De thi thu hoa truong THPT yen phong bac ninh lan 1 nam 2017

S GD T TNH BC NINH THPT YấN PHONG THI TH THPT QUC GIA LN NM 2017 Mụn: KHOA HC T NHIấN HểA HC Thi gian lm bi: 50 phỳt, khụng k thi gian phỏt ( thi cú 40 cõu / trang) Mó : 132 Cho bit nguyờn t ca cỏc nguyờn t : H =1; C = 12; N = 14; O = 16; Na = 23; Mg = 24; Al = 27; S =32; Cl = 35,5; K = 39; Ca = 40; Cr = 52; Fe = 56; Cu = 64; Zn = 65; Ag = 108; Ba=137 Cõu 1: Po i e ca o i v t i u nao sau y c ch a nguyờn t nit A Cao su buna B T ni on-6,6 C T visco D Nha po i (viny c orua) HCl NaOH Cõu 2: Cho chu i ph n ng sau: X Y X Ch t n o sau y ph h p: A H2N-CH2-COOH B C6H5NH2 C Ala-Gly D HCOONH4 Cõu 3: S ng ph n este ch h ng v i c ng th c ph n t C3H6O2 : A B C D Cõu 4: Ch t c ph n ng v i dung d ch r2 : A Phenyl clorua B Alanin C Metyl amin D Triolein Cõu 5: Tr ng h p n o sau y t o h p ch t e( ) A Nh ng s t v o dung d ch 2SO4 oóng B t d y s t b nh ng kh C C Nh ng s t v o dung d ch gNO3 d D Cho b t e v o dung d ch NO3 d Cõu 6: Nh ng t ỏ s t (d) v o dung d ch ch a t cỏc ch t sau: eC 3, AlCl3, CuSO4, Pb(NO3)2, H2SO4 c n ng Sau ph n ng y ỏ s t c bao nhiờu tr ng h p t o ui s t ( ) A B C D Cõu 7: óy ki o i tan ho n to n 2O iu kiờn th ng : A Fe, Na, K B Ca, Ba, K C Ca, Mg, Na D Al, Ba, K Cõu 8: y in tờn g i ca ch t n o sau y A C6H5NH2 B CH3NH2 C H2N-CH2-COOH D CH3-CH(NH2)-COOH Cõu 9: Cho ga a in no n ch c ch h X tỏc d ng v i ng d dung dich C Sau ph n ng y ho n to n thu c ga ui C ng th c ph n t ca X : A C3H9N B C3H7N C CH5N D C2H7N Cõu 10: Ph n ng n o sau y ph n ng nhi t nh Al2(SO4)3 + 3Cu A 3Al + 3CuSO4 to B 8Al + 3Fe3O4 4Al2O3 + 9Fe pnc 4Al + 3O2 Al2(SO4)3 + 3H2 C 2Al2O3 D 2Al + 3H2SO4 Cõu 11: Gluxit nao sau õy c goi la ng mớa? A Saccaroz B Tinh b C ucoz D Fructoz Cõu 12: Cỏc kim oa Fe, Cr, Cu c ng tan dung dich n o sau y A Dung dich HCl B Dung dich HNO3 c ngu C Dung dich HNO3 loóng D Dung dich H2SO4 c ngu Cõu 13: Kim loai X tỏc dung v i H2SO4 loóng cho kh H2 M khỏc oxit ca X bi kh H2 kh thnh kim loai nhiờt ụ cao X la kim loai nao ? A Fe B Al C Mg D Cu Cõu 14: Cho ga h n h p g e v Cu tỏc d ng v i dung d ch 2SO4 oóng d Sau ph n ng thu c ớt lớt khớ hidro ( kc) dung dic h X v ga ki oa kh ng tan iỏ tri c a A 6,4 gam B 3,4 gam C 4,4 gam D 5,6 gam http://bloghoahoc.com Chuyờn trang thi th Húa Trang 1/5 Mó