Đề và hướng dẫn chấm - Kỳ thi thử Tốt nghiệp THPT năm 2020

gini thich hiQntucrng khirc xa.[r]

I

so

GrAo

DUC

& EAO

TAO QUANG TRI

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cxsxtsr,$;

er*

o0s

on

rnr

rntl

16r

NcnrFr

rnrr-

NAnn zozo

\l\bnt\i'.\

f;T

Li

Thdi

gian

ldm

bdi:

50

philt

(40 cdu

triic

nghiQm)

(De

thi

g6m c6 04 trang)

Ho,

t6n

thi

sinh:

SO b6o danh

Ciu

1: Theo dinh 1u0t khirc xp 6nh s5ng

thi

A

g6c

t6i

t[ng

bao nhi6u lAn, g6c khric xa

ctng

t[ng

bAy nhi6u lAn

B g6c khirc xp 1u6n l6n hcrn g6c

tdi.

C tia khirc xp vd tia

t6i

lu6n ngugc chi6u

D tia khric xa vd tia

t6i

nim

trong

ctng

mQt mflt

phing

ggi ld mat

phing t6i.

Ciu

2:

Dat diQn 5p xoay

chi6u

u

=Uo

cos(at +

rp)

vdo hai d6u dopn m4ch g6m diQn

trd

R mEc nOi tl6p

v6i

tU diQn c6 diQn dung C T6ng trO

cta

tlopn mpch ld

A.

R2-

B

R,

_C,A}

-t-

'

C2at2'

D.

+(Ca)2

Me

da

thi

137

c

lir

xtty

(t

)'

lc,

)

C R2

Ciu

3:

Hi6n tugng t6n s8c dugc irng dung

A

gini thich hiQntucrng khirc

xa

B th6ng

tin

1i6n l4c

bing

s6ng v6 tuy,5n

C m6y quang ph6 lnng

kinh

D tiQt trung thgc ph6m tru6c

khi

tl6ng g6i

CAu 4: Nguy6n t8c hopt dQng.cira thi6t

bi

ndo sau ddy khOng dga tr6n hiQn tuqng c6m ring tlien

tu

?

A

M5y phat diQn xoay chi6u mQt

pha

B DQng co kh6ng tl6ng bQ ba pha

C M6y bi0n

6p

D Bdn ld diQn

Ciu

5: TOc d0 truydn Am c6 gi6

tri

nhO nh6t m6i trucrng ndo sau ddy?

A

Nh6m

B Kh6ng

khi

d

0"C

C

SEt

D Nu6c bi6n

o

15"C

Cffu 6:

MQt ch6t

ditim

dao tlQng tti6u hda

v6i

phucrng

trinh

x

:

Acos(ail + cp), gia t5c cira chdt

ditim

c6

gi6trl

cgc dpi

li

A

Aaz

B

-a'x

C

A2o

D

Aat.

Cflu 7:

Tai

hai

di€m

A,

B

trdn

mflt

nu6c c6 hai ngudn s6ng k6t

hqp

ctng

pha PhAn

tu

nu6c

tpi

trung

dii5m ctra do4n

thlng

AB

dao dQng

A vdi

bi6n d0 cpc

dai

B

v6i

bi6n d0 cuc tii5u

C

ctng

pha

v6i

hai

ngudn

D nguoc pha

v6i

hai ngudn

Ciu

8: MQt ch6t di6m c6 khOi lucr-ng

m

dao dQng di6u hda

v6i

tAn

sd

g6c

at

vd bi€n dO

A.Li

dQ vd vpn t6c cria ctr6t Oiem tpi

ctng

mQt

thoi

di6m ln

x

virv DQng ndng cgc dpi cira ctr6t ei6m

h

, I

1)

mv'+-mc)'x'.

