THPT Lấ DUN THI TH THPT QUC GIA LN NM 2017 Mụn: KHOA HC T NHIấN HểA HC ( thi cú 40 cõu / trang) Thi gian lm bi: 50 phỳt, khụng k thi gian phỏt Mó : 132 Cho bit nguyờn t ca cỏc nguyờn t : H =1; C = 12; N = 14; O = 16; Na = 23; Mg = 24; Al = 27; S =32; Cl = 35,5; K = 39; Ca = 40; Cr = 52; Fe = 56; Cu = 64; Zn = 65; Ag = 108; Ba=137 Cõu 1: Kim loi ch c iu ch bng phng phỏp in phõn núng chy l: A Fe B Cu C Na D Ag Cõu 2: Thớ nghim xy phn ng l: A Cho kim loi Fe vo dung dch ZnSO4 B Cho kim loi Cu vo dung dch H2SO4 loóng C Cho kim loi Fe vo dung dch MgCl2 D Cho kim loi Cu vo dung dch FeCl3 Cõu 3: Trong thc t, khụng s dng cỏch no sau õy bo v kim loi st b n mũn ? A Trỏng km lờn b mt st B Gn ng vi kim loi st C Ph mt lp sn lờn b mt st D Trỏng thic lờn b mt st Cõu 4: Mt loi nc cng c un sụi thỡ mt tớnh cng Trong loi nc cng ny cú ho tan nhng hp cht no sau õy ? A Ca(HCO3)2, MgCl2 B Ca(HCO3)2, Mg(HCO3)2 C Mg(HCO3)2, CaCl2 D MgCl2, CaSO4 Cõu 5: Trong quỏ trỡnh iu ch kim loi nhụm, gim nhit núng chy ca nhụm oxit, ngi thờm vo cht no di õy ? A Na3[AlF6] B K3[AlF6] C Na3[AlCl6] D K3[AlCl6] Cõu 6: Hũa tan hon ton 14,8 gam hn hp hai kim loi Fe v Cu (cú t l mol : 2) vo dung dch HCl loóng, sau phn ng thu c V lớt khớ H2 (ktc) Giỏ tr V l: A 2,24 B 3,36 C 4,48 D 5,60 Cõu 7: Phng trỡnh húa hc no di õy ỳng ? to A Fe + Cl2 B Be + 2H2O Be(OH)2 + H2 FeCl2 C Cr2O3 + 3H2SO4 Cr2(SO4)3 + 3H2O D AlCl3 + 3NaOH (d) Al(OH)3 + 3NaCl Cõu 8: Cho dung dch NaOH vo dung dch CuSO4 hin tng quan sỏt c l: A kt ta xanh lỏ cõy B kt ta xanh da tri C kt ta keo trng D kt ta vng Cõu 9: Dung dch X cú cha x mol NaNO3 v x mol HCl Cho x mol Fe vo dung dch X, dung dch sau phn ng khụng tỏc dng c vi cht no di õy ? A NaOH B AgNO3 d C Cu D Zn Cõu 10: Dng c khụng dựng ng dung dch nc vụi l: A cc thy tinh B cc st C cc nhụm D cc nha Cõu 11: t m gam hn hp kim loi gm Zn, Al, Mg oxi d, sau phn ng thu c 8,125 gam hn hp X ch gm cỏc oxit Hn hp X phn ng va ht vi 400 ml dung dch HCl 1M Giỏ tr m l: A 4,925 B 3,450 C 6,525 D 5,725 Cõu 12: Cho hn hp dung dch gm Fe(NO3)2 v CuCl2 vo dung dch AgNO3 d Cht rn thu c sau phn ng l: A AgCl, Cu B AgCl, Ag C Ag, Cu D AgCl Cõu 13: phõn bit cỏc cht riờng bit: KNO3, Ba(HCO3)2, CuCl2, ZnSO4, cú th dựng dung dch: A Na2CO3 B H2SO4 C KOH D NaHSO4 Cõu 14: Sau bi thc hnh hoỏ hc, mt s cht thi dng dung dch, cha cỏc ion: Cu 2+, Zn2+, Fe3+, Pb2+, Hg2+ Dựng cht no sau õy x lớ s b cỏc cht thi trờn ? A Nc vụi d B HNO3 C Gim n D Etanol Cõu 15: Cht no di c ng dng sn xut