thi 132 Cu(OH)2 /OH t Cõu 15: Cho s ụ sau: X dung dịch mu xanh lam kết tủa đỏ gạch X la dung dich n o sau y: A Protein B Triolein C ucoz D Vinyl fomat Cõu 16: Cho ga h n h p b t Zn v Mg (t : ) tan ht dung d ch h n h p g NaNO3 v NaHSO4 thu c dung d ch A ch ch a m ga h n h p cỏc ui trung hũa v ớt (kc) h n h p khớ g N2O v H2 n h p khớ B c t so v i e bng iỏ tr gn nh t ca m l : A 240 B 300 C 312 D 308 Cõu 17: n h p X g m valin (c cụng th c C4H8NH2COOH)) v ipeptit y y a anin Cho ga X vo 100ml dung dich H2SO4 0,5M (loóng), thu c dung dich Y Cho to n b Y ph n ng va v i dung d ch NaO 1M v KO M un n ng thu c dung d ch ch a ga ui Phn tr ng ca Va in X l : A 65,179% B 54,588% C 45,412% D 34,821% Cõu 18: Cho cỏc nh n nh sau: (1) T t c cỏc ion ki o i ch b kh ( ) p ch t cacbohirat v h p ch t a ino a it u ch a th nh phn nguyờn t ging ( ) ung d ch ui ononatri ca a it g uta ic qu tớ chuyn sang u anh (4) Cho kim lo i Ag vo dung d ch FeCl2 th thu c kt ta AgCl (5) Tớnh ch t v t lớ chung ca kim lo i cỏc electron t gõy ( ) Ph n ng thy ph n este v protein i tr ng ki u ph n ng t chiu S nh n nh ng l A B C D Cõu 19: Ch n cp ch t kh ng y ph n ng? A dung d ch AgNO3 v dung d ch Fe(NO3)2 B dung d ch Fe(NO3)2 v dung d ch KHSO4 C dung d ch H2NCH2COONa v dung d ch KOH D dung d ch C6H5NH3Cl v dung d ch NaOH Cõu 20: Cho cỏc dung d ch eC 3, HCl, HNO3 loóng, AgNO3, ZnCl2 v dung d ch ch a (KNO3, H2SO4 oóng) S dung d ch tỏc d ng c v i ki o i Cu nhi t th ng A B C D Cõu 21: óy cỏc po i e t chỏy ho n to n u thu c khớ N2 A t o on t t t capron cao su buna-N B t apsan t en ng t ni on-6, en u oz C protein, nilon-6,6, poli(metyl metacrylat), PVC D amilopectin, cao su buna-S t o on t visco Cõu 22: ũa tan ho n to n h n h p H g Mg ( a o ) v e3O4 (a o ) dung d ch ch a KNO3 v o C c c n dung d ch sau ph n ng th thu c ng ui khan nng h n ng h n h p H g it kt th c ph n ng thu c o h n khớ Z ch a v NO t ca Z so v i bng 11 % ng s t c ui khan c giỏ tr gn nh t v i A 17% B 18% C 26% D 6% Cõu 23: Cho cỏc s ph n ng sau (theo ng t l mol): X1 + X2 + H2O X3 + NaCl C7H18O2N2 (X) + NaOH X1 + 2HCl X4 + HCl X4 X3 t nilon-6 + H2O Phỏt biu n o sau y ng A X2 lm qu tớm húa h ng B Cỏc ch t X, X4 u c tớnh ng tớnh C Phõn t ca X l n h n so v i X3 D Nhi t núng ch y ca X1 nh h n X4 Cõu 24: Tr n ga v i ga e3O4 r i nung n ng