chỉnh lưu 1 pha nửa chu kỳ

... Lụựp ẹieọn _ẹieọn Tửỷ 05 .1 BO CO Mễ PHNG CHNH LU 1 PHA 1. S chnh lu 1 pha na chu kỡ : SV Nguyeón Trửụứng Sinh Trang 1 Trửụứng HCN Si Gũn Lụựp ẹieọn _ẹieọn Tửỷ 05 .1 ã Khi ti tr cm(cú giỏ ... Trang 14 Trửụứng HCN Si Gũn Lụựp ẹieọn _ẹieọn Tửỷ 05 .1 2. S chnh lu cu 1 pha SV Nguyeón Trửụứng Sinh Trang 7 Trửụứng HCN Si Gũn Lụựp ẹieọn _ẹieọn Tửỷ 05 .1 Gúc kớch = 12 0 0 Gúc kớch = 15 0 ... Tửỷ 05 .1 Ta cú : U =220v/50Hz R = 10 , m U = 2 U, = t :gúc / Rad U tb = 1 + m U sin d Vớ d : gúc kớch = 30 0 U tb = 1 2 * 220[-cos 30 30 + ] U tb = 17 1.62 v SV...

Ngày tải lên: 25/01/2014, 11:20

... LHP: 211 4242 01 Trang 2 Danh sách nhóm (Lớp HP: 211 4242 01) o0o STT  MSSV 1 Soutkanda sayakoun 092373 51 2  09 211 4 81 3  0 916 65 81 4  ...  09 218 2 41 5  092098 51 6  090797 21 7  09 216 5 31  LHP: 211 4242 01 Trang 27  ...  LHP: 211 4242 01 Trang 14    LHP: 211 4242 01 Trang 21 III. Mạch chỉnh lƣu cầu: a. Tải R: ...

Ngày tải lên: 10/06/2014, 11:37

... A B D R u t A B D R u t A B D R u t A B D R u t A B D R u t A B D R u t i R t Mét nöa chu kú A B D R + _ u t ...

Ngày tải lên: 20/08/2013, 04:10

... A B D R u t A B D R u t A B D R u t A B D R u t Mét nöa chu kú A B D R u t A B D R + _ u t A B D R u t A B D R u t A B D R + _ u t i R t A B D R u t ...

