1. Trang chủ
  2. » Kinh Doanh - Tiếp Thị

Download test bank for chemistry the central science 10th edition by brown lemay and bursten

33 239 0

Đang tải... (xem toàn văn)

Tài liệu hạn chế xem trước, để xem đầy đủ mời bạn chọn Tải xuống

THÔNG TIN TÀI LIỆU

Thông tin cơ bản

Định dạng
Số trang 33
Dung lượng 695,72 KB

Nội dung

9.1 2 According to VSEPR theory, if there are five electron domains in the valence shell of an atom, they will be arranged in an __________ geometry.. 9.2 3 According to VSEPR theory, if

Trang 1

Chemistry, 10e (Brown)

Chapter 9, Molecular Geometry and Bonding Theories

Instant download Test bank for Chemistry The Central Science 10th

Edition by Brown, LeMay, Bursten

CLICK HERE

Multiple-Choice and Bimodal

1) For a molecule with the formula AB the molecular shape is 2

Diff: 1 Page Ref: Sec 9.1

2) According to VSEPR theory, if there are five electron domains in the valence shell of an atom, they will

be arranged in a(n) geometry

Diff: 1 Page Ref: Sec 9.2

3) According to VSEPR theory, if there are four electron domains in the valence shell of an atom, they will

be arranged in a(n) geometry

Diff: 1 Page Ref: Sec 9.2

4) The electron-domain geometry and molecular geometry of iodine trichloride are and

, respectively

A) trigonal bipyramidal, trigonal planar

B) tetrahedral, trigonal pyramidal

C) trigonal bipyramidal, T-shaped

D) octahedral, trigonal planar

E) T-shaped, trigonal planar

Answer: C

Diff: 1 Page Ref: Sec 9.2

5) The molecular geometry of is square planar

Trang 2

Answer: B

Diff: 2 Page Ref: Sec 9.2

Trang 3

6) The molecular geometry of the H O3 ion is

Diff: 2 Page Ref: Sec 9.3

7) The molecular geometry of the CS molecule is 2A) linear

Diff: 1 Page Ref: Sec 9.2

8) The molecular geometry of the SiH Cl2 2 molecule is A) trigonal planar

Diff: 1 Page Ref: Sec 9.2

9) The molecular geometry of the PHCl2 molecule is A) bent

Diff: 2 Page Ref: Sec 9.2

10) The molecular geometry of the CHCl molecule is 3A) bent

Diff: 1 Page Ref: Sec 9.2

11) The molecular geometry of the SF molecule is 2A) linear

Trang 4

12) The molecular geometry of the PF2 ion is

Diff: 1 Page Ref: Sec 9.2

13) The F–B–F bond angle in the BF2- ion is approximately

Diff: 1 Page Ref: Sec 9.2

14) The Cl–Si–Cl bond angle in the SiCl F2 2 molecule is approximately A) 90°

Diff: 1 Page Ref: Sec 9.2

15) The F–B–F bond angle in the BF molecule is 3

Diff: 2 Page Ref: Sec 9.2

16) The O–S–O bond angle in SO is slightly less than 2

Diff: 1 Page Ref: Sec 9.2

17) The F–N–F bond angle in the NF3 molecule is slightly less than A) 90°

Trang 5

18) According to valence bond theory, which orbitals on bromine atoms overlap in the formation of the bond in Br ? 2

Diff: 1 Page Ref: Sec 9.4

19) The electron-domain geometry of a sulfur-centered compound is trigonal bipyramidal The

hybridization of the central nitrogen atom is

Diff: 1 Page Ref: Sec 9.5

20) The hybridization of orbitals on the central atom in a molecule is sp The electron-domain geometry around this central atom is

Diff: 1 Page Ref: Sec 9.5

21) The hybridization of orbitals on the central atom in a molecule is sp2 The electron-domain geometry about this central atom is

Diff: 1 Page Ref: Sec 9.5

22) The hybridization of the carbon atom in carbon dioxide is

Trang 6

23) The hybridization of the central atom in the XeF4 molecule is

Diff: 2 Page Ref: Sec 9.5

24) The electron-domain geometry of the AsF - ion is octahedral The hybrid orbitals used by the As 6atom for bonding are orbitals