cho ph n ng y t th i gian nh c h n h p X g e O , FeO v Fe O Cho to n b X ph n ng v i dung d ch C d 3 thu c ớt (ktc) v dung d ch Y C c n Y c a ga ui khan Xỏc nh giỏ tr ca a l http://bloghoahoc.com Chuyờn trang thi th Húa Trang 2/5 Mó thi 132 A 27,965 B 16,605 C 18,325 D 28,326 Cõu 25: Cho o h nh pXg este n ch c tỏc d ng va v i dung d ch NaO M un n ng thu c h p ch t hu c no ch h Y c ph n ng b c v ga h n h p ui hu c t chỏy ho n to n Y r i cho s n ph h p th ht v o b nh ch a dung d ch n c v i d th y ng b nh t ng ga Khi ng ca X l A 30,8 gam B 33.6 gam C 32,2 gam D 35,0 gam Cõu 26: n h p E g chu i peptit X, Y, Z u ch h ( c t o nờn t y v Lys) Chia h n h p hai phn kh ng bng Phn 1: c ng ga c e thy ph n ho n to n dung d ch NaO M th d ng ht sau ph n ng thu c h n h p F ch a a ga ui y v b ga ui Lys Mt khỏc t chỏy ho n to n phn cũn i th thu c t th tớch gia CO2 v h i n c thu c : T a : b gn nht v i giỏ tr : A 1,57 B 1,67 C 1,40 D 2,71 Cõu 27: Cho h n h p X g exOy, Fe, MgO, Mg Cho m ga h n h p X trờn tỏc d ng v i dung d ch HNO3 d thu c ớt h n h p khớ N2O v NO (dktc) c t so v i v dung d ch Y C c n dung d ch Y thu c ga ui khan Cho ga h n h p X tỏc d ng v i dung d ch H2SO4 c n ng d thu c ớt khớ SO2 (ktc s n ph kh nh t) v dung d ch Z C c n dung d ch Z thu c ga ui khan iỏ tr gn nht ca m l A 22,0 B 28,5 C 27,5 D 29,0 Cõu 28: Ph n bi t cỏc ch t CaC 2, HCl, Ca(OH)2 c th d ng dung d ch A NaOH B NaHCO3 C Na2CO3 D NaNO3 Cõu 29: Nh n ột n o d i y ng A Tripeptit hũa tan Cu(OH)2 (ph n ng u biure) t o dung d ch anh a B Trong ph n t protein u n c nguyờn t nit C Tinh b t v en u oz ng ph n ca D Este nhng ch t hu c d tan n c Cõu 30: Trong ki o i sau: e Na Cr Ki o i n tip c v i a it v ki o i khỏ d kộo s i d dỏt ng ki o i theo th t A Na v Fe B Cr v Al C Na v Al D Cr v Fe Cõu 31: X phũng h a h n h p g C 3COOCH3 v CH3COOC2H5 thu c s n ph g A ui v anco B ui v anco C ui v anco D ui v anco ki o i ki th Cõu 33: Nguyờn t h a h c n o sau y thu c nh A Natri B Bari C Nhụm D Kali Cõu 34: Nh n ột n o sau y sai A ucoz c d ng thuc t ng c cho ng i gi tr e ng i B c d ng ch bin th nh gi y C Xen u oz c ph n ng u v i iot D Tinh b t t s ngu n cung c p n ng ng cho c th Cõu 35: X, Y, Z, T t cỏc ch t sau: g ucoz ani in (C6H5NH2) fructoz v pheno (C6H5OH) Tin h nh cỏc thớ nghi nh n bit ch ng v ta c kt qu