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ENGNG2024 Electrical Engineering
E Levi, 2002
1
INDUCTION MACHINES
1. PRELIMINARY CONSIDERATIONS
Consider an electric machine with six windings. Stator and rotor are of cylindrical
cross-section and three windings are situated on stator while the remaining three windings are
on the rotor, as shown in Fig. 1. Both stator and rotor windings are displaced in space for 120
degrees electrical. In this electromechanical converter a continual electromechanical energy
conversion may take place provided that, if angular frequency of stator currents is
ω
s
and
angular frequency of rotor currents is
ω
r
, rotor speed is
rs
ωωω
−= . Note that, according to
the condition of average torque existence, this is the only possible correlation between stator
and rotor frequency and frequency of rotation, when both stator and rotor carry AC currents.
Then the developed torque becomes time independent and equal to the average torque value.
This type of the electromechanical energy converter is called asynchronous machine (or
induction machine; the origin of this name will become clearer later), because the rotor rotates
with speed
ω
, while the stator revolving field rotates with synchronous speed
ω
s
. Rotor
currents form a revolving field as well, which rotates with angular velocity
ω
r
with respect to
rotor, while with respect to stator its angular velocity is
sr
ωωω
=+ , i.e. synchronous speed.
Note that creation of the rotating field in stator is enabled by displacing in space the three
windings of the stator by 120 degrees and by feeding these three windings with a system of
three phase currents with mutual phase displacement of 120 degrees.
Rotor
b -c Stator
Air-gap
-a a
c -b Rotor
winding
Fig.1 – Cross-section of a three-phase induction machine.
Before proceeding further into discussion of operating principles and analytical theory
of induction machines, let us here briefly review the main constructional features of induction
machines. Stator of induction machines, together with its three-phase winding, completely
corresponds to the stator of synchronous machines. This means that the stator core is
assembled of laminated iron sheets. An appropriate number of iron sheets are put together,
thus forming stator core of the necessary length. Laminated iron sheets are insulated in order
to reduce eddy-current losses in the iron core. Such a design of iron core is always utilised for
those parts of electric machine where flux density and magnetic flux is time varying. The sheets
are mutually isolated in order to prevent formation of a circuit for eddy-current flow from
sheet to sheet. The iron core material is silicon alloyed. Addition of silicon reduces hysteresis
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E Levi, 2002
2
losses in the iron core. Simultaneously, electric resistivity of the material is increased, thus
giving rise to a substantial decrease in eddy-current losses as well. Windings of induction
machine are placed into slots, which may be of open shape, or semi-closed. Semi-closed slots
are usually selected for power ratings up to 200 kW; above 200 kW slots are open.
Rotor core in inductionmachines is of laminated structure as well, because in rotor
windings flows AC current, giving rise to time-varying flux density in the rotor (in synchronous
machines rotor frequency is zero and rotor can be manufactured using a solid piece of
ferromagnetic material). Rotor winding is placed into rotor slots in one of the two different
ways. Subdivision of inductionmachines into two categories is normally done in conjunction
with the way in which the rotor winding is formed. Rotor winding may be wound three-phase
winding and such a machine is called wound-rotor induction machine or slip ring induction
machine. The latter name stems from the fact that three terminals of the rotor phases are in
wound-rotor machine brought out of the machine and connected to three slip rings (one for
each phase), while the remaining three ends of the phase windings are connected into star
neutral point and they remain inside the machine. Wound-rotor induction machine is illustrated
in Fig. 2. The purpose of slip rings is beyond the scope of interest here. Slip rings are
mechanically fixed to rotor and they rotate together with rotor. Three carbon brushes are
mounted on the stator (one for each phase) and brushes slip along the rings as they rotate, thus
establishing an electric contact between the stationary world and the rotating rotor. An electric
approach to rotor winding (which rotates together with rotor) is enabled in this way. In other
words, electric energy can be either brought or taken away from rotor winding during machine
operation through this assembly, which consists of rotating slip rings and fixed brushes.
Brushes are connected with leads to rotor winding terminals in the terminal box of the
machine. Slip rings can be short-circuited and then rotor winding becomes a three-phase short-
circuited winding. When the slip rings are short-circuited, brushes are raised and detached from
slip rings. This is the normal operating state of a slip-ring induction machine.
The second type of inductionmachines are so-called squirrel-cage induction machines.
Rotor winding is in this case cast into slots and it is formed of solid aluminium or copper bars.
