C 32 03 bai toan ve phan ung cua ancol

www.tuhoc.edu.vn R(OH)a + aNa R(ONa)a + a H2 a a • • • nH nANCOL Tính MR = MANCOL – Mcác nhóm OH R VD1: a a mA MA 2,3 92 + aNa nA 2,3 92 R(ONa)a + a H2 0,025 (mol) a R x Hy x y nH nA = 92 – 17 = 41 41 12 41 12 3H5(OH)3 htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn A) B) C) D) 2 A A) B) C) D) A) CnH2n+2O (n 1) C) CnH2n+2O3 (n 3) B) CnH2n+2O2 (n 2) D) CnH2nO (n 3) H2 A) B) C) D) V lít H2 A) CnH2n+2O (n 1) C) CnH2n+2O3 (n 3) B) CnH2n+2O2 (n 2) D) CnH2nO (n 3) khí H2 CO2 A) CH3CH2OH C) CH2=CHCH2OH B) CH2OH–CH2OH D) (CH3)2CHOH htttp://tuhoc.edu.vn/blog A) CH3CH2OH C) CH2OH–CH2OH B) CH2=CH–CH2OH D) CH2OH–CHOH–CH2OH www.tuhoc.edu.vn A) C2H6O2 C) C3H8O B) C3H8O2 D) C3H8O3 A) C2H4O C) C4H8O2 B) C3H6O D) C4H8O A A) ancol etylic C) glixerol B) etilen glicol D) propan–1,3 A) metanol C) propan–1–ol B) etanol D) butan–1–ol B H2 C A) etilen glicol C) propan–1,3 B) propan–1,2 D) htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn 2 Ancol + Na ChÊt r¾n + H2 i ancolat RONa i natri d− mH2 (mancol + mNa ) mChÊt r¾n VD2: (mancol + mNa ) mChÊt r¾n 0,15 (gam) nH2 0, 075 (mol) CnH 2n 1OH CnH 2n 1OH + Na nancol 2nH 0,15 (mol) mancol 6, (gam) Mà Mancol 14n 18 n CnH 2n 1ONa + Mancol H2 41,33 1, 67 3OH C2H5OH D A) C3H5OH C4H7OH C) C3H7OH C4H9OH B) C2H5OH C3H7OH D) CH3OH C2H5OH A) C2H6O2 C) C3H8O2 B) C3H6O2 D) C4H10O2 E htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn –140 oC: 2ROH mROH mR O mH O nR2O R2O + H2O nROH nH2O VD3: o 2SO4 ROH H2SO (®Æc) 2ROH 140 oC R 2O + H2O mROH Mà: nROH 2nH2O mR O 0, (mol) mH O 7, 0, MROH 21 MR2 39 1OH Tìm CTPT ancol: MR1 7, (gam) MR 21 R2OH (R1 < R2), R1 MR CTPT hai ancol CH3OH C2H5OH F o tác H2SO4 A) CH3OH C2H5OH C) C2H5OH C3H7OH G B) CH3OH C3H7OH D) C2H5OH C2H4(OH)2 o 2SO4 htttp://tuhoc.edu.vn/blog A) CH3OH C2H5OH C) C2H5OH C3H7OH B) CH3OH C3H7OH D) C2H5OH C4H9OH www.tuhoc.edu.vn 2SO4 H2SO (®Æc) • R2O + H2O 130-140 oC • H2SO (®Æc) CnH2n+1OH 170-180 oC CnH2n + H2O 2SO4 dA • dA B • dA B B VD4: dA 1, B R2O + H2O dA MR2O B MROH x Hy 2MR 16 MR 17 x y 1, 43 12 MR 43 43 12 3H7OH htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn H 2SO4 A) C3H8O C) CH4O B) C2H6O D) C4H8O I 2SO4 A) CH4O C2H6O C) C3H8O C4H10O B) C2H6O C3H8O D) C4H10O C5H12O J 2SO4 A) CH4O C2H6O C) C3H8O C4H10O B) C2H6O C3H8O D) C4H10O C5H12O htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn • • • to CnH2n+2O + CuO CnH2nO + H2O + Cu VD4: nH2n+2 nH2n+2O + CuO nCnH2nO nH2O nY dY 15,5 H2 mY mC H n 2nO MY 31 nCnH2nO to CnH2nO + H2O + Cu nCuO (ph¶n øng) nH2O 0, 02 (mol) 0, 04 (mol) mY = 1,24 (gam) mH O (14n 16) 0, 02 18 0, 02 n=2 1, 24 (gam) 2H6O K A) 0,92 B) 0,32 C) 0,64 D) 0,46 L A htttp://tuhoc.edu.vn/blog A) CH4O C) C3H8O < MB B) C2H6O D) C4H10O www.tuhoc.edu.vn M TOPPER Chú ý A) 75 % B) 85 % C) 80 % D) 90 % oxi hóa ancol A) 65 % B) 40 % C) 75 % D) 50 % N O A) C3H5OH C) C2H5OH 19 Ancol X B) CH3OH D) C3H7OH P A) 15 gam C) 12 gam B) 1,8 gam D) 18 gam htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn Câu A Câu E A C F A C G C B H B B I B C J C C K A B L B C M C A C N C B A O D C A P D D B htttp://tuhoc.edu.vn/blog 10