Tuần 14 giao an tieng anh hpt10 2016

Tuần 14 Tiết 28 Ngày / 12 / 2015 Lớp 10T LESSION PLAN THE SYSTEM OF EQUATION Aim of The Lesson: a Knowledge: Students use knowledge: the system of equation and solution system of equation b Skills: Know how to solution, and applications solution system of equation c Attitude: • Careful, accuracy in calculations and reasoning • Positive sense of learning, creative thinking • Understand and apply solution system of equation Subject Matter - Reference: Algebra - Analysis for High-school Textbook - Materials: Sheets of paper, Puzzles Procedure CONTENT Teacher and Students’ activities Exercise 1: Solve the system of equation Solution Reviews:  xy = x + y + 1(1)  2 y = : system of equation satisfactory x y = 10 y − 1(2)  y ≠ , (1) ⇔ x = y −1 y We substitute into (2), we obtain: 39 y + 34 y − y − y + = ⇔ ( y + 1)(3 y + 1)(13 y − y + 1) =  y = −1  −1  ⇔ Thus, the solution set is ( 8; −1) ; 10; ÷  y = −1    Exercise 2: Solve the system of equation (2 x + y )( x + y ) + x(2 x + 1) = − y   x (4 x + 1) = − y Gv: Cao Bảo Đằng Solution From (2) ⇔ = x + x + y We substitute into (1), we obtain: (2 x + y )( x + y ) + x(2 x + 1) = x + x + y ⇔ ( x + y − 1)(2 x + y ) =  y = 1− x ⇔  y = −2 x Substitute y = − x into equation (2), we obtian  + 17 x = x2 − x − = ⇔   − 17 x =  Substitute y = −2 x into equation (2), we obtian x − x + = ( no real roots) Thus, the solution set is  + 17 − 17   − 17 + 17  ; ;  ÷;  ÷ ÷ ÷    Exercise 3: Solve the system of equation  x + y = −1  3  x − 3x = y − y Gv: Cao Bảo Đằng Solution Hint: (1): y = −1 − x  −1  ; ÷, ( −2;1)  2 Thus, the solution set is ( 1; −2 ) ;  ... −2 x Substitute y = − x into equation (2), we obtian  + 17 x = x2 − x − = ⇔   − 17 x =  Substitute y = −2 x into equation (2), we obtian x − x + = ( no real roots) Thus, the solution set