toay 2 viên gạch bông này đến một vị trí giếng nhau được hay không??
b 12)c ww ~ ©
hà
6. Những lình nào đưới đây không giống các hình còn lại?
7. Có bao nhiêu hình vuông mầu den dưới đây? Em hãy viết chi sé vào hình
vuông bên cạnh.
DAP AN aa |
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2 4. Có 7. 41⁄2
BANG PHAN TICH CAC TAN SO LWA CHON TUNG CAU rổ,
(Item Analysis Results tor Observed Responses)
CMe re ree ree ee ee E6 2636 9 (7 S6 6ã CC TT SSS
Trac nghiem : TRI GIAC KHONG GIAN
* Ten nhom lam TN + HOC SINH LOP 5 VÀ 6
* So cau z 40
* So nguoi $ 96
* Do lech TC x 8.197
* Trung binh : 38.240
* Diem be nhat 3 18
* Diem lon nhat : $9
* Trung binh ly thuyet - 50.00
* Do Kho ly thuyet - 62.5 §
* Do Kho Bai TEST (40 cau) = 50.4 $
* He so tin cay bai TEST = 0.625 (cong thuc KUDER RICHARDSON co ban)
* Xu ly luc 3938ph * Ngay 4/ 6/2000
' TY. TY CC OOHRS EEE EEE EEE EEE ERE EE ca... SESE HEHEHE EHEEE EE EEE EEHEHHEEHEH EEE HEHEHE
*** Cau so : 1
Lua chon 0 1 2 Missing
Tan so $ 95 1 6 2 Ti le $ : 99.0 1.0 0.0
Pt-biserial : 0.04 0.05 NA Muc xacsuet : nS NS NA
*** Do Kho cau = 1.01%
onze vs #25 46512/00/99 x26 So'/6s0'6SGcceecvv2ad4a4eee sẽ s62 ô6sxv Lua chon 0 1 2 Missing
Tan 50 $ 28 42 26 2 Ti let $ 29.2 43.8 27.1
Pt-biseriel : -0.22 0.05 0,19
Muc xacsuat : <.05 NS NS
*** Do Kho cau = 710.8 +
Lua chon 6 1 2 Missing Tan 30 H %6 0 0 2
Ti let § 100.0 0.0 0.0
Pt-biserial : 0.08 NA NA
Muc xacsuat : WS NA NA
*** Do Kho cau = 9,0 £
“** Cau so : 4
Lua chon 0 1 2 Missing Tan so 5 59 37 0 5
Tí let 4 61.5 38.5 0.0
Pt-biserial : -0.37 0.42 NA Muc xacsuat : <.01 <,01 NA
*** Do Kho cau * 38.5 8
“eee Cau so : 5 ~ a . , l
Lua chon 0 i 2 Missing Tan so Ệ 85 10 1 4
Trắc nghiệm Tri giác không gian (file tgkg 56.owi) Trang 1/6
Ti le £ ‡ 88,5 10.4 Pt-biserial : -0.14 0.22
Muc xacsuat : NS <.05
*** Do Kho cau * 11.5 %
*** Cau so : 6
Lua chon 0 1 Tan so Ệ 77 19 Ti let : 80.2 19.8
Pt-biserial : 0.08 ~0.03
Muc xacsuat : NS NS
*** Do Kho cau = 19.8 4
ee
*¢* Cau so ; 7
Lua chon 0 1 2 Missing Tan so § 44 0 52 1
Ti let ‡ 45.8 0.0 54.2 Pt-blseria) : 0.28 NA -0.27
Muc xacsuat : <.01 NA <.01
*** Do Kho cau = $4.2 t
Eee Cau so : 8 SSE U00 eS aN OE EN OS ND OES SSE REI RIO
Lua chon 0 1 2 Missing Tan so Ệ 69 0 27 1
Ti let 3 71.9 0.0 28.1
Pt-biserial : -0.33 NA 0.33
Muc xacsuat : <.01 NA <.01
*** Do Kho cau = 28.1 8
ee ee ee
*** Cau so : 9
Lua chon tt) 1 2 Missing
Tan so : 66 9 30 0
Ti le 2 2 68.8 0.9 31.3
Pt-biserial : -0.15 NA 0.15
Muc xacsuat : NS NA NS
*** Do Kho cau = 31.3 t
vs... sox sr toa onc een eena wee C6: 0K ware eed A Kee ae ©:5 6:6')'9:69:6.6.64:6:4:e;©:>:ee/©:e
Lua chon 0 1 2 Missing Tan so : 4 0 92 0
Ti let 3 4.2 0.0 95.8 Pt-biserial : -0.01 NA 0.01
Muc xacsuat : NS NA NS
*** Do Kho cau = 95.8 §
SEETHER
*®*®* Cau so : 11
Lua chon 0 1 Tan so 3 61 0 Tile’ : 63.5 0.0 Pt-biserial : -0.31 NA Muc xacsuat : <.01 RA
*** Do Kho cau = 36.5 $
2
35 36.5 0.31
<.01
Missing 1
DDỤ...:...(...ố...ố...Á...ố...ố...a..a.a.c.. ... cao...
