[r]
(1)GV: Nguy$n minh Tudn
.a (:,, -
il HQC Ki II nr6N VaTLi
sd cr,lo DUC vA DAo r4.oLoNG Al[ MQT sO Dt TI
TRTIONG THpT CAN GIUQC KHOI 1l NANG CAO.TG:60PHUT
B ( Diis6 r.
Cfiu 1(1iI): MOJ day dan th8ng c6 ddng tliQn I d4t vtng kh0ng gian c6 ti trutrng ddu nhu hinh v€ V6 luc ttr t6c dung l6n d6y
l@
Ciu 2(1it): Nguy6n nhdn sinh ddng ctiQn cim img
Cflu 3(1iI): so s6nh vA phuong diQn quang hgc cria mEt Ui tQt c6n thi vd mlt bi tflt vi6n thi
CAu 4(1tI): Hai b4n T1f vd Tdo ru di bpi ,T), l{n xu5ng nu6c cdn bpn Tdo tltrng tr6n b}'H6i khi hai
nguoi,nhin thi dE thAy b3n minh nhdtt giii thich
Cflu 5(1tt): MOt dAy dAn duo.c gflp khung dAy c6 dang tam gi6c vu0ng can MNP Cenh MN = NP = 10 (cm) D4t khung day vao tttrui,ng ddu B
= 10'2 (T) c6 chidu nhu hinh vE Cho dbng di€n I c6 cuirng d0 10 (A) vno
khung diy theo chidu lv:lhtPhfjIim tqrc tir tr{c dr;ng v}ro c6c canh c&a khung day
C6u 6(1tI): Hat a c6 khdi lugng m = 6,67.L0" (kg), diQn tfch q= 3,2.10'te (Ct Xdt rnot hat o c6 vAn
tdc ban ddu kh6ng d6ng kd duo.c tang tdc bdi mOt hiOu diQn thd U = 106 (V) Sau dugc tang tdc n6
bay vio virng khong gian c6 til trucng ddu B = 1,8 (T) theo hu6ng vu6ng g6c v6i duong srlc tt Tim
vAn tdc ctra hat o tI trucrng vi luc Lorenxo t6c dung lOn hat o
C6u 7(1tI): M6t cr{i chiu d6t tren mQt m4t phing nam ngang, chrla m6t l6p nudc dhy 20 (cm), chidt sudr n = 4l3.Ddy chflu li mot gucng phf,ng M6t M c6ch m4t nudc 30 (cm), nhin thing g6c xuOng d6y
chflu Khoing cSch tt 6nh cira mitttormit nu6c bing bao nhi€u?
CAu 8(1iI): Cho hai thdp kinh hoi tq.L,, I, c6 tiOu cq ldn lugt li 20 (cm) vi 25 (cm), d4t ddng truc va c6ch m6J khoang a = 80 (crn).r'V6t sdng AB d4t trudc L, mOJ doan 30 (cm), vu6ng gdc v6i truc chfnh ctra hai thAu kfnh Tim vi tri'cria furh A"B" cira AB qua quang h€ '
CAu 9(1tt): M6r viCn nhin 16 duo c vat dat c6ch m6t gdn nhdt 40 (cm) Dd nhin 16 vat d4t cdch mfi- 8dn
- ^ / t
nhdt 25 (cm) cdn deo kinh (kinh c6ch m6t cm) c6 dQ tu bing bao nhi€u ? 6 Zl 7 u"^
c6u 10(1d): M6t kinh hidn vi c6 vlt kinh v6 tieu cu fr = (mm), thi kinh v6i ti€u c$fr=/Q (mm) vi
(2)a
GV: Nguy1n minh Tudn
khoing D = 25 (cm) Mit d4t
ngim chrrng & cgc can
Ddi soz CAu l(ItI): T6c dpng co bin cria tir trudng ld gi ?
Cf,u 2(1tI): Em Tdo iop I la n6i v6i c6c b4n cria em ring chring ta c6 th6 dirng ddng <tiQn xoay Ae n6u chAy kim loai mdkh6trg cdn cho ddng diQn ch4y qua kim lo4i tl6 Cdu n6i tr€n d0ng hay sai? c6c em h6y
giai thich
Ciu 3(1iI): HEy tinh g6c i*r, 6nh s6ng cli tir m6i trubng thuj' tinh c6 chi6t ,r6t n:.D ra khdng Cflu 4(1tI): HEy vi6t c6c cdng thric l[ng kinh 16ng kinh c6 chi6t su6t n dpt m6i tru]ng c6 chitit
su6t n'.
Ciu 5(1iI): Muon 6nh cria v{t qua thdu kfnh hQi tr,r o v0 cgc thi v6t phni dat cl6u ?