The both ends of bars are electrically connected through end-rings. The winding manufactured
in this way resembles a squirrel cage and this explains the origin of the name. The winding is
shown in Fig. 3. Note that rotor winding is in this case always short-circuited and there is no
possibility of electrical approach to the winding. In other words, electric energy cannot be
either brought or taken away from the rotor winding. A winding formed in this way is
essentially an n-phase winding, where the number of phases n equals number of bars. However,
such an n-phase winding can be always substituted with an equivalent three-phase winding for
all analytical considerations.
As already stated at the beginning of this section, there are rotor currents in the rotor
winding whose frequency is
ω
r
. We have just seen that in a squirrel-cage induction machine
there is no electrical access to the rotor winding. Similarly, the normal operating regime of a
slip-ring induction machine is with rotor winding short-circuited; thus no electrical access is
possible to the rotor winding and the question which arises is how do we get currents in rotor
windings when we cannot approach the winding and connect an appropriate electric source.
2. OPERATING PRINCIPLES OF INDUCTION MACHINES
Consider an induction machine with a three phase winding on the stator and an
equivalent three phase short-circuited winding on the rotor. Let the stator winding be
connected to the utility supply which provides three phase balanced system of AC voltages.
These voltages will cause appropriate three phase currents to flow through stator the winding.
ENGNG2024 Electrical Engineering
E Levi, 2002
3
The currents will give rise to formation of Tesla’s revolving field in the air gap of the machine.
Given the supply frequency of stator voltages and currents f
s
in [Hz], the revolving field will
rotate in space (in the cross section of the machine) at the angular frequency of
ss
f
πω
2= .As
both stator and rotor are initially stationary, the revolving field cuts conductors of both stator
and rotor windings, causing induced electromotive forces in the windings to occur.
slip ring
b
rush
winding
terminal
A
B
C
Three-phase
winding
Slip rings
Brushes
Terminals
Shaft
Fig. 2 – Schematic representation of the rotor of a slip ring induction machine and the
physical appearance.
In stator phase a winding a counter electromotive force is induced and it balances the applied
voltage, the difference in their rms value being caused by voltage drop on the winding
resistance and leakage reactance and being equal to a couple of percents of the applied voltage
rms value. An electromotive force is induced in the rotor winding as well and its direction is
shown in Fig. 4. As the rotor winding is short-circuited, the induced electromotive force will
causeacurrentintherotorconductorsI
r
, whose real component has the same direction as
induced emf. As the conductor, which carries current I
r
, is in the magnetic field, a magnetic
force F will be created. This force will cause rotor to start rotating in the direction of stator
ENGNG2024 Electrical Engineering
E Levi, 2002
4
revolving field rotation. The same happens in all the rotor conductors and sum of all individual
multiples of rotor radius and force gives overall electromagnetic torque in the machine.
Summarising, when stator winding of a three-phase induction machine is connected to the
mains, electromagnetic induction causes currents in rotor windings and a torque is created
which pulls rotor into rotation in the direction of rotation of the stator revolving field. This
implies that transfer of electric energy from stator to rotor is realised exclusively by
electromagnetic induction; therefore asynchronous machines are called induction machines.
Rotor winding
bars
End ring
Fig. 3 – Squirrel-cage winding of a squirrel cage induction machine.
.
ω
s
Rotating field
force
force
N
S
Fig. 4 – Creation of an electromagnetic torque in an induction machine.
Rotor can never reach synchronous speed of rotation. Rotation of rotor at synchronous
speed implies that rotor rotates synchronously with revolving field. In that case there is no
relative motion between stator revolving field and rotor and no electromotive force can be
induced in the rotor windings. Consequently, no current can flow in the rotor winding if the
ENGNG2024 Electrical Engineering
E Levi, 2002
5
speed is synchronous and no electromagnetic force can be generated. Therefore at synchronous
speed the developed torque in an induction machine equals zero. As certain amount of torque
is always necessary in a machine that operates as a motor in order to cover mechanical losses,
induction motor has to operate with certain amount of developed torque even when it is not
loaded at the shaft. Thus the rotor in motoring regime can never attain synchronous speed, i.e.
it can never catch with the revolving field. When the motor is unloaded, it runs under no-load
conditions and the amount of torque that is needed is determined with mechanical losses
(windage losses and friction losses in bearings). The torque that describes mechanical losses is
small, thus indicating that the induction motor will have the highest possible speed when it runs
unloaded; this is so-called no-load speed and it is only slightly smaller from synchronous speed.
