Gas7 2 Stage Compression

... 6.087: Practical Programming in C IAP 20 10 Lab 2: Data compression In-Lab: Wednesday, January 20 , 20 10 Due: Monday, January 25 , 20 10 Overview Assume that the data consists ... {(’a’,0.01),(’b’,0.04),(’c’,0.05),(’d’,0.11),(’e’,0.19),(’f’,0 .20 ),(’g’,0.4)} {(’ab’,0.05),(’c’,0.05),(’d’,0.11),(’e’,0.19),(’f’,0 .20 ),(’g’,0.4)} {(’abc’,0.1),(’d’,0.11),(’e’,0.19),(’f’,0 .20 ),(’g’,0.4)} {(’e’,0.19),(’f’,0 .20 ),(’abcd’,0 .21 ),(’g’,0.4)} ... containing the symbol. 1 1 2 3 4 5 6 7 Consider the following example: Let {(’a’,0.01),(’b’,0.04),(’c’,0.05),(’d’,0.11),(’e’,0.19),(’f’,0 .20 ),(’g’,0.4)} be the exhaustive ...

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Tài liệu Báo cáo khoa học: Differentiation stage-dependent preferred uptake of basolateral (systemic) glutamine into Caco-2 cells results in its accumulation in proteins with a role in cell–cell interaction pptx

... IV75641 2 34 12 13141516 2 1578611 20 21 23 a 24 22 25 101719183031b31c 32 28 27 a 27 b33 29 31a 26 23 b2a132b5a4151487 12 105b5c911b11a13 25 0MW(kDa)1501007537 25 20 15105063b3a95a 32 2apI345678910Fig. ... the Caco -2 proteome, demonstrating a1a1b1383a3b3c3d4a9a9b4b5b5c61c7111415 24 12 10 22 23 a17d1617c17b19a 20 27 17e 28 309c31b31a2b 21 17a1819b 25 23 b 29 26 IIIIII ... 1174 7.8 14.3 20 .9 12. 1 33.4 75.1P14 625 Endoplasmin [precursor] 1081 5.3 15 .2 18.4 4.4 13.8 24 .15 P0 823 8 Heat shock protein HSP 90-beta 22 57 12. 2 12. 2 14.4 2. 6 10.3 24 .0P09 327 Villin 1 NQ6...

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Phương pháp tổ chức công tác Đội thiếu niên tiền phong Hồ Chí Minh phần 2

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Bản lĩnh của người đứng đầu (Phần 2)

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1+1 = nhiều hơn 2

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Sếp ơi, sếp sai rồi! (phần 2)

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2 danh sách các CEO nên xem mỗi sáng

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Đại số tuyến tính bài 2.pdf

... 1.1: Tính định thức cấp n (n  2) sau đây:D =1 2 2 . . . 22 2 2 . . . 22 2 3 . . . 2. . . . . . . . . . . . . . .2 2 2 . . . nBài giải: Nhân dòng (2) với (−1) rồi cộng vào dòng ... . , (n). Ta cóD =1 2 2 . . . 22 2 2 . . . 20 0 1 . . . 0. . . . . . . . . . . . . . .0 0 0 . . . n − 2 (1)=1 2 2 . . . 20 2 2 . . . 20 0 1 . . . 0. . . . . . . ... =sin 2 1sin(α1+ 2) . . . sin(α1+ αn)sin( 2+ α1) sin 2 2) . . . sin( 2+ αn). . . . . . . . . . . .sin(αn+ α1) sin(αn+ 2) . . . sin 2 n5Bài giải: Với n  2 ta có:A =sin 2 1sin(α1+ 2) ...

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Phương pháp biện luận – Thuật hùng biện part 2

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