ị 26.533 22.286 0.322 + 33 43 0.860 0.351 | 24.279 19.143 0.295 + 32 36 0.720 0.454 | 26. 1£? 16.85” 0.692 **

33 29 0.580 0.499 | 25.621 20.714 0.401 **

34 38 0.760 0.431 | 24.737 19.833 0.347 * 35 29 0.580 0.499 | 25.586 20.762 0.394 **

36 42 0.640 0.370 | 24.381 19.250 0.312 *

37 11 0.226 0.418 | 25.818 22.923 0.199

38 13 0.260 0.443 | 27.923 22.027 0.428 **

39 31 0.620 0.490 | 25.000 21.211 0,305 * 40 33 0.660 0.479 | 26.182 18.471 0,605 **

BANG PHAN TICH CAC TAN SO LUA CHON TUNG CAU (item Analysis Results for Observed Responscs)

Trac nghiem : DANXUATHALOGEN-ANCOL-PHENOL

* Ten nhom lam TN: AS-7

* 8o cau : 40

* So nguoi 3 107

* Xu ly luc 14g48ph * Ngay 27/ 4/2008

ee ee ee ...444604964094 9690199499094 ơ... . ee

*** Cau so ; i

Lua chon A B ce D Missing

Tan so t 3 9 93 2 9

TÍ le £ : 2.8 8.4 86.9 1.9 Pt-biserial : -0.10 -0.09 0.16 -0.09 Muc xacsuat : NS NS N8 NS

er Berea 2 EWG Rata dhrele\s a o'ees

Lua chon ^* B c D Missing

Tan sơ t 82 21 2 2 0

Tí le ® † 76.6 19.6 1.9 1.9 Pt-biserial : 0.30 -0.23 0.02 -0.26 Muc xacsuat : <.01 <.05 MS <,01

`... ... .. . . ch ee kh ... ee `... ơơ... . .t....

*** Cau 8O : 3

Lua chon Ae 8 c D Missing

Tan so 3 81 6 14 6 0

Ti le & § 5,7 5.6 13.1 5.6 Pt-biserial . 0.36 -0.19 -0.35 9,0

Muc xacsuat : <.O1 <.05 <.01 NS

°** Cau 8G : $ -

Lua chon ^ B c be Missing Tan so : 1 4 17 85 9

Tí let t 0.3 3.7 15.9 79.4

Pt-biserial : -0.26 -0.18 -0.10 9.23 Muc xaceuaLt : <.01 NS NS ‹,05

24244 96 me eietamieces ĐÀ '9-%:P924/975/4°8191 571):9)02/40)919)02A)71924/0-609/06407249049002539/5)01080416ˆ6)96Đ one

Lua chon A B ce D Missing Tan so Ũ 9 17 78 3 0

Ti le ® ! 8.4 15.9 12.9 2.8 Pt-biserial : -0.24 -0.33 0.46 -0.16 Muc xacsuat : <.05 <,01 <.0ì NS

*** Cau sâ 6 "ơ

Lua chon at 5 c D Missing

Tan 80 t 67 12 4 a 0 Tí le ® ‡ 81.3 11.2 3.7 3.7

Pt-biserial : 0.24 -0.04 -9.32 -0.10

Muc xacsuat : <i0s NS <.01 NS

0N E2 S7 32493.5+ViA ›emes pis. W'V›Y:'9)\'© 6 6:g/a:e ° '©©iyskz:e emi eee sath 'sewera ew anys

Lua chon A 8 c be Missing Tan so : 6 19 47 35 9

Ti le $ : 5.6 17.8 43.9 32.7 Pt-biserial : -0,0 ~0.32 ~9.16 0.4€

Muc XacsuaL : NS <.01 NS <.01

°** Cau so : 8

Lua chon A B ¢c De Missing Tan so : 9 9 13 76 9

Ti let 1 8.4 8.4 12.1 71.0 Pt-biserial : -0.27 -0.14 -0.02 0.27

Muc xacsuat : <.01 NS NS <.01

HN nate pears ot! vie; ejerwe ie g`%›e:6 ©1869 299-6:62665 9 101000940/0)Y.29926;6-9:9292^304)6240726cy422x0e

