!"# $% !&' ()*% % # +,- ./ +0' ./!&1 234 Trắc nghiệm 6 3 30 % ! "#$%&' () *+, 56 78' 9 : -./ 012/1 3-456 -./ 3-4567 ! -./ 89 3:5;<=1.> ? 3@:.> 7 7 7 855A' B C9*D 3@855A B 7 () *+, 'E:7 'B 8F! ./+0' ; < = > >? >: G ./!&1 >@>:A ?@?:A ?@?:A >@>:A BC63 Phần 1. Trắc nghiệm (3.0 điểm) Khoanh tròn vào chữ cái đứng trước kết quả đúng nht : 0'>DH5I8':CJKKL#M1NO;=#;E@ P2Q R N S T 8UEPQ V N S S V !WX • #+@ O ' WN ' WS 3 ' WT Y ' W 0';+'E&*M 7 xy− O 7 x y− ZN& 7 2 3 7 P Qxy− Y xy− 0'E 7 X V 7 y z x y− ,. #+@ OR S 3 Y7 0'?3!F#GHIJE8K%!L1+,,#M+D O ( ) Vf x x= + ( ) 7 Vf x x= − 3 ( ) Vf x x= − Y QVP7QP += xxxf 0'=-+,*I#U#;=#+R*+S9-+&[#+@ O S 3R YX 0'<3'?O34,OWV43W4O3WX':,O443\'A#+@ OO]]3 ]O]3 3O]3] Y3]]O Phần 2. Tự luận (7.0 điểm) NK!>DOE:!&1P3'D SN7VQP 7V +++−= xxxxxP *+ TVXV7QP 7V7 −−+−= xxxxQ Q 012/1%P2Q*+(P2Q\'#^&6_U./ .Q 89P2QW%P2Q`(P2Q*+!P2QW%P2Qa(P2Q Q 89P2Q NK!;DO?:!&1P3'∆O3PO]O3QbD1:OY∆O385cO3#& dE''OdWO Q3∆OYW∆OYd b) 3OY#+;<55Ad c) Gef#+'O*+Yd3∆fYW∆d3Y d) 'E:Y*+Y3 QQ 234D Mỗi câu trả lời đúng được 0,5đ 0' > ; E ? = < FF N N C 56D RS6 T U !&1 :;= := := NK!> a) SN7VQP 7V +++−= xxxxxP %P2QWV2 V `2 7 a72`N2`S SN7VQP 7V +++−= xxxxxP %P2QWV2 V `2 7 a72`N2`S %P2QWV2 V `2 7 `2`S SN7VQP 7V +++−= xxxxxP %P2QWV2 V `2 7 a72`N2`S %P2QWV2 V `2 7 `2`S :;= := := a) TVXV7QP 7V7 −−+−= xxxxQ (P2QWZV2 V `72 7 aV2 7 `XaT TVXV7QP 7V7 −−+−= xxxxQ (P2QWZV2 V `72 7 aV2 7 `XaT (P2QWZV2 V a2 7 a TVXV7QP 7V7 −−+−= xxxxQ (P2QWZV2 V `72 7 aV2 7 `XaT (P2QWZV2 V a2 7 a :;= := := b) P2QW%P2Q`(P2Q W SN7V 7V +++− xxxx `P TVXV7 7V7 −−+− xxx Q P2QW%P2Q`(P2Q WV2 V `2 7 `2`S `PZV2 V a2 7 aQ W2`V %P2QWV2 V `2 7 `2`S ` (P2QWZ V2 V a2 7 a P2QW%P2Q`(P2QW2`V :;= := := b) !P2QW%P2Qa(P2Q W SN7V 7V +++− xxxx ZP TVXV7 7V7 −−+− xxx Q !P2QW%P2Qa(P2Q WV2 V `2 7 `2`S ZPZV2 V a2 7 aQ !P2QW%P2Qa(P2Q %P2QWV2 V `2 7 `2`S ZZ (P2QW ZV2 V a2 7 a !P2QWR2 V `72 7 `2`V :;= := c) !P2Q#+ 2WZVg P2QW⇒2`VW ⇒2WZV⇒2WZVg !P2Q#+2 WZVg :;= := := NK!; := > > a) hi?OY*+?OYd4,@ OWOdPQ OY@ hi?OY*+?OYd4,@ OWOdPQ jYWYjdPOY#+1:Q OY@ &5?OYW?OYdPQ hi?OY*+?OYd4,@ OWOdPQ jYWYjdPOY#+1:Q OY@ &5?OYW?OYdPQ :;= := b) 8,@OWOdPQk YWYdP?OYW?OYdQ 8,@OWOdPQk YWYdP?OYW?OYdQ !cOY#+;<55A d :;= := > c) hi∆fY*+∆d3Y4,@ YfW3YdPlQ hi∆fY*+∆d3Y4,@ YfW3YdPlQ YWYdPQ 3;=@YfWYd3 hi∆fY*+∆d3Y4,@ YfW3YdPlQ YWYdPQ YfWYd3PQ &5@∆BFD = ∆ECD (g.c.g) :;= > d) Y]Y3 8,@ fYm C n P,'+?Q ⇒Yd3m C n PfYWYd3Q ⇒Y3mYdP(,4 :Q ⇒b &Y3mY V% ; ?= . := NK!> a) SN7VQP 7V ++ + = xxxxxP %P2QWV2 V `2 7 a72`N2`S SN7VQP 7V ++ + = xxxxxP %P2QWV2 V `2 7 a72`N2`S %P2QWV2 V `2 7 `2`S SN7VQP 7V ++ + = xxxxxP %P2QWV2 V `2 7 a72`N2`S %P2QWV2 V `2 7 `2`S :;=. x= − 3 ( ) Vf x x= − Y QVP7QP += xxxf 0'=- + ,*I#U#;= #+ R *+ S9- + &[ #+ @ O S 3R. YX 0'<3'?O34,OWV43W4O3WX':,O443'A #+ @ OO]]3 ]O]3 3O]3] Y3]]O Phần 2. Tự luận (7.0 điểm) NK!>DOE:!&1P3'D SN7VQP 7V ++ + = xxxxxP *+ TVXV7QP 7V7 − + =