*** Cau so : 12
Lua chon 0 1 Tan so 2 23 b) Tí le + ? 24.0 0.0 Pt-biserial : 0.18 NA
Trắc nghiệm Tri giác không gian (file tgkg $6 o¿)
2
73 76.0
-0.18
Missing
0
Muc xacsuat ; NS NA NS
*** Do Kho cau = 76.0 $£
se* Cau sọ : 13
Lue chon 0 1 2 Missing
Tan so Ệ 36 0 60 0
Ti let 9 32.5 0.0 62.5
Pt-biserial : -0.29 NA 0.29
Mục xacsuat : <.01 NA <.01
*** Do Kho cau = 62.5 %
°** Cau so : lệ
lua chon 0 1 2 Missing Tan 30 H 33 Ũ 63 0
Ti le $ = 34.4 0.0 65.6
Pt-biserial : -0.17 NA 0.17
Muc xacsuat : NS NA NS
*** Do Kho cau * 65.64
°** Cau so : 15
Lua chon 0 1 2 Missing
Tan so ‡ 62 0 34 0 Ti le $ 3 64.6 0.0 35.4
Pt-biserial : ~0.32 NA 0.32 Muc xacsuat ; <.01 NA <.01
*** Do Kho cau ~ 35.41%
eee Cau so : 16
Lua chon 0 1 2 Missing Tan 20 \ 33 1 62 9
Tỉ le t : 34.4 1.0 64.6 Pt-biserial : -0.33 0.05 0.32 Muc xacsuat : <.01 NS <.01
*** Do Kho cau = 65.6%
*** Cau so : 17
Lua chon 0 1 2 Missing Tan so 3 32 9 64 9
Tí let , 33.3 0.0 66.7 Pt-biserial : ~0.17 NA 0.17 Muc xacsuat : NS NA NS
*** Do Kho cau * 66.7 +
*°* Cau so : 18
Lua chon bì 1 2 Missing
Tan so 3 34 0 62 0 Tí le + | 35.4 0.0 64.6
Pt-biserial ; ~0.16 NA 0.16
Muc xacsuat : NS NA NS
*** Do Kho cau = 6&.6 +
REE EEE EEE EEE EEE EERE HEHE EEE EERE
®** Cau so : 19
Lua chon 0 1 2 Missing Tan so 3 1 0 95 0
Ti let š 1.0 0.0 99.0 Pt-biserial : -0.25 NA 0.25 Muc xacsuat : <.05 NA <.05
*** Do Kho cau * 99.0 +
Trắc nghiệm Tri giác không gian (file igkg56.0ut) Trang 3⁄6
v
COO ca... . cao
*** Cau so ; 20
Lua chon 0 1 2 Missing Tan 30 3 28 0 68 2
Ti le 8 3 29.2 0.0 70.8 Pt-biserial : -0.38 NA 0.45
Muc xa@acsuat : <.01 NA <.01
*** Do Kho cau = 70.8%
*** Cau so : 21
Lua chon 0 1 2 Missing Tan so 3 20 20 56 0
Tí let 3 20.8 20.8 58.3 Pt-biserial : -0.42 -0.19 0.51 Muc xacsuat : <.01 NS <.01
*** Do Kho cau = 79.2%
B*e0 93945 s52 rene Xung s2sẽsseebsðÀ6666eâ9 sie 6,2 &:ỏ'š!ằ/4⁄a6â s66 °
Lua chen 0 1 2 Missing Tan so : 26 9 61 1
Ti let ‡ 27.1 9.4 63.5 Pt-biserial : -0.43 -0.17 0.50 Muc xacsuat : <,01 NS <.01
*** Do Kho cau * 12.9 %
sàng ;xờằx/sÀjÀEhbâ-ÀA và cif ew 4.6:6:6/%đ414i016/9:6:66:9)6604/610)4â 12:5 eee eee
Lua chon 0 1 2 Missing
Tan ao ‡ 21 31 4d 0 Ti le + Ù 21.9 32.3 45.8
Pt-biserial : -0.44 0.02 0.35
Muc xacsuat : <.01 NS <.01
*** Do Kho cau = 78.13
sis susie ites Sa 2 Gie%22781á'Àiz'56)G25/G/678029/6ia3E S\G AY6'€:5!8:4678/6:456`4 S:2)k'SKeẲ©zzs
Lua chon 0 1 2 Missing
Tan so FY 10 32 54 1
Tí le $ 3 10.4 33.3 $6.3 Pt-biserial : -0.30 -0.09 0.26 Muc xacsuat : <.01 NS <.01
*** Do Kho cau = 89.6 +
“v4 ror ole! 66sSSsse 496/666 <siv} 4¿4%ăa 6 ;š:cả &'e'6'9:s'ejộ ee ôwie
Lua chon 0 1 2 Missing Tan so $ 70 0 26 i
Ti let 3 72.9 0.0 27.1