Let us summarise the above given explanations: connection of three-phase stator
winding of an induction machine at standstill to a voltage source causes current flow in stator
windings; these currents give rise to production of revolving field; revolving filed cuts
conductors of both stator and rotor windings; emf is induced in stator and it provides voltage
balance to supply voltage; emf is induced in rotor as well and it causes current flow through
short-circuited rotor winding; an electromagnetic force is created which acts on every rotor
conductor, leading to the creation of the electromagnetic torque which pulls rotor into
rotation; the direction of rotation is the same as the direction of rotation of stator revolving
field; when a steady-state is established, rotor rotates with angular velocity equal to
rs
ωωω
−= ; rotor currents create another revolving field whose absolute speed equals
synchronous speed. Therefore, the torque is consequence of mutual interaction between stator
and rotor revolving fields. At synchronous speed rotor currents become zero and
electromagnetic torque disappears.
Windings are by the virtue of their construction of resistive-inductive nature. Reactive
power has to be provided for magnetisation of iron cores and air gap between stator and rotor.
The question is how this reactive power is provided in induction machines. The machine does
not contain any capacitances that could produce reactive energy. The only electrical
connection with outside world is the connection of the stator winding to the supply, as the
rotor winding is short-circuited. This means that there is no source of reactive power available
inside an induction machine. Therefore induction machine has always to absorb reactive energy
from the supply. Under all the possible operating conditions induction machine will act as a
reactive energy consumer. As there is no rotor winding connected to another electric source,
as is the case in synchronous machines, there is no way of exciting the induction machine in a
manner similar to synchronous machines. This is one of the main reasons why induction
machine is mainly utilised in motoring regime, while synchronous machine is used for
generation purposes. When an induction machine is applied as a generator, reactive power has
to be either taken from the power system or to be provided by a static VAr compensator (e.g.,
capacitor bank).
As already emphasised, during motoring induction machine has to rotate slower than
the revolving field, even under no-load conditions. The angular velocity of the rotor is given
with
rs
ωωω
−= . Revolving fields of stator and rotor rotate with angular velocity
ω
s
.The
difference between rotor speed and synchronous speed is characterised with the so-called slip.
The slip is expressed either as a percentage value of the synchronous speed or as a per unit
non-dimensional quantity. It is usually calculated out of the speeds given in [rpm] in the
following way:
[%]100or[p.u]
s
s
s
s
n
nn
s
n
nn
s
−
=
−
= (1)
where:
ENGNG2024 Electrical Engineering
E Levi, 2002
6
n
s
- synchronous mechanical speed, which is a function of the number of magnetic pole
pairs P and which is correlated with synchronous electrical speed 60f
s
as
P
f
n
s
s
60
=
(2)
For 50 Hz supply synchronous speeds are
P1234
n
s
[rpm] 3000 1500 1000 750
n - asynchronous mechanical speed of rotation of induction machine shaft.
Note that definition of the slip and the values are the same regardless of whether speeds in
[rpm] or angular speeds in [rad/s] are used.
Slip during normal operation of inductionmachines is in the range 10% to 2% for
induction machines with power ratings in the range 1 kW 100 kW. The value of the slip that
corresponds to the rated operating conditions, when speed is n
n
, will be denoted as s
n
.Indexn
will in general always define the rated (nominal) operating condition of the machine.
Let us now investigate correlation between stator and rotor frequencies with respect to
newly introduced notion of slip. From slip definition of (1) it follows that
()()
rs
ss
ss
ss
s
Psnnn
nnsn
ωωω
ωωω
π
+=
+=
+=
−=
timesameat theSince
1260bydivided
(3)
it follows that the rotor frequency is determined with
srsr
sffs ==
ωω
(4)
Example 1:
A 4-pole, 3-phase induction machine is fed from 50 Hz supply and operates in steady
state with slip equal to 0.03. Determine the rotor speed and frequency of rotor
currents.
Solution:
[Hz]5.15003.0
[rpm]14551500)03.01(1
[rpm]15002/5060
60
===
=−==
===
xsff
x-s)n(n
x
P
f
n
sr
s
s
s
Example 2:
A 60 Hz induction motor has one pole pair and runs at 3150 rpm. Calculate the
synchronous speed and slip in per unit and in percents.
