Fundamentals Of Structural Analysis Episode 1 Part 8 pot

... displaced configuration of the frame as shown below. Displaced configuration. P 2P 2P P 1 2 2 1 1 1/ L1/L 1 1/L 1/ L 1 1 2PL 2L 1 1 2L 2L P Beam and Frame Analysis: Force Method, Part II by S. T. Mau 14 6 Example 21. ... ∆ d Load Diagram Moment Diagram (M)(m)(m)(m)(m) a~b EI 1 ( 3 1 ) (2PL)(2L)(2L) = EI PL 3 8 3 00 EI 1 ( 3 1 ) (2PL)(2L)(2L) = EI PL 3 8 3 b~c EI...

Ngày tải lên: 05/08/2014, 11:20

... displaced configuration of the frame as shown below. Displaced configuration. P 2P 2P P 1 2 2 1 1 1/ L1/L 1 1/L 1/ L 1 1 2PL 2L 1 1 2L 2L P Beam and Frame Analysis: Force Method, Part II by S. T. Mau 14 0 The computing ... ∆ d Load Diagram Moment Diagram (M)(m)(m)(m)(m) a~b EI 1 ( 3 1 ) (2PL)(2L)(2L) = EI PL 3 8 3 00 EI 1 ( 3 1 ) (2PL)(2L)(2L) = EI PL 3 8 3 b~c...

Ngày tải lên: 05/08/2014, 09:20

... beginning of the last section now becomes ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦ ⎤ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ ⎡ −− −− −−− −−− −− −−− 8 .12 6. 98 .12 6.900 6 .19 9.236.92.706 .16 8 .12 6.96.25 08 .12 6.9 6.92.704 .14 6.92.7 0 08 .12 6. 98 .12 6.9 06 .16 6.92.76.99.23 ⎪ ⎪ ⎪ ⎪ ⎭ ⎪ ⎪ ⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎪ ⎪ ⎩ ⎪ ⎪ ⎪ ⎪ ⎨ ⎧ 0 0 0 3 2 2 u v u = ⎪ ⎪ ⎪ ⎪ ⎭ ⎪ ⎪ ⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎪ ⎪ ⎩ ⎪ ⎪ ⎪ ⎪ ⎨ ⎧ − 3 1 1 0 0 .1 5.0 y y x P P P Note ....

Ngày tải lên: 05/08/2014, 09:20

... Frame Analysis: Force Method, Part I by S. T. Mau 11 9 (11 ) (12 ) (13 ) (14 ) (15 ) (16 ) Problem 2. Frame problems. 5 m 5 m 10 kN 5 m 5 m 10 kN-m 5 m 5 m 10 kN 5 m 5 m 10 kN-m 5 m 5 m 10 kN 5 m 5 m 10 ... Frame Analysis: Force Method, Part I by S. T. Mau 11 7 Thrust, shear, and moment diagrams of the example problem. 60 kN 48 kN 36 kN 15 kN 12 kN 9 kN 7.2 kN/m 9.6 kN/...

Ngày tải lên: 05/08/2014, 11:20

... is: ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦ ⎤ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ ⎡ −− −− −−− −−− −− −−− 8 .12 6. 98 .12 6.900 6 .19 9.236.92.706 .16 8 .12 6.96.25 08 .12 6.9 6.92.704 .14 6.92.7 0 08 .12 6. 98 .12 6.9 06 .16 6.92.76.99.23 ⎪ ⎪ ⎪ ⎪ ⎭ ⎪ ⎪ ⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎪ ⎪ ⎩ ⎪ ⎪ ⎪ ⎪ ⎨ ⎧ 3 3 2 2 1 1 v u v u v u = ⎪ ⎪ ⎪ ⎪ ⎭ ⎪ ⎪ ⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎪ ⎪ ⎩ ⎪ ⎪ ⎪ ⎪ ⎨ ⎧ 3 3 2 2 1 1 y x y x y x P P P P P P where ... as ⎪ ⎪ ⎭ ⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎩ ⎪...

Ngày tải lên: 05/08/2014, 09:20

... is: ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦ ⎤ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ ⎡ −− −− −−− −−− −− −−− 8 .12 6. 98 .12 6.900 6 .19 9.236.92.706 .16 8 .12 6.96.25 08 .12 6.9 6.92.704 .14 6.92.7 0 08 .12 6. 98 .12 6.9 06 .16 6.92.76.99.23 ⎪ ⎪ ⎪ ⎪ ⎭ ⎪ ⎪ ⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎪ ⎪ ⎩ ⎪ ⎪ ⎪ ⎪ ⎨ ⎧ 3 3 2 2 1 1 v u v u v u = ⎪ ⎪ ⎪ ⎪ ⎭ ⎪ ⎪ ⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎪ ⎪ ⎩ ⎪ ⎪ ⎪ ⎪ ⎨ ⎧ 3 3 2 2 1 1 y x y x y x P P P P P P where ... as ⎪ ⎪ ⎭ ⎪ ⎪ ⎬ ⎫ ⎪ ⎪ ⎩ ⎪...

Ngày tải lên: 05/08/2014, 09:20

... joint. 4 F 6 F 3 F 2 3 5 4 3 4 5 1 F 3 F 1 R y1 R x1 3 4 5 F 4 F 2 R y5 5 R x5 3 5 4 10 kN 3@2m=6m 1 3 2 4 5 6 7 1 2 3 5 6 7 8 10 11 2m 9 4 Truss Analysis: Force Method, Part I by S. T. Mau 43 Problem 1. Use the method of joint ... m 5kN 1. 2 m 1m 1m 1 kN 2 m2 m 1m 1m 2 kN 2 m2 m 1m 1m 2 kN 1 kN Truss Analysis: Force Method, Part I by S. T. Mau 49 This particular c...

Ngày tải lên: 05/08/2014, 09:20

... forces. ΣM E =0, (12 ) 8 – (3) 16 – (8) F GJ =0 F GJ = 6 kN. ΣM G =0, (12 ) 8 – (3) 16 + (8) F EH =0 F EH = −6 kN. B D 8 kN C A F EH E H G F GJ J 8m 6m 16 kN 8 kN J H E G F EH F GJ 8m 3m 9m Truss Analysis: ... joint. 4 F 6 F 3 F 2 3 5 4 3 4 5 1 F 3 F 1 R y1 R x1 3 4 5 F 4 F 2 R y5 5 R x5 3 5 4 10 kN 3@2m=6m 1 3 2 4 5 6 7 1 2 3 5 6 7 8 10 11 2m 9 4 Truss Analysis...

Ngày tải lên: 05/08/2014, 09:20

... form: x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 1 kN 1 kN 1 kN 1 kN 1 kN 1 kN Truss Analysis: ... Entry Member Number Force Number 2i -1 Coeff. 2i Coeff. 2j -1 Coeff. 2j Coeff. 11 1 −0.6 2 −0 .8 3 0.6 4 0 .8 223 −0.6 4 0 .8 5 0.6 6 −0 .8 3 31...

Ngày tải lên: 05/08/2014, 09:20

... form: x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 x y 1 2 4m 3m 3 3m 1 2 3 1 kN 1 kN 1 kN 1 kN 1 kN 1 kN Truss Analysis: Force ... equation. Contribution of Member Forces Equation Number and Value of Entry Member Number Force Number 2i -1 Coeff. 2i Coeff. 2j -1 Coeff. 2j...

Ngày tải lên: 05/08/2014, 09:20