Ngày tải lên: 14/09/2013, 11:10

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VỀ MẠCH CHỈNH LƢU NỬA CHU KỲ. Nhóm sinh viên thực hiện: 1. Nguyễn Văn Tưởng 2. Trần Văn Tùng 3. Thân Văn Phú 4. Nguyễn Thị Tân 5. Ngô Thu Trang Lớp : KTĐ-ĐT K12B Khóa : 2 013 -2 018 Thời ... src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAA5EAAAL+CAIAAAC7ZQfTAAAACXBIWXMAABYlAAAWJQFJUiTwAAAd3ElEQVR42u3deZCteV3f8e+znq2X23ebfZwNRyCOI1IMIiZACAEmIaMVBRXLCKXBFZdYEkHF0iRGTVREjbspClEpAYUhCiIgg0hgZBeRYRZmhjv3zr23l9Pd55xn++UPLMtKVbhTWpVMZV6vv/qPp6u7ns/5 412 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719 dCPio1Fk7p61GarFHnkk6JfrHc7693qZFXc/PQbLmqODGU9bJ04tZx84FPzj3zq1MEq9V0cZlVfeNsAAADNeiFnI04dZLNq9XVP+YIXPOu6Y 31/ JJo8Fb/5x+/+gVfd1lz62HPV5VGMYvv8dGtUnP/rE9PiqstPXLEx/fBH7rlv2eTl2qIZd/04irUun2dDGxHjfn6y/cxLv/lrbvrik+Ms1iKWEV/ytT/arF++Xx/t6vW8ngwp+i 715 cROAACa9QLe84a7nnn9+PnPfuKTHntZ9N0yK37i1g/d9rEH33PnvLnspqYfymG36+rsshP92btf+pU3FfsH06x54c1PL57/9DuH+L23f+S2T+289ZP7eRdDMVSrvaJa/dNryl/4jhcfy9IwDIdZPkT81Kv+JD9x7SpmfT4ZIhv6LiIiz5qhsxMAwCPZQ3qeNaXIsqHvm7YYn434vle++Q8+epC2rmrrI93+dh7z0er8xtqlp+87tTFL7/ulr5pGvPbWt3/3zU+OdrlXrY+6OFjF+87Ev/vl195zfn795Sfu+ej7b/+dHzne95NsGSnbK6YPRDz9 +15 /72o9q4q/+5OzSCl1w3/956YCAHjEyh9S2B4+EMN+k2cPRDz3e/7TH3/sVH3xdU05687vRNeOJ7OirsfzU8943FVffsOVXROLJtq+jciGpi0j0s7Zo3X/5Kvjl3/wq44PO7v3/OVPv+RFs4holhEp+mVEnEpxdliLVKe8SlmkbIisy6LPos+sBACgWS9oMTp6at790V9vf9m3/tzH09U744vnu+di7/5RfVCNu8PlYlVNq/7On/iuxz/u0p1LirioiHGK4SDlo61FxOjo0eXQrYZ49DR+8ru/etotn/6Yk3XbDtU0ZeMhpXYYXvPGT6+ijtkksiGyPosuiy6PLiJSFHYCANCsF/CBob 711 OYLf+p1Z6qLd6utvprko6pP7Wqxm/plkfeRmtWQL/Oo1jZ2ulgWcTCq8lkV3WLo26zdHZeLfvvTm9E94TGX96lYGxWrbmjKbJWVeZnNsub2//lnWbM9SruRVhF9lrVFdFn0ERF5ZScAAM16IXX80E//elcfKUdrw6LJs7zthtF0bbK+1vd9P7RZFseOHFuL2Ds4mIwiIla7Ozv78xhXddZFmUXXnNg6kqU2IspRHhHTyWjRxhCRUpZl9Wh9czSeNvvzLPpIWaQ6hlGW6iLFKFZ2AgDQrBf2uBsePcpSvmqns/VYNpHSql0tuj6VReRl9EO3f34WcbRrUkQWcSLPR2vriy4fdXnk0yjWYiiiH+qISHtNLIqhOVZFnSKK6U7kp9vyMK0X1VaRIo88S5vtarMYjsxW3c03HLUTAIBmvYBLI37k2568njdVPVm02TDdjBjK1IzSYZWaPIYU5d7uXhExLqsh4jAir8aLiGVZHJajeVbvZtPtbhb57LNFG5GKNNQpyhRZDF1Eu9wv+mZSFOvleFishiLPN8btcLBWLq9bb+wEAKBZL2DYXV4WsVF1y+Uyrdp0sMxSFKmvhqZIXZaGISumWxetIpbFaGeIeRfzIT+M6CIWfZzfj1REPY4hYojIU2Qpz2LIUkTfRfQpIq0Osm6Rd123XBVlldIylU1eLIp290nXX2snAIBHsof0mQLXTOerbrjlyY899ed7p5dFXk+GvvvsWekwpCyPPiv3+vFexGFUyyHGZaS8fO3r3zIqyv6gmVXtVzznWVVd9hFZRD5kecrz1EfqY+giIouoi1QXQ+rbZdvVm+uL9iA1B6PY/vxLRk/+govsBADwSPbQnmfNVtVy75anPWkrW66VXZ5HZFWTTVb5rMvrFGWZ2o32/ImIjf7w37/4Pz7vK7/jjb//to/81QOzo9fc/NxnXv2Em1/ys797x240eZQRdWr/5i1XUxZF2cd4L0UzRBRFk+XTkxcv5ruTzdnR9fJY1fzgd37teDATAMAj2kM6Z42hzqezK/J40b94zE+++t35qN+LcarWljHLumVEKmI4nFz8q2/95DI//vhn37y2vv6oa6/q9s/eedddv/GGuze3rjt+zTXvft/t7zp7+iuf9+zU931W9ZFnWd6nfJ7Fb/zBbdttvsrKfkjLw4NsY9acvm9aNrf8ky+8bjO80xUAgGZ9COrjZ86eWzs+e8o/+vybf/Hzn/RNv3zRFY87fWo3NrbSqM6G5SiGT58/fO1t922fO1OXaXVwUKV2fVo1h/PZuLrk5AM//NLnfe+3/vhvv+Ilr33ju45fetm5NouyzFOkMj4xjze+9675shhtTMeb04P5A+NheWKcjXa3v+0rHj+L6EO2AgBo1gvZW2VHjp84OFxeNh0PEd948xN/4rfetfWYJ2zvLKMu0mqVZYdPunL8ipc9dVRGk8UsookYIsqIRUQd8ZpbP3HJVddlo7jiukd99FWv6+vYS1HmsdvGH77/r842ZYxn3XKx2t2OjT5f7W6m5nW/9l1HerUKAEBkKaULXrSM2N9fHplUKdJBk073xS/90Qd/920fntcn2nqtaZtiWB3t9//1LV+6v7u69X+8oxjV/TBsbG7Oz53L19YOD5dFWXzeRRc97UuuvvOes5+4945nPO3G2FucWFt//Vs+cveiPdel6SVXrObtenRVd+qmq9Zf8T1fPWnjSDbkfRR1VmSZqQAANOvnsmjSuM6WB/uT6SjSsIzRTh47Ebd8+3/7xIN9cfyybHKsizIWq8nmxuLc2RjXxfqsP/2ZrWuv3nvwdNRldF2WhmqxStlqef7U9Kqr1tooV8Nhk7rJ6HBSD4v50bLaWuydjNO/98rv7hZxchJ521XRR15EUZoKAOARq3j5y19+wYuqPGWRYuiKooiuKYsYZ0WRoulX+2m632XtMpWj4chmPXSHTbcoR3m+nBfr04O9nSjyoW1S3xaT2XjtxDKrpldfc7hIzWHfxygbTRdZ3g9tNiw3s+7EsPjFH/iWS6exUUezOhjlXdY2kZVRFKYCAHjEekjnrDH0kVJkkYYhK7JIQ+TFQTM0Vf2OD9/7gbvOvvndHzx1mA31bK+JNF5fDSkr6iHrIyKlIYuUFeXQ9EU+GbIspS4bT/LlYtIuivZgreqqYffGay//qn/2RV/+BVeeLKNOkbKURd93qzIvYyiidM4KAKBZL9Csn732735fHC4X4/E4RRYRDx4sn/pNP9ptXnFYH5mXm+XG0e35QeRZpC5iyFOKyFJk6XCRTddTSpGyfLl7+XSo9h949NHilT/0ouPj6A7bjWnlwVUAAP5ezfq/XZJFRKSUhkht35dFuez7eVme6+MdH7zvL+47vZ3N3vm+UzvLJv7mwjwij8iyoSvyLNr2umuv/tJHlxdn7dOe8NhHb8S0i6ztNkblMPRl6TEAAAD+Hs0KAAD/7+RuAQAAmhUAADQrAACaFQAANCsAAGhWAAA0KwAAaFYAADQrAAA8LGUvuO5adwEAgId1s/rsVgAAHu7N6pwVAICHOc+zAgCgWQEAQLMCAKBZAQBAswIAwP+Z97oCAODhzjkrAACaFQAANCsAAJoVAAA0KwAAaFYAADQrAABoVgAANCsAAGhWAADQrAAAaFYAANCsAACgWQEA0KwAAKBZAQDQrAAAoFkBAECzAgCgWQEAQLMCAIBmBQBAswIAgGYFAECzAgCAZgUAAM0KAIBmBQAAzQoAgGYFAADNCgAAmhUAAM0KAACaFQAANCsAAJoVAAA0KwAAmhUAADQrAABoVgAANCsAAGhWAADQrAAAaFYAANCsAABoVgAA0KwAAKBZAQDQrAAAoFkBAECzAgCgWQEAQLMCAKBZAQBAswIAgGYFAECzAgCAZgUAQLMCAIBmBQAAzQoAgGYFAADNCgAAmhUAAM0KAACaFQAAzQoAAJoVAAA0KwAAmhUAADQrAABoVgAANCsAAGhWAAA0KwAAaFYAANCsAABoVgAA0KwAAGhWAADQrAAAoFkBANCsAACgWQEAQLMCAKBZAQBAswIAoFkBAECzAgCAZgUAQLMCAIBmBQAAzQoAgGYFAADNCgCAZgUAAM0KAACaFQAAzQoAAJoVAAA0KwAAmhUAADQrAACaFQAANCsAAGhWAAA0KwAAaFYAADQrAABoVgAA0KwAAGhWAADQrAAAoFkBANCsAACgWQEA0KwAAKBZAQBAswIAoFkBAECzAgCAZgUAQLMCAIBmBQBAswIAgGYFAADNCgCAZgUAAM0KAACaFQAAzQoAAJoVAADNCgAAmhUAADQrAACaFQAANCsAAJoVAAA0KwAAaFYAADQrAABoVgAA0KwAAGhWAADQrAAAaFYAANCsAACgWQEA0KwAAKBZAQBAswIAoFkBAECzAgCgWQEAQLMCAIBmBQBAswIAgGYFAECzAgCAZgUAAM0KAIBmBQAAzQoAAJoVAADNCgAAmhUAAM0KAACaFQAANCsAAJoVAAA0KwAAaFYAADQrAABoVgAANCsAAGhWAADQrAAAaFYAANCsAACgWQEA0KwAAKBZAQDQrAAAoFkBAECzAgCgWQEAQLMCAKBZAQBAswIAgGYFAECzAgCAZgUAAM0KAIBmBQAAzQoAgGYFAICHl/Jvv8qy7BF+L1JKXhAAAA9DzlkBANCsAADwD5P5gzgAAA9zzlkBANCsAACgWQEA0KwAAKBZAQBAswIAoFkBAECzAgCgWQEAQLMCAIBmBQBAswIAgGYFAADNCgCAZgUAAM0KAIBmBQAAzQoAAJoVAADNCgAAmhUAADQrAACaFQAANCsAAJoVAAA0KwAAaFYAADQrAABoVgAANCsAAGhWAADQrAAAaFYAANCsAACgWQEA0KwAAKBZAQDQrAAAoFkBAECzAgCgWQEAQLMCAIBmBQBAswIAgGYFAECzAgCAZgUAAM0KAIBmBQAAzQoAAJoVAADNCgAAmhUAAM0KAACaFQAANCsAAJoVAAA0KwAAmhUAADQrAABoVgAANCsAAGhWAADQrAAAaFYAANCsAABoVgAA0KwAAKBZAQDQrAAAoFkBAECzAgCgWQEAQLMCAKBZAQBAswIAgGYFAECzAgCAZgUAQLMCAIBmB...

