CS193P - Lecture 3 ppsx
Lecture 3 Block
... coding: n =3
’A’=’aaa’ -& gt; p
A
=p
3
’B=’aab’, ’C’=’aba’, ’D’=’baa’ -& gt; p
B
= p
C
=p
D
=p
2
q
’E’=’abb’, ’F’=’bab’, ’G’=’bba’ -& gt; p
E
= p
F
=p
G
=pq
2
’H’=’bbb’ -& gt; p
H
=q
3
Huffman ... c
B
=’111101’, c
G
=’111110’, c
H
=’111111’
Entropy H
3
?
Bitrate:
R
3
= (1*p
A
+2*p
B
+3* p
C
+4*p
D
+6*(p
E
+p
F
+p
G
+p
H
)) /3=
= 0 .35 3 bits/pel
Exercise
Thực...
Tài liệu Lecture 3: ĐẠI SỐ BOOLEAN docx
... 1 0
X nor Y = not (X or Y) =
X Y+
CÁC PHÉP TOÁN
XOR (Exclusive-OR):
X Y Z
0 0 0
0 1 1
1 0 1
1 1 0
Exclusive OR - XOR
XOR - True if both inputs
are different
Z X Y= ⊕
CÁC ĐỊNH LÝ
Luật ... TOÁN
OR:
x y x y x y+ ∨, , |
x or y
x
y
x+y
X Y X or Y
0 0 0
0 1 1
1 0 1
1 1 1
Bảng sự thật:
Lecture 3: ĐẠI SỐ BOOLEAN
Biên soạn:Th.S Bùi Quốc Bảo
(Base on Floyd, Pearson Ed.)
TÍNH CH...
Tài liệu Modulation and coding course- lecture 3 pptx
... filters
Tt
)(
1
ts
Tt
)(
2
ts
T
T
0
0
T
A
T
A−
T
A−
T
A
0
0
Lecture 3 5
Example of M-ary PAM
-B
B
T
‘01’
3B
T
T
-3 B
T
‘00’
‘10’
‘1’
A.
T
‘0’
T
-A.
Assuming real time tr. and equal energy per tr. data bit for
binary-PAM and 4-ary PAM:
• 4-ary: T=2Tb ... TR
=
mRR
b
=
Lecture 3 6
Example of M-ary PAM …
0 Tb 2Tb 3Tb 4Tb 5Tb 6Tb
0 Ts 2Ts
0 T 2T 3T
2.2762 V 1 .36 57 V
1 1 0 1 0 1
0 T...
Tài liệu Kinh tế ứng dụng_ Lecture 3: Outliers, Leverage and Influence docx
... Regression 3 Regression 4
Y X
1
Y X
2
YX
3
Y X
4
8.04
6.95
7.58
8.81
8 .33
9.96
7.24
4.26
10.84
4.82
5.68
10
8
13
9
11
14
6
4
12
7
5
9.14
8.14
8.74
8.77
9.26
8.1
6. 13
3. 1 ...
8.77
9.26
8.1
6. 13
3. 1
9. 13
7.26
4.74
10
8
13
9
11
14
6
4
12
7
5
7.46
6.77
12.74
7.11
7.81
8.84
6.08
5 .39
8.15
6.42
5. 73
10
8
13
9
11
1...
Lecture 3 Creating M - files docx
... 1.9951
-4 .5000 1.9910
-4 .0000 1.9 837
-3 .5000 1.9705
-3 .0000 1.9468
-2 .5000 1.9051
-2 .0000 1. 833 7
-1 .5000 1.71 63
-1 .0000 1. 537 0
-0 .5000 1.29 13
0 1.0000
0.5000 0.7087
1.0000 0.4 630
1.5000 ... 1.9951
-4 .5000 1.9910
-4 .0000 1.9 837
-3 .5000 1.9705
-3 .0000 1.9468
-2 .5000 1.9051
-2 .0000 1. 833 7
-1 .5000 1.71 6...
lecture 3 aas&ir
... Temperature (K)
Acetylene Air 2,400 - 2,700
Acetylene Nitrous Oxide 2,900 - 3, 100
Acetylene Oxygen 3, 300 - 3, 400
Hydrogen Air 2 ,30 0 - 2,400
Hydrogen Oxygen 2,800 - 3, 000
Cyanogen Oxygen 4,800
Furnaces
• ... dispersive IR spectrophotometers are invariably double-beam
instruments, but many allow single-beam operation via a front-panel
switch.
Double-beam operatio...
lecture 3 sniffer tmp
...
được
SSHMITM và WEBMITM
giúp thực hiện tấn công
"active man-in-the-middle"
đối lập với SSH và https.
Tool: Snort
Snort hoạt động ở 3
chế độ chính:nghe
lén(sniffer), lưu nhật
ký(packet ... mạng
sử dụng Arpwatch để theo dõi hoạt động của
mạng
http://www.redhat.com/swr/i386/arpwatch-2.1a1 1-1 .i386.html
ARP(Address Resolution Protocol) là gi
ARP là một giao thức tầng...
Lecture 3 DNA RNA and protein synthesis great
...
FOR?
DNA is in a double strand
The nitrogen bases have compliment
partners
Adenine-Thymine
Cytosine-Guanine
3. Transfer RNA brings amino acids to
the ribosome to match the sequence
codes
DNA ... DNA’s proper name is-
Deoxyribonucleic acid!
Consists of a ribose SUGAR with a
“missing oxygen” (that’s the de-oxy
part)
And it’s found in the nucleus of
eukaryotic ... RNA leave...
CMOS VLSI Design - Lecture 3: CMOS Transistor Theory potx
... Typically 2 -3 x lower than that of electrons µ
n
– 120 cm
2
/V•s in AMI 0.6 µm process
Thus pMOS must be wider to
provide same current
– In this class, assume
µ
n
/ µ
p
= 2
-5 -4 -3
-2 -1 0
-0 .8
-0 .6
-0 .4
-0 .2
0
I
ds
(mA)
V
gs
... this class, assume
µ
n
/ µ
p
= 2
-5 -4 -3
-2 -1 0
-0 .8
-0 .6
-0 .4
-0 .2
0
I
ds
(mA)
V
gs
= -5...
Lecture 3: Object Oriented Programming pptx
... company’s
Internet domain name
e.g. hostname.com -& gt; com.hostname
8
Other initialization methods(2)
Static initialization block
Resembles a non-static initialization block except
that it ... of nextPrime( ). . .
}
13
See this code:
import java.lang.Math;
public class importTest {
double x = sqrt(1.44);
}
Compile:
%> javac importTest.java
importTest.java :3: cannot find symbo...
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