Xc chtl khr{ch clang chay trong bdn.[r]
(1)N{fr ae tni zlq mnnn rRA 4s' HKI zar0-20n- vA'r ly r0 cB
s6 thft
blfthi
I
-l
VIfl phdng thi
Ciiiu 1: Chon phiit bi6u sui:
Vec-to'vin t6c cua chuy6n d6ng tron dAu
A luOn c6 phuo-ng ti6p tuyt5n v6'i duo'ng trdn qu! dao
B c6 dQ l6'n l<hdng dditheo thd'i gian
C co clQ ldn khOng d6i, hu6'ng lu6n thay ct6i
D e6 hu'6'ng khdng tl6i theo thd'i gian
Ciiu 2: MOt vAt ro'itu L,6y e:l0 m/s2 Trong 2 gidy dAu ti6n, n6 didugc quSng rlu'o'ng bbng A l5nr B lOm C.20m D.5rn
(liiu 3: Mfrt v0t chuytin ddng trdn dOu mdi vdng di tr6t Z giay TAn s6 cua vdt ld
A khOng xric cfinh B hz C.2 Hz D 0,5 Hz
Cfiu 4: MOt chSt diiSm M chuy6rr d6ng trdn ddu trOn dud'ng trdn t6m O v6'i t6c d0 g6c ld 2 radls '['rong s b6n kinh OM qu6t duglc mQt g6c bing
A rrid ti.2A'n rad C I0 rad
lAn rad
ban dau barrg , cu' Ix6i gia), vAn toc { Srn 5: MQt vAt chuy6rr dQng thing nhanir ci6n dAu vdi vfln tOc
cira v# lai tlng thOm du'oc Zmls VAn tOc crta vat luc t - 5 s la
A 20 m/s B l0 m/s C 13 m/s D 15 m/s
Cflu 6: MOt vQt chuy6n dOng trdn d6u m6i gi6y v4t cli cluo-c vdrrg Chu kj,'cua chuy6n dQng crla v6t
ln
A.+s 8.0,25s C.2s D ls
Ciiu 7: Phu'<Ing tr)nh chuydn clQng crla mQt ch6't didm doc theo truc Ox c6 dang :x = l5 + 40 t ( x
cto hlng km" t blng giir; Ctrdt Oidm d6 xua't ph6t til clidm nio vd chuydn dQng v(li vAn toc iriurg bao nhie u 'i
A TU mOt diim ciich O li 40km, vdi vdn tdc 1Skm/h
It Tir diCm O, vrli vQn tdc 40km/h C TU didm O, vr'li v6,n tdc l5km/h
D Tir mQt didm cfch O lI l5km, vdi v{n t6'c 40km/h
Cflu 8: 'fil tdng I cria mQt tod nhd, thi cing hic hai hon drl c6 kh6i lu'o.ng I kg vd kg Bo qua s[r'c
can l<h0ng hhi KCt luQn ndo dfrng?
A lrdn dd kgch4m d6t trir6'c B hon d6 I kg cham cl6t tru6'c
(1 kh6ng tne triCt hon c15 ndo ch4m dAt tru6'c D hai hdn tl6 cham d6t cirng lric
Ciiu 9: MQt virt chuyi5n dQng c6 phuong trinh chuyAn ifQng llr x = l0 + 21 , d6 x tinh bing m, t tinh bdng s 'I'irrlr chAt chuy6n ddng cua v4t ld
A thlng nhanh dAn d€u B thing d6u
C thlng clrpm dAn d0u D thing bitin dOi
CAU 10: Chon cAu drtng
T'r'<rrt1r chrryfjrr dong thing chfrm Cfr'n dduth\
(2)*",
A Gia toc lh dai lugng khong ddi
B VAn tdc trlc thiri tang theo hlm sd bac hai cira thdi gian
C V6c to gia t6c cDng chidu v6i v6c to virn
tdc-D Qulng duong di du-o.c ld hlm'sd bac nhdt cira thdi gian
CAu 1l: M6t 6tO di til A tldn B mdt giir, trong2 gid ddu 6tO di vdi tdc 6rd di v<'ri tdc dO 75 km/h t6c d0 trung binh cfia 6t0 tr6n doan ihldng AB
A.70 km/h B" krn/h C 67,5 km/h
Cfiu l2: Cho dd thi toa d0 *thiri gian ctia vat chuydn ilQng thang d6u cfra chuydn dQng Ih
d0 60 km/h, tron g l git) sau
t$t
D 60 km/h
nhd hinh dddi Viin tdc
A 7,5 r"n/s
Cflu t3: Mqt vat chuydn ril/s Gia t6c cria vet [e
A m/s2,
Clfiu 14: Trong dd thi vQn
chuy€ln clOng thlng ddu
A floan Ots
C" Ooan CD
x(m)
ZA
5
0
2 t(s)
B l0 m/s C.20 m/s D 12,5 m/s
dQng thlng ch{m ddn ddu, 2.s v{n tdc giirn til l1rnls xudng cbn
1,5 rr,ls},,, C - 4r5 mls} D 4,5 mlsz
cira chuydn dOng thlng hjnh vd b0n, doan nlto ung v6i
Doan DE Doatr tsC ftE
toc
?
B D
L'f,u 15: Trong c6c phrftIng trinh sau ddy, phtlOng trinh ndLo mO ti chuydn dQng thfrng nhanh ddn
diu'l
A.x=t2-3t B.x=5t+4 C.x=41 D.x= -3t2-t.