Lua chen Ae B c D Missing

Tan so : 38 36 21 12 0 Tỉ let : 35.5 33.6 19.6 11.2

Pt-biserial : 0.2 -0.2 -0.15 0.1

Mục xacsuat : <.05 <.05 NS NS

°** Cau 60 19

Lua chen af B Cc D Missing

Tan so 17 is 27 45 0

Tí let 15.9 16.8 25.2 42.1 Pt-biserial : 0.45 -9.16 9.00 -9.21

Mục xacsuat : ô,01 NS ns ô<.05

spews pases ememtirts 903i rane aap ne mene ASNT

Lua chon at B c D Missing

Tan ứo 54 10 3? 6 9 Ti le & ‡ 50.5 9.3 34.6 5.6

Pt-bigerial : 0,07 -0.12 0.02 -0,05

Mục xaceuat : ns NS NS NS

°** Cau so 12 On

Lua chon Af 8 c D Missing

Tan 80 66 7 9 3 9 Ti let 62.2 6.5 8.4 2.8

Pt-biseria! : 0.20 -0.13 -0.18 0.04 Muc xacsuat : <.05 NS NS NS

*** Cau go 13

Lua chon Ae 8 c D Missing

Tan so 78 13 9 7 0 Tile’ 72.9 12.1 8.4 6,5

Pt-biserial 0.30 0.03 -0.28 -0,2

Muc xacsuat : <,01 NS <.01 <.01

eee Cau so : 14

Lua chon a B8 c De Misaing

Tan so 18 9 14 66 9

Ti le ® 16.8 8.4 13.1 61.7

Pt-biserial 0.08 “0.11 “0.17 0.24 Mục Xacsuat ns NS MS <.05

*** Cau so 7)

Lua chon A B ce D Missing

Tan so 1 22 68 a 0 Tí le ® ! 12.1 20.6 63.6 3.7

Pt-biserial “0.23 0.26 0.46 “0.21

Muc xaceuat <.05 <.01 <.01 <,05

*** Cau so 16

Lua chon A B ce D Missing Tan so 11 30 54 12 0

Tí le ® : 10.3 28.0 S0.5 11.2 Pt-biserial : -0.20 -0.31 0.49 -0.15 Mục xaceuat : ‹.05 <.01 <.01 NS

dN pkagees as Sask eameew CNHOX Baw aM Cane ete ees E

Lua chen A B ce D Missing

Tan so 11 22 s8 16 0 Tile’ 10.3 20.6 54.2 15.0

Pt-biserial -9.01 -0.27 9.38 -9.21

Muc xacsuat Ns <.01 <.01 <.05

°** Cau sc is "ơ

Lua chon a Be ° D Missing

Tan so ; 6 9s 5 1 9 Tí le ® Ũ 5,6 88.8 4.7 0.9

Pt-biserial ; ‹0.2 0,40 “0.27 ~0,07

Muc xacsuat ; ‹.01 <.02 <.01 Ns

ees Cau SỐ (19 2

Lua chon At B c D Missing

Tan 80 t 83 L) 13 8 0 Tí le ® Ệ 75,9 4.7 12.1 7.5

Pr-biserial : 0.40 -0.36 -0.19 -0.13

Muc xacsuat : <.01 <.01 ns NS

asic gnats 26 =6 i0i9,8.1 051654500785 msfns,tisứsssse25.63s65 MORO (4609Xasv43G46exdiằ de Lua chon A Be c Hà Missing

Tan so t 8 82 11 6 0

Tile’ t 7.8 76.6 10.3 5.6 Pt-biserial : 0.37 0.55 -0.32 -0.16 Muc xacsuat : <.01 <,01 <.01 NS

eee Cau so : 21

Lua chon at B c D Missing Tan sơ 51 i1 17 28 0

Ti le’ 47.7 10.3 15.9 26.2

Pt-biserial : 90.15 -0.05 “0.00 -0.13 Muc xaceuat ; ns ns NS ns

eee Cau so : 22

Lua chon A Be c D Missing

Tan so Ũ 24 77 5 1 0 Tí let t 2.4 72.0 4.7 0.9

Pt-biserial : -9.13 0.26 -0.20 -0.25 Muc xacsuat ¡ N& <.01 ‹.05 <.05

"** Cau so : 23°

Lua chon A* B c D Missing

Tan so 1 78 6 18 5 0

Ti let 1 72.9 5.6 16.8 4.7 Pt-biserial ; 0.34 -0,24 -0.27 0.01

Muc xacsuat : <.01 <.05 <.01 NS

*** Cau so : 24

Lua chon A B c poe Missing

Tan so 3 10 6 10 8t 0 Tỉ le + ‡ 9.3 5.6 9.3 75.7

Pt-biserial : -0.00 -0,28 -0.42 0.43 Muc Xxacsuat : NS ‹.01 <.01 <.01

ee* Cau 50 t 25 :