rut phớch, sorbitol ? A Glucoz B Saccaroz C Fructoz D Tinh bt Cõu 16: Thy phõn hon ton 200 mL dung dch saccaroz, sn phm thu c em phn ng vi lng http://dethithpt.com Website chuyờn thi th file word cú li gii mi nht Trang d AgNO3/NH3, thy xut hin 8,64 gam Ag Nng dung dch saccaroz ó dựng l: A 0,02 M B 0,01 M C 0,10 M D 0,20 M Cõu 17: Amin C4H11N cú bao nhiờu ng phõn bc 1? A B C D Cõu 18: Polime no cú tớnh cỏch in tt, bn c dựng lm ng che nc, vi che ma vt liu in A Cao su thiờn nhiờn B Thy tinh hu c C poli(vinylclorua) D polietilen Cõu 19: Tỡm phỏt biu ỳng ? A Cỏc peptit Gly-Ala-Ala v Al-Gly-Gly u cú phn ng mu biure B Tt c cỏc cacbohiủrat u cú phn ng thy phõn mụi trng axit C Este phn ng thy phõn NaOH thu c mui v ancol D Cỏc polime tng hp rt bn mụi trng baz Cõu 20: Amino axit khụng phn ng vi cht no di õy ? A HCl B NaOH C KHCO3 D Na2SO4 Cõu 21: Cho m gam valin vo 200 ml dung dch HCl 1M, dung dch sau phn ng tỏc dng va vi 250 ml NaOH 2M Mc khỏc, nu t chỏy m gam valin thỡ cn V lớt khớ O2 (ktc) Giỏ tr V l: A 15,12 B 30,24 C 45,36 D 75,6 Cõu 22: Cỏc cht u b thy phõn mụi trng kim l: A metyl fomat, glucoz, protein B etyl axetat, protein, nilon-6 C metyl fomat, protein, t olon D etyl axetat, protein, t nitrin Cõu 23: Cho 6,08 gam hai amin metyl amin v etyl amin tỏc dng vi V (ml) dung dch HCl 1M thu c 9,00 gam mui Giỏ tr ca V l: A 50 B 60 C 70 D 80 Cõu 24: Thy phõn hon ton m gam phenyl axetat cn va 200 ml dung dch NaOH, sau phn ng thu c gam mui Nng dung dch NaOH ó dựng l: A 0,40 M B 0,80 M C 0,60 M D 1,20 M Cõu 25: t chỏy 5,6 gam bt Fe khớ clo thu c 14,12 gam rn X Hũa tan ht X lng d nc ct thu c 200 gam dung dch Y Cỏc phn ng xy hon ton Nng FeCl cú dung dch Y l: A 5,20% B 6,50% C 7,80% D 3,25% Cõu 26: Nh t t V (ml) dung dch Ba(OH)2 2M vo dung dch X cha 0,1 mol HCl v 0,1 mol Al2(SO4)3, sau phn ng thu c 77,7 gam kt ta Giỏ tr V l: A 200 B 300 C 400 D 500 Cõu 27: t hn hp bt X gm Al, Cr, Fe mt lng oxi d, sn phm thu c hon tan vo dung dch NaOH c, núng, lc b cht rn, dung dch thu c em thi khớ CO d vo thy cú kt ta Y xut hin Cỏc cht cú Y l: A Al(OH)3 C Cr(OH)3, Fe(OH)3 C Al(OH)3, Fe(OH)3 D Al(OH)3, Cr(OH)3 Cõu 28: in phõn 200 ml dung dch X cú cha Cu(NO3)2 x mol/l v NaCl 0,06 mol/l vi cng dũng in 2A Nu in phõn thi gian t giõy anot thu c 0,448 lớt khớ Nu in phõn thi gian 2t giõy thỡ th tớch thu c in cc l 1,232 lớt Cỏc khớ o iu kin tiờu chun Giỏ tr ca x l: A 0,20 B 0,15 C 0,10 D 0,25 Cõu 29: Cho hai kim loi Fe v Cu vo dung dch X cha KNO3 v