Network Fundamentals – Chapter 4 ppt
... 7) No 10: SEQ = 348 6 + 146 0 = 49 46 No 11: SEQ = 49 46 + 146 0 = 640 6 No 12: ACT = 348 6 (for No. 8) No 13: SEQ = 640 6 + 146 0 = 7866 No 14: ACT = 49 46 (for No. 10) No 15: ACT = 640 6 (for No. 11) No ... –TIMED_WAIT Client enters this state after active close. –ESTABLISHED Client received server's SYN and session is established. –More: http://support.microsoft.com/kb/1379 84...
Ngày tải lên: 05/07/2014, 00:20
... 40 2600 40 45 2900 50 50 3200 2- 64 Handbook 44 - 2007 2. 24. Automatic Weighing Systems Section 2. 24. Automatic Weighing Systems A. Application A.1. - This code applies to devices ... 2. 24. Automatic Weighing Systems Handbook 44 - 2007 N. Notes N.1. Test Requirements for Automatic Weighing Systems. N.1.1. Test Pucks and Packages. (a) Test pucks...
Ngày tải lên: 12/08/2014, 07:22
... given by w = L 11 A + L 12 à, (4. 41) J = L 21 A + L 22 à, (4. 42) with L 12 = L 21 according to Onsagers reciprocal relations. The coefficient L 21 in (4. 42) is responsible for the coupling ... k −1 (˜c B ) eq ,k 2 (˜c B ) eq = k −1 (˜c C ) eq ,k 3 (˜c C ) eq = k −3 (˜c A ) eq . (4. 1.6) Using (4. 1.6) to eliminate k −1 , k −2 ,andk −3 in (4. 1 .4) and (4. 1.5), one obtains w 1 − w 3...
Ngày tải lên: 12/08/2014, 08:22
lubricants and hydraulic fluids Episode 4 ppt
... The low-temperature fluidity of vegetable-based fluids is poor compared to other fluids listed in Table 8-1. However, the pour point of vegetable-based hydraulic fluids and lubricants may be acceptable for ... gears. Spur, helical, and bevel gears have similar load and speed characteristics, and similar requirements for antiscuffing and viscosity. (a) Spur and helical g...
Ngày tải lên: 12/08/2014, 16:20
Optimal Control with Engineering Applications Episode 4 ppt
... Introduction 1 .4 Exercises 1. In all of the optimal control problems stated in this chapter, the control constraint Ω is required to be a time-invariant set in the control space R m . For the control ... equality constraints x − y = 2 and x 2 + y 2 =4. 2 Optimal Control In this chapter, a set of necessary conditions for the optimality of a solution of an optimal control...
Ngày tải lên: 12/08/2014, 16:21
Process Control Systems Episode 4 ppt
... 0 125 -36 P 127r&, 158 220 361 llOTd/T, 127 196 22%,/T, 2 54 540 Process 70 Gain 4. OOsd 0.64rd/r, 4. 80 0.76 6.00 0.95 8.00 1.27 -__ 3.197d 0.517&1 4. 00 0. 64 5.37 0.86 2.867d 0 .45 rJn 4. 00 0. 64 6.79 1.08 Perform- ance, PR/100 m 4 .52sd2/rl 3.65 4. 58 0.9772/71 0.81 0.96 2. ... 0.86 Interacting three-mode _- ? 1 , D 0 0 0 0 __- 0,907d 0. 64 0. 54 ,Controller R...
Ngày tải lên: 12/08/2014, 16:21
ASM Metals Handbook - Desk Edition (ASM_ 1998) Episode 4 pptx
... structural carbon-manganese steels Plate 40 1 0. 24 0.7 0-1 .35 0.1 5- 0.50 0.35 345 50 48 5- 620 7 0- 90 18 Plate 4 0- 65 1 - 2 0. 24 1.0 0-1 .60 0.1 5- 0.50 0.35 345 50 48 5- 620 7 0- 90 18 ASTM ... grade A Plate 100 4 0.18 1.0 0-1 .35 0.1 5- 0.50 . . . 290 42 43 0- 570 6 3- 83 18 ASTM A 662, grade A Plate 4 0- 50...
Ngày tải lên: 13/08/2014, 05:20
Mechanical Engineering-Tribology In Machine Design Episode 4 pptx
... continues rapidly in a direction away from the arrowhead point of origin, increasing in width and length. It is then called spalling. Spalling occurs more often in rolling-element bearings ... so-called inclusion-origin failure. Inclu- 80 Tribology in machine design 3.7.3. Refinement for thermal bulging in the conjunction zone Thermal bulging relates to the fact that fri...
Ngày tải lên: 13/08/2014, 05:21
Membranes for Industrial Wastewater Recovery Episode 4 ppt
... technology 71 ASTM D4692, Standard practice for calculation and adjustment of sulfate scaling salts (CaS 04. SrS 04 and BaS 04) for reverse osmosis. ASTM D4993, Standard practice for calculation ... model for the filtrate flux in crossflow microfiltration of particulate suspensions. Chem. Eng. Commun., 47 , 1-2 7. 15 7-1 8 5. 49 3-500. 2 3 8 5-2 392. 160 ,41 -S0....
Ngày tải lên: 13/08/2014, 05:22
NOISE AND VIBRATION CONTROL Episode 4 pptx
... (lb/ft. 2 ) 48 72 96 120 144 29 32 34 36 36 35 36 36 36 37 36 36 37 37 38 36 38 41 43 44 41 44 45 47 48 45 48 49 50 51 50 52 53 54 55 54 56 57 58 59 58 60 61 62 63 45 48 49 51 52 Table 4- 13. Transmission ... (in.) (Hz) 1 1 1 14 2 31 33 38 41 44 16 63 39 42 44 46 48 125 41 43 46 48 51 250 44 48 51 54 58 500 50 54 57 60 64 1000 56 61 64 66 69 2...
Ngày tải lên: 13/08/2014, 05:22
Vibration Fundamentals Episode 4 ppt
... harmonic of running speed. 07.Mobley.12 Page 1 04 Thursday, February 4, 1999 3:03 PM 1 04 Vibration Fundamentals For example, if the analyzer can provide a 40 0-line FFT, the resolution of a signature ... instability, passing frequencies, and running speed. 06.Mobley.11 Page 94 Thursday, February 4, 1999 2:51 PM 94 Vibration Fundamentals Figure 11.12 Rolls should be unif...
Ngày tải lên: 13/08/2014, 17:20
Vibration Fundamentals Episode 7 pptx
... February 5, 1999 11:25 AM 188 Vibration Fundamentals Figure 16.5 Difference of two signatures. 10.Mobley.15 Page 174 Friday, February 5, 1999 10:38 AM 174 Vibration Fundamentals Figure 15.33 ... the ampli- tude. For example, the vibration amplitude of a centrifugal compressor taken at 100% 10.Mobley.15 Page 177 Friday, February 5, 1999 10:38 AM 177 Failure-Mode Analysis Fig...
Ngày tải lên: 13/08/2014, 17:20
Vibration Fundamentals Episode 9 ppt
... rotating element turning speed may appear to momentarily offer some sig- 19. Mobley.26 Page 2 49 Friday, February 5, 199 9 12:04 PM 2 49 Analysis Setup Rectangular Weighting Option The rectangular option ... Both the number of cables and the average run length create 19. Mobley.26 Page 252 Friday, February 5, 199 9 12:04 PM 252 Vibration Fundamentals more complex criteria. Single...
Ngày tải lên: 13/08/2014, 17:20