Solution:
Note the this is an American machine, since the frequency is 60 Hz. Hence
%5.2100]p.u.[[%]
025.03600/)31503600(/)(]p.u.[
[rpm]36001/6060
60
==
=−=−=
===
xss
nnns
x
P
f
n
ss
s
s
ENGNG2024 Electrical Engineering
E Levi, 2002
7
According to (4), frequency of the current in rotor is slip times frequency of stator
currents. For 50 Hz stator frequency and operating slips of 10% to 2% in an induction machine
rotor frequency is only 5….1 Hz. Consequently, as the losses in the iron core are proportional
to frequency and frequency squared, it follows that rotor iron losses are going to be negligibly
small and that the major part of the iron loss will take place in stator. The total iron loss in an
induction machine is for this reason always assumed to take place in stator only.
According to the slip definition, equation (1), slip is a variable determined with the
speed of rotation. This implies that frequency of rotor currents is, according to (4), a variable
as well, proportional to the slip. Characteristic slip values in motoring operation are:
n = 0 rotor at standstill s = 1
0<n<n
0
rotor rotates, machine is loaded 1 > s > s
0
n=n
0
<n
s
no-load, machine is unloaded s = s
0
n=n
n
<n
0
rotor rotates, rated load s = s
n
Normal operating range of inductionmachines in steady-states is in the speed range between
rated speed and no-load speed, the actual operating speed being dependent on the load torque
that the motor is driving.
Suppose now that a source of mechanical energy is connected to the induction machine
shaft and that the mechanical power provided by mechanical source is exactly equal to the
power which describes mechanical losses (i.e. mechanical source provides torque to overcome
mechanical loss torque). Then the speed of rotation will become equal to synchronous, as the
mechanical loss torque is equated by torque of the prime mover. Simultaneously the induction
machine torque will become equal to zero. Therefore at synchronous speed
00 ===
es
Tsnn
Suppose now that the power provided by the prime mover increases. The induction machine
then enters generating regime. Note that only real power will be generated, while the reactive
power is still absorbed. For generation
00 <<>
es
Tsnn
This means that in generation speed is above synchronous speed, slip is negative and the
machine’s electromagnetic torque is negative as well. In contrast to this, in motoring slip and
torque are positive since the reason for rotation is the machine’s electromagnetic torque. A
representation of induction machine operating modes is given in Fig. 5.
Motoring Generating
10-0.5s
0n
s
1.5n
s
n
Fig. 5 – Schematic representation of induction machine operating modes, in terms of slip and
speed of rotation.
Given the slip s in a steady state, speed can be determined from equation (1) as
ENGNG2024 Electrical Engineering
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8
[]
()
[]
()
[rpm]100/%1
[rpm]p.u.1
s
s
nsn
nsn
−=
−=
(5)
Taking into account that during motoring slip is within the range from 1 to 0, it is obvious that
frequency of rotor currents varies as a function of slip in the range between stator frequency
and zero. At standstill rotor frequency equals stator frequency, while at synchronous speed
rotor frequency becomes equal to zero. Therefore it follows that frequency of rotor currents
and voltages is determined with slip.
3. ANALYTICAL THEORY OF INDUCTION MACHINE OPERATION
It can be shown that a balanced three-phase induction machine fed from symmetrical
sinusoidal three-phase supply can be treated in terms of per-phase equivalent circuit in steady
state. However, such a derivation is pretty involved and time consuming. As only steady states
under symmetrical supply conditions are of interest here, complex representatives of AC
sinusoidal quantities may be used (phasors). Furthermore, for the purpose of steady-state
analysis of a balanced induction machine fed from symmetrical source, the whole analysis can
be performed by utilising per phase representation with complex phasors. Such an approach is
utilised in what follows.
Let stator winding be connected to mains, which provide symmetrical three-phase
voltages and let rotor be at standstill, so that rotor speed is zero. Frequency of stator voltages
and currents is f
s
. An electromotive force will be induced in rotor winding that will cause
current to circulate around the rotor winding. As the rotor is at standstill, slip equals one and
the frequency in rotor winding equals stator frequency. When the rotor is at standstill,
difference between the speed of the rotating field and the rotor speed is of maximum value and
equals synchronous speed. This speed difference determines the induced emf, since the emf is
directly proportional to the speed at which the conductors are cut by the field (i.e. to the
difference between the synchronous speed and the rotor speed). Once when rotor rotates at
certain speed, the speed at which conductors are cut by the rotating field will be determined
with
ssr
sf
πωωω
2=−= and will be smaller than at standstill.