nh sau: Thuc th X T Z Y N c r2 Kt ta Nh t u Kt ta (-) (+): ph n ng o (-): kh ng ph n ng dd AgNO3/NH3, t (-) Kt ta (-) Kt ta dd NaOH (-) (-) (+) (-) Cỏc ch t X, Y, Z, T n t A g ucoz ani in pheno fructoz B ani in fructoz pheno g ucoz C pheno fructoz ani in g ucoz D fructoz pheno g ucoz ani in Cõu 36: Cho 13,5 gam h n h p g a in no n ch c, m ch h tỏc d ng va v i 300 ml dung d ch HCl x M thu c dung d ch ch a 24,45 gam h n h p mui Giỏ tr ca x l A 0,5 B 1,4 C 2,0 D 1,0 http://bloghoahoc.com Chuyờn trang thi th Húa Trang 3/5 Mó thi 132 Cõu 37: X, Y hai h p ch t hu c n ch c ph n t ch ch a C O Khi t chỏy X, Y v i s o bng hoc ng bng u thu c v i t o t ng ng : v v i t o t ng ng : S cp ch t X, Y tha ón A B C D Cõu 38: Polime X dai bn v i nhi t v gi nhi t tt nờn d t v i ay qun ỏo X l A Poliacrilonitrin B Poli (vinylclorua) C Polibutaien D Polietilen Cõu 39: Cú h n h p, m i h n h p g m ch t r n cú s mol bng nhau: Na2O v Al2O3; Cu v Fe2(SO4)3; KHSO4 v KHCO3; BaCl2 v CuSO4; Fe(NO3)2 v AgNO3 S h n h p cú th tan hon ton n c (d) ch t o cỏc ch t tan tt n c l A B C D Cõu 40: Cho m gam b t s t vo dung d ch X ch a AgNO3 v Cu(NO3)2 n cỏc ph n ng kt thỳc thu c ch t r n Y v dung d ch Z Cho dung d ch Z tỏc d ng ht v i dung d ch NaO d thu c a gam kt ta T g m hai hidroxit kim lo i Nung T n ng kh ng i thu c b gam ch t r n Biu th c liờn h gia m, a, b cú th l A m = 8,225b 7a B m = 8,575b 7a C m = 8,4 3a D m = 9b 6,5a HT http://bloghoahoc.com Chuyờn trang thi th Húa Trang 4/5 Mó thi 132 PHN TCH HNG DN GII THI TH THPT YấN PHONG BC NINH LN Cõu 1: Chn B Cõu 2: Chn B HCl NaOH C H 5NH (X) C H 5NH 3Cl(Y) C H 5NH (X) Cõu 3: Chn D C ng ph n este ch h ng v i CTPT C3H6O2 l HCOOC2H5, CH3COOCH3 Cõu 4: Chn D Cõu 5: Chn A B Fe + 3AgNO (d) e(NO3)3 + 3Ag C Fe + Cl2 eC D Fe + 4HNO (d) e(NO3)3 + NO + 2H2O Cõu 6: Chn C C tr ng h p t o ui s t ( ) : FeCl3, CuSO4, Pb(NO3)2 v H2SO (c n ng) Cõu 7: Chn B Cõu 8: Chn C Cõu 9: Chn D m m amin BTKL n HCl n amin muối 0,059 mol M amin 45(C H N) 36,5 Cõu 10: Chn B Cõu 11: Chn A A Saccaroz B Tinh b C ucoz D ructoz ng ớa ng nho ng t ong Cõu 12: Chn C Lu ý : Cr e v Cõu 13: Chn A Cõu 14: Chn C b th ng h a b i NO3, H2SO4 c ngu i BT:e n Fe n H2 0,1 m Cu 10 56n Fe 4,4(g) Cõu 15: Chn C Cõu 16: Chn D 0,3mol 0,6 mol 0,3mol 0,6 mol 2 Zn , Mg NaNO , NaHSO Zn hỗn hợp kim