... 103 m) 0.39 W 15. 25: I 0.250 W m at r 15. 0 m P 4πr I 4π (15. 0 m) (0.250 W m ) 707 W 15. 26: b) a) The wave form for the given times, respectively, is shown 15. 27: b) 15. 28: a) The wave ... A cos 3π ωt e) See Exercise 15. 12; ωA 0. 315 m s f) From the result of part d , y mm v y 0. 315 m s 15. 48: a) From comparison with Eq 15. 4 , A 0.75 cm, f 125 Hz, T ... (15. 12) 15. 36: a) From Eq (15. 35), f1 b) 10 , 000 Hz 408 Hz 2L FL 2(0.400 m) m (800 N)(0.400 m) =408 Hz (3.00 10 kg ) 24.5, so the 24 th harmonic may be heard, but not the 25 th 15. 37:...