2

maA

s

1

2

p

1

2

mx'

2

mv

,1

-+-2 mv

r1

)

s

1

2

2

CAu

9:

C6ne tho6t dti

brit

Olectron

ra

kh6i

bO

m{t

mQt

kim loai

ld

A

Ggi

h

ldhilg

sO

Pling,

t6c d0

6nh s5ng

trong

ch6n

kh6ng Chi6u

vio

kim

lopi ndy bric x4

diQn

tu

c6

budc

s6ng ,2' D6

ra hiQn

tuqng

quang iliQn

thi

A.t>!9

AhcAhc

B.),<!-

c.).<!9

D.).>!.

Cflu

10:

D[t

l6n lucvt c5c ngo4i

lgc

cu0ng bric bi6n thi6n didu hda theo

thoi

gian

v6i ctng

bi6n dQ, c6

tin

s6 lAn

luqt

ld7

:

20

Hz,

fz:

14 Hz,

fz

:

8 Hz,

fi

:

)

H,

vdo mQt l6c cO.tan si5 dao t1Qng ri6ng ln

I4Hz

Con

lic

dao dQng cu6ng birc

v6i

bi6n <10 l6n nh6t img

vdi

ngo4i

luc

co tdn s6

Lfr

B.fi

C.fi

D.f4.

Ciu

11: Hat nhdn

lx

cO khOi

luqng m

Ggikh6i

luqng

cira pr6t6n vd notron

6n luqt

ld mpvd mo, d0 6nh s6ng chAn kh6ng ld c Ndng luqng 1i6n ktit ri6ng cria h4t nhdn ndy ld

A.

lZ*r+(A-Z)m^-*7r'

B

lz*o+Am,-m)c'

A

C lZm,

+

(A-

Z)m,

-

m)

A

o

lzmo

+ Amo

-

*1"'

Ciu12:

MQt s6ng co hinh sin c6 chu

ki

ld

f,

tAn sO

ta;

t5c d0 truydn s6ng

li

v

thi

budc s6ng ld

A

).=:

B

l.:T.f

C.2:+

D

).=v.f

rf

Ciu

13: DiQn 5p xoay

chidu

u:(Jocos(100at

+

nl6)

(/ tinh

bing

s) c6 tAn sO g6c

bing

A.50

radls

B 116

radls

C.Zr

radls

D

100zrad/s

Ciul4z

Trong chAn kh6ng, s6ng diQn

tu

c6 tAn s5 ndo sau ddy ld s6ng v6 tuy6n cgc ng6n?

A

8

MHz

B

5

MHz

C 0,3

MHz

D

900

MHz.

Cflu

15: Mach dao dQng

li

tuong

gdm

tu

diQn co diQn dung C

vi

cuQn

cim

thuAn c6 h0 s,5 t.u

ca-

Z Chu

ki

dao dQng ri6ng ctra m4ch ld

tlrr

A

T:)- lL

'"\lc

B

" -L'LY,

T:z*,[tc

C

T: -:-

D

T

=

]-JLC

2;@'

u"

2r

Cffu

16:

MQt ch6t ph6ng

xp c6

chu

ki

bin

rd

ld

7 Ban

dAu co 1/o

hat

nhdn ch6t phong xp ndry, sau kho6ng

thdi

gian

nio

sau ddy

thi

sO trat nhAn chAt ph6ng xg ndy cdn

lai

lit Nol2 ?

A,

N=27

B

N:7

C

Lt=L

D

Lt:L.

42

CiulTzV6cto culng

d0 diQn

truong

gdy rabdi mQt diQn

tich

di[m

Qc6

chi0u

A

huong

rlxa

Q

n6u Q <

0

B 1u6n hudng vO phia Q.

C hucrng vO phia Q ndu Q <

0

D lu6n

hufng

raxa

Q.

Ciu

1"8:

Khi

dQng co kh6ng d6ng b0 ba pha hopt dQng 6n dinh

thi

t6c cIQ quay cira r6to

A

bdng t6c d0 quay cira tri

trulng

B lon hcrn t6c <IQ quay ctra

tu

truong

ft

C gAp

r/3

ldn t6c d0 quay cira tri

trucrng

D nho hcyn t6c dQ quay cria

tu

trucrng

CAu 19: X6t nguyCn

tu

hitlrd theo m6u nguyCn tu

Bo voi

ro ld b6n

kinh

Bo Tr4ng th6i drmg cria nguy6n

tt

img

vdi

b5n kinh

qu!

dpo drmg cira 6lectron

nio

sau d6y ld tr4ng th6i ccy

bin?

