Digital Communication I: Modulation and Coding Course-Lecture 2 potx

... AGC  Quantization noise variance: 2 Sat 2 Lin 22 2 )()(})]({[ σσσ +==−= ∫ ∞ ∞− dxxpxexqx q E ll L l l qxp q )( 12 2 12/ 0 2 2 Lin ∑ − = = σ Uniform q. 12 2 2 Lin q = σ Lecture 2 14 Uniform and non-uniform quant.  Uniform ... 3.1867 110 2. 27 62 101 1.3657 100 0.45 52 011 -0.45 52 010 -1.3657 001 -2. 27 62 000 -3.1867 PCM codeword 110 110 111 110 100 010 011 100 100 0...

Ngày tải lên: 23/03/2014, 10:21

... bound 1 ψ 1 s 4 s 2 s 3 s 1 Z 4 Z 3 Z 2 Z r 2 ψ 1 ψ 1 s 4 s 2 s 3 s 2 A r 1 ψ 1 s 4 s 2 s 3 s 3 A r 1 ψ 1 s 4 s 2 s 3 s 4 A r 2 ψ 2 ψ 2 ψ ∫ ∪∪ = 4 32 )|()( 11 ZZZ e dmpmP rr r ∫ = 2 )|(),( 1 122 A dmpP rrss r ∫ = 3 )|(),( 11 32 A dmpP ... bound )( 1 t ψ )( 2 t ψ 1 s 3 s 2 s 4 s 2, 1 d 4,3 d 3 ,2 d 4,1 d s E s E− s E− s E 4, ,1 , === iEE sii s s ski Ed ki Ed 2...

Ngày tải lên: 23/03/2014, 10:21

... adder.  Example: The output sequence is found as follows: 22 )2( 2 )2( 1 )2( 02 22) 1( 2 )1( 1 )1( 01 1 )( 1 )( XXgXggX XXXgXggX +=++= ++=++= g g )()( with interlaced )()()( 21 XXXXX gmgmU = Lecture 10 14 Encoder ... details: 1110001011 )1,1()0,1()0,0()0,1()1,1()( .0.0.01)()( .01)()( 1)1)(1()()( 1)1)(1()()( 4 32 4 32 2 4 32 1 422 2 4 322 1 = ++++= ++++= ++++= +=++= +++=+++...

Ngày tải lên: 30/03/2014, 10:20

... 8 .22 .1316)dB()dB()dB( 00 =−=         −         = coded c uncoded b N E N E G 25 .14000 3 9600 loglog 22 ≤⇒≤       ⇒≤       == k n k n W M R k n M R R C b s Lecture 13 23 Design example of coded systems …  Bandwidth compatible BCH codes 0.41.33106 127 4.36 .22 113 127 2. 27.11 120 127 2. 36 .22 5163 2. 28.115763 0 .28 .1 126 31 1010 95 −− == BB PPtkn Co...

Ngày tải lên: 30/03/2014, 10:20

... time) ⎪ ⎪ ⎩ ⎪ ⎪ ⎨ ⎧ > <<− ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ − −+ −< = Wf WfWW WW WWf WWf fH ||for 0 ||2for 2| | 4 cos 2| |for 1 )( 0 0 0 2 0 π Excess bandwidth: 0 WW − Roll-off factor 0 0 W WW r − = 10 ≤≤ r 2 0 0 00 ])(4[1 ])(2cos[ ) )2( sinc (2) ( tWW tWW tWWth −− − = π Lecture ... Digital communications I: Modulation and Coding Course Period 3 - 20 07 Catharina Logothetis Lecture 6 L...

Ngày tải lên: 18/10/2013, 06:15

... AGC  Quantization noise variance: 2 Sat 2 Lin 22 2 )()(})]({[ σσσ +==−= ∫ ∞ ∞− dxxpxexqx q E ll L l l qxp q )( 12 2 12/ 0 2 2 Lin ∑ − = = σ Uniform q. 12 2 2 Lin q = σ Lecture 2 14 Uniform and non-uniform quant.  Uniform ... Digital Communications I: Modulation and Coding Course Period 3 – 20 0/ Catharina Logothetis Lecture 2 Lecture 2 10 Encoding (PCM)  A...

Ngày tải lên: 08/11/2013, 18:15

... adder.  Example: The output sequence is found as follows: 22 )2( 2 )2( 1 )2( 02 22) 1( 2 )1( 1 )1( 01 1 )( 1 )( XXgXggX XXXgXggX +=++= ++=++= g g )()( with interlaced )()()( 21 XXXXX gmgmU = Lecture 10 14 Encoder ... details: 1110001011 )1,1()0,1()0,0()0,1()1,1()( .0.0.01)()( .01)()( 1)1)(1()()( 1)1)(1()()( 4 32 4 32 2 4 32 1 422 2 4 322 1 = ++++= ++++= ++++= +=++= +++=+++...

Ngày tải lên: 25/10/2013, 06:15

... ) ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ = ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ ≈ MN REM Q MMN EM Q M p cbc ππ sin log2 log 2 sin log2 log 2 0 2 20 2 2 c E bcc ERE = 1 00 1 Lecture 9 20 Linear block codes – cont’d  For memory less channels, the probability that the decoder commits an erroneous decoding ... jnj n tj M pp j n P − += − ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ ≤ ∑ )1( 1 jnj n tj B pp j n j n P − += − ⎟ ⎟ ⎠ ⎞ ⎜...

Ngày tải lên: 25/10/2013, 06:15

... decoding )100( ˆ =m )1100111011( ˆ =U )101(=m )1110001011(=U )0110111011(=Z 0 2 0 1 2 1 0 1 1 0 1 2 2 1 0 2 1 1 1 6 t 1 t 2 t 3 t 4 t 5 t 1 0 2 3 0 1 2 3 2 3 20 2 30 ( ) ii ttS ),(Γ Branch metric Partial metric Lecture 12 12 Free distance … 2 0 1 2 1 0 2 1 1 2 1 0 0 2 1 1 0 2 0 6 t 1 t 2 t 3 t 4 t 5 t Hamming weight ... from the received sequence Digital...

Ngày tải lên: 29/10/2013, 13:15