H2SO4, kt thỳc phn ng khụng thy kim loi d, thu c dung dch Y cú mu vng nõu nht Nu thờm mt vi git HCl loóng vo dung dch Y v un nh thỡ thy cú khớ khụng mu húa nõu khụng khớ xut hin Thnh phn cỏc cation cú th cú dung dch Y l: A Cu2+, Fe3+ B Cu2+, Fe2+ C Cu2+, Fe2+, Fe3+ D Cu2+, Fe2+, Fe3+, H+ Cõu 30: Cho cỏc phỏt biu sau: (1) Phốn crom-kali K2SO4.Cr2(SO4)3.24H2O cú mu xanh tớnh, c dựng thuc da, lm cht cm mu ngnh nhum vi (2) Fe phn ng vi HNO3 c, ngui thu c mui st (III) v cú khớ NO2 bay (3) Nhụm t bc chỏy tip xỳc vi khớ Cl2 (4) Nc cú cha cỏc mui CaCl2, MgCl2, CaSO4, MgSO4 gi l nc cng ton phn http://dethithpt.com Website chuyờn thi th file word cú li gii mi nht Trang (5) Cỏc kim lai Na v K dựng lm cht trao i nhit vi loi lũ phn ng ht nhõn S phỏt biu ỳng l: A B C D Cõu 31: Hũa tan hon ton 17,28 gam hn hp X gm Fe, FeO, Fe3O4, Fe(NO3)2 vo dung dch X cha 0,3 mol HCl v 0,12 mol H 2SO4 Kt thỳc phn ng thu c 1,568 lớt hn hp khớ Y (ktc) cú t so vi H2 bng 10, ú cú khớ húa nõu khụng khớ v dung dch Z ch cha mui Cụ cn dung dch Z thu c m gam mui khan Giỏ tr m l: A 34,18 gam B 38,57 gam C 30,69 gam D 35,35 gam Cõu 32: Cho m gam hn hp X gm MgO, Mg, Na2O vo 415 ml dung dch HNO3 1M, sau phn ng thu c dung dch Y v 0,448 lớt khớ NO (ktc) Dung dch Y phn ng va dung dch cha 0,295 mol NaOH, thu c mt lng kt ta, un núng kt ta n lng khụng i thu c 4,4 gam rn Z Bit cỏc phn ng xy hon ton Giỏ tr m gn nht vi ? A 7,36 B 8,82 C 7,01 D 8,42 Cõu 33: t chỏy hon ton mt hn hp khớ X gm hai amin no, n chc, ng ng k tip v hai anken ng ng kip tip (u cú s cacbon nh hn 4) cn V (lớt) khớ oxi, thu c hn hp khớ Y Cho Y vo bỡnh ng dung dch nc vụi d thy xut hin 25 gam kt ta, 0,448 lớt khớ thoỏt ra, ng thi lng dung dch gim 8,42 gam Mc khỏc, X cng phn ng va vi 60 ml dung dch Br2 1M Cỏc khớ o iu kin tiờu chun Giỏ tr ca V v tờn gi ca amin nh hn l: A 9,072; propan amin B 9,072; etyl amin C 6,272; etyl amin D 6,272; propan amin Cõu 34: Cho dóy cỏc cht sau: CH3COONH4, CH3NH2, C6H12O6 (glucoz), H2N-CH2-COOH, CH3COOC2H5, HCOONH4, protein, poli(metyl metacrylat) S cht cú tớnh cht lng tớnh l: A B C D Cõu 35: Cho cỏc s phn ng sau: X1 + 2NaOH X2 + 2X3 X2 + 2HCl X4 + 2NaCl nX4 + nX5 t lapsan + 2nH2O CH3COOH + X3 metyl axetat + H2O Phỏt biu ỳng l: A Trong phõn t X1 cú 10 nguyờn t H B X3 cú nhit núng chy cao hn X4 C X5 cú nhit sụi thp hn X3 D X1 cú phõn t lng ln hn X4 l 30 vC Cõu 36: Cho thụng tin thớ nghim cht di bng sau: Mu th Nhit sụi (oC) Thuc th Hin tng X -6,3 Khớ HCl Khúi trng xut hin