When the rotor is at standstill let the induced electromotive force in one rotor phase E
is identified with index rl. Its existence will cause current flow and rotor currents produce
corresponding revolving field and flux. One part of the flux dissipates around the rotor winding
(leakage flux), while major part links with stator windings contributing to the mutual flux.
Current flow through rotor winding, caused by induced emf, is opposed by the resistance of
the rotor winding and leakage reactance (which describes leakage flux). The value of the rotor
leakage reactance is again frequency dependent. At standstill rotor frequency, rotor leakage
reactance and modulus of rotor current are
22
22
rlr
rl
rl
rsrrrl
ssr
XR
E
I
LfLfX
fsff
+
=
==
==
γγγ
ππ
(6)
Suppose now that the rotor starts rotating, so that slip becomes smaller than 1 since
speed is greater than one. According to the fundamental expression for induced electromotive
force due to the relative movement of a conductor with respect to flux density, induced emf is
proportional to the relative speed of conductor with respect to flux density. As the rotor
rotates with certain speed, while revolving fields rotate with synchronous speed, relative speed
ENGNG2024 Electrical Engineering
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9
of the revolving field with respect to the rotor conductors is equal to the rotor angular
frequency. This means that induced electromotive force at slip s is proportional to frequency of
rotor currents. Consequently, at any other speed different from zero,
()
2
2
22222
1
1
rr
rl
r
rlr
rl
rr
r
r
rlr
rlr
rlr
XsR
E
I
XsR
sE
XR
E
I
sXX
sEE
ssEE
γ
γγ
γγ
+
=
+
=
+
=
=
==
≠=
(7)
The expression for modulus of the rotor current in (7) enables the following phasor equation
(phasors are identified with a bar over the symbol) to be written:
r
rl
r
r
rl
rlr
rl
r
r
r
IjXI
s
R
E
EsIjsXIRE
γ
γ
+=−
−=+=−
(8)
Equation (8) enables construction of the rotor per-phase equivalent circuit, shown in Fig. 6.
Let us consider now voltage balance for one stator phase winding. Stator phase
winding is characterised with resistance and stator leakage reactance. Note that for stator
rotating field always cuts the conductors at the same, synchronous speed. Hence the frequency
of the stator is constant (50 Hz) and the induced emf is proportional to this fixed frequency
regardless of the speed of rotation of the rotor. The induced emf exists in each stator phase and
it holds balance to the applied stator voltage. Following the same approach as for the rotor
phase, one can immediately write the phasor voltage equation for one stator phase as:
ss
s
s
s
EIjXIRV ++=
γ
(9)
Corresponding equivalent circuit for one stator phase is shown in Fig. 7.
jX
γ
rl
I
r
E
rl
R
r
/s
Fig. 6 - Rotor per-phase equivalent circuit
R
s
jX
γ
s
I
s
VE
s
Fig. 7 – Stator per-phase equivalent circuit.
By combining Figures 6 and 7, resulting complete equivalent circuit can be constructed.
It is shown in Fig. 8 and is described with the following two voltage phasor equations:
ss
s
s
s
EIjXIRV ++=
γ
(10)
ENGNG2024 Electrical Engineering
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r
rl
r
r
rl
IjXI
s
R
E
γ
+=− (11)
R
s
jX
γ
s
I
s
VE
s
jX
γ
rl
I
r
E
rl
R
r
/s
Fig. 8 – Induction machine per-phase equivalent circuit.
Two circuits shown in Fig. 8 apply to two different voltage levels, since the induced
emf in stator is in general different from the induced emf in rotor. It is therefore not possible to
directly connect them. In order to be able to put the two circuits together, it is necessary to
apply transformer theory, which means that rotor voltage needs to be referred to stator voltage
level (as the secondary is referred to primary using the transformation ratio in transformers).
