Modeling Tools for Environmental Engineers and Scientists Episode 5 docx

... concentration × mass of solids = ΂ 50 0 ᎏ µ g g ᎏ ΃ × (0. 05 g) ΂ ᎏ 10 6 g µg ᎏ ΃ = 0.000 25 g Hence, total mass of chemical in the sample = 0. 25 g + 0.000 25 g = 0. 250 25 g. 4.3 PHASE EQUILIBRIUM The ... Different Forms of Quantifying Phase Contents and the Resulting Forms of Henry’s Constant Multiplication Factors for Converting to Other Forms Gas Phase Aqueous Phase Content...

Ngày tải lên: 13/08/2014, 05:22

... 1063–10 75, 1988. Gottfried, B. S. (2000) Spreadsheet Tools for Engineers, McGraw-Hill Co., New York. Hardisty, J., Taylor, D. M., and Metcalfe, S. E. (1993) Computerised Environmental Modeling A ... Pollutant Transport, Prentice Hall, New Jersey. Clark, M. M. (1996) Transport Modeling for Environmental Engineers and Scientists, John Wiley & Sons, New York. Cutlip, M...

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... Software for Read and Read and Read and Read and Read and Read and Read and developing review review review review review review review mathematical models 8 Modeling of Read and Read and Read and ... and Read and Read and Read and Review of mathematical review review review review modeling 3 Primer on Read and Read and Review Review mathematics review re...

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... the modeling effort. Modeling projects may be launched for various reasons, such as those pointed out in Chapter 1. The scope of the modeling effort will be dictated by the objective(s) and the expectation(s). ... of calibration and validation, let us use an artificial data set (adapted from Thomann and Mueller, 1987): Distance (mi) – 15 –10 5 0 5 10 15 Concentration (mg/L)...

Ngày tải lên: 13/08/2014, 05:22

... cells F 15 and G 15, and filled down to perform the cal- culations automatically for seven steps, in this case: Cell F 15: IF(($C$4-Co*EXP(-k*F14))*($C$4-Co*EXP (-k*H14))<0,F14,H14) Cell G 15: IF(($C$4-Co*EXP(-k*G14))*($C$4-Co*EXP (-k*H14))<0,G14,H14) As ... foundation. The advantage of reducing the formulations to standard mathematical forms has been pointed out before. For m...

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... HRT for Overall One Two Three One Efficiency CMFR CMFRs CMFRs PFR 75% 30.0 20.0 17.6 13.9 80% 40.0 24.7 21.3 16.1 85% 56 .7 31.6 26 .5 19.0 90% 90.0 43.2 34.6 23.0 95% 190.0 69.4 51 .4 30.0 5. 4 MODELING ... time for removal efficiencies of 75, 80, 85, 90, and 95% . Solution The HRT for a first-order process in a CMFR to achieve a removal effi- ciency of η can be found by rea...

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... nitrite. • MB equation for nitrite + nitrate (C 5 ) in a segment of volume V: V ᎏ d d C t 5 ᎏ = J(C 5 ) – Va 1 ,5 G P C 1 – VK N C 4 ϩ W 5 (6 .51 ) • MB equation for organic phosphorous (C 6 ) in a segment ... k ΃΅ (6. 45) Chapter 06 11/9/01 9:32 AM Page 154 © 2002 by CRC Press LLC 6 .5 Consider the stream and potential functions for a source, a sink, and uni- form flow...

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... Ex 3-2; Ex 3-4; Ex 3 -5; Ex 5- 3; Ex 6-2; § 7 .5. 1 § 7 .5. 1; Ex 8-6; Ex 9-11 TK Solver Ex 8 -5; Ex 8-9; § 7 .5. 5; Ex 8-4 Ex 9-6; Ex 9-11 Mathcad ® § 6.3.4; Ex 6 -5; Ex 8-1; § 7 .5. 2; Ex 8-4 Ex 8-1; ... substitution beforehand. PDEs can be handled efficiently by Mathematica ® and MATLAB ® but with fairly bulky models in the others. Examples of the use of spread- sheets for solving s...

Ngày tải lên: 13/08/2014, 05:22

... (11.0, 100), (12.0, 1 25) , (13.0, 142), (14.0, 150 ) ( 15. 0, 50 .0), (16.0, 50 .0), (17.0, 50 .0), (18.0, 50 .0), (19.0, 50 .0), (20.0, 50 .0), (21.0, 50 .0), (22.0, 50 .0), (23.0, 50 .0), (24.0, 50 .0) CToxicantln ... (Toxicant< 25) then 3/24 else 0 CBODin = GRAPH(TIME) (0.00, 50 .0), (1.00, 50 .0), (2.00, 50 .0), (3.00, 50 .0), (4.00, 50 .0) (5. 00, 50 .0), (6.00, 50 ....

Ngày tải lên: 13/08/2014, 05:22

... C 1 and C 2 are the concentrations of cesium in the water column and the sediment waters, V 1 and V 2 are the volumes of water column and sedi- ment, W c and W s are the input rates of cesium and ... Page 279 © 2002 by CRC Press LLC two- and three-dimensional graphs and animations to visualize the results for better understanding. For example, Plot3D routine and the Cont...

Ngày tải lên: 13/08/2014, 05:22