Y 32,0 AgNO3/NH3 Cú kt ta Ag xut hin Z 184,1 Br2 Kt ta trng T 77,0 Na Khụng phn ng Bit X, Y, Z, T cú cha cỏc cht sau: etyl axetat, metylamin, anilin, metyl fomat Phỏt biu ỳng l: A Y l metyl fomat B T l anilin C X l etyl axetat D Z l metylamin Cõu 37: Hn hp X gm axit glutamic v lysin tỏc dng vi dung dch cha 0,5 mol NaOH, thờm tip 250 ml dung dch H2SO4 2M vo thỡ thy phn ng xy va , cụ cn dung dch sau phn ng thu c 103,9 gam mui Phn trm lng ca lysin X l: A 33,49% B 66,51% C 66,97% D 33,26% Cõu 38: Este X tỏc dng vi NaOH theo t l mol : thu c mt mui Y v mt ancol Z, ú s cacbon mui Y gp ụi ancol Z Nu em Z un núng 170oC vi H2SO4 c thu c khớ etilen Mc khỏc, mol X tỏc dng va vi mol Br2 Phỏt biu no di õy sai ? A X cú bt bóo hũa bng B Y cú cha nguyờn t H C X cú s cacbon gp ln Z D Y tỏc dng vi H2SO4 to thnh mt axit hu c cú phõn t l 114 vC Cõu 39: t chỏy hon ton 3,04 gam mt cht hu c X bng O2 d, thu c 3,584 lớt khớ CO (ktc) v 1,44 gam H2O Mc khỏc 3,04 gam X tỏc dng va vi 60 ml dung dch NaOH 1M thu c dung dch Y cha hai mui Bit X cú lng phõn t nh hn 160 vC Khi lng ca mui cú phõn t ln hn l: A 1,64 gam B 3,08 gam C 1,36 gam D 3,64 gam Cõu 40: Hn hp T gm peptit cú t l mol tng ng : : 4, mi peptit c to nờn t cỏc amino http://dethithpt.com Website chuyờn thi th file word cú li gii mi nht Trang axit X, Y, Z cú cụng thc chung H2N-CnH2n-COOH Thy phõn hon ton 20,19 gam T thu c 0,10 mol X; 0,14 mol Y v 0,07 mol Z Mc khỏc nu t chỏy hon ton 24,19 gam T, ton b sn phm cho vo dung dch nc vụi d, thu c m gam kt ta Bit rng tng s liờn kt peptit T khụng vt quỏ Giỏ tr m gn nht vi ? A 97,10 B 94,60 C 98,20 D 95,80 HT http://dethithpt.com Website chuyờn thi th file word cú li gii mi nht Trang PHN TCH HNG DN GII THPT Lấ DUN - LN Cõu 1: Chn C - Phng phỏp in phõn núng c dựng iu ch cỏc kim loi ng trc Al (k c Al) dóy in húa Cõu 2: Chn D - Phn ng: Cu + 2FeCl3 CuCl2 + 2FeCl2 Cõu 3: Chn B - Gn Cu lờn b mt Fe khụng giỳp bo v st vỡ Fe cú tớnh kh mnh hn Cu nờn Fe úng vai trũ l cc õm v b n mũn trc Cõu 4: Chn B - Khi un núng nc cng tm thi cha Ca(HCO3)2, Mg(HCO3)2 thỡ s lm mt c tớnh cng Cõu 5: Chn A - Tỏc dng ca criolit Na3AlF6 quỏ trỡnh iu ch Al cụng nghip l: + Gim nhit núng chy ca Al2O3 (20500C 9000C) Tit kim nng lng + Hn hp cht lng dn in tt hn + Criolit nh, ni lờn ngn cn nhụm núng chy sinh tỏc dng vi khụng khớ Cõu 6: Chn B - Ta cú: nFe = 0,15 mol VH = 22, 4.n Fe = 3,36 (l) Cõu 7: Chn C o t A Sai, 2Fe + 3Cl2 2FeCl3 B Sai, Be + 2H2O : khụng xy C ỳng, Cr2O3 + 3H2SO4 