A = CgHg - ( C H 2 ) , - NH2 ; B = CnH2n+3N • 2 C 6 H 5 - ( C H 2 ) x N H 2 N 2 "A = 2 n , ^ = 2 . ^ = 0,03 mol - > = = 107. C 5 H ^ - ( C H 2 ) x- N H 2 = 1 0 7 ^ x = l . Vay CTCT cua A la Cf,H5CH2NH2 • CnHzn+sN > n C 0 2 + ( n + l , 5 ) H 2 0 Theo de b a i : = - ^ n = 3. CTPT cua B CH3CH2CH2NH2 . n + 1,5 3
3.67. Cong thiirc diing la C.
Gpi CTPT cua X la H 2 N- C x H y - C O O H . H 2 N- C x H y - C 0 0 H > ( x + l ) C 0 2 + ^ H 2 O + ^ N2. y + 3 n ^ ^ 1 0,05 ' nN2 1 0,05 2 - 2 v a y CTCT cua X la H2N - C2H2 - C O O H .
3.68. Cong thilc dung la B. .
CTPT cua A l a : H j N - C n H j n - i - ( C 0 0 H ) 2 .
H 2 N - C n H 2 n- i - ( C O O H ) 2 > (n + 2 ) C 0 2 1 mol (n + 2) mol - > 4,5 < n + 2 <6 ^ 2,5 < n < 4 - > n = 3.
^ CTCT CLia a - amino axit A Ih cdng thirc B. ..s 3 69. Cong thu-c dung la C.
A la m6t amino axit phan tir co 3 nguyen t u C, c6 2 nhom - C O O H va m6t nhom - N H 2 A la cong thilc C.
3 70. C6ng thiic diing la A . S6' mol cac chat: S6' mol cac chat:
nA = 0,1 .0,2 = 0,02 m o l ; nNaOH = 0,08 .0,25 = 0,02 m o l ; nHCl = 0,08 .0,5 = 0,04 mol.
K h o i luong phan tir ciia A : = 52.2 = 104. CTPT cua A la ( H j N ) ^ - C^Hy - ( C O O H ) ^ , .
(H2N)nC^Hy(COOH)n^ + mNaOH - > (H2N)nC^Hy(COONa)^^ + m H j O 0,02 mol 0,02 mol ^ m = 1
( H 2 N ) n C x H y C 0 0 H + nHCl - > ( C l H 3 N ) n C x H y C O O H 0,02 mol 0,04 mol ^ n = 2.
^ CTPT cua A : (H2N)2 - C^Hy - C O O H = 1 0 4 . 32 + 14x + y + 45 = 104
Cap nghiem phii hop la : x = 2 , y = 3.
CTCTciia A m : ( H 2 N ) 2- C 2 H 3- C O O H . ,
3-71. Cong thurc dung la C.
CTPT cua A la H 2 N - CnH2n - C O O H .
H 2 N - C n H 2 n - C O O H + H C l ^ C l H 3 N- C n H 2 n- C O O H Theo phan ling : 1 mol A + HCl mud'i co khd'i lugng tang 36,5 gam.
X mol A + HCl - > mu6'i co khS'i lugng tang 3,65 gam. ^ x = 0,1 mol ^ M A = — = 89 ^ 16 + 14n + 45 = 89 n = 2. ^ x = 0,1 mol ^ M A = — = 89 ^ 16 + 14n + 45 = 89 n = 2.
^ 0,1
A la a - amino axit nen CTCT la c6ng thiic C.
3.72. Ceng thiic dung la D.
C6ng thirc phan tu trung binh cua 2 aniin la C - H j - ^ j - NH2 . CnH2^., - N H 2 + HCl ^ C - H ^ - , ! - N H 3 C I . .
1 mol amin + HCl -> mu6'i, khd'i lucmg tang 36,5 gam.