Diff: 2 Page Ref: Sec 9.5

25) In order to produce sp3 hybrid orbitals, s atomic orbital(s) and p atomic orbital(s) must be mixed

Diff: 1 Page Ref: Sec 9.5

26) The angles between sp2 orbitals are

Diff: 1 Page Ref: Sec 9.5

27) There are σ and π bonds in the H–C≡C–H molecule

Trang 7

28) There are σ and π bonds in the H C=C=CH molecule 2 2A) 4, 2

Diff: 1 Page Ref: Sec 9.6

29) The total number of π bonds in the H–C≡C–C≡C–C≡N molecule is A) 3

Diff: 1 Page Ref: Sec 9.6

30) There is/are σ bond(s) in the molecule below

Trang 8

31) There is/are π bond(s) in the molecule below

Diff: 1 Page Ref: Sec 9.6

32) There is/are π bond(s) in the molecule below

Diff: 1 Page Ref: Sec 9.6

33) The Lewis structure of carbon monoxide is given below The hybridizations of the carbon and oxygen atoms in carbon monoxide are and , respectively

Trang 9

Multiple-Choice

34) The basis of the VSEPR model of molecular bonding is

A) regions of electron density on an atom will organize themselves so as to maximize s-character

B) regions of electron density in the valence shell of an atom will arrange themselves so as to maximize overlap

C) atomic orbitals of the bonding atoms must overlap for a bond to form

D) electron domains in the valence shell of an atom will arrange themselves so as to minimize repulsions E) hybrid orbitals will form as necessary to, as closely as possible, achieve spherical symmetry

Answer: D

Diff: 1 Page Ref: Sec 9.2

35) According to VSEPR theory, if there are three electron domains in the valence shell of an atom, they will be arranged in a(n) geometry

Diff: 2 Page Ref: Sec 9.2

36) In counting the electron domains around the central atom in VSEPR theory, a is not included

A) nonbonding pair of electrons

B) single covalent bond

C) core level electron pair

D) double covalent bond

E) triple covalent bond

Answer: C

Diff: 1 Page Ref: Sec 9.2

37) The electron-domain geometry of is tetrahedral

Diff: 2 Page Ref: Sec 9.2

38) The O–C–O bond angle in the CO32- ion is approximately

Trang 10

39) The Cl–C–Cl bond angle in the CCl O molecule (C is the central atom) is slightly 2A) greater than 90°

Diff: 1 Page Ref: Sec 9.2

40) Of the following species, will have bond angles of 120°

Diff: 1 Page Ref: Sec 9.2

41) The molecular geometry of the BrO - ion is 3

Diff: 2 Page Ref: Sec 9.2

42) The molecular geometry of the left-most carbon atom in the molecule below is

Trang 11

43) The molecular geometry of the right-most carbon in the molecule below is

Diff: 1 Page Ref: Sec 9.2

44) The bond angles marked a, b, and c in the molecule below are about , , and , respectively

Diff: 2 Page Ref: Sec 9.2

45) The bond angles marked a, b, and c in the molecule below are about , , and , respectively

Trang 12

46) The bond angle marked a in the following molecule is about

Diff: 1 Page Ref: Sec 9.2

47) The central iodine atom in the ICl -4 ion has nonbonded electron pairs and bonded electron pairs in its valence shell

Diff: 1 Page Ref: Sec 9.2

48) The central iodine atom in IF5 has unbonded electron pairs and bonded electron pairs in its valence shell

Diff: 1 Page Ref: Sec 9.2

49) The central Xe atom in the XeF4 molecule has unbonded electron pairs and bonded electron pairs in its valence shell

Trang 13

50) An electron domain consists of

a) a nonbonding pair of electrons

Diff: 1 Page Ref: Sec 9.2

51) According to VSEPR theory, if there are three electron domains on a central atom, they will be arranged such that the angles between the domains are

Diff: 1 Page Ref: Sec 9.2

52) According to VSEPR theory, if there are four electron domains on a central atom, they will be

arranged such that the angles between the domains are

Diff: 1 Page Ref: Sec 9.2

53) According to VSEPR theory, if there are two electron domains on a central atom, they will be arranged such that the angles between the domains are

