Chương 1/ xsinx=1; x F(a)=f(1)=-0.1585290 F(c1)=f[(a+b)/2]=f(1.5)=0.4>0 F(c2)=ff(1.25)=0.18>0 F(c3)= f(1.125)=0.015>0 F(c4)= f(1.0625)=-0.070 F(b)=f(4.5)=-0.10 F(c2)=f(4.375)=1.5>0 F(c3)= f(4.4375)=0.89>0 F(c4)= f(4.46875)=0.44>0 F(c5)= f(4.484375)=0.17>0 F(c6)= f(4.492188)=0.0245>0 F(c7)= f(4.496094)=-0.050 F(c9)= f(0.748047)=-0.0010 F(c6)= f(2.640625)=0.05>0 F(c7)= f(2.632873)=-0.010 F(c9)= f(2.634766)=0.0003>0 F(c10)= f(2.6337895) Vậy nghiệm PT là: 2.6337895 9/ lnx – 3xsinx + = 0; x ϵ [1,0.25] N = 10 F(a)=f(1)=-0.520 F(c1)=f[(a+b)/2]=f(0.625)=0.4>0 F(c2)=f(0.8125)=0.2>0 F(c3)= f(0.90625)=-0.20 F(c6)= f(0.265625)=0.03>0 F(c7)= f(0.257813)=0.001>0 F(c8)= f(0.253907)=-0.01