Handbook of Mechanical Engineering Calculations ar Episode 2 Part 8 ppsx
Handbook of Mechanical Engineering Calculations P1
... isentropic ϭ (c p )(T 2 Ϫ T 1 )/ (c p ) and solve for the temperature after isentropic compression. Solv-(T Ϫ T ), T , 2 Ј 12 Ј ing, ϭ 0. 82 ϭ 0 .24 (7 72. 7 Ϫ 520 )/0 .24 ϭ 82 8 .4 Њ R, or 3 68 Њ F. ThisT (T Ϫ 520 ) 2 Ј 2 Ј is ... fired HRSG Case 7 2 Supp fired HRSG GT output, MW 5 .8 20 .2 20 .2 21 .8 15.5 0 0 ST output, MW 0.9 2. 4 Ϫ 2. 1 Ϫ 13 3.7 8 35 Plant aux...
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Handbook of Mechanical Engineering Calculations P2
... / h) ϭ 4,9 98, 000, say 5,000,000 lb /h (630.0 kg/s). Then, the area required, given 1 ft 2 of pond area per 25 0 lb of water (0. 82 m 2 per 1000 kg) cooled ϭ 5,000,000/ 25 0 ϭ 20 ,000 ft 2 ( 185 8.0 m 2 ). As ... 0. 622 lb (0 . 28 kg) of water per pound (kg) of dry air. Since the water content of the air is a function of the partial pressures, (0. 622 ) (0.5067) /[ (2...
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Tài liệu Handbook of Mechanical Engineering Calculations P3 pdf
... and 2. 5444, or (2. 5444)(0.7 68/ 0 .23 2) ϭ 8. 422 8 lb (3. 82 0 kg). Then the weight of air required for perfect combustion of 1 lb (0.45 kg) of coal ϭ sum of nitrogen and oxygen required ϭ 8. 422 8 ϩ 2. 5444 ϭ 10.96 72 ... or 23 .88 ϩ 4.31 ϭ 28 .19 ft 3 (0.7 98 m 3 ). By the procedure in step 5, the percent CO 2 , wet basis ϭ 2. 265 / 28 .19 ϭ 0. 080 4, or 8. 04 p...
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Tài liệu Handbook of Mechanical Engineering Calculations P4 pptx
... [kJ/(m 2 )( Њ C)(m)] are as follows: 0. 82 at 180 0 Њ F (9 82 Њ C) for fire brick; 0. 125 at 180 0 Њ F (9 82 Њ C) for Sil-O-Cel; 0. 52 at 500 Њ F (26 0 Њ C) for transite. A temperature of 180 0 Њ F (9 82 Њ C) ... C b ϭ 0. 685 Ϫ (0.093)(0.07) ϭ 0.6 78 lb/ lb (0.6 78 kg/kg) fuel; G ϭ [11(0.1 58) ϩ 8( 0. 0 28 ) ϩ 7(0 .81 4)]/ [3(0.1 58) ] ϫ (0.6 78 ϩ 0.0 32/ 2. 67) ϩ 0.0 32/ 1...
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Tài liệu Handbook of Mechanical Engineering Calculations P5 pdf
... Thus, ( 327 .81 Ϫ 23 8) Ϫ ( 327 .81 Ϫ 3 18) t ϭ m ln [ 327 .81 Ϫ 23 8/ ( 327 .81 Ϫ 3 18) ] ϭ 36.5 Њ F (20 .3 Њ C) The average film temperature t f for any closed heater is then t ϭ t Ϫ 0.8t fs m ϭ 327 .81 Ϫ 29 .2 ϭ 29 8. 6 Њ F ... OD ϭ 3 ⁄ 8 ϩ 5 ⁄ 8 ϭ 1 in (2. 5 cm). The number of tubes per ft 2 of tube sheet ϭ 166/(pitch) 2 , or 166/1 2 ϭ 166 tubes per ft 2 (1...