Diff: 1 Page Ref: Sec 9.2

54) The electron-domain geometry and the molecular geometry of a molecule of the general

formula AB are n

A) never the same

B) always the same

C) sometimes the same

Trang 14

55) The electron-domain geometry and the molecular geometry of a molecule of the general

formula AB will always be the same if n

A) there are no lone pairs on the central atom

B) there is more than one central atom

C) n is greater than four

D) n is less than four

E) the octet rule is obeyed

Answer: A

Diff: 1 Page Ref: Sec 9.2

56) For molecules of the general formula AB , n can be greater than four n

A) for any element A

B) only when A is an element from the third period or below the third period

C) only when A is boron or beryllium

D) only when A is carbon

E) only when A is Xe

Answer: B

Diff: 1 Page Ref: Sec 9.2

Consider the following species when answering the following questions:

(i) PCl 3 (ii) CCl 4 (iii) TeCl 4 (iv) XeF4 (v) SF 6

57) For which of the molecules is the molecular geometry (shape) the same as the VSEPR electron domain arrangement (electron domain geometry)?

A) (i) and (ii)

B) (i) and (iii)

C) (ii) and (v)

D) (iv) and (v)

E) (v) only

Answer: C

Diff: 2 Page Ref: Sec 9.2

58) Of the molecules below, only is polar

Diff: 2 Page Ref: Sec 9.3

59) Of the molecules below, only is nonpolar

Trang 15

60) Of the molecules below, only is polar

Diff: 1 Page Ref: Sec 9.3

61) Of the molecules below, only is nonpolar

Diff: 1 Page Ref: Sec 9.3

62) Three monosulfur fluorides are observed: SF , 2 SF , and 4 SF Of these, is/are polar 6A) SF only 2

Diff: 2 Page Ref: Sec 9.3

63) The molecular geometry of the BeCl molecule is , and this molecule is 2A) linear, nonpolar

Diff: 1 Page Ref: Sec 9.3

64) The molecular geometry of the PF molecule is , and this molecule is 3A) trigonal planar, polar

B) trigonal planar, nonpolar

C) trigonal pyramidal, polar

D) trigonal pyramidal, nonpolar

E) tetrahedral, unipolar

Answer: C

Diff: 2 Page Ref: Sec 9.3

Trang 16

65) Of the following molecules, only is polar

Diff: 1 Page Ref: Sec 9.3

66) Of the following molecules, only is polar

Diff: 1 Page Ref: Sec 9.3

67) For molecules with only one central atom, how many lone pairs on the central atom guarantees molecular polarity?

Diff: 1 Page Ref: Sec 9.3

68) The molecular geometry of the CHF3 molecule is , and the molecule is A) trigonal pyramidal, polar

Diff: 1 Page Ref: Sec 9.3

69) The molecular geometry of the BCl3 molecule is , and this molecule is A) trigonal pyramidal, polar

B) trigonal pyramidal, nonpolar

C) trigonal planar, polar

D) trigonal planar, nonpolar

E) trigonal bipyramidal, polar

Answer: D

Diff: 1 Page Ref: Sec 9.3

Trang 17

70) According to valence bond theory, which orbitals overlap in the formation of the bond in HBr? A) 1s on H and 4p on Br

Diff: 1 Page Ref: Sec 9.4

71) The combination of two atomic orbitals results in the formation of molecular orbitals A) 1

Diff: 1 Page Ref: Sec 9.5

72) The electron-domain geometry of a carbon-centered compound is tetrahedral The hybridization of the central carbon atom is

Diff: 2 Page Ref: Sec 9.5

73) Of the following, only has sp2 hybridization of the central atom

Diff: 1 Page Ref: Sec 9.5

74) Of the following, the central atom is sp d3 2 hybridized only in

Trang 18

75) The sp d atomic hybrid orbital set accommodates electron domains

Diff: 1 Page Ref: Sec 9.5

76) The sp2 atomic hybrid orbital set accommodates electron domains

Diff: 1 Page Ref: Sec 9.5

77) The hybridizations of nitrogen in NF3 and NH are and , respectively 3A) sp2, sp2