Cr2(SO4)3 + 3H2O D Sai, AlCl3 + 4NaOHd Na[Al(OH)4] + 3NaCl Cõu 8: Chn B - Phn ng: 2NaOH + CuSO4 Cu(OH)2 xanh lam + Na2SO4 Cõu 9: Chn C 3+ Fe + 4H+ + NO3 Fe + NO + 2H2O mol: x x x 0,25x (Fe d: 0,75x mol v NO d) 2+ - Sau ú : Fe + 2Fe3+ 3Fe mol: 0,75x 0,25x 0,375x Vy dung dch sau phn ng cha Fe2+, Na+, Cl-, NO A Fe2+ + 2OH- Fe(OH)2 3+ + B Fe2+ + Ag+ Fe + Ag v Ag + Cl AgCl 2+ D Zn + Fe2+ Zn + Fe Cõu 10: Chn C - Vỡ Al phn ng vi Ca(OH)2 theo phn ng: 2Al + Ca(OH)2 + 2H2O Ca(AlO2)2 + 3H2 Cõu 11: Chn A - Ta cú: n O (oxit) = 0,5n H + = 0, mol m = m oxit 16n O = 4,925 (g) Cõu 12: Chn B - Phn ng: Fe(NO3)2 + AgNO3 Fe(NO3)3 + Ag CuCl2 + 2AgNO3 2AgCl + Cu(NO3)2 Cõu 13: Chn C http://dethithpt.com Website chuyờn thi th file word cú li gii mi nht Trang Thuc th KNO3 Ba(HCO3)2 CuCl2 KOH d Khụng hin tng Kt ta trng Kt ta mu xanh lam ZnSO4 To kt ta trng keo sau ú tan Cõu 14: Chn A - x lớ nc thi cú cha cỏc ion kim loi nng nh Hg 2+, Pb2+, Fe3+, ngi ta s dng dung dch kim, ú phn ng s xy v hỡnh thnh cỏc kt ta hiroxit ca kim loi nng, t ú ta lc b kt ta i - Lý s dng Ca(OH) m khụng s dng KOH hoc NaOH vỡ Ca(OH) giỏ thnh r (mua CaO ngoi th trng sau ú cho tỏc dng vi H 2O thu c Ca(OH)2), d s dng v ph bin hn so vi KOH (NaOH) Cõu 15: Chn A Cõu 16: Chn C n Ag CM = = 0,1 M 4.V Cõu 17: Chn D Bc S ng phõn C4H11N Cõu 18: Chn C Cõu 19: Chn A B Sai, Monosaccarit khụng cú phn ng thy phõn mụi trng axit C Sai, Mt s este thy phõn mụi trng kim khụng thu c ancol D Sai, Mt s polime tng hp cú cha liờn kt amit (CO-NH) kộm bn mụi trng baz Cõu 20: Chn D Cõu 21: Chn C - Ta cú: n Valin = n NaOH n HCl = 0, mol VO = 22, 4.6, 75.n Valin = 45,36 (l) Cõu 22: Chn B Cõu 23: Chn B 6, 08 VHCl = = 0, 08 (l) = 80 ml 36,5.1 Cõu 24: Chn D - Ta cú: m CH 3COONa + m C6 H 5ONa = 23, 76 n CH 3COONa = n C 6H 5ONa = 0,12 mol VNaOH = 0, 24 = 1, 2M 0, Cõu 25: Chn D n FeCl + n FeCl3 = 0,1 n FeCl = 0, 06 mol - Xột dung dch Y ta cú: 127n FeCl2 + 162,5n FeCl3 = 14,12 n FeCl3 = 0, 04 mol 162,5.0, 04 100% = 3, 25% Vy %m FeCl3 = 200 Cõu 26: Chn A - Gi s mol BaSO4 tớnh theo mol SO l 0,3 mol m BaSO = 69,9 (g) m Al(OH)3 = 77, 69,9 = 7,8 (g) n Suy ra: n OH = n H + + 4n Al3+ n Al(OH)3 = 0,8 mol VBa(OH) = OH = 0, (l) = 200 ml 2.2 Cõu 27: Chn D + O2 + NaOH + CO - Quỏ trỡnh: Al,Cr, Fe Al 2O ,Cr2O , Fe xO y NaAlO , NaCrO Al(OH) ,Cr(OH)3 Cõu 28: Chn D - Trong thi gian t (s): Ti catot: Cu2+ + 2e Cu Ti anot: 2Cl- + 2e Cl2 0,012 0,012 0,006 http://dethithpt.com Website chuyờn thi th file word cú li gii mi nht