Tài liệu Javascript bible Chapter 26 pdf

Tài liệu Javascript bible_ Chapter 26 pdf

Tài liệu Javascript bible_ Chapter 26 pdf

... new window 26 26 CHAPTER ✦ ✦ ✦ ✦ In This Chapter How to parse and work with text Performing search- and-replace operations Scripted alternatives to text formatting ✦ ✦ ✦ ✦ 545 Chapter 26 ✦ The ... first letter is zero) Note 564 Part III ✦ JavaScript Object and Language Reference Listing 26- 10: Nested String Methods <HTML> <HEAD> <TITLE>HTML by JavaScript& lt;/T...
Ngày tải lên : 21/12/2013, 05:17
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Tài liệu Javascript bible_ Chapter 16 pdf

Tài liệu Javascript bible_ Chapter 16 pdf

... concatenating string values and nesting strings. A number of JavaScript string object shortcuts facilitate the formatting of text with HTML tags (see Chapter 27 for details). Whether your script should ... difficult-to-track mistake in string concatenation when 298 Part III ✦ JavaScript Object and Language Reference Figure 16-1: The JavaScript object hierarchy A handful of other invisi...
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Tài liệu Javascript bible_ Chapter 29 pdf

Tài liệu Javascript bible_ Chapter 29 pdf

... spreadsheet. In JavaScript, arrays are limited to a table holding one column of data, with as many rows as needed to hold your data. As you have seen in many chapters in Part III, a JavaScript- enabled ... applications (Chapter 48) on the CD-ROM, I show you an extended version of this usage in a page that lets users search a small table of data for a match 29 29 CHAPTER ✦ ✦ ✦ ✦ In This...
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Tài liệu Javascript bible_ Chapter 30 pdf

Tài liệu Javascript bible_ Chapter 30 pdf

... accuracy. Helping the procedure in JavaScript regular expressions is the string.replace() method that has been added to the language with JavaScript 1.2 (see Chapter 26) . The method requires two parameters, ... that 30 30 CHAPTER ✦ ✦ ✦ ✦ In This Chapter What regular expressions are How to use regular expressions for text search and replace How to apply regular expressions to strin...
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Tài liệu Javascript bible_ Chapter 33 pdf

Tài liệu Javascript bible_ Chapter 33 pdf

... key, 33 33 CHAPTER ✦ ✦ ✦ ✦ In This Chapter Event support in different browser generations How to retrieve information from an event The many ways to assign event handlers ✦ ✦ ✦ ✦ 694 Part III ✦ JavaScript ... LANGUAGE=" ;JavaScript1 .2"> function handleDrag(evt) { netscape.security.PrivilegeManager.enablePrivilege("UniversalBrowserRead") var URLArray = evt.data 696...
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Tài liệu Javascript bible_ Chapter 48 pdf

Tài liệu Javascript bible_ Chapter 48 pdf

... of the HTML coming in with the document. 48 48 CHAPTER ✦ ✦ ✦ ✦ In This Chapter Serverless data collection lookup Data-entry validation ✦ ✦ ✦ ✦ 14 JavaScript Applications <! hide from non-scriptable ... 222 ssn[11] = 231 ssn[12] = 236 ssn[13] = 246 ssn[14] = 251 ssn[15] = 260 ssn[16] = 267 ssn[17] = 302 ssn[18] = 317 ssn[19] = 361 13 Chapter 48 ✦ Application: A Lookup Table Figu...
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Tài liệu Physics exercises_solution: Chapter 04 pdf

Tài liệu Physics exercises_solution: Chapter 04 pdf

...  .7.31arctan,N494)N8.259()N420( 420 8.259 22  θR 4.6: a) N10.8)9. 126( cos)N00.6(120cos)N00.9( 21  xx FF N.00.3)9. 126( sin)N00.6(120sin)N00.9( 21  yy FF b) N.8.64N)(3.00N)10.8( 2222  yx RRR 4.7: 2 s/m2.2kg)(60N)132(/ ... the chair, 0 y a so yy maF   gives 037sin  Fmgn N142n 4.28: a) b)  sinmgT  N2790.26sin)s/m80.9)(kg0.65( 2  4.1: a) For the m...
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Tài liệu Physics exercises_solution: Chapter 14 pdf

Tài liệu Physics exercises_solution: Chapter 14 pdf

... result. e) )kgmN10673.6()(,at and,0at 0 22112   RRGmgRrgrg .sm85.9m)10(6.37kg)1099.5( 2262 4  f) ; 2 3 3 4 4 3 3 4 2                             Br A πGBr Ar dr d πG dr dg setting ... gauge pressure, and the net force due to the water and the air is N.1078.1))m15.0()(Pa1052.2( 526  π 14.12: atm.61.9Pa1027.6)m640)(sm80.9)(mkg1000.1( 6233  ρ...
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Tài liệu Physics exercises_solution: Chapter 15 pdf

Tài liệu Physics exercises_solution: Chapter 15 pdf

... 0;0,(i)or ,4 2323222  fπω 15.23: a) 2 22 2 11 rΙrΙ  2222 2112 mW050.0)m3.1m3.4)(mW 026. 0()(  rrΙΙ b) W04.6)mW 026. 0()m3.4(44 222  πΙπrP Energy = J102.2)s3600)(W04.6( 4 Pt 15.24: (a) Hz.118(b)mm.30.2 2 srad742 2   π ω fA ... F, N.148)Hz4.65)(m600.0)(kg104.14(444 232 1 2 1 2   mLfμfLF b) The tension must increase by a factor of ,)( 2 4.65 4.73 and the percent inc...
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Tài liệu Physics exercises_solution: Chapter 17 pdf

Tài liệu Physics exercises_solution: Chapter 17 pdf

... the output; .mW1015.3 26  17.75: Repeating the calculation with W.167givesK 278C0.5K273 s  HT 17.76: The power input will be equal to net H as given in Eq. (17 .26) ; W.1054.4 )K)290(K)3000)((KmW1067.5)(35.0)(m)1050.1(4( ... the temperature. Thus, kg69.0 kgJ102256 J1055.1 3 5    m and the final mass of steam is 0. 026 kg, and of the water, kg.0.419kg.20kg.069kg150....
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