loại , Mg , Na , NH ,SO dung dịch hỗn hợp BT:e n NH 0,15mol 0,05mol dung dịch A 2n Zn 2n Mg2 8n N 2O 2n H2 N 2O , H H 2O hỗn hợp B BT:N 0,0625mol n NaNO3 2n N 2O n NH 0,3625mol BT:H n NaHSO4 10n NH 10n N 2O 2n H2 2,225mol n H 2O n NaHSO4 4n NH 2n H 2 0,9375mol BTKL m A m kim loại 85n NaNO3 120n NaHSO4 m B 18n H2O 308,1375(g) Cõu 17: Chn B a mol b mol a mol b mol b mol 0,1mol 0,175mol 0,05mol Val ,GlyAla H 2SO dung dịch Y Val ,Gly , Ala , Na , K ,SO NaOH, KOH hỗn hợp X 0,05mol http://bloghoahoc.com Chuyờn trang thi th Húa 30,725(g) muối Trang 5/5 Mó thi 132 116n Val 74n Gly 88n Ala m muối 39n K 23n Na 96n SO42 116a 74b 88b 16,8 a 0,075 BTDT a b b 0,175 n n n n n 2n b 0,05 Val Gly Ala K Na SO %m Val 54,58 Cõu 18: Chn A (1) Sai, Fe2+, Cr2+ b o i h a b i cỏc ch t o i h a nh nh KMnO4, O2 ( ) Sai h p ch t a ino a it ch a C O v N cũn h p ch t cacbohidrat kh ng ch a N ( ) ng OOC-CH2-CH2-CH(NH2)-COONa ( ono natri g uta ate) qu tớ h a anh (4) Sai, cho g tỏc d ng v i dung d ch eC kh ng c ph n ng y ( ) ng cỏc tớnh ch t nh tớnh dn i n dn nhi t ỏnh ki u e ectron t g y ( ) ng ph n ng thy ph n este v protein i tr ng ki u ph n ng t chiu V y c nh n nh ng ( ) ( ) ( ) Cõu 19: Chn C A AgNO3 + Fe(NO3)2 e(NO3)3 + Ag B 3Fe2+ + NO3- + 4H+ e3+ + NO + 2H2O D C6H5NH3Cl + NaO C6H5NH2 + NaCl + H2O Cõu 20: Chn D Cú ch t tỏc d ng c v i ki o i Cu iu ki n th ng l FeCl3, HNO3 loóng, AgNO3 v dung d ch ch a (KNO3, H2SO4 loóng) Cu + 2FeCl3 CuC + 2FeCl2 Cu + HNO3(loóng) Cu(NO3)2 + NO + H2O Cu + 2AgNO3 Cu(NO3)2 + 2Ag 3Cu + 2NO3 + 8H+ Cu2+ + 2NO + 4H2O Cõu 21: Chn A Cỏc po i e t chỏy ho n to n u thu c khớ N2 ch ng t phõn t polime cú ch a N V y cỏc polime cú thnh phn ch a N l : t o on t t t capron cao su buna-N Cõu 22: Chn A BT:N n NH4 n KNO3 n NO (x 0,06) mol m muối m H 39n K 18n NH 35,5n Cl 16n O(trong H) 39x 18(x 0,06) 35,5.0,725 64a m muối m H 26,23 57x 64a 1,5725 x 0,0725mol 10n NH 2n O(trong H) 4n NO 2n H n HCl 10(x 0,06) 8a 0,28 0,725 a 0,04 mol 0,04.3.56 m H 24.5a 232a 14,08(g) m muối khan 40,31(g) % m Fe 100 16,67 40,31 Cõu 23: Chn B - Cỏc ph n ng x y ra: to nH N[CH ]5 COOH (X ) ( HN [CH ]5 CO ) n nH 2O nilon H N[CH ]5 COOH (X ) HCl ClH N[CH ]5 COOH (X ) H N[CH ]5 COONa (X1 ) 2HCl ClH N[CH ]5 COOH (X ) NaCl H N [CH ]5 COO NH 3CH (X) NaOH H N[CH ]5 COONa (X1 ) CH NH (X ) H 