Tài liệu Javascript bible Chapter 30 pdf

Tài liệu Javascript bible_ Chapter 30 pdf

Tài liệu Javascript bible_ Chapter 30 pdf

... instantly reveal whether a string contains a substring and even where in the string that 30 30 CHAPTER ✦ ✦ ✦ ✦ In This Chapter What regular expressions are How to use regular expressions for text search ... string is offered as the main string to search. Table 30- 3 shows the positional metacharacters for JavaScript s regular expressions. Table 30- 3 JavaScript Regular Expression P...

Ngày tải lên: 21/12/2013, 05:17

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Tài liệu Javascript bible_ Chapter 16 pdf

Tài liệu Javascript bible_ Chapter 16 pdf

... “Blank Frames” in Chapter 14 for further details about this technique for Navigator 3 and later. Related Items: document.open() ; document.close() ; document.clear() . ✦ ✦ ✦ 301 Chapter 16 ✦ The ... when the user has the monitor set to 16- or 24- bit color settings. 302 Part III ✦ JavaScript Object and Language Reference JavaScript object property names are case-sensitive. This i...

Ngày tải lên: 10/12/2013, 15:15

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Tài liệu Javascript bible_ Chapter 26 pdf

Tài liệu Javascript bible_ Chapter 26 pdf

... ways in which JavaScript enables scripters to manipulate strings. Much of the syntax you see in this chapter is identical to that of the Java programming language. Because the scope of JavaScript ... window 26 26 CHAPTER ✦ ✦ ✦ ✦ In This Chapter How to parse and work with text Performing search- and-replace operations Scripted alternatives to text formatting ✦ ✦ ✦ ✦ 546 Part III ✦ J...

Ngày tải lên: 21/12/2013, 05:17

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Tài liệu Javascript bible_ Chapter 29 pdf

Tài liệu Javascript bible_ Chapter 29 pdf

... spreadsheet. In JavaScript, arrays are limited to a table holding one column of data, with as many rows as needed to hold your data. As you have seen in many chapters in Part III, a JavaScript- enabled ... applications (Chapter 48) on the CD-ROM, I show you an extended version of this usage in a page that lets users search a small table of data for a match 29 29 CHAPTER ✦ ✦ ✦ ✦ In This...

Ngày tải lên: 21/12/2013, 05:17

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Tài liệu Javascript bible_ Chapter 33 pdf

Tài liệu Javascript bible_ Chapter 33 pdf

... key, 33 33 CHAPTER ✦ ✦ ✦ ✦ In This Chapter Event support in different browser generations How to retrieve information from an event The many ways to assign event handlers ✦ ✦ ✦ ✦ 694 Part III ✦ JavaScript ... NAME="display" BGCOLOR="coral" TOP=100 LEFT=240 HEIGHT=250 WIDTH= 330& gt; <A HREF=" ;javascript: void(0)" onClick="return checkCoords(event)&q...

Ngày tải lên: 21/12/2013, 05:17

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Tài liệu Javascript bible_ Chapter 48 pdf

Tài liệu Javascript bible_ Chapter 48 pdf

... of the HTML coming in with the document. 48 48 CHAPTER ✦ ✦ ✦ ✦ In This Chapter Serverless data collection lookup Data-entry validation ✦ ✦ ✦ ✦ 12 JavaScript Applications The kind of data I’m talking ... say you can’t let your JavaScript- enhanced document act as a front end to data files of other types on your server. In fact, Chapter 51 presents an application that uses JavaScript...

Ngày tải lên: 24/01/2014, 10:20

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Tài liệu Physics exercises_solution: Chapter 04 pdf

Tài liệu Physics exercises_solution: Chapter 04 pdf

...  .7.31 N494 )N300(120sin arcsin           Components: Taking the x -direction to be along dog A’s rope, the components of the resultant are N42060cos)N300()N270(  x R ,N8.25960sin)N300( ... here. Geometric: From the law of cosines, the magnitude of the resultant is .N49460cos)N300)(N270(2)N300()N270( 22 R The angle between the resultant and dog A’s rope (the angle op...

Ngày tải lên: 10/12/2013, 12:15

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Tài liệu Physics exercises_solution: Chapter 14 pdf

Tài liệu Physics exercises_solution: Chapter 14 pdf

... 6.1 107.2 103.11 31 3 3 31 a 1 1 a                      ρ ρ r r 14.6: a)   327 30 3 8 3 4 30 sun sun m10412.1 kg1099.1 m1096.6 kg1099.1       π V M D 33 mkg10409.1  b)   317 313 30 3 4 3 4 30 mkg10594.0 m10351.3 kg1099.1 m1000.2 kg1099.1        π D ... and out is the gauge pressure, so N.1027.2N300)m75.0(m )30( )sm80.9()1003.1()( 5223 ...

Ngày tải lên: 10/12/2013, 12:15

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Tài liệu Physics exercises_solution: Chapter 15 pdf

Tài liệu Physics exercises_solution: Chapter 15 pdf

... antinodes, and so Eq. (15.28) is ).cm0 .302 sin())s0.0752sin(()cm85.0(),( πxtπtxy  c) cm.688.0))cm0 .30( cm)(10.52sin()cm0.850( π m/s.00.4)s0750.0()cm30.0(λλb)  Tfv 15.34: )]cos()cos([ 21 ωtkxωtkxAyy ... specified. 15.41: a) The traveling wave is )s]rad[742)m]rad([6.98cosm )30. 2(),( txtxy  srad742andmrad98.6 mm;60.4somm30.2 SW  ωkAA The general equation for a standing wave...

Ngày tải lên: 10/12/2013, 12:15

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Tài liệu Physics exercises_solution: Chapter 17 pdf

Tài liệu Physics exercises_solution: Chapter 17 pdf

... must be converted to Kelvin temperatures, K.500andK 300 21  TT Insertion of the given values yields K )300 -KK)(500molJmol)(29.500.3( Q ))K )300 (K)500)((KmolJ1010.4( 2223   J.1097.1 4  17.101: ... solved for ,1 , 0350.00650.0 0350.00580.0 121 fff     and the lengths are cm7.00cm)0 .30( andcm23.0cm)0 .30( 21  ff 17.88: a) The lost volume, 2.6 L, is the difference b...

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