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introduction to coldfusion mx 6 1 developer edition

Introduction to Fluke Network Inspector 1

Introduction to Fluke Network Inspector 1

Quản trị mạng

... follows: Host #1 Host #2 IP Address: 19 2. 16 8 .1. 10 IP Address: 19 2. 16 8 .2 .10 Subnet mask: 255.255.255.0 Subnet mask: 255.255.255.0 Default Gateway: 19 2. 16 8 .1. 1 Default Gateway: 19 2. 16 8 .2 .1 Since the ... IP Address: 19 2. 16 8 .4 .1 IP Address: 19 2. 16 8 .3 .1 Subnet mask: 255.255.255.0 Subnet mask: 255.255.255.0 2 -15 Semester Internetwork Troubleshooting v1.0 - Lab 3.3 .12 .1 Copyright  20 01, Cisco Systems, ... Default Gateway: 19 2. 16 8 .1. 1 Default Gateway: 19 2. 16 8 .2 .1 Step From the Start menu, launch the Network Inspector | Console Click on the Agent button at the left end of the toolbar so that the...
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A practical introduction to programming and problem solving 3 edition

A practical introduction to programming and problem solving 3 edition

Cơ khí - Chế tạo máy

... 2: Vectors and Matrices >> layerone = reshape (1: 15,3,5) layerone = 10 13 11 14 12 15 >> layertwo = fliplr(flipud(layerone)) layertwo = 15 12 14 11 13 10 >> mat(:,: ,1) = layerone mat = 10 11 12 >> ... layerone mat = 10 11 12 >> mat(:,:,2) = layertwo mat(:,: ,1) = 10 11 12 mat(:,:,2) = 15 12 14 11 13 10 >> size(mat) ans = 13 14 15 13 14 15 2 Three-dimensional matrices can also be created using ... a 11 a12 / a1n 6a a22 / a2n 7 ¼ aij i ¼ 1; ; m; j ¼ 1; ; n A ¼ 21 « « « « am1 am2 / amn 2 .1. 1 Creating Row Vectors There are several ways to create row vector variables The most direct way is to...
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Introduction to Guideline Procedures Part 1: Equipment docx

Introduction to Guideline Procedures Part 1: Equipment docx

Cao đẳng - Đại học

... difficult both to manipulate and stow Spools have the advantage of being simple, easy to deploy, and easy to both manipulate and stow However, over long distances, winding the line back onto a spool ... enough to allow the entire reel or finger spool to pass through A small loop should be added at the end of the main loop to make it easier to retrieve the line With reels, a small marble attached to ... double-ended Wrong way to clip reel bolt snap is used, make sure it is properly secured to the frame to avoid it being accidentally opened A single clip, using a metal -to- metal attachment to the reel should...
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Introduction to Database Systems: Module 1, Lecture 1 ppt

Introduction to Database Systems: Module 1, Lecture 1 ppt

Cơ sở dữ liệu

... Systems, R Ramakrishnan 11 Ensuring Atomicity y y DBMS ensures atomicity (all-or-nothing property) even if system crashes in the middle of a Xact Idea: Keep a log (history) of all actions carried ... Management Systems, R Ramakrishnan 10 Scheduling Concurrent Transactions y DBMS ensures that execution of {T1, , Tn} is equivalent to some serial execution T1’ Tn’ – Before reading/writing an ... must go to disk before the changed page! – Ti commits/aborts: a log record indicating this action y y y Log records chained together by Xact id, so it’s easy to undo a specific Xact (e.g., to resolve...
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solutions for an introduction to the finite element method (3rd edition), by j. n. reddy

solutions for an introduction to the finite element method (3rd edition), by j. n. reddy

Cơ khí - Chế tạo máy

... -0 .62 8 01 -1. 23083 -1. 78428 -2. 266 15 -2 .65 711 -2.9 414 8 -3 .10 785 -3 .14 955 -3. 064 91 -2.85732 -2 .11 119 0. 215 36 2. 410 51 ∆t = 05 -0.00000 -0. 569 22 -1. 13844 -1 .69 12 3 -2.20984 -2 .67 459 -3. 064 03 -3.3 560 5 ... 0.7 71 16 8 0.72 868 0 0. 564 818 0. 015 2 46 -0.544352 -0.787095 -0.587339 -0.000000 -0 .62 8 013 -1. 230833 -2. 266 1 46 -3 .14 9552 -2 .11 119 0 0. 215 362 2. 410 5 06 -0.000000 -0. 569 2 21 -1. 138442 -2.209838 -3.53 017 8 ... 0.504 96 0.3 712 3 0. 218 03 0.05023 -0 .1 262 8 -0.304 81 -0 .63 965 -1. 05 068 -0.94 062 0.78540 0.77828 0.742 76 0 .67 944 0. 564 82 0.4 762 7 0.34225 0 .19 218 0.0 314 8 -0 .13 374 -0.2 969 0 -0.5 913 1 -0. 911 71 -0.7 467 2...
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introduction to stochastic differential equations 1.2 - evans l c