Trang n e (t) = 0, 068 mol 2H2O - Trong thi gian 2t (s): Ti catot: Cu2+ + 2e Cu 0,05 0,1 2H2O + 2e 2OH- + H2 0,036 0,018 n H = 0, 055 (n O + n Cl ) = 0, 018 mol + 4e 0,056 Ti anot: 2Cl- + 2e 0,012 0,012 2H2O + 4e 0,124 n e (2t) 4H+ + O2 0,014 Cl2 0,006 4H+ + O2 0,031 = 0,136 mol Vy x = 0,25 M Cõu 29: Chn C - Khi nh vi git HCl loóng vo dung dch Y un nh thỡ thy cú khớ khụng mu húa nõu khụng khớ xut hin dung dch Y cú cha Fe 2+ v NO3 (nu nh cú H+ thỡ NO ht vy Y khụng th cha H+) - Mu ca cỏc dung dch Y cú th cú l dung dch Cu2+ cú mu xanh lam, dung dch Fe 2+ cú mu lc nht, dung dch Fe3+ cú mu vng nht Vy cation dung dch Y cú th cú cỏc ion l Cu2+, Fe2+, Fe3+ Cõu 30: Chn B (2) Sai, Fe b th ng húa vi HNO3 c, ngui (4) Sai, Nc cú cha cỏc mui CaCl2, MgCl2, CaSO4, MgSO4 gi l nc cng vnh cu Cõu 31: Chn A - Trong hn hp khớ Y cú H2 (0,025 mol) v NO (0,045 mol) n HCl + 2n H 2SO 2n H BT: H = 0, 245 mol Vỡ sau phn ng cú H2 nờn NO ht nờn n H 2O = - Khi cho hn hp X tỏc dng vi hn hp axit thỡ: BTKL m Z = m X + 36,5n HCl + 98n H 2SO m Y 18n H 2O = 34,18 (g) Cõu 32: Chn A - Cht rn Z l MgO: 0,11 mol - Khi cho dung dch Y phn ng vi NaOH thỡ: n HNO3 d = n NaOH 2n Mg(OH) = 0, 075 mol - Dung dch Y cha Mg(NO3)2; NaNO3 v HNO3 d 3n NO BT: e = 0, 03 mol - Khi cho dung dch X phn ng vi HNO3 thỡ: n Mg = BT: Mg n MgO (X) = n MgO (Z) n Mg = 0, 08 mol m n NaNO3 = n HNO3 p - 2n Mg(NO3 )2 - nNO = 0,1 mol m X = 40n MgO + 24n Mg + 62 n NaNO3 = 7, 02 (g) Cõu 33: Chn B - T d kin ca bi ta cú: n CO = n CaCO3 = 0, 25 mol v n N = 0, 02 mol n a = 2n N = 0, 04 mol nH2O = mCaCO3 mgiaỷm 44nCO2 18 BT: O = 0,31mol VO2 = 22,4 2nCO2 + nH2O = 9,072(l) - Khi cho X tỏc dng vi dung dch Br2 thỡ: n anken = n Br2 = 0, 06 mol n CO C= = 2,5 nờn suy amin cú phõn t nh hn X l C H NH n anken + n a Cõu 34: Chn A - Cú cht lng tớnh l: CH3COONH4, H2N-CH2-COOH, HCOONH4, protein Cõu 35: Chn A - Cỏc phn ng xy ra: http://dethithpt.com Website chuyờn thi th file word cú li gii mi nht Trang o H 2SO ,t (4) CH3COOH + CH3OH (X3) CH3COOCH3 + H2O xt,t o (3) n(p-HOOCC6H4COOH) (X4) + nC2H4(OH)2 (X5) ( OCC 6H 4CO O C H O ) n + 2nH2O (2) NaHOOCC6H4COONa + 2HCl HOOCC6H4COOH + 2NaCl (1) CH3OOCC6H4COOCH3 (X1) + 2NaOH NaHOOCC6H4COONa + 2CH3OH A ỳng, Trong phõn t X1 cú 10 nguyờn t H B Sai, X4 cú nhit núng chy cao hn X3 C Sai, X5 cú nhit sụi cao hn X3 D Sai, X1 cú phõn t lng ln hn X4 l 28 vC Cõu 36: Chn A Mu th Nhit sụi (oC) Thuc th Hin tng X: CH3NH2 -6,3 Khớ HCl Khúi trng xut hin Y: HCOOCH3 32,0 AgNO3/NH3 Cú