Cơ Sở Dữ Liệu Quản Lý Thư Viện.pdf

The clubalso needs to ensure that the player cannot sign a contract with two or more other clubs.Information of the club include: ClubID, Name of the club Clubs also needs to manage numb

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DBI202 – DATABASE SYSTEM OF DORM

FPT UNIVERSITY

STUDENT NAME: NGUYỄN TRẦN VIỆT HƯNG | SE12XXX

STUDENT NAME: TRẦN TRUNG HIẾU | SE12XXX

TEACHER: …………

ASSIGNMENT

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TABLE OF CONTENTS

I) INTRODUCE THE PROBLEM………

1) DESCRIBE THE PROBLEM………

2) MANAGEMENT OBJECTIVES………

II) ENTITY – RELATIONSHIP – ER………

1) DIFINITION ENTITY – ATTRIBUTE………

2) SET-UP ENTITY – RELATIONSHIP………

III) DATA DICTIONARY………

1) DATABASE AND TABLE……….………

IV) ENTITY RELATIONSHIP DIAGRAM (ERD)………

1) GUARD………

2) STUDENT………

3) PANALIZE………

4) ROOM………

5) ITEMS………

6) NORMAL FORM………

V) SQL COMMAND 1) QUERY USING ORDER BY………

2) QUERY USING INNER JOIN………

3) QUERY USING AGGREGATE FUNCTIONS………

4) QUERY USING THE GROUP BY AND HAVING CLAUSES………

5) QUERY THAT USES A SUB-QUERY AS A RELATION………

6) QUERY THAT USES PARTIAL MATCHING IN THE WHERE CLAUSE………

7) QUERY THAT USES A SELF-JOIN………

8) STORE PROCEDURE………

9) TRIGGER………

3/22/2024 DBI202 – DATABASE SYSTEM OF DORM FPT UNIVERSITY 1

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I) INTRODUCE THE PROBLEM

1) DESCRIBE THE PROBLEM

Nowadays, football becomes one of the world’s most popular sports To be able to create such a wonderful sport, it is can not be ignored to mention the players who are dedicating themselves to this sport But, it is still have not database system for manage player After the actual survey, the result are

as follows:

Every player is managed by an agent, an agent can manage many players

Each player have their own country

Player can only play for one club through contract, each club have many players

Information for contract include: StartDate, EndDate, Salary of player

Clubs records information about player, including: name, age, height, weight, position The clubalso needs to ensure that the player cannot sign a contract with two or more other clubs.Information of the club include: ClubID, Name of the club

Clubs also needs to manage number of salary to calculate salary by week or month Each club can only participate one league, but a league can have many clubs

Location of the league depend on countries

Request:

Club need to check market value to have player in their team Otherwise, club can check contract include: start date, end date to guarantee that they can not sign two contracts.Monthly, club need caculate total amount of salary

Club can check information of player

2) MANAGEMENT OBJECTIVES

Manage player and change of player

Manage salary and calculate salary each month

Manage contract for player

Manage market value for player

Important output

Total salary for player each month

Count date of the contract

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II) ENTITY – RELATIONSHIP – ER

1) DIFINITION ENTITY – ATTRIBUTE

Base on the problem description and management objectives, we can present several entities and attributes of the entity as follow:

- Student: StudentID, GuardID, First Name, Last Name, Email, Phone, Gender, Course, Role,

Country

- Register: RoomID, StudentID, Check-In, CheckPrice.

- Room: RoomID , Name Dom, Floor, Location, Number Bed, Gender, Status.

- Fix Detail: RoomID, ItemID, Fixer, Date Report, Date Dix, Quantity.

- Items: ItemID, Name, Content, Price

- Student Penalize: StudentID, PenalizeID, Date, Quantity.

- Penalize: PenalizeID, Name, Price.

- Guard: GuardID, First Name, Last Name, Email, Phone.

- Manager room: RoomID, GuardID, Name Dom, Price

2) SET-UP ENTITY – RELATIONSHIP

* Some symbols used in the model

Key / identifier attribute

Attribute description / description

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Connectivity = N

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LINK: HTTPS://GOO.GL/U4X3JO

III) DATA DICTIONARY

Just for example on some tables (other table are similar, you have to define all the tables in your database) Note: to run the query you have to define the table 1 first then go to the side tables much3/22/2024 DBI202 – DATABASE SYSTEM OF DORM FPT UNIVERSITY 5