Pt-biserial : -0.14 NA 0.16 Muc xacsuat : NS NA NS
*** Do Kho cau = 27.1%
*** Cau so : 26
Lua chon 0 1 2 Missing Tan so 3 23 0 ?3 2
Tỉ le £ Ệ 24.0 0.0 76.0 Pt-biserial : 0.10 NÀ -0.03
Muc xacsuat : NS NA NS
*** Do Kho cau = 76.0 +
Trắc nghiệm Tri giác không gian (file ighgS6.ous)
Lua chon 0 1 2 Missing Tan 30 ‡ 63 0 33 2
Ti le $ š 65.6 0.0 34.4 Pt-biserial : -0.15 NA 0.20 Muc xacsuat : NS NA NS
*** Do Kho cau = 34.4 +
+** Cau so : 28
Lua chon 0 1 2 Missing
Tan so 2 33 0 63 2 Ti let ‡ 34.4 0.0 65.6
Pt-biserial : 0.1 NA -0.06
Muc xacsuat ; NS NA NS
*** Do Kho cau = 65.6 1
*** Cau so : 29
Lua chon 0 1 2 Missing Tan so $ 72 0 24 2
Tí let ‡ 75.0 0.0 25.0
Pt-biserial : -0.22 NA 0.29
Muc xacsuat : <.05 NA <.01
*** Do Kho cau = 25.0 8
re
*** Cau so : 30
Lua chon 0 1 2 Missing Tan so : 63 0 33 2
Ti let 3 65.6 0.0 34.4 Pt-biserial : -0.26 NA 0.31 Muc xacsuat ; <.05 NA <.01
*** Do Kho cau = 34.4 +t
“nee Cau so : 31
Lua chon Ò 1 2 Missing Tan so Ù 87 0 9 1
Ti let Ù 90.6 0.0 9.4 Pt-biserial : ~0.2 NA 0.37
Mục xacsuat : <.01 NA <.01
*** Do Kho cau = 9.4 $
*** Cau so : 32
Lua chon Uì 1 2 Missing
Tan so 3 88 0 8 1 Ti let H 91.7 0.0 8.3
Pt-biserial : -0.26 NA 0.35
Muc xacsuat : <.05 NA <.01
*** Do Kho cau * 9.3 t
s64 cg Ss 5> nương Sas eset Silo eee atin’ di
Lua chon 6 1 2 Missing Tan so : 83 0 13 1
Ti let 8 66.5 0.0 13.5
Pt-biserial : -0.36 NA 0.44
Muc xacsuat : <.01 NA <.01
*** Do Kho cau = 13.5 9
nous 6SS225tetesaas Tan. ca - :
Lue chon 0 1 2 Missing
Trắc nghiệm Tri giác không gian (file ighkgS6.out) Trang 5/6
Tan s0 Ị 57 0 39 1
Ti let : 59.4 0.0 40.6 Pt-biserial : -0.34 NA 0.39 Muc xacsuat : <.01 NA <.01
*** Do Kho cau = 40.6 +
*¢* Cau so : 35
Lua chon 0 1 2 Missing Tan so Ệ 47 0 49 2
Ti let 3 49.0 0.0 51.0
Pt-biserial : -0.14 NA 0.21
Muc xacsuat : NS NA <,05
*** Do Kho cau = $1.08
ed
*** Cau so : 36
Lua chon 0 1
Tan so 3 28 0 Ti let ‡ 29.2 0.0 Pt-biserial : ~0.58 MA
Muc xacsuat : <.01 NA
*** Do Kho cau = 70.8 $
2 Missing
4*4 Cau so : 37
Lue chon 0 1 Tan so $ 5 0 Ti let z 5.2 0.0 Pt-biserial : -0.18 NA
Muc xacsuat : NS NA
*** Do Kho cau = 94.86%
EET a aaa.a..alaa.a. na.
*** Cau so : 38
Lua chon 0 1 Tan so : 21 0 Ti let : 21.9 0.0
Pt-biserial : -0.$7 NA Muc xacsuat : <.01 NA
*** Do Kho cau = 18.1 +
*** Cau so : 39
Lue chon i] 1
Tan so ì 65 1 Ti let H 67.7 1.0
Pt-biserial : -0.35 0.12 Muc xacsuat : <.01 NS
*** Do Kho cau = 32.3%
30 31.3 0.4
<.01
Missing
ee ee ee . -j àaoc..a.a. cha
*°** Cau so : 40
Lua chon 0 1 Tan so C 55 0
Ti let Fi 57.3 0.0
Pt-biserial : -0.40 NA Muc xacsuat : <.91 NA
*** Do Kho cau = 42.7 t
Trắc nghiệm Tri giác không gian (file igkgS6.0ut)
2 Missing
4i 1 42.7
0.45
<.01
ane HET ..e*..