Lua chon At B c D Missing

Tan so i 81 12 9 s 0

Tỉ le ® 75.7 LIX 8.4 4.7

Pt-biserial : 0.51 -0.35 -0.18 -0.27 Mục xacsuat : <.01 ‹,01 NS <.01

eee Cau so: 26 &

Lua chon A B ce D Missing

Tan so ' 6 34 65 2 0 Ti let 1 5.6 31.8 60.7 ARK 2)

Pt-biserial : -0.34 -0.19 0.40 -0.21 Muc xacsuat : <.01 NS <.01 <.05

eee Cau so ; 27

Lua chon A Be c D Missing Tan 80 9 69 6 3 9

Tí le + ‡ 8.4 83.2 5.6 2.8

Pt-biserial ‹ -0,30 0.42 0.24 -0.13

Muc xacsuat : <,01 <.01 <.05 NS

**°* Cau 9G : 28

Lua chon A 8 ce D Missing

Tan so ‡ 3 12 16 16 i) Tí le & D 2.8 113 71.0 15.9

Pt-biserial : 0.08 -0.31 0.33 -0.18

Muc xacsuat :; NS <.02 ô‹.01 NS

ees Cau sco : 29

Lua chon A B ce D Missing Tan so ' 12 10 72 13 0

Ti let t 21.2 9.3 67.3 12.1 Pt-biserial : ~0.25 -0.32 0.50 -0.20

Muc xacsuat : <.01 <.01 <.01 <.05 eee Cau so : 30

Lua chon ar B L2 D Missing

Tan so 60 37 4 € 9 Ti let t 56.1 34.€ 3.7 5.6

Pt-biserial : 0.36 -0,30 -0.13 -0.04

MỤC xacsuat ; <.01 ô.01 NS ns

*** Cau sơ 31

Lua chon A B ce D Missing Tan so 25 11 64 7 9

Tỉ le ® : 23.4 10.3 59.8 6.5 Pt-biserial : -0.05 -0.33 0.36 -0.23

Mục xaceuat ns <.01 ô<.01 <.05

eee Cau so : 32 :

Lua chon A B8 ce Ð Missing

Tan so lá 21 42 30 9 Ti le ® 13.1 19.6 39.3 28.0

12

Pt-biserial : “0.37

Muc xacsuat NS

Lua chos A Tan so 38

Ti le $ 35.5

Pt-biseria! -0.20

Mục xacsuat : <,05

°** Cau 60 34

Lua chơ+ A

Tan so 10 Tỉ le € Ù 9.3

Pt-biserial : -0.18

Muc xacsuat : N8

eer Cau sO : 35

Lua chen A

Tan so ‘ 8

Ti lee 1 1.5

Pt-biserial : -8.33

Muc xacsuat ; <.01 eee Ca, so : 36

Lua chen A Tan 80 i 12

Ti let ' 11.2 Pt-biserial ; ~0.26

Muc xacsuat ; <,01

*“ Cat 6O : 37

Lua chen ^*

Tan so ‡ 12

Tile’ Ũ 67.3

Pt-bigerial : 0.27

Muc xacsuat : <.01

*®** Cai so : 38

Lua chon A

Tan so i 21

Tỉ le ! ! 19.6

Pt-biserial : -0.04

Muc xa:suar : NS

°** Cai so ¡ 39

Lua chan A

Tan 80 1 14

Ti let Ũ 13.1 Pt-bigerial ; -8.,00

73 2 9.4

<.01

...

