Báo cáo hóa (1)

Experiment Prelaboratory Assessment Identification of a compond: chemical properties a) when we say clean glassware its criterion is that it obtained no any lingering chemical that would be developed in the outcomes of a certain experiment b) In regards with the figure show we could see that the size of a small clean test tube will be “ 75mm for the smallest 150mm for the smallest and also 200mm for the the bigger one When it come to the measure of each volume we have the volume at 3ml the smallest 55ml for the smaller one and also we have 70ml for the bigger one To smell the odor you place your hand above the test tube and wave in a circular motion so the air goes towards your face Five observations that indicate that a reaction occurred are change in odor, change in color, appearing or disappearing precipitate, heat evolving or being absorbed, and gas evolving experimental procedure part A.1 referring to appendix G for the substances listed here underline those that are soluble and circle those that are insoluble AgNO3 NaCl AgCl Na2CO3 Ag2vCO3 MgSO4 Ag2SO4 Ionic compound NaCl Na2CO3 MgSO4 NH4Cl a) element Na+ Na+ Mg2+ NH4+ element ClCO32SO42Cl- NH4Cl - Test tube : AgNO3 - Test tube 2: Na2S - Test tube 3: KI b) AgNO3 +KI AgI + KNO3 c) Na2S + 2AgNO3 Ag2S + 2NaNO3  REPORT A Chemical properties of know compounds Test NaCl Na2CO3 MgSO4 NH4Cl AgNO3 Light yellow precipit ate Clear Faint cloudy NaOH Cloudy at bottom white Clear HCL Clear Clear, bubbles CO2 White Clear cloudy precipit ate Ammoni Clear a gas(NH3 ) Clear Clear White cloudy on bottom Clear H2O Write formulas Part a.1: AgCl Ag2CO3 Ag2SO4 AgCl no reaction Part a.2 : no reaction no reaction Mg(OH)2 NH3 no reaction Part a.3 : no reaction CO2 no reaction no reaction no reaction -Sample no of unknown solution part : Y is AgNO -Compound in unknown solution: silver nitrate -Results and discussion: In this experiment we were testing to see compounds react with other compounds We tested different compounds with each other to record a visual reaction As you can tell through our datasome of the experiments did not have a reaction This is normal because some compounds not react with each other For each reaction we created a chemical equation to visualize what actually happened When we tested AgNO3 with NaCl we saw precipitate form in a cloudy white substance When AgNO3 reacted with Na2CO3 the results were that a pale brownish yellow substance appeared This reaction produced NaNO3 + Ag2CO3 When AgNO3 reacted with MgSO4 it formed a faint cloudy precipitate - In this experiment we were testing to see compounds react with other compounds We tested different compounds with each other to record a visual reaction As you can tell through our data some of the experiments did not have a reaction This is normal because some compounds not react with each other For each reaction we created a chemical equation to visualize what actually happened When we tested AgNO3 with NaCl we saw precipitate form in a cloudy white substance When AgNO3 reacted with Na2CO3 the results were that a pale brownish yellow substance appeared This reaction produced NaNO3 + Ag2CO3 When AgNO3 reacted with MgSO4 it formed a faint clou B chemical properties of unknown compound Soluti on no Na2CO3 (1) NaCl (2) NH4Cl (3) MgSO4 (4) H2O (5) Reage No No Ammoni Cloudy No nt reaction reaction a gas reacti A( Na (NH3) on OH ) Reage Light White White White No nt B yellow precipit precipit precipit reacti (AgNO precipit ate ate ate on ate 3) Reage Bubbly No No No No nt C reaction reaction reaction reacti ( HCl) on LABORATORY QUESTIONS Identify a chemical reagent used in this experiment that can be used to distinguish solid CaCl2 (soluble) from solid CaCO3 (insoluble) What is the distinguishing observation? -The chemical reagent used in this experiment that would distinguish CaCl2 from CaCO3 would be HCl If HCl is added to CaCO3 it will fit and if added to CaCl2 it would not The distinguishing observation would be whether the substance fizzed which indicated the creation of gas What test reagent used in this experiment will distinguish a soluble Cl– salt from a soluble SO42– salt? What is the distinguishing observation? -Silver nitrate can be used to distinguish between a soluble Cl- salt from a soluble SO42– salt Cl- will form a white precipitate and SO42– will form clear crystals Predict what would be