Handbook of Mechanical Engineering Calculations ar Episode 2 Part 4 pot

... works International Standard Book Number 0- 849 3- 84 02- 8 Library of Congress Card Number 98 - 24 46 6 Printed in the United States of America 1 2 3 4 5 6 7 8 9 0

Ngày tải lên: 21/07/2014, 15:20

... 7 2 Supp fired HRSG GT output, MW 5.8 20 .2 20 .2 21.8 15.5 0 0 ST output, MW 0.9 2. 4 Ϫ 2. 1 Ϫ 13 3.7 8 35 Plant aux. load, MW 0.05 4. 5 0.7 40 0 0 .2 0 .4 1 Net plant output, MW 6.65 18.1 17 .4 8 .4 ... isentropic ϭ (c p )(T 2 Ϫ T 1 )/ (c p ) and solve for the temperature after isentropic compression. Solv-(T Ϫ T ), T , 2 Ј 12 Ј ing, ϭ 0. 82 ϭ 0 . 24 (7 72. 7 Ϫ 520 )/...

Ngày tải lên: 09/11/2013, 04:15

... rate, gal /min ϭ 950 (25 ,000)/ [500( 94. 6 Ϫ 85)] ϭ 49 50 gal / min (3 12. 3 L /s). Then A ϭ 0.8 12( 49 50) ϭ 4 020 ft 2 (373.5 m 2 ), and loading ϭ 25 ,000/ 4 020 ϭ 6 .23 lb/ ft 2 (30 .4 kg/ m 2 ). Check the correction ... weight of 100,000 lb (44 4, 822 .2 N). De- termine what portion of the total weight of a surface condenser must be supported by the foundation if...

Ngày tải lên: 09/11/2013, 04:15

... CH 4 ϩ 2O 2 ϭ CO 2 ϩ H 2 O; 16 ϩ 64 ϭ 44 ϩ 36; or the CH 4 burns to CO 2 in the ratio of 1 part CH 4 to 44 /16 parts CO 2 . Since, from step 1, there is 0.03896 lb CH 4 per ft 3 (0. 6 24 kg/ m 3 ) of natural ... product of the ratio of the nitrogen and oxygen weights in the air and 2. 544 4, or (2. 544 4)(0.768/ 0 .23 2) ϭ 8. 42 2 8 lb (3. 820 kg). Then the w...

Ngày tải lên: 17/12/2013, 11:15

... 110 ,46 7 ft 3 /min ( 52. 1 m 3 /s), with an outlet velocity of 44 00 ft /min (22 .4 m /s), an outlet velocity pressure of 1 .21 0 inH 2 O (0.30 kPa), a speed of 122 2 r/ min, and an input hp of 25 5.5 ... (0.9 ϫ 2. 4 m) duct size, or a cross- sectional area of (3)(8) ϭ 24 ft 2 (2. 2 m 2 ). At E the duct divides into three equal- size branches, one for each boiler, an...

Ngày tải lên: 17/12/2013, 11:15

... tubes are being used, ID ϭ 0. 625 Ϫ 2( thickness) ϭ 0. 625 Ϫ 2( 0. 049 ) ϭ 0. 527 in (1.3 cm). Then, open area per tube ft 2 ϭ ( ␲ d 2 /4) / 144 ϭ 0.78 54( 0. 527 ) 2 / 144 ϭ 0.001 525 ft 2 (0.000 14 m 2 ) per ... 350°F H 5 = 3 24 .4 H 7 = 44 9 .4 Heater 1,000,000 lb/hr (45 4,000 kg/hr) 1800 psia ( 12, 4 02 kPa) 1050°F (565°C) 500 psia ( 344 5 kPa) 740 °F (393°C) 1379...

Ngày tải lên: 17/12/2013, 11:15

... 24 45 ft 3 /min (69 .2 m 3 /min), step 4, and the engine ra- diator gives 6000 ft 3 /min (169.9 m 3 /min), step 1, or a total of 24 45 ϩ 6000 ϭ 844 5 ft 3 /min (23 9.1 m 3 /min). Thus, 10,500 Ϫ 844 5 ϭ 20 55 ... annual intake of dust is ( 24 h/day)(300 days / year)(336 gr/h) ϭ 2, 41 9 ,20 0 gr (156.8 kg). Since there is 7000 gr/lb, the weight of dust entering the engine per...

Ngày tải lên: 17/12/2013, 11:15

... head v 2 /2g ϭ (7.1) 2 /2( 32. 2) ϭ 0.7 84 ft (0 . 24 m). Using k values from Fig. 11 in this section, h e ϭ k v 2 /2g ϭ (0.5)(0.7 84) ϭ 0.3 92 ft (0. 12 m); h ex ϭ v 2 /2g ϭ 0.7 84 ft (0 . 24 m). 4. Find ... velocity v ϭ gpm /2. 44 8d 2 ϭ 28 1 /2. 44 8 (4. 026 ) 2 ϭ 7.1 ft/s (2. 1 m/s), and the product v d ϭ (7.1) (4. 026 ) ϭ 28 .55. Enter Fig. 30 at a temperature of...

Ngày tải lên: 17/12/2013, 11:15

... size, known/new Pressure factor, P 2/ 1 5.0 92 1 /2 0.0386 3/ 2 2.58 2/ 3 0.150 4/ 3 1.919 3 /4 0 .27 1 6/ 4 2. 6 74 4/6 0.1399 8/ 6 1.933 6/8 0 .26 7 10/ 8 1. 726 8/10 0.335 12/ 10 1.5 42 10/ 12 0. 42 1 When computing such ... of the pressure wave, use the equation L ϩ L ϩ ⅐⅐⅐ L 12 n a ϭ g (L /a ) ϩ (L /a ) ϩ ⅐⅐⅐ ϩ (L /a ) 11 22 nn Substituting, 25 ϩ 15 ϩ 10 a ϭ g (25...

Ngày tải lên: 17/12/2013, 11:15

... P g ϭ 29 . 92 ϫ 7.18 ϫ 60.33 ϫ 32. 0/ ( 144 ϫ 14. 7 ϫ 32. 1 74) ϭ 6.09 in Hg (20 . 62 kPa). 6. Compute the water velocity in the pumped-drain system piping Pump’s flow rate q ϭ (40 gal/ min)/)[7 .48 gal ... V o ϭ (1.00 Ϫ 0.75)(H ϫ 0.78 54 D 2 ) ϭ 0 .25 ( 12. 75 ϫ 0.78 54 ϫ 4 2 ) ϭ 40 .1 ft 3 (1. 14 m 3 ). 4. Compute the final height of liquid above the tank bottom created...

Ngày tải lên: 17/12/2013, 11:15