Mechanical Engineers Handbook Episode 4 pptx

... 26 9.6± 14 3.9±5.6 10 156 1.00 25 26 97 32 11.5± 14. 8 4. 6±6.0 11.5 1 74 1.05 30 31 109 40 13±16 .4 5.2±6.6 14 201 1.10 35 36.5 1 24 48.5 14. 5±17.2 5.8±6.9 16 212 1.15 40 42 .5 140 57 16±20 6 .4 7.8 18.5 ... 2 14 3 .4 RTR Dyad 215 3.5 TRT Dyad 216 4. Kinetostatics 223 4. 1 Moment of a Force about a Point 223 4. 2 Inertia Force and Inertia Moment 2 24 4.3 Free-Body Diagrams 22...

Ngày tải lên: 13/08/2014, 16:21

... (2 .44 ) may be substituted into Eq. (2 .43 ) to calculate the tangent vector t  x H y H z H k  x H  2 y H  2 z H  2 q X 2X46 From Eqs. (2 .43 ) ... 67 Dynamics The value of s H is given by Eq. (2 .44 ) and the value of s HH is obtained differentiating Eq. (2 .44 ): s HH  r H Á r HH r H Á r H  1a2  r H Á r HH s H X 2X48 The expression...

Ngày tải lên: 13/08/2014, 16:21

... was found by Churchill and Chu [27]: Nu y  0X68  0X67Ra 1a4 y 1  0X492 Pr  9a16 45 4a9 3X 244  Nu y  0X68  0X515Ra 1a4 y Pr  0X72X 3X 245  3.3.5 VERTICAL WALL WITH UNIFORM HEAT FLUX The relations ... facing downwardX Nu  0X54Ra 1a4 L 10 4 ` Ra L ` 10 7  0X15Ra 1a4 L 10 7 ` Ra L ` 10 9 X @ Hot surface facing downwardY or cold surface facing upwardX Nu L  0X27Ra 1a4 L 1...

Ngày tải lên: 13/08/2014, 16:21

... 50X 10X 140  In this case, the conditions (10.127), (10.129) require z  0X636 o n ! 63X5Y 10X 141  but, from Eq. (10 .45 ), o B  1X1o n X 10X 142  It is clear that the condition (10. 140 ) can not ... s PZ Y 10X 143  where s PZ is the overshoot determined by the additional pole and zero. We estimate s PZ as s PZ  0X03X 10X 144  Then s* determined by the main poles will be s*  0X...

Ngày tải lên: 13/08/2014, 16:21

... . . . . . . 41 9 4. 4 Elastic System of Machine-Tool Structure . . . . . . . . . . . . . . . . 43 5 4. 5 Subsystem of the Friction Process. . . . . . . . . . . . . . . . . . . . . 43 7 4. 6 Subsystem ... . . . . . . . . . . . . . . . . . . . . . 44 0 References 44 4 CHAPTER 7 Principles of Heat Transfer Alexandru Morega 1. Heat Transfer Thermodynamics 44 6 1.1 Physical Mechanisms o...

Ngày tải lên: 13/08/2014, 16:21

... the center and Table 1 .4 Variation of Shear Stress t  C V A Distance y 1 0 0.2c 0.4c 0.6c 0.8cc Factor C 1.50 1 .44 1.26 0.96 0. 54 0 Source: J. E. Shigley and C. R. Mischke, Mechanical Engineering ... 139 1.11 Shear Stresses in Beams 140 1.12 Shear Stresses in Rectangular Section Beams 142 1.13 Torsion 143 1. 14 Contact Stresses 147 2. De¯ection and Stiffness 149 2.1 Springs 150...

Ngày tải lên: 13/08/2014, 16:21

... r E ÂF 32 r C 4 À r D ÂF 4  M 4  0Y or k x C À x E y C À y E 0 F 34x F 34y 0                k x C 4 À x E y C 4 À y E 0 F 4x F 4y 0                M 4 k  0X 4X28 Continuing ... F 01x , F 01y , and M are computed from the set of eight equations (4. 19), (4. 20), (4. 21), (4. 22), (4. 23), (4. 24) , (4. 25), and (4. 26). 4. 5 Contour Method An...

Ngày tải lên: 13/08/2014, 16:21

... 40 .5 21.5 34. 5 20.9 48 .0 72.9 105 21.0 32.0 43 .5 24. 5 37.5 49 .8 84. 5 110 23.5 35.0 46 .0 27.5 41 .0 55.0 29 .4 54. 3 85 .4 120 24. 5 37.5 28.5 44 .5 61 .4 100.1 130 29.5 41 .0 33.5 48 .0 71.0 48 .9 69 .4 ... 5.50 8.5 30 3.35 5 .40 8.80 3.60 6.00 8.80 8.30 10.0 35 4. 20 8.50 10.6 4. 75 8.20 11.0 9.30 13.1 40 4. 50 9 .40 12.6 4. 95 9.90 13.2 7.20 11.1 16.5 45 5.80 9.1...

Ngày tải lên: 13/08/2014, 16:21

... is k 4  Gd 4 2 8r 3 n 2 NamX Using the mechanical model shown in Fig. 3 .4, one may ®nd 1 k   1 k 1  1 k 3  k   k 1 k 3 k 1  k 3 1 k   1 k 2  1 k 3  1 4k 4  k   4k 2 k 3 k 4 k 2  ... X 2X 142  If we use the identity sinot  ot sin ot cos ot  cos ot sin otY 2X 143  Eq. (2. 142 ) becomes x 0  1 mo sin ot  t 0 F t cos otdt cos ot  t 0 F t sin otdt !...

Ngày tải lên: 13/08/2014, 16:21

... Heat Diffusion Equation 45 7 2.2 Thermal Conductivity 45 9 2.3 Initial, Boundary, and Interface Conditions 46 1 2 .4 Thermal Resistance 46 3 2.5 Steady Conduction Heat Transfer 46 4 2.6 Heat Transfer from ... Table 4. 5, a  a  b 6 4X73 4 a 3 b 3 X For Fig. 4. 15c, a   k c m HH r   3EI L 3 am r   EIL m r 1X875 a  b ! 2 Y and from position 4 in Tabl...

Ngày tải lên: 13/08/2014, 16:21