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1) DATABASE AND TABLE

A CREATE DATABASE PROJECTDBI202

create database

CREATE DATABASE PROJECTDBI202

B CREATE TABLE GUARD

Column Name Data Type Default Check Key/ Index/ Constraint

First Name Nvarchar(45) Not null

Last name Nvarchar(45) Not null

Email Nvarchar(255) @fpt.edu.vn Not null

Phone Varchar(11) 0 to 9 Unique

Code:

create table guard

CREATE TABLE GUARD(

GuardID INT PRIMARY KEY,

[First Name] NVARCHAR( )45NOT NULL,

[Last Name] NVARCHAR( )45NOT NULL,

Email NVARCHAR(255)CHECK(Email LIKE'%@fpt.edu.vn')NOT NULL,

Phone VARCHAR( )11UNIQUE CHECK(Phone LIKE'[0-9][0-9][0-9][0-9][0-9][0-9]

[0-9][0-9][0-9][0-9]'OR Phone LIKE

'[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]')

)

Example:

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C CREATE TABLE STUDENT

StudentID Varchar(7) SE|SB|HExxxxx PK, Not null

First Name Nvarchar(45) Not null

Last Name Nvarchar(45) Not null

Email Nvarchar(255) @fpt.edu.vn Not null

Gender Char(1) M ‘F’ or ‘M’ Not null

Role Nvarchar(30) Thành

Viên

‘Thành Viên’

or ‘Trưởng Phòng’

Not null

Country Nvarchar(50) VietNam Not Null

Code:

create table student

CREATE TABLE STUDENT(

StudentID VARCHAR( )7PRIMARY KEYNOT NULLCHECK(StudentID LIKE

'SE[0-9][0-9][0-9][0-9][0-9]'OR StudentID LIKE'SB[0-9][0-9][0-9][0-9][0-9]'OR

StudentID LIKE'HE[0-9][0-9][0-9][0-9][0-9]'),

GuardID INT FOREIGN KEY REFERENCES dbo.GUARD GuardID( ),

[First Name] NVARCHAR( )45NOT NULL,

[LastName] NVARCHAR( )45NOT NULL,

Email NVARCHAR(255)CHECK(Email LIKE'%@fpt.edu.vn') NOT NULL,

Phone CHAR( )11UNIQUE CHECK(Phone LIKE'[0-9][0-9][0-9][0-9][0-9][0-9][0-9]

[0-9][0-9][0-9]'OR Phone LIKE

'[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]'),

Gender CHAR( )1 DEFAULT'M'CHECK(Gender IN( ,'F' 'M')) NOT NULL,

Course CHAR( )3 CHECK(Course LIKE'K[0-9][0-9]') NOT NULL,

[Role] NVARCHAR( )30DEFAULTN'Thành Viên'CHECK Role( IN (N'Thành

Viên',N'TrưởAng Phòng'))NOT NULL ,

Country NVARCHAR( )50DEFAULTN'Việt Nam'NOT NULL

SE06155 1 Tù Bùi Anh tubase06155@gmail.co

m

01699271212

ViênViệt NamHE13001 3 Công Lê Thành congltthe13001@fpt.ed 0969981 M K13 Thành Việt 3/22/2024 DBI202 – DATABASE SYSTEM OF DORM FPT UNIVERSITY 7

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SE05627 3 Hiệp Đỗ Quang hiepdq05627/2fpt.edu.

vn

01649088188

PhòngViệt NamSE05740 5 Hòa Phạm Ngọc thaycacac@fpt.edu.vn 0968038

714

PhòngCampuchia

A.)CREATE TABLE ROOM

RoomID Char(5) A|B|C|D|Fxxxxx Primary key

Name Dom Varchar(6) A|B|C|D|F Not null

Location Nvarchar(5) ‘Trái’ or ‘Phải’ Not null

Number Bed Smallint 1 to 12 Not null

Gender Char(1) M ‘F’ or ‘M’ Not null

Status Char(1) 1 ‘1’ or ‘0’ Not null

Code:

create table room

CREATE TABLE ROOM(

RoomID CHAR( )5PRIMARY KEY CHECK(RoomID LIKE'[A-F][1-5][0-9][0-9][0-9]'OR

RoomID LIKE'[A-F][1-5][0-9][0-9][0-9][0-9]'),

[Name Dom] VARCHAR( )6CHECK([Name Dom] IN ( , , ,'A' 'B' 'C' 'D' 'F', )),

[Floor] SMALLINT CHECK([Floor] BETWEEN AND ) NOT NULL , 1 5

[Location] NVARCHAR( )5CHECK Location( IN (N'Trái' N'Pha, Ai')) NOT NULL,

[Number Bed] SMALLINT CHECK([Number Bed] BETWEEN AND 1 12 ) NOT NULL,

Gender CHAR( )1 DEFAULT'M'CHECK(Gender IN( ,'F' 'M')) NOT NULL,

[Status] SMALLINT DEFAULT CHECK Status 1 ( BETWEEN AND ) NOT NULL 0 1

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B CREATE TABLE MANAGER ROOM

RoomID Char(5) A|B|C|D|Fxxxxx FK reference ROOM(RoomID)