Ngày tải lên: 02/06/2014, 21:57

... là: A. f = f 1 + f 2 B. 1 2 2 2 1 2 f f f f f = + C. 2 2 1 2 f f f= + D. 2 2 1 2 1 2 f f f f f + = Câu 11 . Treo quả cầu có khối lợng m 1 vào lò so, hệ dao động điều hòa với chu kỳ T 1 . Thay ... kia treo một quả nặng m 1 thì chu kỳ dao động là T 1 = 1, 2s. Khi thay quả nặng m 2 vào thì chu kỳ dao động bằng T 2 = 1, 6s. Tính chu kỳ dao động khi treo đồng thời m 1 và m 2 vào lò xo. A. ... điều hòa với chu kỳ T 2 . Nếu treo quả cầu có khối lợng m = m 1 + m 2 thì hệ dao động điều hòa với chu kỳ là: A. T = T 1 + T 2 B. T = 2(T 1 + T 2 ) C. 2 2 1 2 T T T= + D. 1 2 1 2 T T T TT + = Câu...

Ngày tải lên: 14/09/2013, 23:10

... 15 N B RB TCA780 NGUYỄ S 5 1 9 10 12 14 T1 T4 T3 T6 GVHD: C 8 16 13 6 11 15 Rc TCA780 T5 T2 T 5 1 9 10 12 14 Lc Lc 8 16 13 6 11 15 TCA780 Lc Lc 5 1 9 10 12 14 T'4 T&apos ;1 +15 V R T'6 T'3 Uk1 R Uk2 R 8 16 ... góc mở 1 60 o , 2 12 0 o hoặc 1 12 0 o , 2 60 o Giá trị cực đại của dòng tuần hoàn 6U 2 +15 V H A 8 16 13 6 11 15 TCA780 RA Dz R1 ẠNH R 5 1 9 10 12 14 R3 R2 A B C M 8 16 13 6 11 15 N B RB TCA780 NGUYỄ S 5 1 9 ... R Uk2 R 8 16 13 6 11 15 TCA780 R T'2 T'5 5 1 9 10 12 14 suất tử Cơng 8 16 13 6 11 15 TCA780 5 1 9 10 12 14 L án Điện M CKT S Ư H THNG TRUYƯN NG TRỈÌNG HBK AÌ NƠNG Ư ẠN MN HOC Đồ Khoa in_ Lp 011 SVTH...

