A textbook of Computer Based Numerical and Statiscal Techniques part 20 pptx
A textbook of Computer Based Numerical and Statiscal Techniques part 20 pptx
... −−
+−+
= 147.2251 Approx.
Example 5. In an examination, the number of candidates who obtained marks between certain limits
are as follows:
Marks
No of candidates
−−−−−01 9203 9405960798099
. 41 ... 36.492875
= 198.507 { 198
∴ Total no. of candidates who obtained fewer than 70 marks are 198.
Example 6. The area A of a circle of diameter d is given for the following values:
d
A...
A textbook of Computer Based Numerical and Statiscal Techniques part 6 pptx
... negative.
Thus f(0.5) is negative and f(1) is positive. Then the root lies between 0.5 and 1.
40
COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES
Second approximation: The second approximation ... f(0) is negative and f(1) is positive, therefore, a root lies between 0 and 1.
ALGEBRAIC AND TRANSCENDENTAL EQUATION
37
Here e
i
and e
i + 1
are the errors in i
th
and...
A textbook of Computer Based Numerical and Statiscal Techniques part 19 pptx
... differences are taken into account, the entry corresponding to the argument half way
between the arguments at q and r is
+
B
A,
24
where A is the arithmetic mean of q and r and B is arithmetic
mean of ... quantities p, q, r and s corresponds to argument a, a + h, a + 2h and a + 3h respectively
then the value of the argument lying half way between a + h and a...
A textbook of Computer Based Numerical and Statiscal Techniques part 30 pptx
... S (a
0
, a
1
, a
2
)=
1
1/2 2
01 2
0
xaaxaxdx
−− −
∫
= minimum
The normal equations are
1
1/2 2
01 2
0
0
1
1/2 2
01 2
1
0
1
21/2 2
01 2
2
0
20
20
20
S
xaaxaxdx
a
S
xx a axaxdx
a
S
xx aaxaxdx
a
∂
=− ... dxa xdxa xdxa xdx
1111
3
5/2 2 4
012
0000
x dxa xdxa xdxa xdx=++
∫∫∫∫
or Simplifying above equations, we get
12
0
012
0
12
2
233
2
2345
2
3457
aa
a
a
aa
aaa...
A textbook of Computer Based Numerical and Statiscal Techniques part 35 pptx
... fields of Engineering and Science, we come across physical and natural phenomena which,
when represented by mathematical models, happen to be differential equations. For example,
simple harmonic ... the numerical solutions of the differential equations have
become easy for manipulations. Hence, we present below some of the methods of numerical
solutions of the ordinary diffe...
A textbook of Computer Based Numerical and Statiscal Techniques part 40 pptx
... sensitive
to small changes in A and B i.e., small change in A or B causes a large change in the solution
of the system. On the other hand if small changes in A and B give small changes in the solution,
the ... find that 12 iteration are necessary in Gauss-Jacobi Method to get the same accuracy
as achieved by 7 iterations in Gauss-Seidel method.
SOLUTION OF SIMULTANEOUS LINEAR...
A textbook of Computer Based Numerical and Statiscal Techniques part 41 pptx
... equations (3), (4) and (5), we get the value of a, b and c. Putting the value of a,
b and c in equation (1), we get the equation of the parabola of best fit.
9.2.3 Change of Scale
When the magnitude ... a x b x=+
∑∑∑
(5)
The equation
()
3
and
()
4
are known as normal equations.
On solving equations
()
3
and
()
4
, we get the value of
a
and b. Putting the...
A textbook of Computer Based Numerical and Statiscal Techniques part 46 pptx
... the type and nature of the variations in the data.
2. The segregation and study of the various components is of paramount importance to
a businessman in the planning of future operations and in ... Seasonal indices.
Example 13. Calculate seasonal indices by method of link relatives from the data given in
Example 12.
Sol. Calculate of Average Link Relatives
Link Relatives
Y...
A textbook of Computer Based Numerical and Statiscal Techniques part 50 pptx
... shows that some assignable causes of variation
are operating which should be detected and removed.
478
COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES
whether there are any assignable causes. ... 11.19
Range Chart
10
8
6
4
2
0
Sample Range
0 5 10 15
Sample Number
FIG. 11 .20
Example 3. In a glass factory, the task of quality control was done with the help of mean (x
—...
A textbook of Computer Based Numerical and Statiscal Techniques part 58 pptx
... e
where v is any vairable (or anything like a[ i]), op is any of the binary arithmetic operators, and
e is any expression.
558
COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUES
printf("can’t compute ... i);
break;
}
}
}
return 0;
}
Arrays
The declaration
int i;
declares a single variable, named i, of type int. It is also possible to declare an array of several
elem...