1. Trang chủ
  2. » Sinh học

Lam quen voi Toan tieng Anh

2 15 0

Đang tải... (xem toàn văn)

THÔNG TIN TÀI LIỆU

Thông tin cơ bản

Định dạng
Số trang 2
Dung lượng 15,07 KB

Nội dung

Các em hãy làm quen với các bài toán bằng tiếng Anh sau đây.. Chúc các em học tốt.[r]

(1)

Các em làm quen với toán tiếng Anh sau Chúc em học tốt ***

1. (a) It is given that  = {1, 2, 3, 4, 5, , k} where k is a positive integer P is a subset where P = {x: x is a prime number}

Q is another subset and Q = {x: the unit digit is 9} (i) List all the members of Q given that k = 100

(ii) If n(P  Q) = 4, list the elements of the set P  Q and hence state the largest possible value of k

(b) It is given that n() = 23, n(A  B) = x, n(A) = y, n(B) = 2y and n(A'  B') = (i) Use a Venn diagram and show that 3y = 16 + x

(ii) Hence find the least possible value of y

2. Find the equation of the perpendicular bisector of AB where A is (3, 10) and B is (7, 2) 3. The roots of the quadratic equation x2 -

√6 x + √x = are  and  Without using a calculator, show that 1α + 1β = √3

4. The tangents TA and TD are drawn from a point T to the circle, centre O The diameter DB and the tangent TA when produced meet at E Given that  ADO = 26o, find

(a)  ADT (b)  ATD (c)  BAE

(d)  ACD ( C is a point on the cirlce, centre O)

Tơn Nữ Bích Vân giới thiệu

(2)

1. (a) (i) Q = {9, 19, 29, 39, 49, 59, 69, 79, 89, 99} (ii) P  Q = {19, 29, 59, 79} ; k = 88

(b)

least value of y = [when x = 2]

2. The mid-point of AB is (5, 6) The gradient of the line AB is - 107 - 3 = -2 The perpendicular is the

line with gradient 12 and passing through the point (5, 6) Equation of the perpendicular of AB is:

y - = 12 (x - 5) y = 12 x + 72 Alternative method

Let P(x, y) lie on the perpendicular of AB Therefore PA = PB

y - 10¿2

x - 3¿2+¿ ¿

√¿

=

y - 2¿2

x - 7¿2+¿ ¿

√¿

 x2 - 6x + + y2 - 20y + 100 = x2 - 14x + 49 + y2 - 4y + Simplifying, 8x - 16y + 56 =

 y = 12 x + 72

3. The quadratic equation whose roots are  and  is (x - ) (x - ) = x2 - (

 + )x +  = By inspection:  +  = √6

 = √2

Now 1α+1

β= α+β

αβ =√

6

√2=√3 [Hence shown]

4. (a) ODT = 90o (tan  rad ) ADT = 90o - 26o

= 64o

(b) TA = TD (tangents from an external point) TDA = TAD (base s of isos ) ATD = 180o - 64o - 64o ( sum of )

= 52o

(c) BAE = ADB ( in alt segment) = 26o (d) ACD = ADT ( in alt segment) = 64o

A B

7

(y-x) x (2y-x)

26o O E

A B

C

D

Ngày đăng: 04/03/2021, 19:53

w