54

50.5

0.25 -0.05

<,0§ NS

c D Missing 18 16 0

16.8 15.0

-0,24 0.03

<,05 ns

c D Missing

22 18 9 20.6 16.8

+0.16 -0.29

NS <.02

c D Missing

9 6 0 8.4 5.6

-0.19 -0.25

ns <.01

c D Missing 11 11 0

10.3 10.3

~0.16 -0.22

NS <.05

c ÐĐ Missing

s 20 0 4.7 18.7

~-0.04 0.02 NS NS

ce D Missing

31 30 0 29.0 28.0

0.08 0.01

NS ns

ce D Missing 27 12 0

25.2 11.2 0.30 -0.07 -0.,21

13

Muc xacsuat :

Tan so

Tí let

Pt -biserial

Muc xacsuat

Tan so

Ti let

Pt-biserial

Mục xacsuat

...

NS <.05

1 40

Ae B

$9 3

t 92.5 2.8 t 0.27 0.12

<.01 NS

*** HET *+*#*++

ee

BANG PHAN TICH CAC TAN SO LUA CHON TUNG CAU (Item Analysie Results for Observed Responses)

Trac nghiem : DANXUATHALOGEN -ANCOL-PHENOL

* Ten nhom lam TN :

* So cau

* So nguoi

* Xu ly luc 14949ph

tr.

A B

‡ 1 2 ' 1,9 3.8 t -0.10 0.03

NS NS

12

at by

2 43 8

1 81.1 15.1

! 0.24 -0.15

i NS NS

oe . .

*** Cau so : 3

Lua chon At B Tan so a4 3 Tilest 8 83,0 s$.7 Pt-biserial : 0.47 -0.29 Muc xacsuat : <.01 <.05

eee Cau s 4

Lua chon A B

Tan se 1 1

Tile’ 1,9 Lae Pt-biseria! : -0,42 -0.27

Muc xacsuat : <.01 Ns

Ai at baka ew Wile peak Sin’

Lua chon A B

AS

f 4ô

“e Ngay 27/ 4/200853

eee eee ew www wee

c

...

l4

Tan so ‡ 3 9 41 9 0 Ti le ® 3 8.7 17.0 77.4 0.9

Pt-biserial : -0,21 -0.,59 0.64 MA

Mục xacsuat + NS <,01 ‹,01 NA

eee Cau so : 6

Lua chon ar B c D Missing

Tan so 2 44 5 2 2 0

Tí le i . $3.0 9.4 3.8 3.8 Pt-biserial : 0,51 -0.21 -0.52 -0.16

Muc xacsuat : <.01 NS ô<,01 NS

uc i. eee

Lua chon A B c oe Missing Tan ứo ! 2 3 30 18 0

Tiler 1 3.8 5.7 56.6 34.0 Pt-biserial : 0,16 -0.32 -0.21 0.45

Muc xacsuat : NS <,05 NS <.91

eee Cau so : 8

Lua chon A B c De Missing

Tan so t 4 4 2 43 0 Tí le *® Ù 7.5 7.8 3.8 81.1

Pt-biserial : -9.40 -0.17 “0.23 0.50

Muc xacsuat : <.01 ns us <.01

*e* Cau so : 9 ; :

