C 25 03 bai toan ve ankan

• • • nH2n+2 + X2 askt CnH2n+1X + HX MX 14n MX %X 100% VD1: Y2 Trong Y1 Y2 Y1 Y2 Y1 Y2 Y1 Y2 nH2n+2 nH2n+2 %Cl askt + X2 35,5 14n 35,5 CnH2n+1X + HX 100% 45, 22% 3H8 n CH3—CH2—CH3 VD2: Y2 Y = 11,1 + 2,6 = 13,7 (gam) nH2n+2 5, 14n askt + X2 = CnH2n+1X + HX 13, 14n 81 n=4 X C4H10 1 A) CH4 B) C2H6 C) C3H8 D) C5H12 A) CH4 B) C3H8 C) C5H12 D) C6H14 A) 2,2 C) B) 2–metylbutan D) pentan A) C5H12 B) C6H14 C) C7H16 C) C8H18 A) 2–metylpropan B) butan C) –metylpropan D) 2–metylbutan A) 2–metylpropan C) butan B) 2,3 D) 3–metylpentan A) 3–metylpentan C) 2,3 B) 2–metylpentan D) A) CH4 B) C3H8 C) C4H10 D) C5H12 A) CH4 B) C3H8 C) C5H12 D) C2H6 A A) 2–metylpropan C) –metylpropan B) butan D) 2,4 A) 2–metylpropan C) 2–metylpentan B) 2–metylbutan D) 3–metylpentan B nH2n+2 + aX2 askt CnH2n+2–aXa + aHX C A) CHCl3 C) C2H4Cl2 B) CH2Cl2 D) C2H5Cl D danh pháp IUPAC A) 2,2 C) 2,3 B) etan D) metan xt ANKAN X to ANKEN Y1 + ANKAN Y2 x = mY 24 mY VD3: Do: d Y 12 H2 MY X 24 72 (gam) = mY = 72 (gam) MX nH2n+2 mX nX 72 MX = 14n + = 72 n = 5H12 E A) 2,2 C) 2,3 B) etan D) F nP¦ (thùc tÕ) h% nban ®Çu 100% VD4: 4H10 C3H6 + CH4 • • xt C4H10 to C3H6 + CH4 0 –x +x +x 1–x x x = (1 – x) + x + x = + x (mol) Y = mBUTAN = 58 (gam) Y MY dY 58 x MY MH2 H2 36,5 h% mY nY 18, 25 x 58 x MY 36,5 0,59 0,59 100% 59% G xt C3H8 to C2H4 + CH4 4, C2H4 C3H8 H xt to h% X, MX MY 100% MY I A) 42,86 % C) 60 % B) 57,14 % D) 75 % A) 50 % C) 53,92 % B) 85,45 % D) 92,73 % J K A) 50 % B) 60 % C) 40 % D) 62,5 % L phân metan A) 10,5 % C) 79,0 % B) 21,21 % D) 89,5 % nH2n+2 3n + to O2 (1) nANKAN (2) – Chú ý (1) nCO2 (2) nO nCO nO2 nCO2 nH O nCO n H2O nCO2 n (3) – nCO2 + (n+1)H2O nANKAN VD5: nH O 2 Cách 1: CO2 + H2O CaCO3 + H2O CO2 + Ca(OH)2 nCO 100 nCaCO nO2 0, 04 (mol) 0, 065 0, 04 nCO2 X ankan nH2n+2 nH2n+2 + 3n to O2 nH2O nX n Cách 2: n nH O n 2 nO2 nH O nCO2 nX nCO nCO2 0, 05 (mol) 0, 01 (mol) 4H10 nCO nCO2 + (n+1)H2O 0, 04 0, 05 n 4H10 M 0,72 gam H2 danh pháp IUPAC A) propan C) 2–metylpropan B) butan D) pentan N A) C2H6 B) C3H8 C) C4H6 D) C4H10 O A) 2–metylpropan C) 2,3,4–trimetylpentan B) isobutan D) 2,3 P A) C4H10 B) C6H14 C) C8H18 D) C5H12 Q A) 2–metylpentan C) 2,3 B) 2,4 D) pentan R 0,132 mol H2 A) 2–metylbutan C) 2,2 H2 B) etan D) 2–metylpropan Chú ý CnH2n n n, VD6: VCO2 12 17 VH2O A < MB nCO2 12 17 nH2O nH2O nCO2 A B hai ankan CnH2n CnH2n nCO2 n nH2O n + H2O có 3n 12 17 n O2 to nCO2 + n H2O 2, 2H6 C3H8 S H2 VH O VCO A) CH4 C2H6 C) C3H8 C4H10 13 (các B) C2H6 C3H8 D) C4H10 C5H12 T • • H2O 2SO4 A) CH4 C2H6 C) C3H8 C4H10 B) C2H6 C3H8 D) C4H10 C5H12 U 2O A) C2H6 C3H8 C) C2H2 C3H4 Chú ý B) CH4 C2H6 D) C2H4 C3H6 V A A) metan C) propan B) etan D) butan W MX < MY A) CH4 < MB B) C2H6 14,58 gam H2 C) C3H8 D) C4H10 X A) C2H6 C3H8 C) C2H2 C3H4 B) CH4 C2H6 D) C2H4 C3H6 Y A) CH4 C2H6 C) C3H8 C4H10 B) C2H6 C3H8 D) C4H10 C5H12 10 Z 5,76 gam H2 Chú ý A) 8,512 B) 7,168 C) 42,56 D) 35,84 a 2 A) 70,0 lít C) 84,0 lít B) 78,4 lít D) 56,0 lít b CO2 A) 33 B) 26,4 C) 1,32 D) 13,2 c 0,2 M Tính (a) (b) (c) 11 Câu Câu E B A A C F G H I D C D B J B C K B A L B C M A A C N D B B O C C C P D D A Q C Câu R S T U V W X Y Z a C A B B A A A A C A b A c F (CH3)3CH : isobutan G h = 35 % H h = 64,8 % c 12 [...]... 2 và 5,76 gam H2 Chú ý A) 8,512 B) 7,168 C) 42,56 D) 35,84 a 2 2 là A) 70,0 lít C) 84,0 lít B) 78,4 lít D) 56,0 lít b CO2 A) 33 B) 26,4 C) 1,32 D) 13,2 c 2 0,2 M Tính (a) (b) (c) 11 C u 1 C u E B A 2 A C F G H I 3 D 4 C 5 D 6 B J B 7 C K B 8 A L B 9 C M A A C N D B B O C C C P D D A Q C Câu R S T U V W X Y Z a C A B B A A A A C A b A c F (CH3)3CH : isobutan G h = 35 % H h = 64,8 % c 12