GuardID Int FK reference GUARD(GuardID) Not nullName Dom Char(1) A|B|C|D|F Not null

Price Varchar(10) %VND Not null

Code:

create table manager room

CREATE TABLE [MANAGER ROOM](

RoomID CHAR( )5FOREIGN KEY REFERENCES dbo.ROOM RoomID ( )CHECK(RoomID LIKE'[A-F][1-5][0-9][0-9][0-9]'OR RoomID LIKE'[A-F][1-5][0-9][0-9][0-9][0-

9]'),

GuardID INT FOREIGN KEY REFERENCES dbo.GUARD GuardID( )NOTNULL,

[Name Dom] CHAR( )1CHECK([Name Dom] IN ( , , , ,'A' 'B' 'C' 'D' 'F')) NOT NULL,

Price VARCHAR( )10CHECK(Price LIKE'%VND') NOT NULL

C CREATE TABLE REGISTER

RoomID Char(5) A|B|C|D|Fxxxxx FK reference ROOM(RoomID)StudentID Varchar(7) SE|SB|HExxxxx FK reference STUDENT (StudentID)Check-in Datetime < =Getdate() Not null

Check Price Smallint 1 0 or 1 Not null

Code:

create table register

CREATE TABLE REGISTER(

RoomID CHAR( )5FOREIGN KEY REFERENCES dbo.ROOM RoomID ( )CHECK(RoomID LIKE'[A-F][1-5][0-9][0-9][0-9]'OR RoomID LIKE'[A-F][1-5][0-9][0-9][0-9][0-

9]'),

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StudentID VARCHAR( )7FOREIGN KEY REFERENCES dbo.STUDENT StudentID ( )

CHECK(StudentID LIKE'SE[0-9][0-9][0-9][0-9][0-9]'OR StudentID LIKE

'SB[0-9][0-9][0-9][0-9][0-9]'OR StudentID LIKE'HE[0-9][0-9][0-9][0-9][0-9]')

NOT NULL,

[Check-in] DATETIME CHECK([Check-in] <=GETDATE()) NOT NULL,

[Check Price] SMALLINT DEFAULT CHECK( 1 [Check Price] BETWEEN AND ) NOT 0 1

D CREATE TABLE ITEMS

Code:

create table items

CREATE TABLE ITEMS(

ItemID INT PRIMARY KEYNOT NULL,

[Name] NVARCHAR( )50 NOT NULL,

Price INTNOT NULL,

Content NVARCHAR(255)NOT NULL

)

Example:

5 Bóng điện 120000 Bóng đèn LED tuýp T8 N01 60/10W nhựa Rạng

Đông

6 Bình Nóng Lạnh 1800000 Bình nước nóng 30L Aiston AN30RS-MT

7 Toilet 500000 Toilet KOHLER Highline Classic White

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ItemID Name Price Content

3 Giường 3000000 Giường tầng sắt Ký túc xá FPT – Hòa Phát

E CREATE TABLE FIX DETAIL

RoomID Char(5) A|B|C|D|Fxxxxx FK reference ROOM(RoomID)

Fixer Nvarchar(90)

Data report Datetime <= Getdate() Not null

Date Fix Datetime <= Getdate()

Code:

create table fixdetail

CREATE TABLE [FIX DETAIL](

RoomID CHAR( )5CHECK(RoomID LIKE'[A-F][1-5][0-9][0-9][0-9]'OR RoomID LIKE

'[A-F][1-5][0-9][0-9][0-9][0-9]')FOREIGN KEY REFERENCES dbo.ROOM RoomID( ),

ItemID INT FOREIGN KEY REFERENCES dbo.ITEMS ItemID( ),

Fixer NVARCHAR( ),90

[Date Report] DATETIME CHECK([Date Report] <=GETDATE()) NOT NULL,

[Date Fix] DATETIME CHECK([Date Fix]<=GETDATE()),

Quantity INTNOT NULL

F CREATE TABLE PENALIZE

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Code:

create table penalize

CREATE TABLE PENALIZE(

PenalizeID INT PRIMARY KEY,

[Name] NVARCHAR(255)NOT NULL,

Price INTNOT NULL

)

Example:

2 Hút thuốc trong ký túc xá 50000

4 Nuôi động vật trong ký túc xá 500000

G CREATE TABLE STUDENT PENALIZE

StudentID Varchar(7) SE|SB|HExxxxx FK reference

STUDENT(StudentID)