BANG PHAN TICH CAC TAN SO LUA CHON TUNG CAU
(Item Analysis Results for Observed Responses)
<=
Trac nghiem : TRI GIAC KHONG GIAN
* Ten nhom lam TN HOC SINH LOP 7, 8 VA 9
* So cau 8 40
* So nguoi 3 124
* Do lech TC Ệ 10.170
* Trung binh - 31.750
* Diem be nhat t 0
* Diem lon nhat : s3
* Trung binh ly thuyet - 50,00
* Do Kho ly thuyet - 62.5 %
* De Kho Bai TEST (40 cau) = 41.4 +
* He so tin cay bai TEST = 0.745 {cong thuc KUDER RICHARDSON co ban)
* Xu ly luc 3g5lph * Ngay 4/ 8/2000
J
*** Cau ao 7s foo
Lua chon 0 1 2 Missing
Tan so 8 121 3 0 11 Ti let 8 97.6 2.4 0.0
Pt-biserial : 0.2 “0.11 NA Muc xacsuat : <.05 NS NA
*** Do Kho cau = 2.4%
SẺ? TH g: 5.2 ”c<c666266369662aeasesee ii soeeeoa2csee22v4524esešssaeeza
Lua chon 0 1 2 Missing
Tan so 3 85 38 1 lá
Ti le Ệ 68.5 30.6 0.8
Pt-biserial : 0.01 0.06 0.07
Muc xecsuat : NS NS NS
*** Do Kho cau = 31.5%
*°* Cau so : 3
Lua chon 0 1 2 Missing
Tan so 3 124 0 0 15 Ti let Ệ 100,0 0.0 0.0
Pt~-biserial : 9.13 NA NA Muc xacsuat : NS NÀ NA
*** Do Kho cau = 0.0 8
px 4218 nnn SesS
Lua chon 0 1 2 Missing Tan so $ 123 1 0 25
Tí le £ : 99.2 0,8 0.0
Pt-biserial : 0.28 0.03 NA
Muc xacsuat : <.01 NS NA
*** Do Kho cau = 0.8 $
XJJW0VGĐSS BS NI Ni ennai a ints area RANTS RIA ANN ROR
Lua chon 0 1 2 Missing Trắc nghiệm Tri giác không gian (file TGKG789.0ut)
Tan so : 122 2 0 26 Ti let 3 98.4 1,6 0.0
Pt-biserial : 0.26 -0.02 NA Muc xacsuat : <.01 NS NA
*** Do Kho cau = 1.6 %
*** Cau so : 6
Lua chon 0 1 2 Missing Tan so ‡ 124 0 0 21
Tí le $ E 100.0 0.0 0.0 Pt-biserial : 0.26 NA NA Muc xacsuat : <.01 NA NA
*** Do Kho cau = 0.0 (
`" ..._._.._._._...Ắ.Ố.ỐK.Ốố..lddraoao - cao.
*** Cau so : 7
Lua chon 0 1 2 Missing Tan so : 56 0 68 5
Ti le £ : 45.2 0.0 54.8
Pt-biserial : 0.09 NA 0.10 Muc xacsuat : NS NA NS
*** Do Kho cau = 54.8 +
*°* Cau so : 8
Lua chon 0 1 2 Missing
Tan so — 24 0 100 5 Ti let 2 19.4 0.0 80.6
Pt-biserial : 0.00 NA 0.23
Muc xacsuat : NS NA <.01
*** Do Kho cau ô 80.6 1
*** Cau so : 9
Lua chon 0 1 2 Missing Tan so : 109 0 15 5
Ti let Ệ 67.9 0.0 12.1 Pt-biserial : 0.45 NA -0.22 Muc xacsuat : <.01 NA <.05
*** Do Kho cau = 12.1 t
*** Cau so : 10
Lua chon 0 1 2 Missing Tan so Ệ 104 0 20 5
Ti let Ù 83.9 0,0 16.1 Pt-biserial : 0.33 NÀ -0.11
Muc xacsuat : <.01 NA NS
*** Do Kho cau = 16.1 %
Sa 16A meee OO OT TS Oe ơ
Lua chon 0 1 2 Missing Tan so 8 44 0 80 8
Tí let Ệ 45.5 0,0 64.5 Pt-biseriaì : -0,09 NA 0.29 Muc xacsuat : NS NA <.01
*** Do Kho cau = 64.5 +
DEW, EENENANGSEENEMEIHHEGOGVERUENUDIORORITIẾ S09S©ši6š691(4()44/6€56%6/66sẽ Lua chon 0 1 r 3 Missing
Tan so Ệ 34 0 90 7
Trắc nghiệm Tri giác không gian (file TGKG789.0u!) Trang 2⁄6
Ti le + Ệ 27.4 0.0 72.6 Pt-biserial : -0.09 NÀ 0.29 Muc xacsuat : NS NA <.01
t*“* Do Kho cau = 72.6 1
*** Cau so : 13
Lua chon 0 1 2 Missing Tan so 3 36 0 88 a
Tí let g 29.0 0,0 71.0
Pt-biserial : -0.26 NA 0.43
Muc xacsuat : <.01 NA <.01
*** Do Kho cau = 71.0%
*** Cau so : lá
Lua chon 0 1 2 Missing Tan so Ệ 69 0 55 7
Ti let 3 55.6 0.0 44.4 Pt-biserial : -0.10 NA 0.36 Muc xecsuat ; NS NA <.01
*** Do Kho cau = 44.4 1
ơ...Ắ....Ắố...ac....c...ố...ố.ố..ố...ố..(..ố...ố....Áốaố....ÁaẶÁa.a....Á.aẶ...-. ca
*** Cau so : 15
Lua chon 0 1 2 Missing Tan so š 51 0 73 7
Ti lo $ E 41.31 0,0 58.9 Pt-biserial : ~0.17 NA 0.43 Muc xacsuat : NS NA <.01
*** Do Kho cau = 58.9 +
*** Cau so : 16
Lua chon 0 1 2 Missing Tan so = 37 0 87 7
Tỉ le %# $ 29.8 0.0 70.2 Pt-biserial : -0.06 NA 0.34
Muc xacsuat : NS NA <.01
*** Do Kho cau = 70.2 4
*®** Cau so : 17
Lua chon 0 1 2 Missing
Tan so = 85 9 39 9
Ti le £ $ 68.5 0.0 31.5 Pt-biserial : 0.23 NA 0.00 Muc xacsuat : <.01 NA NS
*** Do Kho cau ô 31.5 8
*** Cau so : 18
Lua chon 9 1 2 Missing Tan so Ệ 60 0 64 9
Tí let ‡ 48.4 0.0 51.6
Pt-biserial : -0.01 NA 0.30
Muc xacsuat : NS NA <.01
*** Do Kho cau = $1.61
Z Canceg 235° 2. " peeaaaeeoeer..ệạ
Lua chon 0 1 2 Missing Tan so ‡ 52 6 66 17
Ti let 3 41.9 4.8 $3.2 Pt-biserial : ~0.0 0.01 0.35
Trắc nghiệm Trí giác không gian (file TGKG789.0ut) Trang 345
Muc xacsuat ;: NS NS <.01
*** Do Kho cau * 58.1%
Nee Cau so; 200” “
Lua chon 0 i 2 Missing
Tan so 3 21 3 94 12
Ti let 8 21.8 2.4 75.8 Pt-biserial : -0.17 0.06 0.50
Muc xacsuat : NS NS <.01
*** Do Kho cau = 78.2%
BR Ei erapit a lala c66e6xiessš¿&s “áZzá£YYeseksvzs¿AY<%s6<
Lua chon 0 1 2 Missing
Tan 4© ‡ 23 38 63 12 Ti lel : 18.5 30.6 50.8
Pt-biserial : -0.12 0.05 0.35 Muc xacsuat : NS NS <.01
*** Do Kho cau ô 61.5 9
*¢* Cau so : 22 . . :
Lua chon Ô 1 2 Missing
Tan so ‡ 26 12 81 15
Ti le £ 3 21.0 13.7 65.3
Pt-biserial : -0.,13 0.05 0.44
Muc xacsuat : NS NS <.01
*** Do Kho cau = 79.0 8
a Me MCE CC :
Lua chon 0 ì 2 Missing Tan so $ 25 11 88 18
Tỉ let Ệ 20.2 8.9 71.0 Pt-biserial : -0.2 -0.04 0.56
Muc xacsuat ; <.05 NS <.01
*** Do Kho cau = 79.8%
wee Pee ee eee eee ee ee eee ee eee eee ee eee ee ee eee eee eee eee eee eee eee eee
*** Cau so : 24
Lua chon 0 1 2 Missing Tan 30 : 49 44 31 18
Ti le $% Ệ 39.5 35.5 25.0
Pt-biserial : -0.07 0.17 0.34 Muc xacsuat : NS NS <.01
*** Do Kho cau = 60.5 +
e** Cau so : 25
Lue chon 9 1 2 Missing
Tan so L 86 0 38 15 Ti let L 69.4 0.0 30.6
Pt-biserial : 0.17 NA 0.19 Muc xacsuat : NS NA <.05
*** Do Kho cau = 30.6%
*** Cau so : 26
Lua chon 0 1 2 Missing Tan so 8 75 0 49 7
Tilet s 69.5 9.0 39.5 Pt-biserial : -0.09 NA 0.37 Muc xacsuat : NS NA <.01
*** Do Kho cau * 39.5 +
Trắc nghiệm Tri giác không gian (file TGKG789 out) Trang 44
Tee eee eee ee eee ee eee eee eee eee eee eee eee eee eee eee eee eee can.
¢** Cau so : 27
Lua chon 0 1 2 Tan so kì 64 0 60 Tí le *% ‡ 51.6 0.0 48.4
Pt-biserial : -0.06 NA 0.33
Muc xecsuat : MS NA <.01
*** Do Kho cau = 40.4 +
*¢* Cau so : 28
Lua chon 0 1 2 Tan so 8 81 0 43
Tí let Ệ 65.3 9.0 34.7 Pt-biserial : ~0.05 NA 0.32 Muc xacsuat : NS NA <.01
*** Do Kho cau = 34.718
Missing
CORRE ERE EERE EEE EEE EEE HO OEE EEE EEE EEE HEHEHE HEHEHE EEEEEEHEE HEE EE EHEEEE
*®** Cau so : 29
Lua chon 0 1 2 Tan so : 82 1 41 Ti le? : 66.1 0.8 33.1 Pt-biserial : 0.00 -0.02 0.28 Muc xacsuaL ; MS NS <.01
*** Do Kho cau = 33.9 8
w Cau so : 30 mua. k“
Lua chon 0 1 2 Tan 30 ‡ +1 0 47 Ti le £ Ệ 62.1 0.0 37.9
Pt-biserial : -0.0 NA 0.36 Muc xacsuat ; WS NA <.01
*** Do Kho cau = 37.9 4
“nee Cau so : 31 l m8
Lua chon 0 1 2 Tan so 3 85 1 38 Ti le $ é8.5 0.8 30.6 Pt-biserial : 0.02 -0.02 0.35 Muc xacsuat : NS NS <.01
*** Do Kho cau = 31.5 8
*** Cau so : 32
Missing
Lua chon 0 1 z Missing Tan so Ệ 92 0 32 16
Ti let ‡ 74.2 0.0 25.8 Pt-biserial : -0.07 NA 0.42
Muc xacsuat : NS NA <.01
*** Do Kho cau = 25.8 3
See ag Scble is! Shwreiatmcer tá) 2/2 22a 2S Mine << RRR yee EUR Ae
Lua chon 0 1 2 Missing
Tan so t 94 0 30 15
Tí le $ 8 75.8 0.0 24.2 Pt-biserial : 0.12 NA 0.24 Muc xacsuat : NS NA <.01
*** Do Kho cau = 24.2 %
P9028 SA22%55355 20 beet ộâ46466u<ấtsâ66s64e664129466666v944eôveezbề Se ST
Trắc nghiệm Tri giác không gian (file TGKG789.0us) Trang 54
Lua chon 0 l 2 Missing
Tan xo 12 0 52 17 Ti le & ° 58.1 0.0 41.9
Pt-biserial : -0.10 NA 0.42 Muc xacsuat ; ws NA <.01
*** Do Kho cau ô 41.914
— ... Cau so : 35
Lua chen 0 1 2 Missing
Tan so 4 97 0 21 17
Ti let : 78.2 0.0 21.8 Pt-biserial : 0.02 NA 0.43
Muc xacsuat ; NS NA <.01
*** Do Kho cau = 21.8 8
*** Cau so ; 36
Lua chon 0 1 2 Missing Tan se ‡ 58 0 66 7
Tỉ let £ 46.8 0.0 $3.2 Pt-biserial : -0.21 NA 0.49 Muc xacsuat : <.05 NA <.01
*** Do Kho cau = 53.2%
“*“* Cau so ; 37
Lua chon 0 1 2 Missing
Tan so : 93 0 31 9 Ti let $ 75.0 0.0 25.9
Pt-biserial : -0.10 NA 0.45
Muc xacsuat : NS NA <.01
*** Do Kho cau = 25.0%
Lua chon 0 1 2 Missing Tan so H 63 9 61 7
Ti let 8 50.8 0.0 49.2 Pt-biserial : -0.09 NA 0.3
Muc xacsuat : NS NA <.01
*** Do Kho cau = 49.214
ee
4** Cau so : 39
Lua chon 0 1 2 Missing Tan so ! 81 0 31 8
Tí let : 70.2 0.0 23.8 Pt-biserial : 0.91 NA 0.31
Muc xacsuat : NS NA <.01
*** Do Kho cau = 29.8%
Lua chon i) 1 2 Missing
Tan so H 93 0 31 9
Ti let : 75.0 0.0 25.0 Pt-biserial : 0,05 NA 0,29 Muc xecsuat : NS NA <.01
*** Do Kho cau = 25.0 +
eee HET .“c...
Trắc nghiệm Tri giác không gian (file TGKG789 oul)
45
BANG PHAN TICH CAC TAN SO LUA CHON TUNG CAU {Item Analysis Resuits for Observed Responses)
Trac nghiêm ¡ TRI GIAC KHONG GIAN (lan thu 2)
* Ten nhom lam TN : HOC SINH LoP 5 VÀ 6
° So cau : 40
* So nguoi ‡ 200
* Do lech TC § 11.263
* Trung binh ‡ 36,255
* Diem be nhạt $ l4
* Diem lon nhat : 63
* Trung binh ly thuyet = 50,00
* 0o Kho ly thuyet = 62.5 %
* Do Kho Bai TEST (40 cau) = 45,3 4
* He so tin cay bai TEST = 0.797 fcong thuc KUDER RICHARDSON co ban)
* Xe ly luc 16g Oph * Ngay 29/ 9/2002
Cee
ed ... -ˆˆˆˆễễệễệễŠệ`ễệ `ễệ`...Ắ...Š.Š5...
eee Cu so 3 31
Lee chon 0 1 2 Missing
Tan so : 185 13 1 3 Ti le 34 : 92.5 5.5 0.5
Pe-biserial : -0.12 0.19 0.10 Muc xacsuat : NS <.03 nS
*** Do Kho cau ô 6.0 4
°*°* Cau so : 2 ơ
Lua chon 9 1 2 Missing Tan 4o ' 7 65 47 11
Ti le + ‡ 38.5 32.5 23.5 Pr-bisersal : “0.42 0.03 0.55
Mục xacsuat : <.0 NS <.0ì
*** Oo Kho cau = 56.0 %
°“* Cau so : 3
Lua chon 0 1 2 Missing
Tan so ơ 183 Z| 0 14
Ti le % § 91.5 1.5 0.0 Pt-bisorial : 0.19 0.09 NA Muc xacsuat : <.01 NS NA
*** Do Kho cau = 1,5 6 eee Cau so : 4
Lua chon 0 1 2 Missing
Tan ao ‡ % 79 6 22 Ti le t : 45.5 39.5 4.0
Pt-biserial : ~0.38 0.4€ 0.28 Muc xacsuat : <,01 <,01 <.01
*** Do Kho cau = 43.5%
22° CAU Sa có `
Loa chon 0 1 2 Missing
Kết quá phần lich bài, cầu Tex TG KG the 2 (nhóm 10-12 tuổi} Trang 1/1
Tan so $ 166 12 1 21 1€
Ti les Ệ 93.0 6.9 0,5 Pt-biserial : 0.02 0.23 0.14 Muc xacsuat : ns <.01 MS
*** Do Kho cau ô 6.5%
eee ee ee ... (AC... ... nh. ...ố... ỐC...
°°* Cau so : 6
Lua chon 0 1 2 Missing Tan so ‡ 150 22 0 26
Ta le} : 75.0 11.0 0.0 Pt-biserial : 0.08 0.19 NA Muc xacsuat : NS <.01 NA
*** Do Kho cau * 1.0 @
°** Cau so : 7
Lua chon 9 3 2 Missing Tan so Ệ 58 0 140 2
Ti le \ : 29.0 0.6 76.0
Pt-biserial : 0.30 NA -0.28
Muc xacsuat : <.,0ì NA <.01
*** Do Kho cau = 70,0 4
°*°* Cau so : 8 " : ẽ
tua chọn 9 3 2 Missing
Tan so ‡ 146 9 $3 1
Ti le & : 73.0 0.0 26.5
Pt-biserial : -0,4 NA 0.45
Mục xacsuat : <.01 nA <.01
*** Do Kho cau = 26.5 +
°°*° Cau so : 9
Lua chon 9 ì ? Missing Tan so : 138 9 61 1
Ti le & 2 69.0 0.0 30.5 Pt-blserial : -0.30 NA 0.32 Mục xacsvat : <.01 NA <,03
*** Do Kho cau * 30.5 6
*** Cau so : 10
Lua chon © 1 2 Missing
Tan 40 2 ` bì 193 1
Tí le & : 3.0 0.9 96.5
Pt-biserial : -0.07? NA 0.11
Muc xacsuat : ns NA nS
*** Do Kho cau = 96.5 +
*** Cau so : 11
Lua chon © 1 2 Missing
Tan 30 5 135 fe) 63 2
Ti le \ = 67.5 0.0 31.5 Pt-biserial : -0,3? NA 0.40 Muc xacsuat : <.01 NA <.01
*** Do Kho cau = 32.5 %
*** Cau so : 12
Lue chon G i 2 Missing Tan so t SỐ 9 145 5
Ti le & 2 25.0 0.0 72.8 Pt-biserial : 0.14 RA -0.06
Kết quả phần (Ích hài, câu Test TG KG the 2 (nhóm 100-12 tuổi) Trang 2⁄2
Muc xacsuat : NS NA
*** Do Kho cau = 72.5 t
°** Cau so 13
Lua chon ũ 1 Tan so 66 0 Ti le *% 34,0 0,0 Pt-biserial : -0,37 NA
Muc Xacsuat : ô.f01 NA
°®°* Do Kho cau = 64.5 +
eee Cau go : l4
Lua chon 0 l
Tan 30 al ©
Ti le’ : 20.5 0.0 Pt~biaerlali : -0.13 NA Muc xacsuat : NS NA
*** Do Kho cau # 78.0 +
°°*° Cau 30 15
Lua chon 0 1 Tan so 3 125 ọ Ti le & : 62.5 9.0
Pt-biserial : -0,33 NA
Muc xacsuat : <,01 NA
*** Do Kho cau ~ 35.5 9 ees Cau go : 16
lua chon 9 1
Tan 80 83 9 Ti le + 3 41.5 0.9 Pt-biserial : ~0.53 NA Muc xacsuat : <,01 NA
*** Do Kho cau ~ $6.5 +
*** Cau so 1?
Lua chon 0 1
Tan so 2 §3 0 Tí le & ° 26.5 0.0 Pt-biserial : -0,10 NA Muc xacsuat : NS NA
*** Do Kho cau * 71.0 4
Đà tinh “+ sáa( S4 mele’
Lua chon 9 1
Tan sơ : 18 9 Ti leằ : 39.0 0.0 Pt-bisecial : -0.35 NA Muc xacsuat : <,01 NA
*** Do Kho cau = $7.0 %
°°* Cau so : 19
Lua chon 0 ì Tan so 3 9 0 Ti let ‡ 4,5 0.0 Pt-biserial : -0.30 NA
Moc xacsuat : <.01 NÀ
*** Oo Kho cau =
...
95.0 %
ed
...
Kết quả pide tích bai, câu Text TG KG lắn 3 (sbóm 1): |2 toi
7
35.5 0.36
‹<,01
xố...
es
2 113 56.5 0.58
<,01
142
71.0
0,18
‹,05
Missing
4ÿ
*°* Cau so =: 20
Lea chon 0 by 2 Missing
Tan so : s3 0 123 24 Tí le & : 26.5 6.6 61.5
Pt-biserial : “0.39 NA 0.54 Muc xacsuat : <.03 NA <.01
°**° Do Kho cau = 61,5 £
Cua chon 9 1 2 Missing Tan so 3 ss 0 137 8
Ti le ( : 27.5 6.0 68.5 Pt-biserial : -0,46 NA 9.51 Muc xacsuat : <,01 NA <,0)
Lua chon 0 1 2 Missing Tan so 3 58 ° 128 l4
Tí le % 3 29.0 0.0 64.0 Pt-biserial : -0.40 NA 0.54 Muc xacsuat : <,01 NA <.01
*** Do Kho cau * 64.0 $
S52 0U lào: lo Hố, 7777 77277907700000044005051n4€7E vEẾV chu)? KEE- XA/SĐASXNNAY VỤ. Êt AÃ xế
Lua chon 0 1 2 Missing
Tan sơ = 94 © s6 18
Ti le 4 s 47.0 0.© 480 Pt-biserial : -0.31 NA 0.39 Muc xacsuat : <,0I NA <,01
*** Do Kho cau ô 49.0 $
MS lin ge wae baleen ake 2 PPE RT ier OOO PPO (xả Lua chon i) 1 2 Missing
Tan so 3 62 i 124 13
Ti le W Ệ 31.0 0.5 62.0
Pt-biserial : -0.36 -0.06 0.48 Mục xacsuat : <-0! Ns <.01
*** Do Kho cau = 62.5 %
ees Cau so : 25
Lua chon 0 i 2 Missing Tan so Ệ 162 9 33 5
Tí le & 3 81.0 0.0 16.5 Pt-biserial : -0.0 NA 0,13 Muc xaocsuat : NS NA MS
*** Do Kho cau " 16.5 $®
*** Cau sơ : 26
Lua chon 0 1 2 Missing Tan so Ị 58 0 135 3
Ti le \ ‡ 29.0 0.0 67.5 Pt-biserisi : 0.12 NA -0.00
Mục xacsuat : NS NA NS
*** Do Kho cau = 61.5 %®
ees Cau sợ ; 27
Lua chon 0 1 2 Missing
Kết gud phân lich bài. câuTew TG KG lắn 2 (nhám 16-12 tuổi] Trang 4/4
AY
Tan s¢ ; 127 0 64 8 T3 le 4 ‡ 63.5 ọ.0 32.0
Pt-biaserial : -0,20 NA 0.3:
Mục xacsuat : <,0] NA <.01
*** Do Kho cau = 42,5% *
¡223 chà const 65e%3/0 E66 sbs 014 xã á'6/e/e s405/612324)4:26 615266 4134066
tua chon 8 i 2 Missing
Tan so 3 40 0 151 9
Ti le ¥ : 20.90 9.9 ‘Gee
Pt-biserial : 0.17 NA -0.02 Muc xacsuat : <.05 NA NS
*** Do Kho cau - 7.5 2
° S1 TỶ PT ores S8 SS ent cEC s53 Se ROME 52s mssnãn 555805 đang .
Lua chon 0 1 ? Missing Tan so 3 155 0 37 8
Ti le È : 11.5 6.0 18.5 Pt-biserial : 0.04 NA 0.09
Muc xacsuat : NS NA NS
*** De Kho cau * 16,5 4
*** Cau so : 30
Lua chon bì 3 2 Missing
Tan so ‡ 141 0 s4 s
Tí le‘ ‡ 10.5 0.0 21.0 Pe-biserial : -0.09 NA 0.18
Mục xeacsuat : NS NA <.95
*** Do Kho cau = 21.0 3%
*** Câu go : 31 oo
Lua chon 0 1 2 Missing
Tan so : 138 9 $4 1â Tí le 4 : 63.0 0.0 22.0
Pt-biserial : -0.14 NA 0.31 Mục xacsuat : MS NA <.01
*** Do Kho cau - 22.0%
*** Cau so : 32
Lea chon 0 1 2 Missing
Tan so $ 182 0 30 18 Tí let Ệ 76.0 0.0 15.0
Pt-biserial : -0.11 NA 0.38
Muc xacsuat : NS NA <,01
*** Do Kho cau = 15.0 *
*** Cau go : 33
Lua chon 0 1 2 Missing Tan so : 144 9 36 28
Tí le * : 72.0 0.0 18.0
Pt-biserial : ~Ẩ0,16 NA 0,41
Muc xacsuat : <.05 NA <.01
*** Do Kho cau ~ 18.0 %
*®** Cau so : 34
Lue chon 9 1 2 Missing
Tan so : 97 ° 78 25
Ti le ( ‡ 48.5 0.0 39.0 Pt-biserial : -0.21 NA 0.3?
Kết quá phần tích hài, cầu Test TG KG la 2 (nhóm 10-12 tuổi) Trang S/S
Muc xacsuat : ‹,0I NA <,01
*** Do Kho cau * 39.0 +
*°** Cau so : 35
Lua chon 0 1 2 Missing Tan so F a 0 86 23
Ti le + t 45.5 6.0 43.0 Pt-biserial : 0.01 NA 0-23 Mục xacsuat : NS NA <.01
*** Do Kho cau * 43.0 %
Lua chon 9 i 2 Missing
Tan so 3 66 ũ 1i9 13 Ti le 4 Ệ 34.0 0.0 59.5
Pt-biserial : -0.5%7 NA 0.70
Mục xacsuat : <.01 NA <,01
*** Do Kho cau = 59.5 9
—... Ce a
ee? Cau so : 37
Lua chon 0 i 2 Missing Tan so Ù 20 1 161 is
Tí le % › 10.8 0.5 60.5
Pt-biserial : -0.29 -0.10 0.45
Mục xacsuat : <.0I MS <,0I
*** Do Kho cau =7 61.0
*** Cau so : 38
Lua chon 9 1 2 Missing
Tan so 2 $s? 0 122 z1
Tí le 4 28.5 0.0 61.0
Pr-biserial : -0.50 NA 0.66
Mục xacsuet : <.Ct NA <.91
*** Do Kho cau = 61.0 *
...
...Á...n:
°** Cau so : 39
Lua chon 0 1 2 Missing Tan so C 36? 0 55 38
Ti le 4% H 33.5 0.0 27.5
Pt-biserial : -0.24 NA 0.61 Mục xacsuat : <.01 NA <.01
*** Do Kho cau * 21.5 %
Lua chon 0 1 2 Missing
Tan 4o ‡ 76 0 87 37 Tí le + ‡ 36.0 0.0 43.5
Pe-bisersal : -0.36 NA 0.65 Mục xacsuat : <.01 NA <.0ì
*** Do Kho cau * 43.5 $
eee eee eee ee ee ee
... HET ****
Kết quả phán lích bài. cáuText TG KG Un 3 (ahd 10-13 tuối]