introduction to stochastic differential equations 1.2 - evans l c

Kế hoạch kinh doanh

... = 1, n? 38 a3 a1 b1 t1 a2 a5 b3 a4 b2 t2 b5 b4 t3 t5 t4 We can guess the answer as follows We know b1 P (a1 ≤ W (t1 ) ≤ b1 ) = a1 x2 − 2t1 e √ 2πt1 dx1 ; and given that W (t1 ) = x1 , a1 ≤ ... 1, , m Then Ai = X 1 (Bi ) for some Bi ∈ B Hence i P (A1 ∩ · · · ∩ Am ) = P (X1 ∈ B1 , , Xm ∈ Bm ) = B1 × ×Bm = fX1 ···Xm (x1 , , xm ) dx1 · · · dxm fX1 (x1 ) dx1 fXm (xm ) dxm B1 ... a density Then E(X1 · · · Xm ) = Rm = R x1 · · · xm fX1 ···Xm (x1 , , xm ) dx1 xm x1 fX1 (x1 ) dx1 · · · = E(X1 ) · · · E(Xm ) 19 R xm fXm (xm ) dxm by (3) THEOREM If X1 , , Xm are independent,...
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an introduction to the analysis of algorithms 2nd edition

an introduction to the analysis of algorithms 2nd edition

Kỹ thuật lập trình

... 813 ,890 1, 039 ,67 7 1, 269 ,492 1, 502 ,65 5 1, 738 ,68 5 1, 977,2 21 2, 217 ,985 1 76, 354 374,7 46 583,473 794, 560 1, 010 ,65 7 1, 2 31, 2 46 1, 4 51, 5 76 1 ,67 2 , 61 6 1, 9 01, 7 26 2 ,1 26, 16 0 Average number of compares used ... Asymptotics S 6. 1 6. 2 6. 3 6. 4 6. 5 6. 6 6. 7 6. 8 6. 9 6. 10 6. 11 6. 12 6. 13 6. 14 6. 15 : A Notation for Asymptotic Approximations Asymptotic Expansions Manipulating Asymptotic Expansions Asymptotic ... Table 1. 1 exact solution approximate empirical 17 5,7 71 379,250 593 ,18 8 813 ,9 21 1,039, 713 1, 269 , 564 1, 502,729 1, 738,777 1, 977,300 2, 218 ,033 17 5,7 46 379, 219 593 ,15 7 813 ,890 1, 039 ,67 7 1, 269 ,492 1, 502 ,65 5...
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Introduction to Probability - Chapter 6 doc

Introduction to Probability - Chapter 6 doc

Kế toán - Kiểm toán

... 2 26 CHAPTER EXPECTED VALUE AND VARIANCE n = 10 0 Frequency Relative Frequency 17 17 17 17 16 16 18 18 16 16 16 16 Winning -2 -4 -6 n = 10 000 Frequency Relative Frequency 16 8 1 16 8 1 16 7 8 16 7 8 16 2 6 ... and using Theorem 6. 5 gives E(T ) 12 + 1+ 36 36 + 1+ 5 +6 36 + 1+ 4 +6 557 = 16 5 ≈ 3.375 = 36 3 +6 + 36 + 36 + 1+ 36 36 1+ 5 +6 36 1+ 3 +6 36 4 +6 36 36 36 6 .1 EXPECTED VALUE 2 41 Martingales We ... both having expected value 0: pX = −2 3 /11 1 2 /11 1/ 11 2 /11 3 /11 ; pY = −2 1/ 11 1 2 /11 5 /11 2 /11 1/ 11 264 CHAPTER EXPECTED VALUE AND VARIANCE A coin is tossed three times Let X be the number of...
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Business Process Modeling Introduction to ARIS Methodolgy PHẦN 1 pdf