PENALIZE(PenalizeID)Date Datetime <= Getdate() Not null

Code:

create table student penalize

CREATE TABLE [STUDENT PENALIZE](

StudentID VARCHAR( )7CHECK(StudentID LIKE'SE[0-9][0-9][0-9][0-9][0-9]'OR

StudentID LIKE'SB[0-9][0-9][0-9][0-9][0-9]'OR StudentID LIKE

'HE[0-9][0-9][0-9][0-9][0-9]')FOREIGN KEY REFERENCES dbo.STUDENT StudentID( ),

PenalizeID INT FOREIGN KEY REFERENCES dbo.PENALIZE PenalizeID( ),

[Date] DATETIMENOT NULLCHECK Date( <=GETDATE()),

Quantity SMALLINT DEFAULT 1 NOT NULL

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StudentIDPenalizeID Date Quantity

IV ENTITY RELATIONSHIP DIAGRAM (ERD)

A GUARD

This is the Guard entity, the root of whole

diagram Tournament entity has 5

attributes

The attribute GuardID also is the primary

key of this entity Each guard has Name

and contact Name is FirstName and

LastName Guard’s contact is Email and

Phone

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B STUDENT

This is the Student entity This has 10

attributes

Each student have StudentID is Primary

key Contaxt of Student has Phone number

as Phone, Email Student’s Information has

FirstName, LastName Role, Country,

Gender, Course Last, each Student is

Guarded by Guards so this have GuardID is

foriegn key

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C PANALIZE

Student could violate the rule do need

have Penalize Entity It Know as Name of

rule be violate PenalizeID is Primary key

to insert to database The last, Price is

penaties

D ROOM

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Room entity have 7 attributes.

To find this ROOM need information is

NameDom, Floor, Location of room Gender

to know gender of Student this room, Check

NumberBed to know Number of Student

this Room Status as (Full or not), The Last,

RoomID to insert to database

E ITEMS

Each Student as a room hava many ITEM so this is ITEM entity

ITEM has 3 attributes This is ItemID is Primary key to mark many the same Items in different room, Name of Item and Content as (need fix or not)

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F 3 NORMAL FORM

Because, the DomName and Floor can get by RoomID (ex: a room’s name A207 A207the first word mean this room from DomA A207 the first number mean this room from secondFloor) We can get Gender of each room by Student’s gender So we can drop entities to get 3NF

G FULL DIAGRAM

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V SQL COMMAND

I using Microsoft SQL Server 2016, this server build intelligent, mission-critical applications using

a scalable, hybrid database platform that has everything built in—from in-memory performance and advanced security to in-database analytics

A QUERY USING ORDER BY

B QUERY USING INNER JOIN

Code:

select s.PlayerID, s.Name , c.CountryID

from Players s inner join Countries c on c.CountryID = s.CountryID

where c.CountryID = 6

Result:

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In this query, we use INNER JOIN

command to find out who is the Players

have country is ‘Argentina’ Focus on

details, we inner join Player table with

Country table, choose the rows adapts

condition that the CountryID must equal to

number written Then we select columns

PlayerID and Name from Players table

and Check Country from Country table

where the CountryID is equal to 6

C QUERY USING AGGREGATE FUNCTIONS

Code:

select c.ClubID , c.Name , sum(p.MarketValue) as 'TotalClubValues'

from Players p , Clubs c

where c.ClubID = p.ClubID

and c.ClubID = 3

group by c.ClubID , c.Name

Result:

This is query to count total player’s values of a club name ‘Bayern Munich’ We need

to use function Sum() with parameter is MarketValue and condition is clubID = 3 or c.Name =

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Shows another example of query using aggregate functions, which is TOP command.

We use this command to find out top of two Players in Players table and sort them by the

from Players p , Clubs c

where p.ClubID = c.ClubID

group by c.ClubID , c.Name

having sum(p.MarketValue) >= all (

select sum(p1.MarketValue)

from Players p1 , Clubs c1

where p1.ClubID = c1.ClubID

group by c1.ClubID , c1.Name

)

Result:

This SQL query selects the ClubID, Name, and total market value of clubs along with their players It groups the results by ClubID and Name, calculating the total market value for each club Then, it display clubs whose total market value is greater than or equal to the total market value of all clubs

E QUERY THAT USES A SUB-QUERY AS A RELATION

Code:

select p.PlayerID, p.Name

from Players p , Leagues l , Clubs c

where p.ClubID = c.ClubID

Tiêu đề	Database System of Dorm
Tác giả	Nguyễn Trần Việt Hưng, Đặng Hải Ninh, Trần Trung Hiếu
Trường học	Fpt University
Chuyên ngành	Database System
Thể loại	assignment
Năm xuất bản	2024

Định dạng
Số trang	26
Dung lượng	2,2 MB