Lua chon at 8 c D Missing

Tan so 5 22 is 11 0 Tỉ le ® 3 9.4 41.5 28.3 20.8

Pt-biserial : 0.36 -0.24 -0.16 0.21

Mục xaceuat : <,01 ns NS NS

eee Cau so : 10

Lua chon at B c D Missing Tan 80 ’ 5 9 14 25 0

Ti le $ ‡ 9,4 17.0 26.4 47.2 Pt-biserial : 0.46 -0.10 -0.01 -0.19

Mục xacsuat : <.01 NS NS Ns

*ee Cau so : 11

Lua chon Ae B c D Missing

Tan Bo 3 16 3 30 4 9 Tỉ let ‡ 30.2 §.7 56.6 7.5

Pt-biserial : 0.12 -0.,58 0.16 0.00

Muc xacsuat : NS <,01 NS MS

eee Cau sO : 12

Lua chon Af B c D Missing

1S

Tan so f 51 9 2

Ti le’ ! 96.2 0.0 3.8 Pt-biserial : 0.42 NA -0.42

Mục xacsuat ; <,01 NA ‹c.01

eee Cau so +: 13

Lua chon A* B c Tan go t 42 + 2 Ti let 3 79.2 13.2 3.8

Pt-biserial : 9.42 -0.09 -0.23 Muc xacsuat : <,01 NS NS

*** Cau 80 lá

Lua chon ˆ 8 c

Tan so t 13 5 3

Tí le + 1 24.5 9.4 1.9 Pr-biserial : -0,20 -0.24 0.02

Muc xacsuat : NS NS us

eee Cau so ; 15

Lua chon A 8 ce Tan so 3 7 10 35

Tí le + : 13.2 18.9 66.0 Pt-biserial : -0.34 -0,21 0.42

Muc xacsuat : <.,0§ ns <.01

eee Cau so : 16

Lua chon A B ce

Tan so 3 5 18 22

Tí let 3 9.4 34.0 41.5 Pt-biserial : -0.08 -0.36 0.52

Muc xacsuat : NS <.01 <.01

eee Cau so + 17

Lua chon A 5 ce Tan so i 11 8 24 Ti let 1 20.8 15.1 45.3 Pt-biseria! ; -0.09 0.14 0.41

Muc xacsuat : NS ns <.01

eee Cau so : 18

Lua chon A Bf c

Tan so 2 1 51 1

Ti let : 1.9 96.2 1.9 Pt-biserial : -0.27 0,47 “0.39 Muc xacsuat | NS <.01 <.01

eee Cau sơ 4 1s

Lua chon Af 8 c Tan so ! 4s 2 é

0 9 0.0

NA NA

D Missing

2 0 3.8

-0.49

<.01

De Missing

34 0 64.2

0.31

<.05

D Missing 1 0

1.9

~0.17 ns

D Missing

8 9 15.1

-0.14

NS

COO 999499090 00 90v

D Missing 10 0

18.9 -0.29

<.05

D Missing

° 0 0.9

NA NA

D Missing

9 9

l6

Ti le &

Pt-biserial

Muc xaceuat

Tan wo Ti let

Pt-biserial :

Muc xaceuat :