Ngày tải lên: 11/03/2014, 16:04

...

Ngày tải lên: 26/04/2014, 14:41

... tần số dao động chân 7: chân xả 18 11 Đề cương sơ bộ Chương 1: Tổng quan về công nghệ nghịch lưu 1 pha. 1. 1 .Tổng quan về công nghệ. 1. 2. Yêu cầu của công nghệ. 1. 3 . Phạm vi ứng dụng . Chương ... 0.93)/3 ,14 )= 1. 08 cm ở đây chúng ta chọn dây 11 mm hay 11 li Thiết diện dây thứ cấp: Atc = 2,5/I2 Đường kính dây thứ cấp: Atc=π dtc^2/4. Atc=2.5/24.47=0 .10 2 Dtc= √ (4Atc/π) Dtc=sqrt(4*0 .10 2)/3 .14 =0.36cm suy ... nghịch lưu được chia làm hai loại. 6 chân 8: nối với tụ để làm khởi động êm chân 9: chân bù chân 10 : bật tắt hoạt động của chíp chân 11 : phát xung nửa chu kỳ đầu chân 12 :nối đất chân 13 : cấp...

Ngày tải lên: 08/05/2014, 20:07

... (Hz) Ta có chu kỳ xung của mạch là: T = 2.RC.ln         + 1 2 21 R R Do đó ta chọn: R1= 1 k Ω và R2= 0,86 k Ω Khi đó: T = 2.RC = 1 / f dk = 1 60000 = 1, 67 .10 -5 (s) Chọn R =1 k Ω => ... chọn van: Chỉnh lưu cầu 3 pha tạo ra nguồn một chiều có trị số: E = 2,34 . 400 = 936 (V) U RLC = U R = I 1 .R” = 21, 5. 3,7 .10 -6 = 8 .10 -5 (V) Tỉ số máy biến áp : K= 5 8 8 .10 8,56 .10 936 RLC U E − − = ... Tuấn Lớp : DTD 51- DH2 Mã sinh viên : 392 21 Đồ án điện tử công suất Đề tài: Đề số 14 Thiết kế bộ nghịch lưu 1 pha. Mục tiêu:thiết kế bộ nghịch lưu điện áp thấp Nội dung:+ Nguồn cấp 12 VDC + Nguồn...

Ngày tải lên: 08/05/2014, 20:16

Ngày tải lên: 10/06/2014, 18:48

Ngày tải lên: 10/07/2014, 18:21

... luu V5 VSINE TR2 TRAN-2P3S U9 EC 113 C U10 EC 113 C 3 2 6 7 4 1 5 U 11 UA7 41 3 2 6 7 4 1 5 U12 UA7 41 +12 V -12 V +12 V -12 V C1 0.01uF R1 330K C2 0.01uF R2 330K 3 2 6 7 4 1 5 U1 UA7 41 3 2 6 7 4 1 5 U2 UA7 41 RV1 10 k R3 10 0 R4 10 0 D1 DIODE D2 DIODE TR2(S1) Chinh ... hành: 11 II. Các khối mạch điều khiển Thyristor: 11 1. Khối nguồn: 12 2. Khối cách ly ngõ vào và ra: 12 3. Khối đồng bộ : 12 5.Khối tạo dạng xung: 13 III. Tính toán chọn MBA một pha: 13 1. ... như sau : V0= - ∫ dtVi CR * 1* 1 1 = - ω *1* 1 1 CR Cos(wt) vậy nếu R1 * C1* w = 1 thì : Vi = UmSin(wt) -> V0= UmCos(wt) Suy ra ta chọn R1 = 330k, C1= 0. 01 uF, w = 50 Hz BỘ GIAO THÔNG...

Ngày tải lên: 27/04/2013, 09:31

Ngày tải lên: 05/09/2013, 11:49

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