A

16ro

B

,o

C

4ro

D

3610

Ciu

20: Tia ndo sau ddy

kh6ng

c6 b6n ch6t s6ng diqn tu?

A.Tia

a

B Tia hdng

ngo4i

C Tia tu

ngo4i

D

Tia

X.

Ciu

212 Trong

thi

nghiQm giao thoa khe

Y-ing v6i

6nh s6ng dcrn

sic

c6

bu6c

s6ng 0,5 pm,

ti

s6

gita

khoing

c6ch tu hai khe d6n mdn vd

khoing

c6ch

gita

hai khe

ld

1,5.103

Khoing

vin

quan s6t duoc tr6n mdn

b[ng

A

0,5

mm

8.0,75

mm

C 0,75

m

D

0,3 mm

Cil22:

M6t

con l6c dcrn c6 chiAu dei 80 cm, dao dQng

v6i

bi6n d0 g6c ld 5o Bi6n dQ dao dQng cira

l[c

ld

A

0,7

m

B

cm

C.4

m

D.4

cm

Cflu

23:

Dit

mQt hiQu diQn thti

khdng

dOiZ+

V vio

hai dAu mQt do4n mach

thi

cudng dQ dong diQn chay qua dopn mpch

ld2JrA

C6ng su6t ti6u thu diQn ndng cria dopn m4ch ndy ld

A

96

W

B 48

W

C.24o

W

D 48

o

W

Chu 242 Cho ph6n img h4t nh?'n

lHe

+'lw

*

lX

+

itt

56 nortron ctra hpt

nhdnXld

A

17

8.25

C

9

D

8

C6u 25: Dat mQt diQn 6p xoay

chi6u

u

= 220Jicos(1002r

+

d

U)

vio

hai d6u dopn mpch

RLC

nf,i ti€p

thi culng

d0 ddng diQn qua doan mpch

li

i

=

Ocos(100

nt) (A) Bitit

c6ng su6t tiCu thu dign ndng cira do4n mpch ln 39

W

Gi6

tri

cta

gbitg

I

C6u

26: TrCn mQt sgi ddy ddn

h6i

hai

diu

cO Oinn ddi2,4

m

dang c6 s6ng dimg

v6i bu6c

song 60 cm

56 bpng s6ng trdn ddy ld

4

t2

8.4

c

8

D

6.

ciu27:

MQt th6u

kinh

hOi tr,r c6 ti6u cp ld 25 cm, d6 tu cua th6u

kinh

ndy

bing

A.0,05

dp

B

5

dp

C.4

dp

D

0,04 dp

CAu 28: Hai

lic

ld

xo

A

vd

B

nhu

rlirr,

ctng

dao dQng di6u hda

v6i

bien dQ l5n

luqt

lit

Ar

:10

cm

vd

Az:

4 cm

Ti

s6 tlQng ndng cira l6c

A vntQng

narg

.o, lic

B

khi

chirng

ctng di

qua

vi

tri

cdn

rJ Dang ta

4.2,50

B

0,04

c

0,16

D.6,25.

Cdu

29:

ei6t hing

so Pl5ng Id h:_6,625.10-3aJs

Anh

s6ng d<rn

sic

c6 tdn s5 5.10ra

Hz

ducrc tao thdnh

btti

cilc ph6t6n mang

nlng

luqng

bing

A

1,1041.10-27

J-

B

3,3125.10-te

J

c.3,3125.10-20

J

D

1,1041.10-2s

l.

