. 5240C 0,4503 10 F;4 c L 4 (3 10 ) 10 40C 17 ,59 10 F.4 c L 4 (3 10 ) 10 −−−−λ= − = ×π π × × ×λ= − = ×π π × × ×Vậy ta có 1min 2maxC C C≤ ≤Hay 10 10 9,006 10 F C 17 ,59 10 F.− −×. hce . V= +λ λ 19 max6 34 80e . V 1 1 1 1,6 10 1, 5hc0,5 10 6,625 10 3 10 −− −× ×⇒ = − = −λ λ× × × ×Suy ra 60 1, 2 619 10 m 1, 2 619 m.−λ = × = µCau IX (2 điểm) 1) Góc lệch đạt cực. F;4 c L 4 (3 10 ) 0,5 10 250C 3 51, 8 10 F;4 c L 4 (3 10 ) 0,5 10 −−−−λ= − = ×π π × × × ×λ= − = ×π π × × × ×Khi L = L2 = 10 x 10 -6H thì22 10 min2min2 2 2 8 2 5222 10 max2max2...