. 62 2108665,010)0(++−+=++⇔pppipRLRpLRLCpLaϕ))(10(10.8,686608,1( 26 2) 62 RpLRLCppppRLa+++++=⇔ϕ)101010.5)(10(3410.33,410.9)101010. 2 1.10.10)(10()10.8,686608,1(10. 2 1.10.10))(10()10.8,686608,1()( 22 6 62 223 6 22 426 2 624 2 26 2 62 +++++=+++++=+++++==⇒−−−−−−−−−ppppppppppppRpLRLCpppppRLCpCpIaCϕĐặt. 62 2108665,010)0(++−+=++⇔pppipRLRpLRLCpLaϕ))(10(10.8,686608,1( 26 2) 62 RpLRLCppppRLa+++++=⇔ϕ)101010.5)(10(3410.33,410.9)101010. 2 1.10.10)(10()10.8,686608,1(10. 2 1.10.10))(10()10.8,686608,1()( 22 6 62 223 6 22 426 2 624 2 26 2 62 +++++=+++++=+++++==⇒−−−−−−−−−ppppppppppppRpLRLCpppppRLCpCpIaCϕĐặt 2 1)(FFpIC=Với F1=9.10-6p3+4,33.10 -2 p 2 +34p F 2 =(p 2 +106)(5.10-6p 2 +10 -2 p+10)=5.10-6p4+10 -2 p3+15p 2 +104p+107 F’ 2 =20 .10-6p3+3.10 -2 p 2 +30p+104Ta. do :))(1000cos (2 1000 2 AteAitCtdψ+=−Trong đó ψ∠= 2 2AA 0 422 36 22 3610001000' 2 1 2 1417,11000 020 000346001600010)10001000.(30)10001000.(10.3)10001000.(10 .20 )10001000.(34)10001000.(10.33,4)10001000.(10.9−∠=+−−=++−++−++−+−++−++−==−−−−+−=jjjjjjjjFFAjp...