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Kh6a ngiy 20 thimg n5m 2$1,8 naoN THr: SINH [rQC
Thdi gian ldm bdi: 150 philt, kh6ng kA thdi gian giao di
Ciu 1 (2,0 diAm)
Khi n6i vC thAn kinh vi giic quan i' ngucri, c6c ph6t bi6u sa,r dny li d,ing hai, sai? Giai thich
r Phan x4 kh6ng cii6u kiQn c6 tinh ch6lcii truy€n va 4a11glLjIlxl,1ifoCt}.][h(r.
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^-Z.Dsavdo c6u truc, hQ thAn ki-nh d"# ctriittranh hQ thin t<Hn van dQng hQ th6n
kinh siirh du6ng
3 Ngucri cQn thi mu6n nhin rO nhtng vpt o xa ph6i deo kinh m6t l6i
4 Khi b4n d6 chdn tr6i thi phAn vo b6n cAu bdn ndo tr6i se khoi ph6t ho4t tlQng cIo"
Ciu2 (3,0 di€m)
1 Khi n6i vC lodi ong vd lodi hoa, c6c ph6t bi6u sau ddy ld dring hay sai? Giii thich a) Tflp hqp nhfrng ong thq l6y mflt hoa o mQt vuln hoa ld mQt quAn thO
b) Trong m6i quan h6 gifra mQt lodi hoa vh lodi ong hft m4t hoa d6 thi lodi ong c5 ltyi cdn lodi hoa bihai
2 Gih sr? lu6'i thfc 5n ctia mQt quin x6 sinh vpt gdm c6c lodi sinh vAt ki hi6u laA, B,
C, D;-E, F, G vd Il Cho bi€t loai A vd loi\i C 1a sinh ,'flt sdn suit, c6c loii con iqri ld sinh r,4t ti6u thU Trong iudi th,3c In nlry, n€u bo lodi C kii6i qriiin xd thi chi loai D vd loii Ir rn6t
di So AO tuOi thric dn ndo sau dAy dring voi chc thdng tin d6 cho? GiAi thich
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Cffu (2,0 di€m)
T4i lai hai ddng thuAn, uu thti lai bi6u hiQn cao ntr6t O F1, sau d6 gi6m dAn qua
cac tht! hgt
Cflu (2,0 di€m)
Gen B c6 900 nucl€dtit lopi timin (T) va c6 ti lQ .A+T3:i: : f c"r, B bi dQt bi6n dang thay th6 mQt cflp G-X bAng mQt c4p A-T tr& thAnh gen b finl tOng sO 1i6n t<tit triOrO cta gen b bdng hai c6ch
Cffu (2,0 diAm)
O mQt lodi c6n trtng, gen A quy dinh thdn xdm trQi hodn todn so vdi gen a quy dinh
th6n tlen; gen B quy ttinh c6nh ddi trQi hodn toin so v6i gen b quy dfnh cdnh cpt Cdc gen quy dinh mdu sic th6n vd hinh dpng c6nh nim tr€n mQt c4p nhi6m iAc thC thudne vA lien ktit hoan.toan Lai phdn tfch co ttriS.ai hcyp tg vO hai c{p gin.n6i tr6n thu duqc E6 fheo l1i
thuyiSt, ti lQ kiiiu hinh F6 nhu thti ndo? Vit5t scr OO tai Bitit ring, kh6ng x6y ra d0rbi6n.
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(2)y) C6ra 6 ('2,0 dt\m)
K iti n6i -,,e dOt bit5n nhiErn sis th6, c6c phdtbi6u sau d6y ld dting hay sai? Gi6i thfch Dot bi6n nhiSrn s6c th6 ohi xay b cdc nhi6m s6c thO thudng md kh6ng xiy ra o c6c nhiSrn sic th6 gi6i tinh
2 HQi chrlng Eao chi e?p e nam md kh6ng c6 nt.
3 Co chO ph6t sinh th6 da bQi ch8n ld tlt cd c6c c[p nhiSm sic th0 tg nhan ddi nhung cc mgt s0 cap nhi6rn shc thiS khdng ph6n ly
4 Lolt tac nh6n tiQt bitin eid dugc sri dpng d6 tac, gi6ng dfiu tiin da bQi c5 16 to vd
div hon dan_e ltrdng bOi binh thuone ld EMS (6t1,1 rndtan sunphdnat).
Ciu 7 13,tt diintl
Cho bi6t rnSi gen quy dlnh mQt tinh trang, gen trQi lA trQi hodn todn, kh6ng ph6t sinh
dQt biiSn X6t cdc phdp lai sau:
(1) AaBb x aabb {Z; aanb x AaBB (3) aaBb x aaBb ;(4) AaBb x AaBB '(5) AaBb x aaBb (6) AAbb x aaBb
Theo li thu1,[1, troug c6c ph6p lai tr6n, phep lai nao cho doi co sO loai ki6u gen
nhiOu hon s6 loai ki6u hinh? Gi6i thich
" C6u (2,0 dilm)
Then l,.thuy6t, te bao sinh tinh cua mot co thO co kieu gen Hatsb giArn pirit l;inir
thudng c6 thO tpo bao nhi6u lo4i giao tri? Vi6t ti lQ c6c lopi giaoi* AO
a-A',3 r) q t:i -t i_arj r iz,:) :!!,_'in,i
) ? ' O mQt
lodi thFc v4t tg thu phAn bit budc, gen A quy dinh hoa d6 trQi hoin toin so v6i
gen a qu1' ,Jinh hoa trdng Cho c61, lrou d6 (P) tU thU ph6n, thu duoc F1 Theo ly thuy6t, ti l0 ki6u hinh o Fr ld bao nhi6u? Bi0t 6t gen een ndrn tr6n nhiSrn ndm tr6n nhi6m sic s[c th6 thrriyns vA th6 thulng va kh6ng kh6no *ay xAv rar:u
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