interchange 4th 1 wb

Ngày tải lên: 20/08/2015, 09:57

... with my thesis ii ABSTRACT The main aim of this minor thesis is to evaluate the reliability of the final Achievement Computer-based MCQs Test for the 4th semester non- English majors at Hanoi University ... undertake this study entitled A study on the reliability of the final achievement Computer-based MCQs Test for the 4...

Ngày tải lên: 10/04/2013, 14:46

... name and title In lieu of professional titles, the Chinese equivalents of “Mr.” and “Mrs.” are used Thus, Wang Jian-Jun can also be called “Mr.” Wang, but never simply Wang and rarely ever Jian-Jun ... people and officials are referred to by their titles and last names Friends and relatives often drop in on one another, but it is more important to make advance arrangements with acquaintances...

Ngày tải lên: 20/08/2013, 10:10

Ngày tải lên: 02/06/2014, 09:28

... 15 in front of class - Listen and copy the title in their - Call on some representatives to repot in front of class notebooks => Lead in the new lesson - Work in pairs to II / Pre Writing : ... answering these questions in - Exchange their front of class 17 - Practice answering writings and correct - Remark and correct mistakes if any mistakes - Read...

Ngày tải lên: 03/07/2014, 21:20

... "How many programming languages have you used? "; cin >> numberOfLanguages; 10 11 12 13 14 15 16 if (numberOfLanguages < 1) cout

Ngày tải lên: 04/07/2014, 05:21

... 14 CHAPTER adiastola group (3 16 ) 14 15 21 17 34 35 26 38 80 31 33 46 59 50 54 55 60 61 57 63 64 65 71 72 73 78 62 68 70 76 74 75 81 79 87 77 81 82 83 84 89 45 56 53 52 51 44 43 67 81 29 41 42 ... group (66 10 1) 30 27 40 49 48 66 28 47 39 punalua 58 group (58–65) 25 23 36 glabriapex group (34–57) 12 16 22 24 18 19 20 32 11 10 13 planitidia group (17 –33) 85 86 88 92 95...

Ngày tải lên: 06/07/2014, 13:20

Ngày tải lên: 01/08/2014, 17:26

... 0.933 0.966 1. 033 1. 067 1. 1 1. 133 1. 167 1. 2 1. 233 1. 267 1. 3 1. 333 1. 367 1. 4 1. 433 1. 466 1. 5 10 4.4 11 8.86 13 2.86 14 6.46 15 9.78 17 2 .18 18 3.98 19 5.04 205 .18 214 .52 223.06 2 31. 2 238 244 .14 249.74 255.08 ... R3 + R4 ) R1 + R2 + R3 + R4 ( R1 + R2 ) φ right = φTOT = R1 + R2 + R3 + R4 (90 .1 + 77.3) 90 .1 + 10 8.3 + 90 .1 + 77.3 φTOT = (90 .1 +...

Ngày tải lên: 05/08/2014, 20:22

... 11 6.3 2. 28° V 27 VR = (3) 11 6.3 -11 5 × 10 0% = 1. 1% 11 5 0.8 PF Leading: VP ′ = VS + Z EQ IS = 11 5∠0° V + ( 0 .14 0 + j 0.5 32 Ω )(8.7∠36.87° A ) VP ′ = 11 3.3 2. 24° V 11 3.3 -11 5 VR = × 10 0% = 1. 5% 11 5 ... 11 5∠0° V + ( 0 .14 0 + j 0.5 32 Ω )(8.7∠ − 36.87° A ) VP ′ = 11 8.8 1. 4° V 11 8.8 -11 5 VR = × 10 0% = 3.3% 11 5 (2) 1. 0 PF: VP ′ = VS + Z EQ I S = 11 5∠0...

Ngày tải lên: 05/08/2014, 20:22

... 19 .9 kV 7.97 kV 200 kVA 2.50 :1 19.9 kV 13 .8 kV 200 kVA 1. 44 :1 Y-∆ 34 .5 kV 7.97 kV 200 kVA 4 .33 :1 ∆-Y 34 .5 kV 13 .8 kV 200 kVA 2.50 :1 ∆-∆ 34 .5 kV 13 .8 kV 34 6 kVA 2.50 :1 open-∆ 19 .9 kV 13 .8 kV 34 6 ... (low-voltage) side is Vbase (15 kV ) = 1. 125 Ω = S base 200 MVA Z base = so REQ = ( 0. 012 ) (1. 125 Ω ) = 0. 0 13 5 Ω X EQ = ( 0.05) (1. 125 Ω ) = 0.05 63 Ω...

Ngày tải lên: 05/08/2014, 20:22

... Load = (0 .47 65∠ − 41 . 6°) (1. 513 + j1 .13 4 ) = 0.9 01 − 4. 7° VLoad = VLoad,puVbase3 = (0.9 01) (48 0 V ) = 43 2 V The power supplied to the load is PLoad,pu = I RLoad = ( 0 .47 65) (1. 513 ) = 0. 344 PLoad ... j0. 040 + 0.00723 + j0. 048 2 + 0. 040 + j 0 .17 0 + 1. 513 + j1 .13 4 Z EQ = 1. 5702 + j1.3922 = 2.099∠ 41 . 6° The resulting current is I= 1 0° = 0 .47 65∠ − 41 . 6° 2....

Ngày tải lên: 05/08/2014, 20:22

... Phase − T / 12 T / 12 3T / 12 5T / 12 7T / 12 9T / 12 11 T / 12 T / 12 3T / 12 5T / 12 7T / 12 9T / 12 11 T / 12 T / 12 c a a b b c c b b c c a a b 88 Conducting SCR (Positive) SCR3 SCR1 SCR1 SCR2 SCR2 ... from R1, the time at which iD(t) reaches IH is t2 = − R2C ln I H R2 (0.00 05 A ) ( 15 00 Ω ) = 5. 5 ms = − ( 0.0 0 15 ) ln 30 V VBO Therefore, the period of the relaxation...

Ngày tải lên: 05/08/2014, 20:22

... below: 11 2 0 .15 Ω j1 .1 Ω IA + EA + - Vφ Z 6. 667 ∠30° - The magnitude of the phase current flowing in this generator is IA = EA 13 77 V 13 77 V = = = 18 6 A RA + jX S + Z 0 .15 + j1 .1 + 6. 667 ∠30° 1. 829 ... A = 12 40∠0° + ( 0 .15 Ω ) (18 6 − 30° A ) + j (1. 1 Ω) (18 6 − 30° A ) E A = 13 77 6. 8° V The resulting phasor diagram is shown below (not to scale): E = 13 77 6. 8...

Ngày tải lên: 05/08/2014, 20:22