Correlation between the stator and rotor induced emf is established at standstill through the
transformation ratio
m. Transformation ratio is defined as
rls
rl
EEEEm
s
// == (12)
and in an induction machine it is dependent on design features. Rotor voltage equation (11) is
multiplied next with the transformation ratio
r
rl
r
r
rl
r
rl
r
r
rl
IjmXI
s
mR
Em
IjXI
s
R
E
γ
γ
+=−
•+=− m/
(13)
and new fictitious rotor variables, referred to stator, are then introduced respecting the
condition that power in terms of original variables and in terms of new (primed) variables has
to be the same:
mII
IEIE
EmE
rr
rrrr
rlrl
=
=
=
'
''
'
(14)
Rotor current and induced emf in (13) are replaced next with the new rotor current and new
induced emf
'''
2
2
r
rl
r
r
rl
IXjmI
s
Rm
E
γ
+=− (15)
Finally, new rotor parameters (primed symbols) are introduced and the equation is brought into
final form of
rlrlrr
r
rl
r
r
rl
XmXRmR
IjXI
s
R
E
γγ
γ
22
''
'''
'
'
==
+=−
(16)
[...]... power appears across the magnetising reactance) 4 NO-LOAD AND LOCKED-ROTOR REGIMES OF AN INDUCTION MACHINE No-load and mechanical short-circuit (locked-rotor, rotor at standstill) are two important regimes of an induction machine which occur during normal operation and which are performed as standard tests on inductionmachines as well When performed as tests, these two tests enable calculation of the parameters... characteristic state of an induction motor is mechanical short-circuit, which is in no way connected to, and thus is not to be confused with, electric short-circuit Mechanical short-circuit simply denotes an induction machine whose stator winding is supplied with threephase symmetrical voltages and whose rotor does not rotate (i.e the rotor is at standstill) This state is met whenever an induction motor is... time in normal operation of inductionmachines As the rotor is at standstill, s = 1, n = 0, and therefore Pout = 0 η =0 Te ≠ 0 (23) Note that although there is no electromechanical conversion as the rotor is at standstill, torque does not equal zero When the motor starts running-up (s = 1) and the voltage equals rated value, this being the normal starting condition for induction motors, torque has... would cause very high stator current to flow In some machines this value would be even ten times greater than rated current Consequently, the test is performed with voltage value that is just sufficient to cause rated stator current to flow The value of the voltage is for machines of low power rating above one third of the rated voltage, while for machines of high power rating it is in between one sixth... Note that it is not possible to separate total leakage reactance into stator and rotor part in an exact manner For vast majority of inductionmachines it can be assumed however that stator and rotor leakage reactance are mutually equal Example 7: A squirrel cage three-phase induction motor has the following parameters: R s = 0.5 Ω R 'r = 0.25 Ω ' X γs = X γr = 0.4 Ω The motor is four-pole, three-phase,... its typical value is five to eight times the rated motor current The issue is elaborated in more detail in the next section Mechanical short-circuit is at the same time a test which is performed on inductionmachines During the test rotor is prevented from rotating and it is forced to remain at standstill This test is most frequently termed as locked rotor test (it is for this reason that index l was... Equivalent per-phase circuit of an induction machine with included iron loss representation Note that the addition of the equivalent iron loss resistance in Fig 11 changes the node current balance equation From Fig 11 (19) I Fe + I m = I s + I r ' Note as well that the fact that rotor parameters in the circuit of Fig 11 are referred to stator is irrelevant, since in a cage induction machine it is anyway... once more that an induction motor, when connected to the supply, will start running-up from mechanical short-circuit state This state will last shortly, because the speed will start increasing very soon after the motor is switched on During that short time interval a stator current flows which is significantly greater than the rated current Example 5: A three-phase squirrel-cage induction motor with... to the machine) At the same time, the reactive power drawn from the mains is basically the same as it is when machine delivers its mechanical output (real) power equal to rated No-load current in inductionmachines is in the range from 30% to 80% of the rated current This is significantly higher than for transformers, the reason being the existence of the air gap that requires large reactive power for... of the starting current From this circuit I st = 5 Vn ( ph ) Z in = Vn ( ph ) ( R s + Rr ' ) 2 + (X γs + X γrl ') 2 = 240 0.75 2 + 0.8 2 = 288.6 A TORQUE CHARACTERISTIC OF AN INDUCTION MACHINE As a starting point in derivation of induction machine torque characteristic it is convenient to utilise per-phase equivalent circuit, which is for convenience redrawn in Fig 14, for an arbitrary speed, i.e slip . features of induction
machines. Stator of induction machines, together with its three-phase winding, completely
corresponds to the stator of synchronous machines. . operating state of a slip-ring induction machine.
The second type of induction machines are so-called squirrel-cage induction machines.
Rotor winding is in