2O A Sai, X2 lm qu tớm húa xanh B ỳng X v X4 u c tớnh ng tớnh C Sai, Phõn t ca X l 162 phõn t ca X3 l 167,5 D Sai, Nhi t núng ch y ca X1 l n h n X4 Cõu 24: Chn A http://bloghoahoc.com Chuyờn trang thi th Húa Trang 6/5 Mó thi 132 0,09 mol 0,04 mol - Quỏ trỡnh: 0,105 mol to Al , Fe3O hỗn hợp X HCl dư AlCl , FeCl , FeCl H 2O H dung dịch sau pư BT: H + Ta cú: n O (Fe3O4 ) n H 2O 0,16 mol n HCl 2(n H2 n H2O ) 0,53 mol - Hng t 1: BTKL a m Y 36,5HCl 2n H 18n H 2O m X 36,5HCl 2n H 18n H 2O 27,965 (g) - Hng t 2: + Ta cú: a m KL 35,5n Cl 27n Al 56n Fe 35,5n HCl 27,965 (g) Cõu 25: Chn C - Nh n th y: nX = 0,3 < nNaOH = 0,4 X c ch a este ca pheno (A) v este cũn i (B) (A) : RCOOC H R ' n A n B 0,3 n A 0,1 n H 2O n A 0,1 V i (B) : R1COOCH CHR 2n A n B 0, n B 0, n Y n B 0, - Khi t chỏy ch t Y no n ch c ch h (R2CH2C O: o ) u n thu c n CO2 n H 2O 44n CO2 18n H 2O 24,8 n CO2 0, mol m C Y BTKL mX m ui n CO : Y l CH 3CHO 0, + mY + m H 2O mNaOH = 32, (g) Cõu 26: Chn A + Cỏc t ớch t o t ng ng v i cỏc - amino axit: - Hng t 1: S dng CTTQ ca peptit + i s c ớch ca y v Lys y ta c CTTQ ca E l: O2 ,t C2x 6y H3x 12y 2Ox y1N x 2y (2x 6y)CO2 (1,5x 6y 1)H 2O 3x 12y n CO2 n H2O 2x 6y x 2 + Ta cú: n E 0, 0658 mol 14,88 y 0, 7353 n NaOH n E (x y) (x y) 0,18 57x 128y n GlyNa xn E 0,1316 mol a BT: Gly Lys 1,57 n LysNa yn E 0, 0484 mol b - Hng t 2: Quy i v hn hp cỏc - amino axit v H2O H + Ta cú : Glym Lysn (E) H2O mGly nLys Gly(C2 H5O N):x mol BT: C n CO2 2x 6y O2 ,t E Lys (C6 H14O N ):y mol n CO2 n H 2O 0,5x y z (1) BT: H n 2,5x 7y z H O : z mol H 2O http://bloghoahoc.com Chuyờn trang thi th Húa Trang 7/5 Mó thi 132 BTKL 75n Gly 146n Lys mE 18n H2O 75x 146y 14,88 18z v (2) BT: Na x y 0,18 n n n GlyNa LysNa NaOH a 1,57 b - Hng t 2.1: Ta cú th quy i h n h p E v cỏc axyl v H2O nh sau: C2 H3ON, C6 H12ON v + T (1) ( ) ta tớnh c: x 0,1316 mol ; y 0,0484 mol; z 0,1141 mol V y H2O sau gi i t ng t nh trờn ta cng c th t - Hng t 3: Tỏch cht + Ta c kt qu tách C H 5O2 N(Gly) C H 3ON H 2O v cú: tách C H12 O2 N (Lys) C H 3ON (CH ) NH H 2O C H3ON :x mol BT:C n CO2 2x 4z O2 ,t E H O :y mol m n H2O n CO2 0,5x 0,5z y (1) BT:H n 1,5x 4,5z y (CH ) NH :z mol H2 O BTKL + Ta cú : x n NaOH 0,18 mol 71n (CH2 )4 NH 18n H2O mE 57n C2H3ON 71x 18y 4,62(2) y 0, 0658 mol n GlyNa x z 0,1316 mol a 1,57 + T (1) ( ) ta