C0u 6(1iI): Thanh MN dei I = 20 (cm) c6 khdi luong (g) treo nam ngang bang hai soi chi mdnh CM vi
DN Thanh nam dr trudng ddu c6 cim rlng tt B = 0,3 (T) nam ngang w6ng g6c vdi c6 chiiiu
nhu hinh vE M6i sgi chi treo c6 thd chiu du-o c luc k6o t6i da li 0,04 (10 Dbng diOn ch4y qua
MN c6 cudng dQ nh6 nhat ld bao nhiOu ? vd chay theo chiiiu nio ?thi mQt hai so i chi treo bi
dr1t Cho gia tdc tro.ng trudng I = 9,8 (m/s2)
Cf,u 7(1d): Hai day dan thing dii song song c6ch.nhau 10 (cm) kh6ng khi, ddng di6n chay hai d6y c6 cirng cuirng dQ (A) ngugc chidu Cim ring tt tai didm M c6ch ddu hai ddng di€n mdt khoing l0 (cm) c6 d0lon bing bao nhi€u ?
CAu 8(1tI): MQt khung day phing c6 diOn tich2O(cm2) gdm 100 vdng dAy duo.c ddt tirtruong ddu c6 vecto c6m ring til vu6ng g6c v6i m4t phing khung ddy vi c6 dO lon bang 2.104 (T) Ngudi ta cho tt
tru&rg giim ddu lan ddn khoing thdi gian 0,01 (s).Tim sudt diQn d0ng cAm rlng.xudt hiQn
khung
{;\
tai tiOu didm anh ctra thi kinh Tim khoin g cdcht[ v0t tdi vQt kinh
C0u 9(1d): Lang kinh c5 g6c chidt quang A - 60", chilrn s6ng song
tidu }e D,, - 42o Tim chidt suat cfra lang kfnh
song qua hng kfnh c6'gdc lOch cuc
'
;-Cf,u 10(1tI): Cho thdu kinh O, (D, = 4 dp) d4t d6ng truc v6i thdu kinh O, (D, = -5 dp), chidu tdi quang
hQ mQt chim sring song song vi song song v6i truc chinh cira quang he Dd chilm 16 kh6i quang hC lh chim song song thi khoing c6ch gilra hai thAu kfnh bing bao nhi€u?
(3)GV: Nguy*n minh Tuan
o6 sOs
CAu l(td): H6ychimg tO rang hai ddng di€n ctng chiAu thi hirt nhau, ngu-o c chiAu thi d6y
CAu 2(1tl): Dinh nghia lgc'Lorentz
CAu 4(1tI): NOu c6u tno vi img dpng cria sgi quang hqc
Cf,u 5(1tI): V€ 6nh c6a vft qua kinh hir5n vi khi ngim chirng v0 ctrc cua mit nguoi khOng bi t0t C6u 6(Id): MQt kinh thign vin c6 var kinh vdi dO tu 0,5 (dp) Thi k(nh cho phdp nhin vnt cao (mm) d4t ti6u diQn vflt du6i g6c h 0,05 (rad).Tim dO bOi gi6c cfia kinh thiOn vin khi ngim chirng & vd cuc
Cf,u 7(ttl): M6t nguoi c6 mit binh thudng (kh6ng tflt) nhin th6y c6c v6t d $t *1m.u kh6ngphii diAu titit.oiBm cgc ctra ngudi ndy c6ch mit 25cm.E0 cria m6t ngubi ndy diAu ti6t t6i da tang th6m bao nhi6u?
Ciu 8(ltl): M6t tia s6ng chidu thing g6c ddp m4t bOn thrlnhdt cira lang kinh co g6c chidt g{og A = 300 c6c tectr !ffiu iiu 16 vd t]a l6i le D = 30u.Ti* chidt suat ctra chdt th.rn tang Knh n^ G
-/
e
CAu 9(1d): MOr soi day tl6ng c6 ducrng kinh 0,8 (mm), diQn tr&R = 1,1 (Cl), lop scrn c6ch di€n bOn ngoii
rdt m6ng Dilng sgi d6y niy dd quan m6.t 6ng day dii I = 40 (cm) Cho dbng diQn chay qua dng day thi
clm rlnf tt bcitrong 8ng aay "O
OO t* B = 6,28.10-' (T).Tdm hieu drc.n thd & hai ddu dng d6y lt, ,l V) Cflu 10(1d): Cho mach diQn nhu hinh v6 Ngudn di0n c6 sudt di€n dOng Eo = 1,5V , diQn tr& Eong.r = 0,1O Thanh MN dai lm c6 dien trb R = 2,9Q T[ trudrng c6 v6c to ^B thing g6c vdi MN vi hu&rg xu6ng
du6i Ci.m rlng tt le 0,1T Ampe kd c6 diQn tr6 kh0ng ddng kd '
Mudn cho ampe kc chi sd phii dd NIN chuydn dQng vd phia nho vi vfln tdc bao nhi€u?
",,1\
(4)t
GV: Nguy1n minh TuSn
e
oc +: C6u 1(ltI): Dinh nghia tuong t6c tir
CAu 2(JtI): Vi6t c6ng thric,tinh nlng lugng tu trudng cta t5ng d6y co dong <liQn chay qua
Cflu 3(1iI): Quan s6t mQt chi6t dfia dugc cfm nghiOng nghi€ng vio mQt ch$u nu6c ,tathdyth6 nio?Em
hay gi6i thich hiQn tusng d6
Ciu 4(1iI):Di5 co tia 16 khoi mit thri'hai cria ldng kfnh ta c6 cAn diAu kiQn nho cho g6c dinh A hay kh6ng?
