Chii y : Bac ancol va bac amin la khac nhau :
C 6 H 5- N H- C H 3 : amin bac 2. CgH, - C H ( O H ) - C H 3 : ancol bac 2. 3.56. Dap an dung la Ạ
3.57. ThiJ tu sap xép diing la B.
3.58. Dap an dung 1^ D. ' 3.59. C6ng thirc dung la Ạ - . r J ' r 3.59. C6ng thirc dung la Ạ - . r J ' r
Cn^an+S^ > n CO2 + (n +1,5) H2O
Theo Mi: — ^ = - ^ n = 1,5 -> nj = 1 n2 = 2. n + 1,5 2 C6ng thiic phan tir cua hai amin : C H 3 - N H 2 C 2 H 5 - N H 2 • 3.60. C6ng thiJc dung Ik D.
S6' mol cac chat:
Urn^ " 2 4 4 = -^-^ = 0,4 mol -> c6 0,4 mol C. 12 6
nil o = —— = 0,7 mol -> c6 1,4 mol H.
69,44 _ , ,
n N , = =22,4 3,1 mol.
Goi CTPT cua amin X la CxHyNz :
C , H y N , + ( x+ ^ ) 0 2 -> X C O 2 + | H 2 0 + | N 2
S6' mol O2 c^n d6't chdy amin la : x + ^ = 0,4 + — = 0,75 mol. 4 4 SÓ mol N2 trong khfing khi la : .80 = 3 mol.
-> S6 mol N2 trong amin la : 3,1 - 3 = 0,1 mol -> njsi = 0,2 mol. Tac6: x : y : z = 0,4 : 1,4 : 0,2 = 2 : 7 : 1.
C6ng thiic phan tir cua amin X 1^ : C2H7N hay C2H5 - NH2 •
3.61. COng thiic dung la C.
Goi c6ng thdrc chung ciia 2 amin no, dom chiic Ik C-H2-^jNH2.
CnH2;ịlNH2-^HCl^ C-H2-,,NH3C1 Theo phuong trinh phan ling ta tháy :
180
3.62.
3.63.
3.64.
3.65.
I mol X phan ung tao th^nh mudi, khdi lirpng tSng 36,5 gam
X mol X phan ling tao thanh mud'i, kh6i luang tang 31,68 - 20 = 11,68 gam ^ x = ^ = 0 . 3 2 . o , ^ M x = ^ = 6 2 . 5 . ^ x = ^ = 0 . 3 2 . o , ^ M x = ^ = 6 2 . 5 .
Amin c6 M < 62,5 Ik C3H7 - NHj (M = 59). Amin c6 M > 62,5 la C4H9 - NH2 (M = 73). Ten goi diing la B.
Goi CTPT cua amin no, dcm chiic 1^ CnH2n+3N.
CnH2n+3N ) nCOs + ( n + l , 5) H 2 0
Theo d^ bai: n = 3. CTPT cua X C3H9N.
n + 1,5 3 (adsbygoogle = window.adsbygoogle || []).push({});
CTPT cua X : CH3 - NH - CHj - CH3 : Etylmetylamin. C6ng thiic dung 1^ B.
D6't chay a mol amino axit cho :
2a mol CO2 Trong phan tix amino axit c6 2 nguyfin tii C. a
- mol N2 ^ Trong phan til amino axit c6 1 nguyfen tir N -> Ddp an B. C6ng thiic diing la C.
X la amin no, don chiic (suy tir nx : n^a = 1 : 1), c6 CTPT CnH2n+3N .
14n + 3 + 14 100 ^CTPTcuaXlaCgHgN. C6ng thiic diing la D.
X + HCl theo ti 16 mol nx: n^Q = 1 : 1 . -> X la amin no, don chiic, CTPT CnH2n+3N.
14 ^ 23,73
14n + 3 + 14 100 n = 3 ^ CTPTciiaXla C3H9N.
- > X 1& amin bSc I , co mach cacbon kh6ng phan nhdnh ntn co CTCT la cong thurc D. cong thurc D.
3.66. Cong thiifc dung la A .