tớnh c: b z 0, 0484 mol n LysNa z 0, 0484 mol Cõu 27: Chn D - Hng t 1: Fe3 , Mg , NH , NO3 NO , N 2O (1) HNO -T t t quỏ trỡnh: Fe, Mg, O m gam X 0,26 mol 0,04 mol 129,4(g) dd Y H 2SO4 Fe3 , Mg ,SO 24 SO (2) 0,7 mol 104(g) dd Z BT: e cho (1) v (2) n NH4 NO3 2n SO2 3n NO 8n N2O 0, 0375 mol m KL m NH m NO3 129, (1) BTKL BTDT cho (1) v (2) 2n SO24 n NO3 n NH4 (2) m KL m SO 24 104 (1) (2) 62(2n SO24 n NH4 ) 96n SO42 24,725 n SO42 0,8 mol + Xột quỏ trỡnh BT: e BTDT 2n SO24 2n SO2 2n O n O 0,1 mol m m KL m O 28,8 gam m m m 104 0,8.96 27, gam KL Y SO - Hng t 2: 2n SO2 3n NO 8n N2O BT: e cho (1) v (2) n NH4 NO3 0, 0375 mol + i T h n h p ui ch a e(NO3)2 v Mg(NO3)2 suy ra: mT mY m NH4 NO3 126, 4gam (2): + p d ng ph ng phỏp t ng gi ng + b o to n i n tớch cho h n h p T v Z ta cú: mT m Z 126, 104 2n NO n SO 0,8 mol 2.M NO MSO 2.62 96 BT:S BT: H + Xột quỏ trỡnh (2): n H2O n H2SO4 nSO2 nSO 1,5 mol mX mH2SO4 mZ mSO2 mH2O m 28,8gam BTKL Cõu 28: Chn B http://bloghoahoc.com Chuyờn trang thi th Húa Trang 8/5 Mó thi 132 Thuc th A NaOH B NaHCO3 C Na2CO3 D NaNO3 CaCl2 HCl Kh ng hi n t ng Cú khớ CO2 thoỏt Cú khớ CO2 thoỏt Kh ng hi n t ng Kh ng hi n t ng C kt ta tr ng Ca(OH)2 C kt ta tr ng C kt ta tr ng Cõu 29: Chn B A Sai, Tripeptit hũa tan Cu(OH)2 (ph n ng u biure) t o dung d ch mu tớm B ỳng, Trong ph n t protein u n c nguyờn t nit C Sai, Tinh b t v en u oz kh ng ph i ng ph n ca D Sai, Este nhng ch t hu c ớt tan n c v ph n t kh ng c iờn kt hiro Cõu 30: Chn C Cõu 31: Chn D - Ph ng tr nh ph n ng: CH3COOCH NaOH CH 3COONa CH 3OH CH3COOC 2H5 NaOH CH3COONa C2 H5OH Cõu 32: Chn B - Cỏc ki o i ki th thu c nh Cõu 34: Chn C - Xen u oz kh ng c ph n ng v i Cõu 35: Chn B g cỏc nguyờn t: e Mg Ca Sr ch tinh b t Thuc th X: C6H5NH2 N c r2 dd AgNO3/NH3, to dd NaOH Cõu 36: Chn D Kt ta tr ng Kh ng ph n ng Kh ng ph n ng ui v a Ra i c ph n ng n y t o dung d ch c T: C6H12O6 (g ucoz ) Nh t u Kt ta g Kh ng ph n ng anco Z: C6H5OH Kt ta tr ng Kh ng ph n ng C ph n ng u anh tớ Y: C6H12O6 (fructoz ) Kh ng ph n ng Kt ta g Kh ng ph n ng RNH 3Cl - Ph ng tr nh: RNH HCl m m RNH BTKL n HCl RNH 3Cl 0,3mol C M(HCl) M 36,5 Cõu 37: Chn B - Khi t chỏy X, Y cú cựng s o ng MX = MY n CO (X) : n CO (Y) : n (X) n C(X) X : C H 4O 2 - Ta cú: v n C(Y) n H(Y) Y : C H 8O n H O(X) : n H O(Y) 1: +C ng ph n ca X