C6u 30:

D[t

mQt diQn.ap xoay chi6u

co

gi|tri

hiQu dsng

Uvdo

hai dAu doan mach gdm tu diQn m6c

n5i

ti6p

v6i

cu6n.c6m thuAn

Khi

d6 di6n 5p hiQu dsng hai dAu tr; tliQn lA 30

V,

t1iQn ep hiQu dUng hai ttAu

cuQn c6m thuAn le 40

V

Gi6

tri

cria

Ubing

'

a - -

-' A

10

V

B

50

V

c

70

v

D

50.,8 V.

Ciu

31:

Trong chdn kh6ng, b1rc

xp

dign

tu

c6

bu6c

s6ng

2r

:

10

pm

thuQc vung h6ng ngoai,

birc

xa

diQn

ttr

c6

bu6c

s6ng

Az:

l0-e

m

thuQc

vtng

tia

x

Ti

sigita

tAn s6

tia

hdng ngJpi

"alirisO

iiu

x

Ai

cho o trOn

bing

A

10-3

B

104

C

103

D

10-4.

Ciu

32:

M$t

s6ng dign

tu

c6 chu

ki

0,25 prs, truydn m6t

m6i

trucrng

v6i

bu6c s6ng 60 m T6c d0 s6ng diQn tu

m6i

trudng ndy ld

A.2,40.108

m/s

8.2,25.108

m/s

c.3,00.10s

m/s

D.0,15.108 m/s.

C0u

33: Hai

dao dQng

ili6u

hda

ctng

phuong

c6 phucrng

trinh

ld

xt

=

Acos(at

+ rpr)

vd

xz

:

4cos(rtt

+

g)

D6

thi

bi6u di6n

sg

bitin thi0n

cria

xr

vd

xz

theo

thdi

gian

r

nhu

hinh v6 T4i thcri

di6m

r

:0

thi

pha cria dao dQn! t6ng hqrp

cria hai dao dQng tr6n

bing

B xl6

D.5r/6

J

.6,

-.6

-3

x(cm)

{(cm)

r(s)

A

0

C

rl3

CAu

34:

MQt

con

ldc.lo xo

dang dao

cl6ng

di6u hda

theo phucrng

thing

drmg (dAu

tr€n

lo

^o

.5

dinhldAu du6i lo

xo

gin

v6i

v4t

n[ng)

OO

thi

bi6u di6n ss bi6n thi6n cria chi6u ddi

(

ctla ld xo theo

thdi

gian r dugc cho nhu hinh vE Ldy

g: t

m/s2" giiSt dQ ctmg cira tO xo

ld

120

N/m, luc

tlnn h6i

.,iJtO

"o

c6 dQ lcrn cuc dai

bing

A

12

N

B

22,9

N.

c

10,9

N

D.24,2N.

lt

I

l. t

-

r r .1-I t I t, -r 40 20

t

-I I

-a { -F-tll -{ -t -rrtl

- -

l-

ltlltl| i-r - l- - -!- I .1 -r-

l-ltlltltr

lttltlt r(s)

9

Ciu

35:

Q*u}

s6t s6ng.drmg tr6n sqi ddy

AB,

dAu

A

dao itQng tli6u hda theo phucrng vu6ng g6c

v6i

sgi

9:f

Xt

tgn s,O4t1aV AOi Auqc,

A

dusc

*.*

ia nirt

Khi diu B

Lu

vdl:

22 Hzthi

tr6n

diy

c6 nrit

N6u d6u

B

c6 dinh vd coi t6c tto truy6n s6ng kh6ng aoi, ac tr6n d6y c6 nrit

thi

gi6

*i

c1pfkji

d6 ln

A

15

Hz

B

16

Hz

C.20

Hz

D.24

Hz.

Ciu

36: Ept diQn 6p xoay

chi6u

u =

u

Ji

cos(l\\rt

+ @

(U

ldrfing doi) vdo hai dAu dopn m4ch

RrC

ri;i

ti6p c6

C

thay

doi

duqc

Ei6u

chinh C dc

he s6 c6ng suAt cria

riach ld

0,8

thi

c6ng su6t

iicu

,t

o

.t

u mach

le

100

W

Khi

di0u

chinh

C dC mach

*iy

,ucQrig huong tliQn

thi

c6ng

*i,

ril,i1"f,o

trl,

iu.f,

1.1,i

d6 le

A

186,45

W

B

140,56

W

c.201,15

W

D

156,25 W.

