SOIL MECHANICS - CHAPTER 8 ppt
... solution (8. 9) with respect to z. This gives q z = − kH π x x 2 + z 2 . (8. 10) Arnold Verruijt, Soil Mechanics : 8. GROUNDWATER FLOW 52 where γ s is the volumetric weight of the saturated soil (about ... stress reaches zero, anywhere in the soil. Such a situation should be avoided, even if it seem s to be costly. Arnold Verruijt, Soil Mechanics : 8. GROUNDWATER FLOW 54 8. 3 Fl...
Ngày tải lên: 05/08/2014, 23:24
SOIL MECHANICS - CHAPTER 2 pptx
... the case of Figure 2.1 this is about 8. 5. This indicates that the soil is not uniform. This is sometimes denoted as a well graded soil. In a poorly graded soil the particles all have about the ... Verruijt, Soil Mechanics : 2. CLASSIFICATION 16 2.4 Consistency limits For very fine soils, such as silt and clay, the consistency is an important property. It determines whether the soil...
Ngày tải lên: 05/08/2014, 23:24
SOIL MECHANICS - CHAPTER 4 ppt
... wall. The container at Arnold Verruijt, Soil Mechanics : 4. STRESSES IN SOILS 29 Calculating the effective stresses in soils is one of the main problems of soil mechanics. The effective stresses are ... stress. Arnold Verruijt, Soil Mechanics : 4. STRESSES IN SOILS 27 the extreme right in Figure 4.3 resembles a soil body, with its pore space. It can be concluded that the water in a...
Ngày tải lên: 05/08/2014, 23:24
Soil mechanics - Chapter 17 ppt
... Verruijt, Soil Mechanics : 17. NUMERICAL SOLUTION 106 x t = 0 t = ∆t t = 2∆t t = 3∆t t = 4∆t 1.0 0.000 0.000 0.000 0.000 0.000 0.9 1.000 0.750 0.625 0.547 0.492 0 .8 1.000 1.000 0.937 0 .87 5 0 .82 0 0.7 ... "Time step ";DT 180 A=C*DT/(DZ*DZ):FOR I=0 TO N:P(I)=1:NEXT I:P(N)=0 190 U=1:T=T+DT:FOR I=1 TO N-1:PA(I)=P(I)+A*(P(I+1 )-2 *P(I)+P(I-1)) 200 NEXT I:PA(0)=P(0)+A*(P(1 )-...
Ngày tải lên: 05/08/2014, 23:24
SOIL MECHANICS - CHAPTER 28 ppt
... y 2 + z 2 . ( 28. 6) The solution for the displacements is u r = P (1 + ν) 2πER [ r 2 z R 3 − (1 − 2ν)(1 − z R )], ( 28. 7) u θ = 0, ( 28. 8) u z = P (1 + ν) 2πER [2(1 − ν) + z 2 R 2 ]. ( 28. 9) 160 Arnold ... 2ν) 1 R(R + z) ], ( 28. 2) σ θθ = P 2π 1 − 2ν R 2 ( R R + z − z R ), ( 28. 3) σ rz = 3P 2π rz 2 R 5 . ( 28. 4) In these equations r is the cylindrical coordinate, r = x 2 + y 2 , ( 28...
Ngày tải lên: 06/08/2014, 01:20
SOIL MECHANICS - CHAPTER 30 pptx
... (30.7) and (30 .8) can also be written as x = 0 : σ zz = 2p π [arctan( a z ) + az a 2 + z 2 ], (30.10) x = 0 : σ xx = 2p π [arctan( a z ) − az a 2 + z 2 ]. (30.11) Chapter 30 FLAMANT In 189 2 Flamant ... θ 1 cos θ 1 + sin θ 2 cos θ 2 ], (30.5) σ xz = p π [cos 2 θ 2 − cos 2 θ 1 ]. (30.6) 1 68 Arnold Verruijt, Soil Mechanics : 30. FLAMANT 170 . . . . . . . . . . . . . . . . . . . . . ....
Ngày tải lên: 06/08/2014, 01:20
... paper and making copies for one another. 96 18$ $ $CH8 0 9-0 6-0 2 15:00: 08 PS 2 08 Preparing for the Project Management Professional Certification Exam Figure 8- 8 . Network communications circle: Free and ... chain of command. The strict chain of command is required be- 96 18$ $ $CH8 0 9-0 6-0 2 14:59: 58 PS 197Communications Management Figure 8- 2 . Communications model. Loo...
Ngày tải lên: 24/12/2013, 12:16
... 'long de sho' som'ers 'bove de town, but dey wuz people a-stirring yit, so I hid in de ole tumble- down cooper-shop on de bank to wait for everybody to go 'way. Well, I wuz dah ... en he pay me thirty-five at de en' er de year. "So I done it. Den I reck'n'd I'd inves' de thirty-five dollars right off en keep things a-movin'. Dey...
Ngày tải lên: 24/12/2013, 16:15
Tài liệu Javascript bible_ Chapter 8 pptx
... whatever text you pass as a parameter (see Figure 8- 2 ). A single OK button (which cannot be changed) lets the user dismiss the alert. Figure 8- 2 : A JavaScript alert dialog box The appearance ... window. If you need to access one of its properties or methods, you must use that reference 89 Chapter 8 ✦ Window and Document Objects </FORM> </BODY> </HTML> Window Prop...
Ngày tải lên: 24/01/2014, 09:20
A Practical Guide to Particle Counting for Drinking Water Treatment - Chapter 8 ppt
... L1306/frame/pt02 Page 88 Friday, June 23, 2000 1:54 PM © 2001 by CRC Press LLC PARTICLE COUNTER ELECTRONICS 91 1 5 9 13 17 21 25 29 33 37 41 45 49 53 57 61 65 69 73 77 81 85 89 93 97 101 105 109 113 117 121 125 129 133 137 Counts 1000 900 80 0 700 600 500 400 300 200 100 0 Pulse ... Figure 8. 1 Comparator counting method. Particle pulses counted and sorted by amplitude. Picture...
Ngày tải lên: 18/06/2014, 19:20