Diff: 1 Page Ref: Sec 9.5

78) The hybridizations of iodine in IF3 and IF5 are and , respectively A) sp3, sp d3

Diff: 1 Page Ref: Sec 9.5

79) The hybridizations of bromine in BrF and of arsenic in 5 AsF5 are and , respectively

Trang 19

80) The hybrid orbitals used for bonding by the sulfur atom in the SF molecule are orbitals 4A) sp

Diff: 1 Page Ref: Sec 9.5

81) The hybrid orbitals used for bonding by Xe in the unstable XeF2 molecule are orbitals A) sp2

Diff: 2 Page Ref: Sec 9.5

82) The hybridization of the oxygen atom labeled y in the structure below is

The C–O–H bond angle is

Diff: 2 Page Ref: Sec 9.5

83) The electron-domain geometry of the AsF5 molecule is trigonal bipyramidal The hybrid orbitals used

by the As atom for bonding are orbitals

Trang 20

84) hybrid orbitals are used for bonding by Xe in the XeF4 molecule

Diff: 1 Page Ref: Sec 9.5

Consider the following species when answering the following questions:

(i) PCl 3 (ii) CCl 4 (iii) TeCl 4 (iv) XeF4 (v) SF 6

85) In which of the molecules does the central atom utilize d orbitals to form hybrid orbitals? A) (i) and (ii)

Diff: 2 Page Ref: Sec 9.5

86) Which of the molecules has a see-saw shape?

Diff: 3 Page Ref: Sec 9.3, 9.5

87) In which of the molecules is the central atom sp d3 2 hybridized?

A) (i) and (ii)

Diff: 1 Page Ref: Sec 9.5

88) There are unhybridized p atomic orbitals in an sp-hybridized carbon atom A) 0

Trang 21

89) When three atomic orbitals are mixed to form hybrid orbitals, how many hybrid orbitals are formed? A) one

Diff: 1 Page Ref: Sec 9.5

90) The blending of one s atomic orbital and two p atomic orbitals produces

A) three sp hybrid orbitals

B) two sp2 hybrid orbitals

C) three sp3 hybrid orbitals

D) two sp3 hybrid orbitals

E) three sp2 hybrid orbitals

Answer: E

Diff: 1 Page Ref: Sec 9.5

91) A triatomic molecule cannot be linear if the hybridization of the central atoms is A) sp

Diff: 1 Page Ref: Sec 9.5

92) A typical double bond

A) is stronger and shorter than a single bond

B) consists of one σ bond and one π bond

C) imparts rigidity to a molecule

D) consists of two shared electron pairs

E) All of the above answers are correct

Answer: E

Diff: 1 Page Ref: Sec 9.6

93) A typical triple bond

A) consists of one σ bond and two π bonds

B) consists of three shared electrons

C) consists of two σ bonds and one π bond

D) consists of six shared electron pairs

E) is longer than a single bond

Answer: A

Diff: 1 Page Ref: Sec 9.6

Trang 22

94) In a polyatomic molecule, "localized" bonding electrons are associated with

A) one particular atom

B) two particular atoms

C) all of the atoms in the molecule

D) all of the π bonds in the molecule

E) two or more σ bonds in the molecule

Answer: B

Diff: 1 Page Ref: Sec 9.6

95) Which of the following molecules or ions will exhibit delocalized bonding?

Diff: 1 Page Ref: Sec 9.6

96) Which of the following molecules or ions will exhibit delocalized bonding?

Diff: 1 Page Ref: Sec 9.6

97) In order to exhibit delocalized π bonding, a molecule must have

A) at least two π bonds

B) at least two resonance structures

C) at least three σ bonds

D) at least four atoms

E) trigonal planar electron domain geometry

Answer: B

Diff: 1 Page Ref: Sec 9.6

98) In a typical multiple bond, the σ bond results from overlap of orbitals and the π bond(s) result from overlap of orbitals

A) hybrid, atomic

B) hybrid, hybrid

C) atomic, hybrid

D) hybrid, hybrid or atomic

E) hybrid or atomic, hybrid or atomic

Answer: A

Ngày đăng: 01/03/2019, 08:49

TỪ KHÓA LIÊN QUAN

w