Đề ôn ĐH 6 có đáp án

Ố Thời gian: 120 phút (không kể phát đề)            !"#"$%& 3 2 1 2 3 1 3 y x x x= − + − a) '"( ) #%( * +,( - ,. / 0 - +" 1 C2 ) ("$%&+345 b) 6 * 5"74 1 5+6 * 2""6 - 5"8"9 ) 5::; * "( 1 5<; ) C,( - 2( * 2=; - 5:+"9 ) 5: 0, 2, 3y x x= = = > ! ?5"2@2+?2"8"5%(  3 2 0 x I dx 1 x = + ò > ( ) 5 1 ln e I x x x dx= + ∫ !  6 - 052 ) (%0 * 8"= * 2z<4 * +39 - 5: ( ) 1 2 (4 5 ) 1 3i z i i− + − = + AB! C2%5""C22"=;5:+3D5"5$#+"D2"E=F2G$8"H57$5"345:2"#2"=;5:+3D5"I8"H5"#J28"H5>  ".#2"=;5:+3D5""K5 L (>  3#5:M"05::(5,N"O+C(PQRS2"#"( A(1;2;0)  B(3;4; 2)- ,$J+8"T5: U x y z 4 0- + - =  VW+8"=;5:+3D5"J+8"T5:XY("(Z[,$,05::I2,NJ+8"T5: > CG$+"\(]5 IA IB 0+ = uur uur r  ]R,W+8"=;5:+3D5"J+2H+,$+W8Q^2,N J+8"T5: _ (  Tìm x (0; )Î +¥ thỏa mãn : ( ) x 2 0 2sin t 1 dt 0- = ò > ".#2"=;5:+3D5"5:2(# L <>  3#5:M"05::(5,N"O+C(PQRS2"#"( A(1;2;0)  B(3;4; 2)- ,$J+8"T5: U x y z 4 0- + - =  VW+8"=;5:+3D5"J+8"T5:XY("(Z[,$,05::I2,NJ+8"T5: > CG$+"\(]5 3IA 2IB 0- = uur uur r ]R,W+8"=;5:+3D5"J+2H+,$+W8Q^2,N J+8"T5: _ <  `a+%&8"b2 ( ) z x yi x,y R= + Î DQR%(#2"# ( ) 2 x yi 8 6i+ = + Hết HƯỚNG DẨN ĐỀ 6 I. PHẦN CHUNG;(7 điểm) c(d`U ¡ d 2 ' 4 3y x x= − + ef 2 1 ' 0 4 3 0 3 x y x x x  = = ⇔ − + = ⇔  =  d; * "( 1 5 lim x y →+∞ = +∞ ,( -  lim x y →−∞ = −∞ • [( ) 5:<4 * 5+"45 - $%&0 - 5:<4 * 5+3452( * 2M"#( ) 5: ( ) ;1−∞ ,( -  ( ) 3;+∞ - $%&5:" 1 2"<4 * 5+345 ( ) 1;3 - 4 ) 2= 1 2( 1  1 1; 3    ÷   - 4 ) 2= 1 2+4 )  ( ) 3; 1− d0 - +" 1  0 - +" 1 "$%&29 * ++3 1 2"#( - 5"+( 1 !4 ) 8"5<4 1 + g0 1 +%0 * 4 ) +"0 1 20 - +" 1 x   > ! L y 1− 1 3 1 3 − 1− 1 3 U<74 1 5+6 * 2""6 - 5"8"9 ) 5::; * "( 1 5<; ) C,( - 2( * 2=; - 5:+"9 ) 5: 0, 2, 3y x x= = = G( -  3 3 2 2 1 2 3 1 3 S x x x dx= − + − ∫ 3 3 2 2 1 2 3 1 3 x x x dx   = − − + −  ÷   ∫ 3 4 3 2 1 2 3 12 3 2 x x x x   = − − + −  ÷   3 4 =  >(?5"2@2+?2"8"5%( 3 2 0 x I dx 1 x = + ò J+ 2 u 1 x du 2xdx= + Þ = h2i5U u 4 x 3 u 1 x 0 = = Þ = =  j#IU 4 1 4 1 I du u 1 1 2 u = = = ò ViR I 1= >< ( ) 5 5 6 1 1 1 ln ln e e e I x x x dx x xdx x dx= + = + ∫ ∫ ∫ 6 * 5" 5 1 1 ln e I x xdx= ∫ 9 1 + 5 6 1 ln 6 du dx u x x dv x dx x v  =   =   ⇒   =    =   6 5 6 6 6 1 1 1 1 1 ln ln 5 1 6 6 6 36 36 e e e e x x x x x x e I dx + = − = − = ∫ d6 * 5" 7 7 6 2 1 1 1 7 7 e e x e I x dx − = = = ∫ V 1 R 6 7 5 1 1 36 7 e e I + − = + !(2# * ( ) ( ) ( ) ( ) ( ) ( ) ( ) + = + = + = + + + + + + + = = = = = + + + 2 2 2 1 2 (4 5 ) 1 3 1 2 1 3 (4 5 ) 1 2 3 8 3 8 1 2 3 8 3 6 8 16 19 2 19 2 1 2 1 2 1 2 1 2 5 5 5 i z i i i z i i i z i i i i i i i i z z z i i i i j## * 2 2 19 2 19 2 73 365 5 5 5 5 5 5 z i = + = + = = ữ ữ AB! Hc sinh hc chng trỡnh no thỡ ch c lm phn dnh riờng cho chng trỡnh ú (phn 1 hoc phn 2) ".