Tan so

Tí le +

Pt-biserial

Muc xacsuat

Ff Cau =o

Lua chon

Tan ứo

Tỉ le

Pt-biserial

Muc xacsuat

Tan so

TÍ lest

Pt-biserial

Mục xacsuat

eee Cau so Lua chon

Tan 80

Ti le ‡

Pt-biserial

Mục xaceuat

`... .. xa

94.9 3.8

0.48 -0,47

<.01 <,01

20

A a*

1 46

1,98 86.8 -9.,32 0.51

<.05 <,01

21

A* B 33 3 62.3 §.7 0,00 0,02 N8 Ns

22

A Be

l4 37

26.4 69.8

©.00 0.24 ns N8

23

Af 8

45 2

64.9 3.8 0.45 -0.25

<.01 NS

24

A B

8 2 15.1 3.8

0.04 “0.42

N8 <.01

25

Af B

47 2

98.7 3.8

90.52 -0,32

<.01 ‹.0S

26

A 8

1 24

| 45.3

Missing

Cee eee eee eee eee

Se

17

Pt-biserial -0.27 -0.27 0.34 NA Muc xacsuat NS NS <.05 NA

Cong 22201:0 : S#B:125G0000)510666301tvÁ NEAR ROAARERT NRA ROTC NED

Lua chon ˆ Be c D Missing

Tan so 2 49 2 ° ° Tiles $ 3.8 92.5 3.8 0.0

Pt-biserial - -0.33 0.61 -0.51 NA Muc xacsuat -: <.05 <.01 <.01 NA

*** Cau so : 28

Lua chon A B ce D Missing

Tan se 2 3 45 3 9 Ti le % : 3.8 5.7 84.9 5.7

Pr-biserial : 0.08 -0.42 0.18 0.08

Mục xacsuat : NS <.01 Ns NS

eee Cau so : 29

Lua chon A B ce D Missing

Tan so i 2 48 2 ° Ti le ® 3 1.9 3.8 90.6 3.8

Pt-biserial : “0.0 0.42 9.48 -0.28

Muc xacsuat ns <.01 <.01 <.05

*** Cau so 30

Lua chon ar B ¢ D Missing

Tan so : 35 1€ 1 1 0

Ti let ' 66,0 30.2 1.9 1.9 Pt-biseria) : 0.23 ~0.17 -0.0 -0.17

Muc xacsuat : NS NS NS NS

°** Cau so : 31

Lua chon A 8 ce D Missing

Tan so 1 1? 5 29 2 °

Tí le ® : 32.1 9.4 54.7 3.8 Pt-biserial : 0.04 -0.45 0.32 -0.25

Muc xacsuat : NS <.01 <.05 Ns

eee Cau so : 32

Lua chon A B ce D Missing

Tan so 6 12 14 21 °

Ti let 11.3 22.6 26.4 39.6

Pt-biseria) 0.29 0.00 0.22 -0.01

Muc xacsuat ô.05 NS NS NS

eee Cau so : 33

Lua chon A Be c b Missing

Tan so 25 8 12 s 9

Tí le & : 47.2 15.1 22.6 15.1 Pt-biseria. : -0.0s 0.31 -0.28 0.14

Muc xacsuat : NS <.05 <.05 Ns

*** Cau so : 34

Lua chon A Be c D Missing

Tan so t 1 31 10 11 9

Ti le & ' 1.9 $4.5 18.9 20.8 Pt-biserial ; 0.04 0.58 -0.28 -0.45

Muc xacsuat : Ns <,01 ‹.05 <.01

*** Cau so 3S

Lua chon A Be c D Missing Tan so t 2 49 i 1 0

Tí le $ t 3.8 92.5 1.9 1.9 Pt-biserial : -9.42 0.67 -0.39 -0.32 Muc xacsuat : ‹.01 <.01 <.01 <.05

*°* Cau so : 36

Lua chon A Be ¢c D5 Missing

Tan so t 2 46 5 0 0

Tí let 8 3.8 66.8 9.4 0.0 Pt-biserial : -0.33 0.48 “0.34 NA Muc xacsuat : <.05 <,01 <.05 NA

resi ety ee PUN OTe ee CT Oe

Lua chon AY 8 c D Miesing

Tan 50 $ 31 Ä 2 16 0 Tí le + t 58.5 7.8 3.8 30.2

Pt-biserial : 0.42 0.60 “0.1 -0.03 Muc xeceuat ; <,01 <,01 NS MS

*** Cau so : 38

Lua chon A B c D Missing

Tan so : 13 10 3 27 9 Ti le t 1 24.5 18.9 5.7 50.9

Pt-biserial : 0.06 0.07 -0.18 -0.02

Muc xaceuat ; NS NS Ns N8

ees Cau so ;¡ 3%

Lua chon A B ce D Missing

Tan so 3 7 33 12 1 0

TÍ le t 1 13.2 62.3 22.6 1.9 Pt-biserial : ~0,13 0,02 0.17 -0.27

Muc xacsuat : NS NS NS

eee Cau sco : 40

Lua chon At 8 c D Missing Tan sơ ‡ 52 © 3 9 9

Ti let ' 98,1 0.0 1.9 0.0 Pt-bigerial ‹ 0.27 NA -0.27 NA

Muc xac@uat | NS NA MS NA

19

...,...s.Ss...

BANG PHAN TICH CAC TAN SO LUA CHON TUNG CAU

{Item Analysis Results for Observed Responses)

OS SSR ESS SSR SSR SSRSSRSSRRSSSSSRSSSSSSESSSVSSSS

Trac nghiem : DANXUATHALOGEN -ANCOL-PHENOL

* Ten nhom lam TN: A?

* So cau t 40

* So nguoi z s4

*“ Xu ly luc 14g50ph * Ngay 27/ 4/2008

Lua chon A 8 ce D Missing

Tan so ' 2 7 43 2 0 Tiles’ ! 3.7 13.0 79.6 3.7

Pt-biserial | -0.09 -0,12 0.19 -0.09

Muc xacsua:r : NS NS NS us

*** Cau 30 2

Lua chon Af R c D Mi naing

Tan so ‡ 3498 13 1 1 0

Tí let t 72.2 24.1 1.9 1.9 Pt-biserial ; 0.33 *0.27 -0.08 ~0.34

Muc xaceuat ; <.05 <,05 ns Ns

Ev))-2rekke.3 tye 0292512419 RSW OSES NN IONE IEG, PORES POA PIT Oe 8 56081420:-6:/2:/27646 jee Seas NT, Lua chon Af B c D Missing