Cflu 5(1iI): VAt s6ng AB d4t vu6ng goc vdi truc chinh cira thdu kfnh, c6ch thdu kinh m6t khoing 20 (cm), \
qua thdu kinh chp anh th4t A'B' cao gdp ldn AB.Hey tim ti€u cu cira thAu kinh li:
Ciu 6( 4tI): MQt kim lo4i CD c6 chiAu ddi lOcm, ktr5i tuq,ng m=50g ,d{t w6ng g6c voi hai ray AB song song nim ngang ve n5i v6i ngudn di€n c6 hi€u diQn th6 U.He th6ng duqc d4t tir trulng
c16u huong thdng dung xu5ng duoi vd c6 d,0lcrn B:0,1T ,HQ s5 ma s6t gita thanh CD vd c6c ray IA
k= 0,1 86 qua tliQn tr0 c6c thanh ray , cliQn trO c6c di6m ti6p xtc vd dong diQn cim img m4ch a)Gi6 sri CD trugt sang tnii ( v€ phia AB ) v6i gia t5c a=l.5m/s2 .Xalinf, chi6u vi dO lon cuorrg
dQ ddng di€n chay qua CD
b)Ngudi ta nAng hai Aau a,g cfia hai th4nhray OC c,ac-tUanh ray-hqpv6'ic*c n*+t pheng m6t g6c 300.Tim
huong vi gia tdc chuy6n dQng ctiathanh CD, bi6t ring thanh CD bit dAu chuy6n dQng voi v6n t6c cliu bing kh6ng
Cfiu 7(1iI): MOt th6u kinh m6ng, hai m6t ldi gidng nhau,lhm bang thuf tinh chidt suAt n = 1,5 d6t kh6ng khi, bict d0 tu cfra kinh le D = + 10 (dp) Bdn kfnh m6i mf,t cdu ldi cria thau kfnh bing bao nhiOu?
(5)
ai.-. -GV: Nguy\n minh TuAn
DCsoS
CAu l(tiI):HEy n€u tinh ch6t co b6n ctra tir trudng
CAu 2(1d): Em Tf l6p- 11A4 n6i voi c6c b4n cta em rdng chirng ta c6 thiS ding ddng diQn xoay eC n6u
chiy kim 1o4i mi kh6ng cAn cho ddng diQn ch4y qua kim 1o4i d6 CAu n6i tr€n cl6ng hay sai? c5c em h6y giei thich
CAu 3(1iI): Phet bieu dinh luat khfic x4 6nh sang
CAu 4(1d ): Dinh nghia ss diAu ti6t cria m6t
CAu 5(16): M6.t do4n day din di,i (cm) dat ffong tirtrutrng ddu vi vu6ng g6c v6i vecto cim rlng tt. Ddng diQn chay qua day c6 cuinrg dO 0,75 (A) Lrlc tt tr{c dgng lOn doan day d6 lh 3.10' ($ Cf,m ring tt cira til truong d6 c6 d0 lon b5ng bao nhi6u?
Cf,u 6(1rI): Hai day din thing ddri song son! c6ch l0 (cm) kh6ng khf, dbng di€n chay
hai d6y c6 cDng cudng dg (A) nguo.c chidu Cim rlng tttai didm M c6ch ddu hai dbng diO.n mQt
khoing 10 (cm) c6 dQ l6n bing bao nhi0u?
Cfiu 7(1d):
cho m4ch di6n nhu hinh v€ ' Ngudn di$n c6 sudt diQn dQng E' = 3v ' dien tr& r = 0'2{l'
Thanh MN dei 1m c6 di6n tr6 R = 2,8f) Tt trucrng c6 v6c to ,B thing g6c vdi MN vi hu6ng
xudng du6i CAm rmg t[ la 0,4T Ampe kd c6 di€n tr& khOng d6ng kd Mudn cho ampe kd chi sd phii dd MN chuydn dQng vd phia nho vi v6n t& bao nhi6u ?
Cflu 8(1d): MQt midng 96 hinh trbn, b6n kinh (cm) & tam O, c6m thing g6c mOJ dinh OA
Thi midng 96 ndi rrong mQt chiu nudc c6 chidt sudt n = 1,33 Dinh OA nudc, cho OA
= (cm) M6t dat tron! khong khi, chi€u den lon nhdt ctra OA dd m6t kh6ng thdy ddu A bing
bao nhi€u?
C6u 9(ltl): Cho mQt tia s{ng dcrn s6c di qua lang kinh d{t khdng c6 g6c chidt quang A = 300
vi thu duoc g6c lOch cuc tidu D* = 30o.Tim chidt suat cira lang kfnh '
Cffu 10(1d): VQt s6ng AB qua thiu kinh hQi tu c6 ti0u cu f = 20 (cm) cho 6nh th4t A'B' cao gdp ldn
vAt H6y tim khoing cdch tt v6t tdi th0'u kinh
"A