A textbook of Computer Based Numerical and Statiscal Techniques part 33 pot
A textbook of Computer Based Numerical and Statiscal Techniques part 33 pot
... 32.98 33. 54 33. 97 33. 48 32.13 t x Evaluate dx dt at t = 0.1 and at t = 0.5 [Ans. 32.44166 cm/sec.; −24.05 833 cm/sec.] 9. A rod is rotating in a plane. The following table gives the angle θ (radians) ... a table, but no mathematical relationship between them is known as is often the case with experimental data. 6.4 GENERAL QUADRATURE FORMULA Let ()yfx= be a function, w...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 7 potx
... 1.4036 0.10203 = Since, x 3 and x 4 are approximately the same upto four places of decimal, hence the required root of the given equation is 1.4036. 48 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Using ... between 1.6866 and 2. 50 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES and f(3) = (3) 3 – 2(3) – 5 = 16 Therefore, a root lies betw...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 23 pot
... 206 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES 7. Apply Stirling’s formula to find a polynomial of degree four which takes the values of y as given below: x y −− 12345 11111 [Ans. 42 28 1 33 uu−+ ] 8. ... 0.25 Also, w = 1 – u = 1 – .25 = 0.75 214 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES 7. Apply Bessel’s interpolation formula, show that tan160°...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 28 potx
... = 0.86742. Ans. Example 4. A switching path between parallel railroad tracks is to be a cubic polynomial joining positions (0,0) and (4,2) and tangent to the lines y = 0 and y = 2 as shown in ... Hermite’s interpolation formula. () () () () () () xfx fx afa fa bfb fb ′ ′ ′ INTERPOLATION WITH UNEQUAL INTERVAL 261 Example 1. Apply Hermite’s interpolation formula to obtain a polynomi...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 38 potx
... 1.3997 3 =+ ++ = 364 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES which is same as the predicted value. ∴ 60.30 1.3997 yy== and 6 1.6997 y ′ = The result can be put in the tabular form x 0.20 ... differential equation () , dy yfxy dx ′ == by this method we first obtain the approximate value of 1n y + by Predictor formula and then improve the value of 1n y + by me...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 39 potx
... value y i and the true value y(x i ) at any stage is known as the total error. The total error at any stage is comprised of truncation error and round-off error. The most important aspect of ... DIFFERENTIAL EQUATION 371 Inherent stability is determined by the mathematical formulations of the problem and is dependent on the eigen values of Jacobian Matrix of the differential...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 42 potx
... method of least squares a parabola of the type 2 yabx=+ . Sol. Error of estimate for i th point (,) ii xy is () 2 ii i eyabx =−− By the principle of least squares, the values of a and b are ... = ∑ x 2 300 = ∑ xY ∑ Substituting the values of x ∑ , etc. and calculated by means of above table in the normal equations. We get, 5.7536 = 5A + 34B and 40.8862 = 3 4A...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 43 pot
... n ≤≤ and 1}jn≤≤ be a bivariate distribution. If we plot the corresponding values of x and ,y taking the values of x along x-axis and the values of y along y-axis, we obtain a collection of ... [Ans. 2 13 22 yx=+ ] 410 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES Example 3. Prove that arithmetic mean of the coefficient of regression is greater t...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 54 potx
... that the sailors are on the average taller than soldiers? [Ans. Highly significant] 22. The yield of wheat in a random sample of 1000 farms in a certain area has a S.D. of 192 kg. Another random ... population with mean height 162.5 cms and standard deviation 4.5 cms? [Ans. H 0 : Accepted] 13. A random sample of 200 measurements from a large population gave a mean value...
Ngày tải lên: 04/07/2014, 15:20
A textbook of Computer Based Numerical and Statiscal Techniques part 55 potx
... E(c)= accd N ++ bgbg and E(d)= bdcd N ++ bgbg abab cdcd ac bd N + + ++ ∴ χ 2 = aEa Ea bEb Eb cEc Ec dEd Ed –––– af af af af af af af af 2222 +++ (2) a – E (a) =a – abac N ++ bgbg = a a b c d a ac ... the tabulated value, H 0 is rejected. i.e., the data are not consistent with the hypothesis that the Binomial law holds and that the chance of a male birth is not equal to that...
Ngày tải lên: 04/07/2014, 15:20