Ciu

37: Tai hai

didm

A,

B

tr€n

m[t

ch6t

l6ng c6 hai

ngu6n s6ng

k6t

hqp ctng

pha

dao dQng theo

phucrnglhing

dung Tpi ditim

M

tr€nm[t

ch6t lSng c6

cyc?pi

gir"

ti""

Fii6i

ea

:25

cm,

AM:15

cm,

MB

: ?0

cm,

gita

Y

"d

1"Tg

trung

tryc

c:ira

AB

c6

2

vdn giao thoa cuc ti6u Tr6n dudn

g

thing

ua,

,6

cpc ti6u giao thoa

nlm

gifta

Mvd B

lir

A ln

r) r^

)

{

Ciu

38: MQt lEc

ld

xo dflt tr6n

m{t

sdn

nim

ngang khdng ma s6t nhu hinh v6 Lo xo nhg c6 d0

[:

100

N/m,

vft

nho c6 ktr6i luqng

m:

I

kg, mang

Q:

l}'s

c chqn

tryc

ox

gan vor mat ,! , san, song song

v6i

tryc

ld

xo,

chiOu ducrng hudng xa

dinh

k

m

E

cua lo xo

Khi

ld xo kh6ng bitin d4ng

diQn

tich

-.,1

dlem co

kh6ng gian img

v6i

x

>

0 c6 mQt diQn

thi

v4t g6c tqa dQ O

trulng

d6u

mi

v6cto

MiAn cudng

+

x

dQ diQn trucrng cung hu6ng

truc Ox

vd c6

d0

l6n

E:

5.10s

V/m.

Ban dAu

ngudi

ta

git

m

b

vi tri

ld

xo n6n

10 cm

rdi

th6 nhg tpi

dugc tinh

tri

/:0

di5n

thoi

di6m vflt d6i chi6u chuy6n dQng lAn thtr

thoi di6m

/:0

Qu6ng ducrng vat

di

2020bins

A.612,45

m

B 528,84

m

C

167,78

m

D.200,28

m

Ciu

39: Dat mQt ttiQn 6p xoay

chidu

u:(JJicos(100ar+p)

(V)

vdo hai ddu cuQn dopn m4ch

AB

mdc

n5l

t6p

theo

thf

ry

g6+

diQn

tro

R, tu diQn c6 diQn dung C, cu6n

cim

thuAn

.9

hC

:6

F:{T

Z

thay d6i

dugc

Gqi

M

li

di6m

nim gita

tU dipn vdL cuQn cdm

Khi

L:

Lt

vd

L:

Lzthi

diQn 5p hai ddu cuQn

cim

bing

nhau, d6ng

thoi

cudng tlQ ddng diQn qua mpch hai

trulng

hqrp lQch pha mQt g6c xl3

DiQn 6p hiQu dtmg tr6n dopn

AMkhi

L:

Lt

vd

L:

Lz ch0nh lQch mQt luqng bdng

A

uJT

B

u

c

o,su

D

uJ,

Ciu

40: DiQn

nlng

tu

nhd mby phdttliQn xoay chi6u dugc truydn di5n

noi

tiOu thu

bing

duolg

ddy mQt pha Ban AAu Aq

glPji?"r6p

trdn ducrng day

bing l0%

diQn

6p

cirtr-tii

ti6uthu

Xem

hQ s6 c6ng suAt cua mAcn rnryen tar 1u6n

Uing

f Can phai teng diQn 6p dAu ilucrng d6y truy6n

tdi

l6n bao nhi6u lAn de gi6m c6ng su6t hao

phi

tr6n ducrng truydn 100 16n nhrmg v6n

dim

bdo c6ng suAt

noi

ti6u thg

nh{n

dugc ld kh6ng d6i?