C2H4O2 l: CH3COOH v HCOOCH3 +C S ng ph n ca Y C3H8O l: CH3CH2CH2OH; CH3CH(OH)CH3 v CH3OC2H5 V y s cp (X Y) tha : = Cõu 38: Chn A Cõu 39: Chn D H n h p Na2O v Al2O3: 2NaOH 2NaAlO2 + H2O Na2O + H2O 2NaOH + Al2O3 mol mol mol mol - Dung d ch sau ph n ng ch a NaAlO2 l ch t tan tt n c http://bloghoahoc.com Chuyờn trang thi th Húa Trang 9/5 Mó thi 132 H n h p Cu v Fe2(SO4)3: 2Cu + Fe2(SO4)3 2CuSO4 + FeSO4 mol 0,5 mol - Dung d ch sau ph n ng ch a CuSO4; FeSO4 v Fe2(SO4)3 d l cỏc ch t tan tt n c H n h p KHSO4 v KHCO3: KHSO4 + KHCO3 K2SO4 + CO2 + H2O mol mol - Sau ph n ng thu c K2SO4 tan tt n c nhng khớ CO2 ớt tan H2O, v y h n h p trờn kh ng ho n to n tan n c BaCl2 + CuSO4 BaSO4 + CuCl2 mol mol - Sau ph n ng thu c BaSO4 kt ta kh ng tan n c H n h p BaCl2 v CuSO4: H n h p Fe(NO3)2 v AgNO3: Fe(NO3)2 + AgNO3 Fe(NO3)3 + Ag mol mol - Sau ph n ng thu c Ag kt ta kh ng tan n c V y cú h n h p cú th tan tt n c d Cõu 40: Chn B - Hng t 1: Fe + 2AgNO3 Fe + Cu(NO3)2 Fe(NO3)2 + 2Ag ; Fe(NO3)2 + Cu mol: x 2x y y (Y) Ag : 2x mol, Cu : y mol (x y) mol 2x mol t mol Fe AgNO3 ,Cu(NO )2 m (g) X dung dịch X x y mol t y mol Fe , Cu x mol y mol 0,5x mol y mol t0 NaOH , NO Fe(OH)3 ,Cu(OH) Fe O3 ,CuO dung dịch Z a (g) b(g) Theo m gam m 56(x y) m (1) xy Theo a gam 56 (1), (3) + Ta cú h sau: 90(x + y) 98(t y) a (2) Theo b gam t y b m 80(x + y) 80(t y) b (3) 80 56 + Thay (x + y) v (t y) v o ( ) ta c biu th c: b 7a - Hng t 2: m m 45 mol n Fe 2O3 mol m Fe(OH) m gam 56 112 28 10 49b 70m BT: Cu M m Fe2O3 m CuO b m CuO b m gam m Cu(OH) gam 40 45m 49b 70m a m 8,575b 7a - Ta cú: m Fe(OH) m Cu(OH) a 28 40 BT: Fe n Fe n Fe(OH) Kh ng c th nh c ng n o kh ng tr i qua kh uy n C ờn b n ca t i i! http://bloghoahoc.com Chuyờn trang thi th Húa Trang 10/5 Mó thi 132 ... m = 9b 6,5a HT http://bloghoahoc.com Chuyờn trang thi th Húa Trang 4/5 Mó thi 13 2 PHN TCH HNG DN GII THI TH THPT YấN PHONG BC NINH LN Cõu 1: Chn B Cõu 2: Chn B HCl NaOH C H... mE 18 n H2O 75x 14 6y 14 ,88 18 z v (2) BT: Na x y 0 ,18 n n n GlyNa LysNa NaOH a 1, 57 b - Hng t 2 .1: Ta cú th quy i h n h p E v cỏc axyl v H2O nh sau: C2 H3ON, C6 H12ON v + T (1) (... 0,5z y (1) BT:H n 1, 5x 4,5z y (CH ) NH :z mol H2 O BTKL + Ta cú : x n NaOH 0 ,18 mol 71n (CH2 )4 NH 18 n H2O mE 57n C2H3ON 71x 18 y 4,62(2) y 0, 0658 mol n GlyNa x z 0 ,13 16 mol