... = 0; 2 F 2 ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ 2 W 2 ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ − 0= FW= F 175lb= Man: + ↑ Σ F y = 0; N C W− 2 F 2 ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ − 0= N C WF+= N C 350 lb= b() Bar: + ↑ Σ F y = 0; 2 W 4 ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ 2 F 2 − 0= F W 2 = ... lb= W 2 30 lb= Solution: (a) Bar: + ↑ Σ F y = 0; 2 F 2 W 1 W 2 + () − 0= FW 1 W 2 += F 20 5lb= Man: + ↑ Σ F y = 0; N C W 1 − 2 F 2 − 0= N C FW 1 += N C 380lb=...
Ngày tải lên: 21/07/2014, 17:20
... /kWh) 1 ⁄ 4 100 ϫ 1 ⁄ 4 ϭ 25 50 ⁄ 25 ϩ 9 .5 ϭ 11 .5 (5 .22 ) 2 ⁄ 4 100 ϫ 2 ⁄ 4 ϭ 50 50 ⁄ 50 ϩ 9 .5 ϭ 10 .5 (4.77) 3 ⁄ 4 100 ϫ 3 ⁄ 4 ϭ 75 50 ⁄ 75 ϩ 9 .5 ϭ 10.17 (4. 62) 4 ⁄ 4 100 ϫ 4 ⁄ 4 ϭ 100 50 ⁄ 100 ϩ 9 .5 ϭ 10.00 (4 .54 ) Related ... fired HRSG Case 7 2 Supp fired HRSG GT output, MW 5. 8 20 .2 20 .2 21.8 15. 5 0 0 ST output, MW 0.9 2. 4 Ϫ 2. 1 Ϫ 13 3.7...
Ngày tải lên: 09/11/2013, 04:15
Handbook of Mechanical Engineering Calculations P2
... loading. Or, U ϭ 58 5(0. 95) ϭ 55 5. Then x ϭ 0.8 12( 55 5/ 50 0) ϭ 0.90; e x ϭ 2. 7183 0.90 ϭ 2. 46; t 2 ϭ 101.1 Ϫ (101.1 Ϫ 85/ 2. 46) ϭ 94.6 Њ F (34.8 Њ C). Check ⌬ t ϭ t s Ϫ t 2 ϭ 101.1 Ϫ 94.6 ϭ 6 .5 Њ F (3.6 Њ C), ... than 5 Њ F (2. 8 Њ C). The cooling-water flow rate, gal /min ϭ 950 ( 25 ,000)/ [50 0(94.6 Ϫ 85) ] ϭ 4 950 gal / min (3 12. 3 L /s). Then A ϭ 0.8 12( 4 950...
Ngày tải lên: 09/11/2013, 04:15
Tài liệu Handbook of Mechanical Engineering Calculations P3 pdf
... burned ϭ 12. 39 /22 .1 ϭ 0 .56 0 lb (0 . 25 2 kg). This, plus the weight of N 2 in the fuel, step 1, is 0 .56 0 ϩ 0.0 0 25 ϭ 0 .5 6 25 lb (0 . 25 3 kg) of N 2 in the products of combustion. Next, find the total weight of ... (10.96 72) (0 .20 )( 359 / 28 . 95) (2. 15) ϭ 58 .5 ft 3 (1. 656 m 3 ). In this calculation the value 28 . 95 is the molecular weight of air. The t...
Ngày tải lên: 17/12/2013, 11:15
Tài liệu Handbook of Mechanical Engineering Calculations P4 pptx
... of HRSG Load, % 25 50 75 100 Steam generation, lb/ h (kg / h) 25 ,000 (11, 350 ) 50 ,000 (22 ,700) 75, 000 (34, 050 ) 100,000 ( 45, 400) Duty, MM Btu/ h (MW) 25 .4 (7.4) 50 .8 (14.9) 76.3 (22 .4) 101.6 (29 .8) Exhaust ... h) 1 52 , 000 (69,008) 153 ,140 (69, 52 6 ) 154 ,330 (70,066) 155 ,57 0 (70, 629 ) Exit gas temperature, Њ F( Њ C) 319 ( 159 ) 28 5 (141) 27 3 (134) 26 9 (1 3...