kt ta Ag xut hin Z: C6H5NH2 184,1 Br2 Kt ta trng T: CH3COOC2H5 77,0 Na Khụng phn ng Cõu 37: Chn B n axit glutamic + 2n lysin = 2n H 2SO n NaOH = 0,5 n axit glutamic = 0,1 - Ta cú: 147n axit glutamic + 146n lysin = 103,9 + 18.0,5 40n NaOH 98n H 2SO = 43,9 n lysin = 0, %m lysin = 66,51 Cõu 38: Chn B - em Z un núng 170oC vi H2SO4 c thu c C2H4 nờn Z l C2H5OH + Vỡ s cacbon mui Y gp ụi ancol Z nờn s C Y l + mol X phn ng va vi mol Br2 nờn gc H.C ca axit cú cha liờn kt + X tỏc dng vi NaOH theo t l mol : nờn este X l este chc Vy X l C2H5-OOC-C C-COO-C2H5 ; Y l NaOOC-C C-COONa ; Z l C2H5OH A ỳng, X cú bt bóo hũa bng = B Sai, Y khụng cú cha nguyờn t H C ỳng, X cú cacbon Z ch cú cacbon D ỳng, Y tỏc dng vi H2SO4 to thnh HOOC-C C-COOH cú phõn t l 114 vC Cõu 39: Chn B n NaOH - Khi cho X tỏc dng vi NaOH thỡ: n X = (1 : a l t l phn ng ca X : NaOH) a n CO 0,16 2n a=3 = a C X = H X = H2O = v O X = - Khi t chỏy hon ton X thỡ: C X = nX 0, 06 nX - Cu to ca X l CH3COOC6H4OH mui cú PTK ln hn: NaOC6H4ONa m = 3, 08 (g) - Cu to ca X l HCOOC6H3(CH3)OH mui cú PTK ln hn: NaOC6H3(CH3)ONa m = 3,36 (g) Cõu 40: Chn A - Khi gp A, B v C vi t l mol tng ng l : : thỡ 2A + 3B + 4C A B3C + 8H 2O + T: nX : nY : nZ = 0,1: 0,14: 0,07 = 10:14: A B3C l (X)10k (Y )14k (Z3)7k số mắ c xích(min) < số c xích(max) 20 < 31k < 40 k = 2Z43 3T4 < số mắ 4mắ 4c4xí 4ch 4Y4 144244 m 4 4 (7+3).2 10k+14k+7k (7+3).4 nA = 2nA 2B3C4 = 0,02mol nX + Vớ i k =1 nA 2B3C4 = = 0,01mol nZ = 3nA 2B3C4 = 0,03 mol 10 n = 4n A 2B3C4 = 0,04mol T + Quy i hn hp X thnh C2H3ON, CH2 v H2O http://dethithpt.com Website chuyờn thi th file word cú li gii mi nht Trang nC2H3ON = nX + nY + nZ = 0,31mol m 57nC2H3ON 18nH2O Vớ i nCH2 = T = 0,35mol 14 nH2O = nA + nZ + nT = 0,09mol Vy m CaCO3 = 100n CO = 100.(2n C 2H 3ON + n CH ) = 97 (g) http://dethithpt.com Website chuyờn thi th file word cú li gii mi nht Trang ... : nZ = 0 ,1: 0 ,14 : 0,07 = 10 :14 : A B3C l (X )10 k (Y )14 k (Z3)7k số mắ c xích(min) < số c xích(max) 20 < 31k < 40 k = 2Z43 3T4 < số mắ 4mắ 4c4xí 4ch 4Y4 14 4244 m 4 4 (7+3).2 10 k +14 k+7k (7+3).4... 5ONa = 0 ,12 mol VNaOH = 0, 24 = 1, 2M 0, Cõu 25: Chn D n FeCl + n FeCl3 = 0 ,1 n FeCl = 0, 06 mol - Xột dung dch Y ta cú: 12 7n FeCl2 + 16 2,5n FeCl3 = 14 ,12 n FeCl3 = 0, 04 mol 16 2,5.0, 04 10 0%... + H2 0,036 0, 018 n H = 0, 055 (n O + n Cl ) = 0, 018 mol + 4e 0,056 Ti anot: 2Cl- + 2e 0, 012 0, 012 2H2O + 4e 0 ,12 4 n e (2t) 4H+ + O2 0, 014 Cl2 0,006 4H+ + O2 0,0 31 = 0 ,13 6 mol Vy x =