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Tài liệu Handbook of Mechanical Engineering Calculations P6 pdf
... percent CO 2 in the exhaust gases, 0.09 ϭ (CO 2 )/(CO 2 ϩ N 2 ) ϭ 0.0654/(0.0654 ϩ N 2 ). Solving for N 2 , we find N 2 ϭ 0.661 mole. The weight of N 2 therefore ϭ 0.661 ϫ 28 ϭ 18. 5 lb (8. 399 kg). 3. ... installed at an altitude of 80 00 ft (24 38 m), the power loss will be (80 00/1000)(3.5) ϭ 28 percent. Further, the increased inlet-air temperature of 90 Њ F (...
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Tài liệu Handbook of Mechanical Engineering Calculations P7 docx
... kg/h) ϭ aflowof (140,000)(0. 120 2) ϭ 16 ,84 0 gal/ h (63,739.4 L / h), or 16 ,84 0 /60 ϭ 28 1 gal/ min (17.7 L/ s). Then the liquid velocity v ϭ gpm /2. 448d 2 ϭ 28 1 /2. 4 48( 4. 026 ) 2 ϭ 7.1 ft/s (2. 1 m/s), ... velocity head v 2 /2g ϭ (7.1) 2 /2( 32. 2) ϭ 0. 784 ft (0 .24 m). Using k values from Fig. 11 in this section, h e ϭ k v 2 /2g ϭ (0.5)(0. 784 ) ϭ 0.3 92 ft (0. 12 m...
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Tài liệu Handbook of Mechanical Engineering Calculations P8 doc
... diameter of pipe, in (cm). From a table of pipe properties, d ϭ 22 . 626 in (574.7 mm). Also, k ϭ z/S ϭ 75/0 .85 ϭ 88 .2 cSt. Then R ϭ 31 62( 500)/ [88 .2( 22. 626 )] ϭ 7 92. Since R Ͻ 120 0, laminar flow exists ... 3/4 0 .27 1 6/ 4 2. 674 4/6 0.1399 8/ 6 1.933 6 /8 0 .26 7 10/ 8 1. 726 8/ 10 0.335 12/ 10 1.5 42 10/ 12 0. 421 When computing such a listing, the actual inside...
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Tài liệu Handbook of Mechanical Engineering Calculations P9 pdf
... operate to within 2. 5 inHg (9.7 kPa) of the barometer, or a vacuum of 29 .8 Ϫ 2. 5 ϭ 27 .3 inHg (105.5 kPa). 2. Compute the quantity of free air removed from the receiver Select a number of absolute pressures ... ft 3 ( 28 .3 m 3 ), 720 0 grains of dirt will pass into the air compressor in 1 week’s oper- ation. With the higher level of 4 grains per 1000 ft 3 ( 28 .3 m 3 )...
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Tài liệu Handbook of Mechanical Engineering Calculations P11 doc
... (1): 0.467 0 .22 2 0 .2 0 .8 ⌬ T 1.7 ϫ 1 18 307.5 ϫ 6 0.495 i ϭ 10.43 ϫ ͫͬͫͬͫͬ 0 .89 0 .2 ⌬ T 0 .85 30.4 89 ϫ 12 M ϭ 10.43 ϫ 4 .27 ϫ 0. 621 ϫ 0.0193 ϭ 0.535 Shellside, Eq. (11): 0 .26 7 0 .22 2 0.4 0 . 28 2 0.6 ⌬ T ... 0.3 ϫ 62 32. 8 ϫ 45 1 ϫ 5 o ϭ 4 . 28 ϫ ͫͬͫͬͫͬ 0 .89 0.7 18 ⌬ T 0.95 30.4 89 ϫ 12 M ϭ 4 . 28 ϫ 1 .89 ϫ 5. 98 ϫ 0.0 08 72 ϭ 0. 424 Tube Wall, Eq. ( 18)...
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