- Cac yeu du v~ tiOOtoan va ki~m tra 1'rngsudt trong than d~p:
R: Cuemg dQchiu nen tinh toan Clla n€n da.
c. DiJu ki~n an toim cua nJn ddt
V 6i n€n dftt khi tinh toan sa bQ ho~c khi chQn kich thuac day mong co th~ dUng cac di~u ki~n an toan sau day d€ ki€m tra.
- Khi cong trinh khong co ho~c khong thuemg xuyen chiu mc d\lllg cua tai trQng ngang:
Rio °lb:S [K1
- Khi cong trinh thuemg xuyen chiu tac d\lllg cua tai trQng ngang, ngoai di€u ki~n ( 4-28) con pMi thoa man di€u ki~n sau:
12R'"
omax:S '[K1
RIC: Cuemg dQ tieu chul1n Clla dllt n€n, xac dinh theo ph\ll\lc II .
0max, 0lb : Tri s6 trng sul1t phap Ian nhllt va trung binh cua trng sullt day
mong do tai trQng tieu chul1n gay ra.
Ngoai ra cful chu y la di€u ki~n 0min? 0 luon pMi duqc thOa man. Vi dy 4-4. Cho mQt d~p tran co m~t c~t ngang tinh toan nhu hinh 4-23.
Bi~t:
D~p thuQc cong trinh clip IV, t6 hQ'Pl\Ic co ban .
H=5,50m; B=2,2Om;t=0,50m; a=0,50m; hA =2,50 m; he =1,80 m (hA, he la cQtnucrcdAynAitAng len day d~p)
TrQng lugng rieng v~t Ii~u lam d~pYVL =2,40T/m3;
TrQng lugng rieng CllanucrcYn =1,OT/m3;
H~ s6 rna sat Cllam~t truqt f= 0,35 L\I'cdinh tren m~t truqt C=I,5T1m2;
Cuang d(Jchiu tai Cllan6n R=15,50kG/cm2
Yeu cAu:
I. Tinh toan va ki6m tra Andinh cho ~p.
2. Tinh toan va ki6m tra tmg suAtphap cho m~t c~t gilip mong cua d~p. 3. Kiem trawang d(Jcho n6n d~p
Ghi eM:
- Ap l\I'cnuac thugng luu tac d\lng len d~p chi tinh ti.rcao trinh Do tra len. - Khi tinh b6 qua tac dvng ch6ng truqt, I~t cua cac b(Jph~ acua ra d~p.
Hlnh 4-23 I I I I :c ~ I ~< b ~. Bili giiii I. L~p sO"d6 tinh
M~t truqt va diem I~t co the xay ra cua d~p Iii m~t n6nAB v~y ta chi xet cac l\I'ctac d\lIlg len m~tAB.
SO"d6 cac l\I'cnhu hinh 4-24
va tam I~t B, vi
1
2. Tinh toan trj sd cae h,rctac dl,ll1glen m~t AB va mo men chdng I~t, gay I~t. vo; diemB.
- Xac dinh h~ sd I~ch tai n Cllacac h,rc: tra ph\ll\lc 6 .
Khi xac dinh n cM y: Tn,mg luqng ban than ~p c6 xu the chdng tnrQt va chdng I~tnen lAyn = 0,95
- Tinh toan trj sd cac h,rc: + Cac h,rcthiing dUng:
PI = 5,3*0,5*2,4*0,95 = 6,04 TP2 = 0,5*2,1*5,5* 2,4*0,95 = 13,17 T P2 = 0,5*2,1*5,5* 2,4*0,95 = 13,17 T P3 = 2,2*5,5*2,4*0,95 = 27,59 T P4 = 0,5*5,5*1*1 = 2,75 T LP = 6,04+ 13,17+27,59+2,75 = 49,55 T C. I ..•J! A' + ac 1,lCuay nO!: Wi = 5,3*1,8*1*1 = 9,54 T W2 = 5,3*(2,5-1,8)*0,5*1*1 = 1,85 T LW = 9,54 + 1,85 = 11,4 T
+ Cac 11,lcxo ngang (sa dd nay chi mQt11,lc): Q = 0,5*5,52 * 1*1 = 15,12 T
- Tinh toan mo men + Mo men chdng I~t: Mp1 = 6,04*5,3/2 = 16,01 T.m Mn = 13,17*(0,5+2/3*2,1) = 25,02 T.m Mp3 = 27,59*(0,5+2,1+2,2/2) = 102,08 T.m MP4 = 2,75*(5,3-0,5/2) = 13,89 T.m LMCL = 16,01+25,02+102,08+13,89 =156,99 T.m. + Mo men gay I~t:
MWi = 9,54*5,3/2 = 25,28 T.m MW2 = 1,85*5,3*2/3 = 6,55 T.m
Mo = 15,12*(5,5/3+0,5) = 35,29 T.m LMoL = 25,28+6,55+35,29 = 67,13 T.m 3. Tinh toan cac h~866n djnhvil kiem tra
KL=LMCL/ LMGL= 156,99/67,13 = 2,34
K = (Lp- LW}f+C.F = (49,55-11,4)*0,35+1,5*5,3 =141
T. LQ 15,12'
Kcln =LP / LW = 49,55/ 11,4 = 4,35
Tra vii tiOO[K] (ph\ll\lc 5): Cong trinh c~p IV: kn= 1,15, t6 hqp h.rcC(J ban: I1c= 1, d~p Iii d~p be tong tren n~n da: m = 1
[K] = kn.l1c/m= 1,15*1/1 = 1,15 Kiem ra vii k~t lu~:
Kmin= 1,41> [K]=1,15 : D~p an toan v~ 6n djnh 4. TiOOvii kiem tra tmg s~t day m6ng
DQ I~ch tam ecUa hqp h.rccua ap h.rcday m6ng:
e= 5,3_156,99-67,13 =029m 2 49,55 ' amax,min = ~L~P_-~L~W_,(l:t_6e)= F Bi 49,55-11,4 (l:t 6 *0,29J 5,3 5,3 amax =9,60 T/m2 amin = 4,80 T/m2
amax =9,60 T/m2 < R =15,5 T/m2 viiamin = 4,80 T/m2 > q, 0: N~n d~p an toiln v~ cuang dQ.
Vi d\l 4-5. Cho mQt tubng canh Clla d~p tran bfutg be tong lilIn vi~c theo sad6 nhu hinh (4-25).
Biit: Cong trinh thuQc cdp N
N€n la d8.va co Rtc = 15,5 kG/cm2
Yeucdu: