A textbook of Computer Based Numerical and Statiscal Techniques part 49 pps

A textbook of Computer Based Numerical and Statiscal Techniques part 49 pps

A textbook of Computer Based Numerical and Statiscal Techniques part 49 pps

... to chance variation only, the process is said to be in a state of statistical control. These type of causes are also known as random causes. These small variations, which are natural to and inherent ... Control charts for attributes (p, pn and C-chart) 466 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES 8. The presence of an SQC scheme in any manufacturing concern ha...
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A textbook of Computer Based Numerical and Statiscal Techniques part 2 ppsx

A textbook of Computer Based Numerical and Statiscal Techniques part 2 ppsx

... problems. A major advantage for numerical technique is that a numerical answer can be obtained even when a problem has no analytical solution. However, result from numerical analysis is an approximation, in ... significant figures at each step of computation. At each step of computations, retain at least one more significant figure than that given in the data, perform the last...
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A textbook of Computer Based Numerical and Statiscal Techniques part 3 ppsx

A textbook of Computer Based Numerical and Statiscal Techniques part 3 ppsx

... 3 Hence maximum percentage error (E p ) max = 11.667%. Example 26. How accurately should the length and time of vibration of a pendulum should be measured in order that the computed value of g is ... 4008 and 30.4647 + 0.0639 = 30.5286. Example 12. Find the product of 346.1 and 865.2 and state how many figures of the result are trustworthy, given that the numbers are corr...
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A textbook of Computer Based Numerical and Statiscal Techniques part 5 ppsx

A textbook of Computer Based Numerical and Statiscal Techniques part 5 ppsx

... roots of the equation, obtained by x 1 = 2 22 44 and 22 bb ac bb ac aa −+ − −− − =x These are called closed form solution. Similar formulae are also available for cubic and biquadratic polynomial ... 26 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES The basic operations specified by IEEE arithmetic are first and foremost addition, subtraction, multiplication, and div...
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A textbook of Computer Based Numerical and Statiscal Techniques part 14 ppsx

A textbook of Computer Based Numerical and Statiscal Techniques part 14 ppsx

... 122 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Example 22. Evaluate: ∆ n [sin (ax + b)] Sol. We know f∆ (x) = f(x + h) – f (x) therefore ∆ sin (ax + b) = sin [a (x + h)+b] – sin)(ax ... hD hD hD 116 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Example 14. Evaluate the following: I. ∆ 2 (cos 2x) II. ∆ 2 (3e x ) III. ∆ tan –1 x IV. ∆(x + cos x) the inte...
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A textbook of Computer Based Numerical and Statiscal Techniques part 16 ppsx

A textbook of Computer Based Numerical and Statiscal Techniques part 16 ppsx

... given a set of equidistant values of arguments and its corresponding value of f(x). Suppose for n + 1 equidistant argument values x = a, a + h, a + 2h, , a + nh, are given. 140 COMPUTER BASED NUMERICAL ... 0f−+×−×+= 138 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES i.e., 4f(3) = 124 i.e., f(3) = 31 (function values are 3 n type and this is not a pol...
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A textbook of Computer Based Numerical and Statiscal Techniques part 17 ppsx

A textbook of Computer Based Numerical and Statiscal Techniques part 17 ppsx

... R.H.S. 3.9 FACTORIAL NOTATIONS The product of n consecutive factors each at a constant difference and the first factor being x is called a factorial function or a factorial polynomial of degree n and ... L.H.S. 150 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES CorCor CorCor Cor ollary:ollary: ollary:ollary: ollary: To show that, () n n x ∆ = n! h n and 1n+ ∆...
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A textbook of Computer Based Numerical and Statiscal Techniques part 22 pps

A textbook of Computer Based Numerical and Statiscal Techniques part 22 pps

... 16.047 x x y [Ans. 19.704] 202 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Example 4. Apply Stirling’s formula to find a polynomial of degree three which takes the following values of x and y: x y ... 32.625 thousands Hence, the population in 1936 is 32625 thousand. 196 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Example 5. If f(x) is a polynomial...
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A textbook of Computer Based Numerical and Statiscal Techniques part 25 ppsx

A textbook of Computer Based Numerical and Statiscal Techniques part 25 ppsx

... interpolation formula. Sol. We are given () :78910 :311 9 x fx 226 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Example 1. Using Lagrange’s formula, find the value of (i) y x if y 1 ... age group are given below: Age less than :25304050 Percentage of Criminals :5267 8494 Apply Lagrange’s formula to find the percentage of criminals under 35 years of age. [Ans. 77]...
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A textbook of Computer Based Numerical and Statiscal Techniques part 26 ppsx

A textbook of Computer Based Numerical and Statiscal Techniques part 26 ppsx

... differences where as the difference defined earlier are called ordinary differences. Lagrange’s interpolation formula has the disadvantage that if any other interpolation point were added, the interpolation co-efficient ... life. [Ans. 15.67] 13. Find the value of tan 33° by Lagrange’s formula if tan 30° = 0.5774, tan 32° = 0.6 249, tan 35° = 0.7002, tan 38° = 0.7813. [Ans. 0. 6494 2084] 14...
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