Business Process Modeling Introduction to ARIS Methodolgy PHẦN 1 pdf

Tiếp thị - Bán hàng

... Overloaded? Balances Queues How Did We Do? Provides Workflow Statistics Page Situation today Economical situation: back to the basics Globalisation Cost reduction Merge/Acquisition Performance IT situation ... Avoidance of nonproductive activities Reduction of waiting times Optimize resources usage Time to market Page 10 Reduce delivery time ... Agenda What’s in modeling ? Situation today Objectives of Process Management ARIS Framework and methods ARIS suite of products Live demo...
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An introduction to multiagent systems - part 1 potx

An introduction to multiagent systems - part 1 potx

Kĩ thuật Viễn thông

... spectrum We return to the topic of auctions later, but here are two different examples that illustrate the problem of mechanism design 15 3 15 4 CHAPTER MECHANISM DESIGN Example 7 .1. 1 Strategic Voting ... they wish to maximize their revenues You wish to route the message along the least-cost route (note that this is different from wishing to pay the least amount of money; you care about the total costs ... agent’s type 1 56 CHAPTER MECHANISM DESIGN Note that a problem and a mechanism as above together define a set of games (N, A, O, µ, u), one for each u ∈ U Informally speaking, a solution to a mechanism...
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An introduction to predictive maintenance - part 1 pot

An introduction to predictive maintenance - part 1 pot

Kĩ thuật Viễn thông

... 1. 150 1. 322 1. 5 21 1.749 2. 011 2. 313 1. 200 1. 440 1. 728 2.074 2.488 2.9 86 10 11 12 1. 072 1. 083 1. 094 1. 105 1. 1 16 1. 127 1. 149 1. 172 1. 195 1. 219 1. 243 1. 268 1. 3 16 1. 369 1. 423 1. 480 1. 539 1 .60 1 1.3 16 ... Principal (1 + Interest )n 1% 2% Interest 4% 10 % 15 % 20% 1. 010 1. 020 1. 030 1. 0 41 1.0 51 1. 062 1. 020 1. 040 1. 0 61 1. 082 1. 104 1. 1 26 1. 040 1. 082 1. 125 1. 170 1. 217 1. 265 1. 100 1. 210 1. 3 31 1. 464 1 . 61 0 1. 772 1. 150 ... 1. 3 16 1. 369 1. 423 1. 480 1. 539 1 .60 1 2 .66 0 3.059 3. 518 4.0 46 4 .65 2 5.350 3.583 4.300 5. 16 0 6. 19 2 7.430 8.9 16 18 24 36 48 60 1. 1 96 1. 270 1. 4 31 1 . 61 2 1. 817 1. 428 1 .60 8 2.040 2.587 3.2 81 2.0 26 2. 563 ...
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An Introduction to Thermodynamics and Statistical Mechanics Second Edition pps

An Introduction to Thermodynamics and Statistical Mechanics Second Edition pps

Điện - Điện tử

... conductors, 479-4 81 conserved quantities, 242, 362 5 51 552 Index constraints first law, 16 7 - 16 8 natural, 15 5 -17 8 second law, 15 8- 16 5 second order, 16 0 - 16 2 , 16 4 third law, 16 6 ,17 5 -17 7 types of, 15 7 ... equations of state, 18 7 for ideal gases and solids, 18 7 -18 9 for liquids, 19 1 for real gases, 18 9 -19 1 equilibrium, 10 2 -10 3 ,15 8 diffusive, 85- 86 the approach to, 15 8, 15 9- 16 0 thermal, 13 equilibrium ... 494-4 96 cycles gas and vapor, 260 open and closed, 260 Debye cutoff, 460 - 4 61 energy, 4 61 frequency, 4 61 function, 462 model, 459- 465 temperature, 4 61 degenerate levels, 10 4 degenerate systems, 17 5 -17 7,...
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An Introduction to Thermodynamics phần 6 docx

An Introduction to Thermodynamics phần 6 docx

Năng lượng

...  f1o f1  f1   With this substitution, after multiplying through by f 1o, N1 f1 − N1 f1o + N f1o + N f1o = Divide by N1 and rearrange, writing N2 for N2 /N1 and N3 for N3 /N1 because N1 is ... n 1, n 2, and n and the integrated equation divided by N1 to give the same result 7 /10 /07 3- 72 f1 P1 = o f1 P1 o Thus Raoult’s law may be written in the more common form, (N1 1) P = Po N1 1 ... pseudo-derivation is as follows If P1o V1 = N 1o RT for pure solvent, P1V1 = N RT for the solution, and V1 can be assumed equal for both, then (P1o − P1 )V1 = (N1o − N1 )RT or ∆PV1 = N2 RT (But of course the...
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Introduction to Fracture Mechanics phần 1 ppsx

