525 Appendix A Solulioiis to the Exercises Solution 13.8 The locntioii of the poles is the dccidiiig factor (see Sec 13.5) I No poles except at iiiliiiity + finite, KO(‘ : 121 < K No poles r x ( y ) t at the origin + finite, ROC O < 22 0.5 4.I&(?) = infinite, ROC - > 0.3 #? - 0.5 2(.Z 1) &(?) = + finite ROC : O < ~ + ~ + ~ - ~ * -7 Solution 13.9 Because the series a.rc infinite, the iiiverse transform is carried out by sp1it)ting X,,(.) p;i,rt,ial fractions of -: r2[k] = -46[kj - c + (4 - GX-)(-O.~)’E[~] Solution 13.10 R) H , ( Z ) = ( : - ~ ) ( Z ’ ~= + ) = ( : - I ) ( ; :)( ~ + - + j - ; f) -+ I-