Tan so 1 31 3 s s 9 Tile’ ’ 68.5 5.6 16.7 9.3

Pt-biserial : 0.24 -0.11 -0.34 9.15

Muc xacsuat : NS NS <.05 NS

ae ee sees 6sei6eseee6ib6seececs6646906ce°60490662s60466sb66b66ó3

Lua chon A B c De Missing

Tan so 0 3 14 37 0

Tile’ t 0,0 5.6 25.9 68.5

Pt-biserial : NA -0.1 -0,01 0.06

Muc xacsuat : NA NS ns NS

Lua chon A B ce D Missing

Tan so z 6 8 37 3 0 Ti le % t 11.1 14.8 68.5 5.6

Pt-biserial : -0.24 -0,06 0.30 -0.19 Muc xacsuat : NS Ns <.05 NS

eee Cau sc 6

Lua chon A* B c D Missing Tan so 43 7 2 2 9

20

Tiles t 79.6 13.0 3.7 3.7 Pt-biserial | 0.00 0.11 -0.16 -0.05

Muc xacsuat : NS NS NS NS

M205 9001361008 awe sẽ... ơ TA A Oe Ie

Lua chon A 5 ¢ De Missing Tan so Ũ a 16 17 11 0

Tile’ ' 7.4 29.6 31.5 31-5 Pe-biseria!l ; 0.02 -0.30 -0.20 0.48

Muc xacsuat : NS <.0S ns <.01

*** Cau so 8

Lua chon A B8 c De Missing

Tan 80 t 5 L) 11 33 ©

Ti le ® t 9.3 9.3 20.4 61.1 Pt-biseria) . 0.16 -0.11 0.12 0.06

Muc xacsuaL : NS NS NS ns

**°* Cau 8G 3

Lua chon at B c DB Missing

Tan so t 33 14 6 1 0

Tiles t 61.1 25.9 11.1 1.9 Pt-biserial : 0.32 -0.21 -0.23 0.06

Muc xacsuat : <.05 NS NS NS

eee Cau so : 10

Lua chon AY B c DB Missing

Tan so t 12 9 13 20 0

T¡ le * ' 22.2 16.7 44.1 37.0

Pt-biserial 0.5 -0.22 0.03 -0.27 Muc xacsuat : <.01 ns xs <.05

eee Cau so : 11

Lua chon at 8 c D Missing

Tan so 38 7 7 2 it]

Tilet 70.4 13.9 13.0 3.7

Pt-biseríal 9.16 0.19 -0.33 -0.14

Muc xacsuat : NS NĐ ô.05 NS

*** Cau so 12

Lua chon At B c D Missing

Tan so Ệ 37 1 7 3 0 Ti let ‡ 68.5 13.0 13.0 5.6

Pt-biserial : 9.08 -0.33 -0.04 0.08

Muc xacguat : NS NS NS NS

ee* Cau so : 13

Lua chon Ar B c D Missing

Tan so ‘ 36 6 7 s 9

Tí le © ' 66.7 11.1 13.0 9.3

21

Pt-biserial Muc xacsuat

“oer Cau 66

Lua chon

Tan so

Tile t

Pt-biserial

Muc xacsuat

Tan so

Tỉ le ®

Pt-biserial Muc xaceuat

Tile’

Pt-biserial :

Muc xaceuat

“oan Cau so

Lua chon

Tan so

Ti le $

Pt-biserial :

Muc xacsuat :

Tan so

Ti le t

Pt-biserial

0.17 0.15

NS NS

A B

5 4

9.3 7.4

-0.01 0.01 NS NS

A R 6 12 11.3 22.2 0.14 -0.29 NS <.05

A 8

6 12 11.1 22.2 -0.29 -0.30

<.05 <.05

A B 0 l4 0.0 25.9

NA “0,34 NA <.05

36 66.7 0.56

...

Missing

`... eee eee eee eee eee ee eee eee ee ee ÔÔ

Một phần của tài liệu Khóa luận tốt nghiệp Hóa học: Kiểm tra kiến thức học sinh phổ thông chương dẫn xuất halogen - ancol - phenol bằng phương pháp trắc nghiệm khách quan nhiều lựa chọn (Trang 184 - 200)

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