Introduction to Fracture Mechanics phần 1 ppsx

Kĩ thuật Viễn thông

... approach and a more rigorous mechanics approach Introduction Griffith Fracture Theory Key Idea : Griffith (19 21) postulated that for unit crack extension to occur under the influence of the applied ... results of Inglis (19 13) Griffith found that the net change in potential energy of the plate caused by the introduction of the crack is: a  B WP   E' 2 E E' Plane strain 1 v =E Plane stress ... forces Irwin (19 56) proposed an approach for the characterization of the driving force for fracture in cracked bodies, which is conceptually equivalent to that of the Griffith model 10 ...
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INTRODUCTION TO COMPUTER SCIENCE - PART 1 ppsx

INTRODUCTION TO COMPUTER SCIENCE - PART 1 ppsx

Hệ điều hành

... terminates; n is the answer E3 [Reduce.] Set m ← n, n ← r, and go back to step E1 1. 3 C ESSENTIALS RAM 68 10 2 10 2 pt 25 i 1. 3 C ESSENTIALS The two main parts of the programming language C: Data ... is INTRODUCTION TO COMPUTER SCIENCE: HANDOUT #1 REVIEWS located at address 10 2 This address is the value of the object pt, an object of type "pointer to int" The address of the pointer pt is 68 ... problem to be represented and manipulated in a computer to model: mô hình hóa Data Model: Mô hình liệu A way of describing and representing data 10 INTRODUCTION TO COMPUTER SCIENCE: HANDOUT #1 REVIEWS...
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An Introduction to Genetic Algorithms phần 1 ppsx

An Introduction to Genetic Algorithms phần 1 ppsx

Kỹ thuật lập trình

... For example, the strings 10 00 010 0 and 11 111 111 could be crossed over after the third locus in each to produce the two offspring 10 011 111 and 11 10 010 0 The crossover operator roughly mimics biological ... Fitness E' 10 110 000 F 011 011 10 C 0 010 0000 B' 011 011 10 Note that, in the new population, although the best string (the one with fitness 6) was lost, the average fitness rose from 12 /4 to 14 /4 Iterating ... 0000 011 0 B 11 1 011 10 C 0 010 0000 D 0 011 010 0 A common selection method in GAs is fitness−proportionate selection, in which the number of times an individual is expected to reproduce is equal to its...
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Introduction to Probability phần 6 pptx

Introduction to Probability phần 6 pptx

Quản trị kinh doanh

... the program to compare the variances for the following densities, both having expected value 0: pX = −2 3 /11 1 2 /11 1/ 11 2 /11 3 /11 ; pY = −2 1/ 11 1 2 /11 5 /11 2 /11 1/ 11 A coin is tossed three ... Thus, P (S2 = 2) = m (1) m (1) 1 · = , = 6 36 P (S2 = 3) = m (1) m(2) + m(2)m (1) 1 1 = · + · = , 6 6 36 P (S2 = 4) = m (1) m(3) + m(2)m(2) + m(3)m (1) 1 1 1 = · + · + · = 6 6 6 36 Continuing in this ... VARIANCE x m(x) 1 /6 1 /6 1 /6 1 /6 1 /6 1 /6 (x − 7/2)2 25/4 9/4 1/ 4 1/ 4 9/4 25/4 Table 6. 6: Variance calculation From this table we find E((X − µ)2 ) is V (X) = = 25 1 25 + + + + + 4 4 4 35 , 12 and the...
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Introduction to Medical Immunology - part 1 pot

Introduction to Medical Immunology - part 1 pot

Sức khỏe giới tính

... (lymphocyte homing); leukocyte adherence to endothelial cells in inflammatory reactions Intercellular adhesion molecule -1 (ICAM -1) LFA -1 (CD11a/CD18), Mac -1 (CD11b) Expressed by leukocytes, endothelial ... I62 86 19 97] RC582.I59 19 97 61 6.07'9—dc 21 DNLM/DLC for Library of Congress 97-22373 CIP The publisher offers discounts on this book when ordered in bulk quantities For more information, write to ... intestine J Immunol., 15 1 :1 765 , 19 93 Collins, T Adhesion molecules and leukocyte emigration Sci Med., 2 (6) :28–37, 19 95 Dustin, M.L., and Springer, T.A Role of lymphocyte adhesion receptors in transient...
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