Mechanical Engineers Handbook Episode 2 pptx

... write s H r H Á r H  1a2 x H  2 y H  2 z H  2  1a2 X 2X44 The arc length s may be computed with the relation s   a a o x H  2 y H  2 z H  2  1a2 daY 2X45 where a o is the ... 3X28 where V 1 and V 2 are the values of V at the positions r 1 and r 2 . The principle of work and energy would then have the form 1 2 mv 2 1  V 1  1 2 mv 2 2 ...

Ngày tải lên: 13/08/2014, 16:21

... 21 1 3.1 Driver Link 21 2 3 .2 RRR Dyad 21 2 3.3 RRT Dyad 21 4 3.4 RTR Dyad 21 5 3.5 TRT Dyad 21 6 4. Kinetostatics 22 3 4.1 Moment of a Force about a Point 22 3 4 .2 Inertia Force and Inertia Moment 22 4 4.3 ... (kpsi) H B K f 20 22 83 26 9.6±14 3.9±5.6 10 156 1.00 25 26 97 32 11.5±14.8 4.6±6.0 11.5 174 1.05 30 31 109 40 13±16.4 5 .2 6.6 14 20 1 1.10 35 36.5 124 48.5 14.5±1...

Ngày tải lên: 13/08/2014, 16:21

... p 2 at station (2. 2), we obtain p 2  r 2 v 2 1 À v 2 2 p 1  35X2 2 32X2 1X531 2 À 2X 723 2 46Y080  46Y082X798 psfg  320 X018 psigX Because of the elevation at station (3), p 3  p 2  ... number): Ma pA  rL 3 Â L T 2 pL 2  rL 4 V 2 L 2 pL 2  rL 2 V 2 pL 2  rV 2 p X 1X23 Inertia±viscous force ratio (Reynolds number): Ma tA  Ma m dV dy  A...

Ngày tải lên: 13/08/2014, 16:21

... m 1 l 2 1  J 1  m 2 l 2 1  l 2 c 2  2l 1 l c 2 cos q 2 J 2 a 2  a 3  m 2 l 1 l c 2 cos q 2  m 2 l 2 c 2  J 2 a 4  m 2 l 2 c 2  J 2 b 2  b 3  b 1 2  m 2 l 1 l c 2 sin q 2 c 1  ... q 1  m 2 gl c 2 cosq 1  q 2 l 1 cos q 1  c 2  m 2 gl c 2 cosq 1  q 2 Y and m 1 , m 2 , l 1 , l 2 , J 1 , J 2 , l c 1 ,...

Ngày tải lên: 13/08/2014, 16:21

... identities cos 2 a  0X51  cos 2a sin 2 a  0X51 À cos 2a 2 sin a cos a  sin 2aY Eq. (2. 17) becomes I x H x H  I xx  I yy 2  I xx À I yy 2 cos 2a À I xy sin 2aX 2X18 Figure 2. 19 28 Statics Statics Contributors Numbers ... as I x H x H   A y H  2 dA   A Àx sin a  y cos a 2 dA  sin 2 a  A x 2 dA À 2 sin a cos a  A xy dA  cos 2 a  A y 2 dA  I...

Ngày tải lên: 13/08/2014, 16:21

... C 1 x  C 2 2X29 EI y  R 2 2 hx À ai 2 À w 6 hx À ai 3  C 1 2 x 2  C 2 x  C 3 2X30 EIy  R 2 6 hx À ai 3 À w 24 hx À ai 4  C 1 6 x 3  C 2 2 x 2  C 3 x  C 4 X 2X31 Figure 2. 4 Cantilever ... R 2 hx À ai À1 À whx À ai 0 X 2X27 Integrating this equation four times according to Eqs. (2. 15) to (2. 19) yields V  R 2 hx À ai 0 À whx À ai 1  C 1 2X28 M ...

Ngày tải lên: 13/08/2014, 16:21

... r B ÂF in 2  G 2 M in 2  0Y or  F 2 ÁF 32x Àm 2  x C 2 F 12x  0 4X21  F 2 ÁF 32y Àm 2  y C 2 Àm 2 g  F 12y  0 4X 22 k x C À x B y C À y B 0 F 32x F 32y 0                k x C ... C R for the link 2,  M 2 C r B À r C ÂF 12 r C 2 À r C ÂF 2  M 2  0Y or k x B À x C y B À y C 0 F 12x F 12y 0            ...

Ngày tải lên: 13/08/2014, 16:21

... 1. 02 1. 42 1.90 1. 02 1.10 1.88 12 1. 12 1. 42 2.46 1.10 1.54 2. 05 15 1 .22 1.56 3.05 1 .28 1.66 2. 85 17 1. 32 2.70 3.75 1.36 2. 20 3.55 2. 12 3.80 4.90 20 2. 25 3.35 5.30 2. 20 3.05 5.8 3.30 4.40 6 .20 25 ... 17.0 24 .5 13.4 19 .2 29.5 23 .6 44.0 75 12. 2 17.0 25 .5 13.8 20 .0 32. 5 23 .6 45.4 80 14 .2 18.4 28 .0 16.6 22 .5 35.5 17.3 26 .2 51.6 85 15.0 22 .5 3...

Ngày tải lên: 13/08/2014, 16:21

... expression x 2  o 2  p 2 q o 2  p 2  2  4a 2 p 2 sin pt  2apq o 2  p 2  2  4a 2 p 2 cos pt 2X108 or x 2  B 2 sinpt fY 2X109 where B 2   D 2 1  D 2 2 q and ... model a 11  a 3 3EI a 22  l 3 3EI a 12  a 2 2EI 1  a 3  a 11  a 2 1  a 2 3EIl a 22  b 2 l  b 2 3EIl a 12  ab 6EIl l 2  a...

Ngày tải lên: 13/08/2014, 16:21

... A n1  m n1 A 11 A 22  m 22 A 12 Y A 32  m 32 A 12 Y FFFY A n2  m n2 A 12 F F F A 2n  m 2n A 1n Y A 3n  m 3n A 1n Y FFFY A nn  m nn A 1n Y V b b b ` b b b X 3X49 Figure 3 .21 Mechanical model ... obtain q 2  q 1 À F 1 k 1 F 1  F 0  m 1 o 2 q 1 X V ` X But F 0  0, so q 2  q 1 1 À mo 2 ak 1 ÀÁ and q 3  q 2 À F 2 k 2 F 2  F 1  m 2 o 2 q 2 X V...

Ngày tải lên: 13/08/2014, 16:21