Cflu 16: 1'hi nghi6m trapg 24 shch VAf lV l0 : Til cirng mQt cl6 cao(trong kh6ng khi), d6ng thdi
tha nlie nhdng iaiio gi6y ctrng lopi cirng kich thu6'c nhung mOt td dC phing cdn td' vo trdn vd n6n
clidt thi ro'gi6y bi vo trdn s€ cham ddt tru6'c Theo em, thi nghiem ndy-nhdm chf'ng to di6u gi?
A Trong khdng khi, vflt nhe bao gid'cfrng roi ch4m hon vdt n[ng
B 'l-rong kh6ng khi, v4t roi nhanh ho'n kh6ng ph6i bao gio'cfing ld vdt nlng hu-n
C Trong kh6ng khi, v4t nflng bao gid' cfrng ro"i nhanh ho-n,vflt nhg' D Mgi v4t dD nflng hay nhg cl6u roitrong kh6ng khf nhu CAu 17: Chuydn dQng th.ing lhTl dAn dAu co
^ ,
A gia t6c kh6ng O-Oiifreo thoi gian B vpn t5c gi6m dAu theo tho-i gian
C lio t5c giam?Au theo tho'i gian D gia t5c tlng d6u theo thdi gian
Cflu l8: M6t 0t6 rlang chuydn clQng v<1i vdn tdc 36km/h thi h6m phanh vI chuydn clQng ch{m ddn
ddu vr,ti gia tdc - 2mls2 Sau h6m phanh bao i6u thi xe dtrng hln'?
A lOs R.5s C l8s D'25s Cfiu 19: Phurlng trinh chuydn clQng cria mQt ctrdt didm doc theo trqc Ox c6 dang :
x = - 50 + 20 t( x blng km, t rlo bXng gid)
(3)'
Quang drrdng rli dugc ctia chdt clidm sau 2h chuydndQng ld :, ri r ^r
A.40km B.90km C' - 10km' D' l0km'
Cffu 20: MQt vflt chuy6n dQngthEng nhanh dAn d6u v6'i vQn trSc ban ddu ld3 m/s vd giatdc litZmls2 VAn tOc cira vAt tfic t: 5 s lh
A 20 rnis B I m/s C l0 m/s D' 15 mis
Cftu 21: Tr6ng cdc phtfclng trinh sau tl6y, phrrOng trinh nio mO ti chuy0$dQng thSng chdm ddn dcu.'
A.K= -t2+3t I].x= -3t2-t.
Cffu 22: N4gt v4t chgy$n dQng co c$ng thirc bdng sl Cia t6c cita vflt llr'
A tr/s2
C l0 rn/s2
Cfiur 23: Mc2t vt1t chuyen d6ng thdng dAu xu6t d6rrg ld mQt duo'ng thang
A c[t truc tung t4i tung d0 xt,
C di qLIa g6c top dQ
Cflu 24t Cho c1d thi vfln t6c -tht)i gian cria vat
han cldu (irng voj to = 0) cira chuydn d0ng lh
C.x-5t+4 , D-x= -4t
vdn tOc Ii v - l0 + 2t,trong do v t[nh bdng m/s., t tinh B 12 mlsz
t
D kh6ng du dU'kien d0 xdc dinh'
ph6t rtl toa dQ x0 thi dO thi toa dQ-thd'i gian cua chu5,$p
B c[t trpc hoanh tpi x 61
D cft truc tung tai x - v
chuydn dQng thlng nhu hinh dtldi VAn tdc vfln tOc
v(mis)
35
ZA
0
D m/s2
drrd'ng ph6 So vo'i ngu'd'i hi xe thi vat niro
A.J,5mls. (1 10 m/s
B 20 m/s
D 35 m/s
Cf,u 25: Chuy6n dQng tron ddu 2
(s)
A c6 dQ l6'n v6n t6c tlng ddiu theo thoi gian
B kh6ng c6 gia t6c, vi c6 d016'n vQn t6c kh6ng tl6i theo thoi gian
Cl co dO l6'n vpn t5c gi6m ddu theo thd'i gian
D c6 vecto gia t5c lu6n hu6'ng vdo tAm qu! dao trdn Cfru 26: Ro'i tu ld lo4i chuy€n clQng
,t thing chpm dAn il6u B kh6ng x6c dinh'
C ttr8ng Aeu O ttring nhanh dAn deu
Cfr.u 27:'l'rur)ng h<tp nho drrdi dAy c6 thd coi vdt li chdt Oidm'i
A Hai hirn bi hic va cham v(Ji
It Xc chtl khr{ch clang chay bdn C" Xc dc) chzry til Cdn GiuQc din Vfrng Tiru
D Tr;iiDt't chuydn dQng t\I quay quanh truc cria n6 Clf,u 28: Don vi c[ra giat6c li
A kg B m/s C- m
Cffu 292 Mqt xe clro' kh6ch dang ch?y' thdrtg dAu tren
sau day chuy6n d0ng? '
A c6y' cQt dien tt€n du'o'ng PhO
C satr xe
Clfiu 30: J-Oc c10 goc cua chuy0n d6ng tron d6u
A l<lrOng dOi theo tho'i gian
{1, thay c1,3i theo thd'i gian
B hlrn g ghe thu' ba tr6n xe D hlrng ghe thu'ndm trOn xe
B t[ng theo tho'i gian
tr) giam theo tho'i gian