#2"=;5:+3D5""K5 L> 1. Vit phng trỡnh mt phng (Q) i qua hai im A, B v vuụng gúc vi mt phng (P). Mt phng (P) cú vect phỏp tuyn l : P n (1; 1;1)= - uur , AB (2;2; 2)= - uuur Vỡ (Q) qua A,B v vuụng gúc vi (P) nờn (Q) cú mt vect phỏp tuyn l: ( ) Q P 1 1 1 1 1 1 n n ;AB ; ; 0;4;4 2 2 2 2 2 2 ổ ử - - ữ ỗ ộ ự ữ ỗ = = = ữ ỗ ờ ỳ ữ ở ỷ ỗ - - ữ ỗ ố ứ uuur uur uur Do ú phng trỡnh mt phng (Q) l 4(y 2) 4(z 0) 0 y z 2 0 - + - = + - = Vy phng trỡnh (Q): y z 2 0+ - = 2. Gi I l trung im ca AB. Hóy vit phng trỡnh mt cu tõm I v tip xỳc vi mt phng (P). Do I tha món IA IB 0+ = uur uur r nờn I l trung im ca AB Ta trung im I ca AB l: I(2;3; 1)- Gi (S) l mt cu cú tõm I v tip xỳc vi (P) Bỏn kớnh ca mt cu (S) l: R d(I,(P)) 2 3 1 4 6 2 3 3 3 = - - - - = = = Vy phng trỡnh mt cu (S) l 2 2 2 (x 2) (y 3) (z 1) 12- + - + + = _ ( Tỡm x (0; )ẻ +Ơ tha món : ( ) x 2 0 2sin t 1 dt 0- = ũ (1) Ta cú: ( ) x x 2 0 0 x 1 1 2sin t 1 dt cos2tdt sin2t sin2x 0 2 2 - = - = - = - ũ ũ Do ú: 1 (1) sin2x=0 sin2x=0 2 2x k k x 2 - = p p = Do x (0; )ẻ +Ơ nờn ta chn k x 2 p = vi k Z + ẻ 2 ".#2"=;5:+3D5"5:2(# L<># 1. Vit phng trỡnh mt phng (Q) i qua hai im A, B v vuụng gúc vi mt phng (P). Mt phng (P) cú vect phỏp tuyn l : P n (1; 1;1)= - uur , AB (2;2; 2)= - uuur Vỡ (Q) qua A,B v vuụng gúc vi (P) nờn (Q) cú mt vect phỏp tuyn l: ( ) Q P 1 1 1 1 1 1 n n ;AB ; ; 0;4;4 2 2 2 2 2 2 ổ ử - - ữ ỗ ộ ự ữ ỗ = = = ữ ỗ ờ ỳ ữ ở ỷ ỗ - - ữ ỗ ố ứ uuur uur uur Do ú phng trỡnh mt phng (Q) l 4(y 2) 4(z 0) 0 y z 2 0 - + - = + - = Vy phng trỡnh (Q): y z 2 0+ - = 2. Gi I l im tha món 3IA 2IB 0- = uur uur r . Hóy vit phng trỡnh mt cu tõm I v tip xỳc vi mt phng. Gi I(x;y) l im tha món 3IA 2IB= uur uur , ta cú: ( ) ( ) ( ) ( ) ( ) ( ) 3 1 x 2 3 x x 3 3IA 2IB 3 2 y 2 4 y y 2 z 4 3 0 z 2 2 z ỡ ỡ ù ù - = - = - ù ù ù ù ù ù ù ù = - = - = - ớ ớ ù ù ù ù ù ù = - = - - ù ù ù ợ ù ợ uur uur . Suy ra: I( 3; 2;4)- - Gi (S) l mt cu cú tõm I v tip xỳc vi (P) Bỏn kớnh ca mt cu (S) l: 3 2 4 4 1 3 R d(I,(P)) 3 3 3 - + + - - = = = = Vy phng trỡnh mt cu (S) l 2 2 2 1 (x 3) (y 2) (z 4) 3 + + + + - = _ < Xột s phc ( ) z x yi x,y R= + ẻ . Tỡm x, y sao cho ( ) 2 x yi 8 6i+ = + Ta cú: ( ) 2 2 2 4 2 2 2 2 2 2 x yi 8 6i x y 2xyi 8 6i x 3 9 x 8x 9 0 x 9 x 8 y 1 x y 8 x 3 3 3 xy 3 x 3 y y y x x x y 1 + = + - + = + ộ ỡ = ù ù ờ ỡ ù ớ ỡ ỡ ờ - - = = ù ù ù - = ỡ ù = ù ù - =ù ù ờ ù ù ù ù ợ ù ù ù ù ù ờ ớ ớ ớ ớ ờù ù ù ù ỡ= = - ù = = ù ù ù ù = ù ợ ù ờ ù ù ù ù ù ợ ợ ớ ù ờ ù ợ ù = - ờ ù ợ ở Vy giỏ tr x, y cn tỡm l x 3 y 1 ỡ = ù ù ớ ù = ù ợ hoc x 3 y 1 ỡ = - ù ù ớ ù = - ù ợ d .   ⇒   =    =   6 5 6 6 6 1 1 1 1 1 ln ln 5 1 6 6 6 36 36 e e e e x x x x x x e I dx + = − = − = ∫ d 6 * 5" 7 7 6 2 1 1 1 7 7 e e x e I. >< ( ) 5 5 6 1 1 1 ln ln e e e I x x x dx x xdx x dx= + = + ∫ ∫ ∫ 6 * 5" 5 1 1 ln e I x xdx= ∫ 9 1 + 5 6 1 ln 6 du dx u x x dv x dx