ĐỀ THI HSG 9 MÔN HÓA HỌC TỈNH ĐỒNG NAI 14-15

Diln toan b9 san pMm chay 19itir tir vao dung dich H2S04 diic du tMy co 1,6 lit khi khOngbj hdp th\l Xac djnh cong thuc phiin tu cua hidrocacbon va tinh ph~n tram th~ tich cua CH4 trong [r]

(1)

Sa

GIAo

vA DAD

DE THI CHINH THUC

KY THI CHQN HQC SINH GIOI LOP NAM HOC 2014 - 2015

MON;HOAHQC

ThiJi gian h'tm hai: 150 phut Ngay thi: 03/04/2015

(D~ thi gbm co trang, co diu) Clin I: (4,0 di~m)

Can 1.1: Nen va giai thich hien tu<;mg(ghi phuO'ng trinh philn Ung) a/ Cha miln qui tim ~m vaa binh chua cia kho

blCha tif tif SO, suc cham vaa nuac voi trang d~n duo

cl Cha nhom vaa dung dich NaOH du

d/ Cha tUng lu<;mgnhO natri d~n du vaa dung dich CUS04

Can 1.2: Tbng

sb

a/ Tim cong thUc h(JJl c~t T bi~t rfutg h(JJl ch~t co th~ t<ta thilnh tif phan ung cua cac dan c~t nguyen

tb

bl Haan thilnh So' db phan ung sau: (m6i mili ten la m(lt phan Ung khac nhau, ghi ro di~u kien (' ') (T) +"'0") (Y) +(T» (Z) +"'0") (Y) +(G» (Z)

neu Co' (1) (') (3) (,)

Can II: (4,0 di~m)

Can II.1: Haan va din b~ng cac ph!m Ung hOa h<;>csau day:

alFeS, +HO ~ 7+7+7 b/FexOy+H,SO,,,,, ~SO,+7+7

clCU,O+HN03 ~CU(N03)2+N.ob +7 dlP+NH,CIO, ~H3PO, +N, +CI, +H,o

eI C6H,o,N + Fe + HCI ~C6H8NCI + FcCl, + H,O f! Cu+O,+?~CuS04+H20

Can 11.2: Tren baa bi m(lt la<tiphiin bOn NPK co ki hieu bfutg cM

sb

- Cha bi~t

y

sb

- Tinh hilm lu<;mgcua nguyen

tb

Can Ill 1: Cha binh chUa m~t nhan chua rieng biet tUng sau: CO, metan, sunfurO', etilen Hay trlnh hay cach nh(in bi~t chua trang cac binh tren (m(lt cach an taan) Vi~t philn ung xay (n~u co)

Can Ill.2: Tif tlnh b(lt (dung cu, di~u kien, ch&t xuc tac va vo Co' co du) vi~t cac phuO'ng trinh di~u ch~ palietilen

Can IV: (4,0 di~m)

Can IV.l: D(l tan cua MgS04 iJ 20°C la 35,1 gam Khi them 1,0 gam MgS04 vaa 100,0 gam dung dich MgSO, baa hOa th~y xu~t hien 1,584 gam MgS04 k~t tinh iJ d<tng mubi ngam nuac (X) Tim cong thuc cua (X)

(2)

Can IV.2: Cho m (gam) Fe vao V (ml) dung djch AgN03 I,OM d~n phan ung hoan toan thu duqc m] (gam) h6n hqp kim 10(li(X) Chia m] (gam) X ph~n Phiin I co kh6i luqng m2 (gam) cho tac d\lng v6i luqng dung djch HCI du thu duqc 2,24 lit PMn co kh6i lm;mgm3(gam) cho tac d\lng v6i luqng du dung djch H2S04 diic nong thu duqc 8,96 lit S02 (S02 la san ph~m khu nh~t cua H2S04) Bi~t cac phan ung xay hoan toan, iJ di~u ki~n tieu chu~n va

m,-m,

aJ Vi~t cacphuong trinh phan ung xiiy

b/Timm

va

Can V: (5,0 diSm)

Can V.I: f!idrocacbon lahqp ch~t him co phiin tu ch] chua hai nguyen t6 eva H Hidrocacbon iJ the thuiJng co so C phiin tu nho han Hon hqp A gom metan va m9t hidrocacbon D6t chay hoan toan 1,0 lit A c~n dung vila du 2,6 lit 02 thu duqc C02 va hoi nu6c Diln toan b9 san pMm chay 19itir tir vao dung dich H2S04 diic du tMy co 1,6 lit khOngbj hdp th\l Xac djnh cong thuc phiin tu cua hidrocacbon va tinh ph~n tram th~ tich cua CH4 h6n hqp A Bi~t rimg thS tich cac iJ cimg di~u ki~n nhi~t d9 va ap suk

Can V.2: Cho m (gam) h6n hqp X g6m ancol etylic va axit hiiu co A (CnH2n02) d6t chay oxi chi

thu duqc h6n hqp Y (g6m vahail. Toan b9 Y bi hdp th\l hoan toan vao dung djch NaOH (6 nhi~t d9 thuiJng) thi thdy kh6i luqng dung dich NaOH tang 4,08 gam thu duqc dung djch Z Cho h~t Z tac d\lng v6i dung djch CaCh du thu duqc dung dich T va m] (gam) kSt tua Cho h~t T tllC d\lllg v6i dung djch Ca(OHh du thu duqc m2 (gam) kSt tua Bi~t m]+m2=6,00.Bi~t thS tich iJ di~u kien tieu chudn va X co 37,0%<%mA<42,0%

aJ Vi~t cac phuong trinh phan ung

bl Tim cong thuc phiin tu, goi ten A

cl Dun m (gam)h6n hqp X (co xuc tac H2S04 diic) thu duqc 0,528 gam este Tinh hi~u sudt phiin ung t(lOeste

-H~t -Cho bi~t nguyen tu kh6i{theo u) cua cac nguyen t6: H=I; C=12; N=14; 0=16; S=32; CI=35,5; Br=80; Li=7; Na=23; K=39; Rb=85,5; Cs=133; Mg=24; Ca=40; Ba=137; AI=27; Mn=55; Fe=56; Cu=64; Zn=65; Ag=108

Thi sinh ilu(fc sir t4tng bang

hf

thdng tniln hoi'm cac nguyen

hoa h(Jc

Ho va ten thi sinh: s6 bao danh:

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