lecture 3 sniffer tmp

. nào đó  tcp.port==4 43  ip.addr=192.168.1.10 && tcp.port=4 43  Lọc khác  ip.dst==10.0.0.1 && frame.pkt_len.400  ip.src==205.162.0.1 or ip.dst==205.1 53. 60.10 Theo vết luồng. không? Tool: Snort  Snort hoạt động ở 3 chế độ chính:nghe lén (sniffer) , lưu nhật ký(packet logger), hệ thống phát hiện xâm nhập(Instrusion Detection System)  Sniffer: đọc các gói tin t...

Ngày tải lên: 11/03/2014, 16:06

. c B =’111101’, c G =’111110’, c H =’111111’ Entropy H 3 ? Bitrate: R 3 = (1*p A +2*p B +3* p C +4*p D +6*(p E +p F +p G +p H )) /3= = 0 .35 3 bits/pel Block coding: n→ ∞ p a =p=0.99, p b =q=0.01 Entropy. =(0.0284+0.0659+0.0659+0.00 13) /2= 0.081 bits/pel Why H 2 =H 1 ? 2) Huffman code: c A =’0’, c B =’10’, c C =’110’, c D =’111’ L A =1, L B =2, L C =2, L D =3 Bitrate R 2 = (1*...

Ngày tải lên: 26/10/2012, 11:57

. Lecture 3: ĐẠI SỐ BOOLEAN Biên soạn:Th.S Bùi Quốc Bảo (Base on Floyd, Pearson Ed.) BIỂU DIỄN HÀM BOOLEAN A

Ngày tải lên: 13/12/2013, 04:15

. pulse) ‘11’ 22 10BA = Lecture 3 6 Example of M-ary PAM … 0 Tb 2Tb 3Tb 4Tb 5Tb 6Tb 0 Ts 2Ts 0 T 2T 3T 2.2762 V 1 .36 57 V 1 1 0 1 0 1 0 T 2T 3T 4T 5T 6T Rb=1/Tb =3/ Ts R=1/T=1/Tb =3/ Ts Rb=1/Tb =3/ Ts R=1/T=1/2Tb =3/ 2Ts=1.5/Ts Lecture. TR = mRR b = Lecture 3 4 Quantization example t Ts: sampling time x(nTs): sampled values xq(nTs): quantized values boundaries Quant. levels 111 3. 1867 110...

Ngày tải lên: 27/01/2014, 08:20

. X 2 YX 3 Y X 4 8.04 6.95 7.58 8.81 8 .33 9.96 7.24 4.26 10.84 4.82 5.68 10 8 13 9 11 14 6 4 12 7 5 9.14 8.14 8.74 8.77 9.26 8.1 6. 13 3. 1 9. 13 7.26 4.74 10 8 13 9. 7.81 8.84 6.08 5 .39 8.15 6.42 5. 73 10 8 13 9 11 14 6 4 12 7 5 6.58 5.76 7.71 8 8.47 7.04 5.25 12.5 5.56 7.91 6.89 8 8 8 8 8 8 8 19 8 8 8 3) The ide...

Ngày tải lên: 27/01/2014, 11:20

. 1.9 837 -3. 5000 1.9705 -3. 0000 1.9468 -2.5000 1.9051 -2.0000 1. 833 7 -1.5000 1.71 63 -1.0000 1. 537 0 -0.5000 1.29 13 0 1.0000 0.5000 0.7087 1.0000 0.4 630 1.5000 0.2 837 2.0000 0.16 63 2.5000. 1.9 837 -3. 5000 1.9705 -3. 0000 1.9468 -2.5000 1.9051 -2.0000 1. 833 7 -1.5000 1.71 63 -1.0000 1. 537 0 -0.5000 1.29 13 0 1.0000 0.5000 0.7087 1.0000 0.4 630 1.5000 0.2 83...

Ngày tải lên: 07/03/2014, 08:20

. (K) Acetylene Air 2,400 - 2,700 Acetylene Nitrous Oxide 2,900 - 3, 100 Acetylene Oxygen 3, 300 - 3, 400 Hydrogen Air 2 ,30 0 - 2,400 Hydrogen Oxygen 2,800 - 3, 000 Cyanogen Oxygen 4,800 Furnaces • Improved sensitivity. measure of the number of atoms of the metal in the solution Metal Zn Fe Cu Ca Na λ (nm) 214 248 32 5 4 23 589 Atomic Absorption Spectroscopy: An Aussie Invention • Developed by A...

Ngày tải lên: 08/03/2014, 15:35

. codes  2. The messenger RNA leaves the nucleus and attaches to a ribosome in the cytoplasm  3. Transfer RNA brings amino acids to the ribosome to match the sequence codes At the ribosome,  Amino

Ngày tải lên: 13/03/2014, 16:36

. Plot I ds vs. V ds – V gs = 0, 1, 2, 3, 4, 5 – Use W/L = 4/2 λ ( ) 14 2 8 3. 9 8.85 10 35 0 120μA/V 100 10 ox W WW C L LL βµ − −  ×⋅  = = =   ⋅   0 1 2 3 4 5 0 0.5 1 1.5 2 2.5 V ds I ds. contacted diff – ½ C g for uncontacted – Varies with process Lecture 3: CMOS Transistor Theory CMOS VLSI DesignCMOS VLSI Design 4th Ed. 3: CMOS Transistor Theory 2 Outline  Introduction ...

Ngày tải lên: 19/03/2014, 10:20

. new java.util.Date( ); 13 See this code: import java.lang.Math; public class importTest { double x = sqrt(1.44); } Compile: %> javac importTest.java importTest.java :3: cannot find symbol symbol. modifier on a data field when necessary! The default access modifier for fields is package 1 Lecture 3: Object Oriented Programming 20 How the virtual machine located classes?  How to tell th...

Ngày tải lên: 24/03/2014, 03:20