Ngày tải lên: 17/12/2013, 11:15
Tài liệu Handbook of Mechanical Engineering Calculations P5 pdf
... BWG 5 ⁄ 8 -in (1.6-cm) OD tubes are being used, ID ϭ 0. 6 25 Ϫ 2( thickness) ϭ 0. 6 25 Ϫ 2( 0.049) ϭ 0. 52 7 in (1.3 cm). Then, open area per tube ft 2 ϭ ( d 2 /4)/144 ϭ 0.7 854 (0. 52 7 ) 2 /144 ϭ 0.001 52 5 ... tube sheet ϭ 1 12/ 166 ϭ 0.6 75 ft 2 ,or97in 2 ( 6 25 .8 cm 2 ). The inside diameter of the heater shell ϭ (tube sheet area, in 2 /0.7 854 ) 0 .5 ϭ (97/0.7...
Ngày tải lên: 17/12/2013, 11:15
Tài liệu Handbook of Mechanical Engineering Calculations P6 pdf
... ENGINES INTERNAL-COMBUSTION ENGINES 6.41 35 30 25 20 15 1100 1 050 1000 950 900 850 Horsepower Torque, inch-lb. 1,000 1,400 Speed, rpm 1,800 2, 200 (a) 35 30 25 20 15 950 900 800 Horsepower Torque, inch-lb. 1,000 ... inch-lb. 1,000 1,400 Speed, rpm 1,800 2, 200 (b) SI Values hp kW in lb Nm 15 11 .2 850 96.1 20 14.9 900 101.7 25 18.7 950 107.4 30 22 .4 1000 113.0...
Ngày tải lên: 17/12/2013, 11:15
Tài liệu Handbook of Mechanical Engineering Calculations P7 docx
... gal/min (73.1 L/ s); H p ϭ (1.9 05) 2 (0.3 35) 2 ( 350 ) ϭ 1 42. 5 ft (43.4 m); NPSH p ϭ (1.9 05) 2 (0.3 35) 2 (10) ϭ 4.06 ft (1 .24 m); P p ϭ (1.9 05) 5 (0.3 35) 3 (55 ) ϭ 51 .8 hp (38.6 kW). 3. Compute the ... N s ϭϭ 9 65; S ϭ 0 .5 0. 75 0 .5 350 0 (50 0) /( 350 ) 350 0 (50 0) / ϭ 13,900. For the prototype, N s ϭϭ 9 65; 0. 75 0 .5 0. 75 (10) 1170(1 158 ) /(1 42. 5) S...
Ngày tải lên: 17/12/2013, 11:15
Tài liệu Handbook of Mechanical Engineering Calculations P8 doc
... size, known/new Pressure factor, P 2/ 1 5. 0 92 1 /2 0.0386 3/ 2 2 .58 2/ 3 0. 150 4/ 3 1.919 3/4 0 .27 1 6/ 4 2. 674 4/6 0.1399 8/ 6 1.933 6/8 0 .26 7 10/ 8 1. 726 8/10 0.3 35 12/ 10 1 .5 42 10/ 12 0. 421 When computing such ... diameter of pipe, in (cm). From a table of pipe properties, d ϭ 22 . 626 in (57 4.7 mm). Also, k ϭ z/S ϭ 75/ 0. 85 ϭ 88 .2 cSt. Then R ϭ 31 62(...
Ngày tải lên: 17/12/2013, 11:15
Tài liệu Handbook of Mechanical Engineering Calculations P9 pdf
... operate to within 2. 5 inHg (9.7 kPa) of the barometer, or a vacuum of 29 .8 Ϫ 2. 5 ϭ 27 .3 inHg (1 05. 5 kPa). 2. Compute the quantity of free air removed from the receiver Select a number of absolute pressures ... d ϭ 0 .23 6(100) 0 .5 (0.0) 0 . 25 / (21 4.7) 0 . 25 ϭ 0.60 in (1. 52 cm). Related Calculations. Rupture disks are used in a variety of applications— proce...
Ngày tải lên: 17/12/2013, 11:15