A textbook of Computer Based Numerical and Statiscal Techniques part 35 pptx
A textbook of Computer Based Numerical and Statiscal Techniques part 35 pptx
... numerical solutions of differential equations. In researches, especially after the advent of computer, the numerical solutions of the differential equations have become easy for manipulations. Hence, ... % Numerical Solution of Ordinary Differential Equation 7.1 INTRODUCTION In the fields of Engineering and Science, we come across physical and natural phenomena which, whe...
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A textbook of Computer Based Numerical and Statiscal Techniques part 6 pptx
... negative. Thus f(0.5) is negative and f(1) is positive. Then the root lies between 0.5 and 1. 40 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Second approximation: The second approximation ... f(0) is negative and f(1) is positive, therefore, a root lies between 0 and 1. ALGEBRAIC AND TRANSCENDENTAL EQUATION 37 Here e i and e i + 1 are the errors in i th and...
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A textbook of Computer Based Numerical and Statiscal Techniques part 19 pptx
... the argument half way between the arguments at q and r is + B A, 24 where A is the arithmetic mean of q and r and B is arithmetic mean of 3q – 2p – s and 3r – 2s – p. Sol. Given A is the arithmetic ... 0.7880 Example 7. Following are the marks obtained by 492 candidates in a certain examination: 04040454550505555606065 . 210 4354 743279 Marks No of Candidates −−−−−− Fi...
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A textbook of Computer Based Numerical and Statiscal Techniques part 20 pptx
... gives best estimation when 11 . 44 u−< This formula is obtained by taken mean of Gauss forward and Gauss backward difference formula. Gauss forward formula for interpolating central difference ... + ×− = 235 – 24.65 – 10.76625 – 1.076625 = 235 – 36.492875 = 198.507 { 198 ∴ Total no. of candidates who obtained fewer than 70 marks are 198. Example 6. The area A of a circle o...
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A textbook of Computer Based Numerical and Statiscal Techniques part 30 pptx
... dxa xdxa xdxa xdx 1111 3 5/2 2 4 012 0000 x dxa xdxa xdxa xdx=++ ∫∫∫∫ or Simplifying above equations, we get 12 0 012 0 12 2 233 2 2345 2 3457 aa a a aa aaa ++= ++ = ++= 284 COMPUTER BASED NUMERICAL ... NUMERICAL AND STATISTICAL TECHNIQUES Minimax polynomial approximation: Let f(x) be continuous on [a, b] and it is approximated by the polynomial P n (x) = a 0 + a 1 x +...
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A textbook of Computer Based Numerical and Statiscal Techniques part 40 pptx
... sensitive to small changes in A and B i.e., small change in A or B causes a large change in the solution of the system. On the other hand if small changes in A and B give small changes in the solution, the ... find that 12 iteration are necessary in Gauss-Jacobi Method to get the same accuracy as achieved by 7 iterations in Gauss-Seidel method. SOLUTION OF SIMULTANEOUS LINEAR...
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A textbook of Computer Based Numerical and Statiscal Techniques part 41 pptx
... value of a, b and c. Putting the value of a, b and c in equation (1), we get the equation of the parabola of best fit. 9.2.3 Change of Scale When the magnitude of the variable in the given data ... a x b x=+ ∑∑∑ (5) The equation () 3 and () 4 are known as normal equations. On solving equations () 3 and () 4 , we get the value of a and b. Putting the valu...
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A textbook of Computer Based Numerical and Statiscal Techniques part 46 pptx
... the type and nature of the variations in the data. 2. The segregation and study of the various components is of paramount importance to a businessman in the planning of future operations and in ... Seasonal indices. Example 13. Calculate seasonal indices by method of link relatives from the data given in Example 12. Sol. Calculate of Average Link Relatives Link Relatives Y...
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A textbook of Computer Based Numerical and Statiscal Techniques part 50 pptx
... shows that some assignable causes of variation are operating which should be detected and removed. 478 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES whether there are any assignable causes. ... 11.19 Range Chart 10 8 6 4 2 0 Sample Range 0 5 10 15 Sample Number FIG. 11.20 Example 3. In a glass factory, the task of quality control was done with the help of mean (x — )...
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A textbook of Computer Based Numerical and Statiscal Techniques part 58 pptx
... e where v is any vairable (or anything like a[ i]), op is any of the binary arithmetic operators, and e is any expression. 558 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES printf("can’t compute ... i); break; } } } return 0; } Arrays The declaration int i; declares a single variable, named i, of type int. It is also possible to declare an array of several elem...
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