observed (and why) from an aqueous mixture for each of the following (all substances are water soluble) a Potassium carbonate and hydrochloric acid -By mixing the two we get potassium chloride CO and water will also be present but no precipitate will form b Zinc chloride and silver nitrate - By mixing zinc chloride and silver nitrate we will get zinc nitrate and silver chloride The silver chloride will form a precipitate because it is not soluble in water c Magnesium chloride and sodium hydroxide - By mixing magnesium chloride and sodium hydroxide, we would get magnesium hydroxide and sodium chloride Since magnesium hydroxide is insoluble it will produce a precipitate d Ammonium nitrate and sodium hydroxide -By mixing ammonium nitrate and sodium hydroxide we get sodium nitrate, ammonia, and water No precipitate would form in this situation because they are all soluble Three colorless solutions in test tubes, with no labels, are in the test tube rack on the lab bench Lying beside the test tubes are three labels: silver nitrate, AgNO3; hydrochloric acid, HCl; and sodium carbonate, Na2CO3 You are to place the labels on the test tubes using only the three solutions present Here is your analysis prodedure: • A portion of test tube added to a portion of test tube produces CO2 • A portion of test tube added to a portion of test tube produces a white silver carbonate precipitate a On the basis of your observations, how would you label the three test tubes? Test tube 1: HCl Test tube 2: Na2CO3 Test tube 3: AgNO3 b What would you expect to happen if a portion of test tube is added to a portion of test tube 3? - If we mixed a portion of test tube and test tube then we would get AgCl, this will form a precipitate because it is insoluble For individual solutions of the cations Ag + , Ba2+ , Mg2+, and Cu2+ the following experimental observations were collected NH3 HCl H2SO4 a Ag No change White ppt No change 2+ Ba No change No change White ppt 2+ Mg White ppt No change No change 2+ Cu Blue No change No change ppt/deep blue soln with excess From these experimental observations, a Identify a reagent that distinguishes the chemical properties of Ag+ and Mg2+ What is the distinguishing observation? -The reagent that distinguishes the chemical properties would be HCl because this forms a precipitate with Ag + forming AgCl If we mix it with Mg+ then we get MgCl2 b Identify a reagent that distinguish the chemical properties of the HCl and the H2SO4 What is the distinguishing observation? -The reagent that distinguishes the chemical properties would be Ag+, when it reacts with HCl we get AgCl which forms a precipitate If mixed with H2SO4 no precipitate forms because it is soluble c Identify a reagent that distinguishes the chemical properties of Ba2+ and Cu2+ What is the distinguishing observation? -The reagent that distinguishes the chemical properties would be NH3, when it reacts with Cu2+ we see a blue + solution form due to its reaction with ammonia When Ba + is mixed with NH3 a reaction will not occur because it is soluble d Identify a reagent that distinguishes the chemical properties of Cu2+ and Mg2+ What is the distinguishing observation? -The reagent that distinguishes the chemical properties would be NH3, when we react it with Cu2+ we get a blue colored solution indicating there was a reaction If we mix it with Mg2+ no reaction would form Three colorless solutions in the test tubes, with no labels, are in a test tube rack on the lab bench Lying beside the test tubes are three labels: 0.10 M Na 2CO3, 0.10 M HCl, and 0.10 M KOH You are to place the labels on the test tubes using only the three solutions present Here are your tests: • A few drops of the solution from the test tube added to a similar volume of the solution in the test tube produces no visible reaction but the solution becomes warm • A few drops of the solution from the test tube added to a similar volume of the solution in test tube produces carbon dioxide gas • Identify the labels for test tubes 1,2, and Test tube 1: 0.10 M HCl Test tube 2: 0.10 M KOH Test tube 3: 0.10 M Na2CO3 ++++observation? " The chemical reagent used in this experiment that would distinguish CaCl2 from CaCO3 would be HCl If HCl is added to CaCO3 it will fit and if added to CaCl2 it would not The distinguishing observation would be whether the substance fizzed which indicated the creation of ga